BellworkFor the following problems, use A(5,10), B(2,10), C(3,3)•Find AB•Find the midpoint of CA•Find the midpoint of AB•Find the slope of AB

Bellwork SolutionFor the following problems, use A(5,10), B(2,10), C(3,3)•Find AB

Bellwork SolutionFor the following problems, use A(5,10), B(2,10), C(3,3) Find the midpoint of CA

Bellwork SolutionFor the following problems, use A(5,10), B(2,10), C(3,3)•Find the midpoint of AB

Bellwork SolutionFor the following problems, use A(5,10), B(2,10), C(3,3)•Find the slope of AB

Use Perpendicular BisectorsSection 5.2

Use Angle Bisectors of Triangles

Section 5.3

Use Medians and Altitudes

Section 5.4

The ConceptYesterday we investigated the concept of circumcentersToday we’re going to look at a couple of other kinds of

points of concurrencyWe’ll look at each of the theorems that helps us to

create these points, while also enhancing our understanding of triangles

Isosceles TrianglesWhat is the hallmark of an Isosceles Triangle?

A

Isosceles triangles can also be made by combining two right triangles

A

This creates a situation in which the base is twice the size of the previous triangle, as well the two end vertices are equidistant to the top vertex

Perpendicular BisectorsThis isosceles triangle is also created when a perpendicular

bisector extends from a point to a line segment

A A

This gives us the Perpendicular Bisector Theorem

B B

TheoremsTheorem 5.2: Perpendicular Bisector Theorem

In a plane, if a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.

C

B

Theorem 5.3: Converse of the Perpendicular Bisector TheoremIn a plane, if a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment

A

ExampleFind the length of segment AB

5x

CD

B

A

4x+3

TheoremTheorem 5.4: Concurrency of Perpendicular Bisectors of a

TriangleThe perpendicular bisectors of a triangle intersect at a point that is equidistant from the vertices of the triangle

This point is called the circumcenter which means all circles created from it will include all of the vertices

TheoremsTheorem 5.5: Angle Bisector Theorem

If a point is on the bisector of an angle, then it is equidistant from the two sides of the angle.

C

B

Theorem 5.6: Converse of the Angle Bisector TheoremIf a point is in the interior of an angle and is equidistant from the sides of an angle, then it lies on the bisector of the angle

AD

ExampleFind x

C

B

AD

x

15

27o

27o

ExampleFind x & y

C

B

AD

5y-8

3y+12

35o

4x-1o

TheoremTheorem 5.7: Concurrency of Angle Bisectors of a Triangle

The angle bisectors of a triangle intersect at a point that is equidistant from the sides of the triangle

This point of concurrency is

called the incenter. Circles centered at this point will equally touch all three sides of the

triangle

Homework

5.2 Exercises1-9, 16, 17, 20-255.3 Exercises3-20, 24, 25

Theorems

Theorem 5.8: Concurrency of Medians of a TriangleThe medians of a triangle intersect at a point that is two thirds of

the distance from each vertex to the midpoint of the opposite side

Median: Segment from the vertex of a triangle to the midpoint of the opposite side

This point of concurrency is

called the centroid. The centroid is the

center of area of the object. It’s the point on which we could balance the

entire object

ExampleFind x

10

x

ExampleFind x & y if EB=15 and DA=14

A

2x-1

BC

D

E

F

G y+2

3y

DefinitionAltitude:

Perpendicular segment from a vertex to the opposite side or to the line that contains the opposite side

TheoremsTheorem 5.9: Concurrency of Altitudes of a TriangleThe lines containing the altitudes of a triangle are concurrent

Orthocenter

Homework

5.4 Exercises1-7, 12-15, 25-28, 33-35,39

Most Important Points• Perpendicular Bisector Theorem• Circumcenters• Angle Bisector Theorem• Incenters• Medians• Centroids• Altitudes• Orthocenters