friction kinetic friction: f k - friction force n - normal force - coefficient of kinetic friction...
TRANSCRIPT
Friction
Nf kk
Nf ss
Kinetic friction:
fk- friction forceN - normal force
k - coefficient of kinetic friction
Static friction:
- coefficient of static frictionssk
Fbook,hand Nbook,wall
fS,book,wall
Wbook,Earth
For the book not to fall down, fS = W
Pushing harder (increasing Fbook,hand) increases Nbook,wall and therefore fS,MAX increases, but not the actual value of fS that we had, which needs to continue to be exactly W.
Example: When you push a book against a wall, the static friction between the wall and the book can prevent it from falling.
If you press harder, the friction force will be:
A. Larger than before
B. The same
C. Smaller than before.
Example: A 49 kg rock climber is climbing a “chimney” between two rock slabs. The coefficient of static friction between her shoes and the rock is 1.2; between her back and the rock it is 0.80. She has reduced her push against the rock until her back and her shoes are on the verge of slipping. What is her push against the rock?
W
N
Nfs backfs feet
x
y
N
fS backfS feet
N
w
0 :
0 :
,,
yfeetSbackS
x
mamgffy
maNNx
If the climber dos not slip or move up, the value of the sum of frictional forces is fixed:
mgff feetSbackS ,,
S SS,back S,f eet
S
with
I f is large enough, both f orces will be than
ff mg f N
N N
less
S,back S,f eet
2
S,back S,f eet
0
(49 kg)(9.8 m/ s )240 N
( ) 1.2+0.80
N N mg
mgN
S S
As decreases, the maximum static f riction gets closer
to the actual value of f riction.
Eventually, is just enough so that . I f the
climber pushes less than this, the f riction will not be
enou
N
N f N
gh to compensate her weight.
Answer B
Fby you fS by floorfk by floor
Fby you
friction
μsN
μkN
Static friction Kinetic friction
Example: Trying to move a trunk
Fby you
fS by floor
You increase the applied force, but the trunk still does not move: static friction is increasing too.
Example: Trying to move a trunk
Fby you
For “small” forces, the trunk does not move. So there must be a friction force fS = Fby you fS by floor
Fby you
fS by floorfk by floor
You increase the applied force even more. Eventually, the trunk moves. Static friction cannot be larger than a certain value.
And then friction becomes kinetic!
Example: Box on incline with friction
yW xW
N
W
y
x
f
cos
sin
mgW
mgW
mgW
y
x
mafmg
mgN
sin
0cos
criticals
s
s
s
sss
mgmg
mgf
mgNf
a
tan
tan
cossin
sin
cos
0
1)Static:
2) Kinetic
)cos(sin
cossin
cos
k
k
kkk
ga
mamgmg
mgNf
mgsinθ – F = m ax = 0
N – mgcosθ = m ay = 0
F = mg sinθ
N = mg cosθ
mg
x
y
θθ
N
FB,hand
Example: A hand keeps a 20-kg box from sliding down a frictionless incline. The plane of the incline makes an angle θ = 30° with the horizontal. What is the magnitude of the force exerted by hand?
mgsinθ
mgcosθ
F = (20 kg)(9.8 m/s2)sin(30°) = 98 N
Directions:
•Draw the free-body diagram
• Choose axes (draw them!)
• Use Newton’s 2nd law in the x and y-directions.
Centripetal force
F = ma rT
mrmr
mvF
222
Example: A stone of mass m sits at the bottom of a bucket. A string is attached to the bucket and the whole thing is made to move in circles. What is the minimum speed that the bucket needs to have at the highest point of the trajectory in order to keep the stone inside the bucket?
F = mar
mvF
2
r
mvmgN
2
mgr
mvN
2
grv min0min N
Examples (centripetal force)
(3)
(2)
(1) mgN
r
mvmgN
2
r
mvmgN
2
mgr
mvN
2
mgr
mvN
2
r
mvmgN
2
r
mvNmg
2
mg
N
N
mg
F = mar
mvF
2
Example: Little Jacob (15 kg) sits on the edge of a merry-go-round of radius 1.0 m while big sister makes it turn… faster and faster. How fast can the system go before Jacob takes off if the coefficient of static friction between Jacob’s pants and the merry-go-round is 0.5?
mg
N
fs
Static friction provides the needed radial acceleration:2
Sf mr
Maximum speed Maximum static friction:2MAXS mg mr
MAXS gr
2(0.5)(9.8 m/ s ) 12.2 rad/ s turn/ s
1 m 3
Example: A car of mass m with constant speed v drives through a curve of radius R. What is the minimum value of the coefficient of static friction between the tires and the road for the car not to slip?
s S Sf N mg netF ma
2
S
vm mg
R
2
s
vf m
R
2
S
vgR
fs