formula estimate
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DETAILED OF THE CONSTRUCTION ESTIMATE
CONCRETE MATERIALS : FOOTING 1
CLASS "A" MIXTURE
FOOTING DEMINSION
LENGTH: 1.2 m
WIDTH: 1 m
THICK: 0.35 m
VOL. OF FOOTING 0.42 cu.m.
TOTAL VOLUME OF THE 12 FOOTING
VOLUME= 5.04 cu.m.
CEMENT: 5.04 x 9 = 45.36 bags
SAND: 5.04 x 0.5 = 2.52 cu.m.
GRAVEL: 5.04 x 1 = 5.04 cu.m.
REINFORCE BARS MATERIALS : FOOTING 1
NET LENGTH :
1.2 - 0.075 + 0.075 = 1.05 m
TOTAL NO. OF CUT BARS IN ONE FOOTING BY DIRECT COUNTING
6 x 2 = 12 pcs
TOTAL NO. OF BARS FOR THE 12 FOOTING
12 x 12 = 144 pcs @ 1.05 m
SELECT THE STEEL BARS WHOSE LENGTH IS ECONOMICALLY CUT INTO 1.05 M LONG
6 / 1.05 = 5.714 pcs
Divide the result:
144= 29 pcs of 16mm diameter bars
5
TIE WIRE
NUMBER OF THE BAR INTERSECTION IN ONE FOOTING
6 x 6 = 36 ties
TOTAL TIES FOR 12 FOOTINGS
12 x 36 = 432 ties
Using 0.25 m length per tie= 432 x 0.250 = 108 meters
One kilo of no. 16 G.I. wire is approximately 30 m
108 / 30 = 3.6 kilos
CONCRETE MATERIALS : FOOTING 2
CLASS "A" MIXTURE
FOOTING DEMINSION
LENGTH: 1 m
WIDTH: 1 m
THICK: 0.35 m
VOL. OF FOOTING 0.35 cu.m.
TOTAL VOLUME OF THE 4 FOOTING
VOLUME= 1.4 cu.m.
CEMENT: 1.4 x 9 = 12.6 bags
SAND: 1.4 x 0.5 = 0.7 cu.m.
GRAVEL: 1.4 x 1 = 1.4 cu.m.
REINFORCE BARS MATERIALS : FOOTING 2
NET LENGTH :
1 - 0.075 + 0.075 = 0.85 m
TOTAL NO. OF CUT BARS IN ONE FOOTING BY DIRECT COUNTING
5 x 2 = 10 pcs
TOTAL NO. OF BARS FOR THE 4 FOOTING
10 x 4 = 40 pcs @ 0.85 m
SELECT THE STEEL BARS WHOSE LENGTH IS ECONOMICALLY CUT INTO 0.85 M LONG
6 / 0.85 = 7.0588 pcs
Divide the result:
40= 6 pcs of 16mm diameter bars
7
TIE WIRE
NUMBER OF THE BAR INTERSECTION IN ONE FOOTING
5 x 5 = 25 ties
TOTAL TIES FOR 4 FOOTINGS
4 x 25 = 100 ties
Using 0.25 m length per tie = 100 x 0.250 = 25 meters
One kilo of no. 16 G.I. wire is approximately 30 m
25 / 30 = 0.8 kilos
COLUMN 1 TIES :
HEIGHT FROM GROUND LINE TO BEAM
HT. = 6.6 Mtrs. @ 0.2 m. spacing
- Divide:6.6 = 44 pcs0.2
- Total ties of the columns= 12
- Multiply:12 x 44 = 528 pcs
- Length of one lateral ties1.45 m. long cut from a 6.00 m. steel bars
6 = 5 pcsw= 0.275 1.45
- Result528 = 104 pcs- 10 mm ties bars
d= 0.45 10 pcs 5tiesl bars
- Tie wireno. of ties in a column
6 x 44 = 264
total wire for the 12 columns264 x 12 = 3168 pcs
multiply:3168 x 0.25 = 792 m
One kilo of no. 16 G.I. wire is approximately 35 m
792 / 35 = 22.6 kilos
w= 0.275 12 column post
A= 7.5
d= 0.45 6bars
B= 0.200
TOTAL = 7.6 mtrs. Length
Result:no. of vertical bars 8 pcs of one column
Total of vertical bars = 99.94 pcs 16mm vertical bars