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Marn g Schemes cument w e p ared f or ma' rence. It sho not be r d as a set o f model swers. Ctes d tehers who were not voed the mk g cess e aised to ret iʦ connt with ce. Chemistr y Paper 1 SECTION A Question No. K ey Question No. Part I Part II 1. A(81%) 25. 2. C(88%) 26. 3. D (59%) 27. 4. C (75%) 28. 5. B (8 6 % ) 29. 6. B (5 9 % ) 30. 7. A (58 % ) 31. 8. A (6 6 %) 32. 9. C(77%) 33. 10. B (6 3 % ) 34. 11. A (8 4 % ) 35. 12. B (50%) 36. 13, C (51%) 14. D (7 5 %) 15. B (36%) 16. A (6 8 % ) 17. C (73%) 18. A(85%) 19. C (27%) 20. D (38%) 21. C(72%) 22. D (49 % ) 23. C(77%) 24. D (58%) Note: Fires bcts ina e percens ofcidas choosing the correct awe. 44 K e y C (7 7 %) B (6 0 % ) D(67%) C (58%) C (2 6 % ) D(68%) A(34%) B (6 6 % ) D (7 2 % ) B (77%) A( 64 % ) A(65%) 更多試卷歡迎瀏覽 http://dsepp.com

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Page 1: fôY fSwka Îp ½ ://dsepp.com/.../2018/10/2016-DSE-CHEM-1-MS-1.pdf• Heat respectively the two remaining solids in a test tube and place a piece of dry CoCli paper 1 in the mouth

Marking Schemes

This document was prepared for markers'reference. It should not be regarded as a set of model answers. Candidates and teachers who were not involved in the marking process are advised to interpret its content with care.

Chemistry Paper 1

SECTION A

Question No. Key Question No.

Part I Part II

1. A(81%) 25.

2. C(88%) 26.

3. D (59%) 27.

4. C (75%) 28.

5. B (86%) 29.

6. B (59%) 30.

7. A(58%) 31.

8. A(66%) 32.

9. C(77%) 33.

10. B (63%) 34.

11. A(84%) 35.

12. B (50%) 36.

13, C (51%)14. D (75%)15. B (36%)16. A(68%)17. C (73%)18. A(85%)19. C (27%)20. D (38%)21. C(72%)22. D (49%)23. C(77%)24. D (58%)

Note: Figures in brackets indicate the percentages of candidates choosing the correct answers.

44

Key

C (77%) B (60%) D(67%) C (58%) C (26%) D(68%) A(34%) B (66%) D (72%) B (77%) A(64%) A(65%)

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General Marking Instructions

I. In order to maintain a uniform standard in marking, markers should adhere to the marking scheme agreed atthe markers'meeting.

2. The marking scheme may not exhaust all possible answers for each question. Markers should exercise theirprofessional discretion and judgment in accepting alternative answers that are not in the marking scheme butare correct and well reasoned.

3. In questions asking for a specified number ofreasons or examples etc. and a candidate gives more than therequired number, the extra answers should not be m釕ked. For instance, in a question asking candidates·toprovide two examples, and if a candidate gives three answers, only the frrst two should be marked.

4. In cases where a candidate answers more questions than required, the answers to all questions should bemarked. However, the excess answer(s) receiving the lowest score(s) will be disregarded in the calculation ofthe fmal mark.

5. Award zero marks for answers which are contradictory.

6. Chemical equations should be balanced except those in reaction schemes for organic synthesis. Forenergetics, the chemical equations given should include the correct state symbols of the chemical speciesinvolved.

7. In the question paper, questions which assess candidates'communication skills are marked with an asterisk(*). For these questions, the mark for effective communication (1 mark per question) will be awarded ifcandidates can produce answers which are easily understandable. No marks for effective communicationwill be awarded if the answers produced by candidates contain a lot of irrelevant materials and/or wrongconcepts in chemistry.

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9. • Dissolve the solids separately in water. • Add aqueous ammonia/ NaOH(aq) to each of the solutions obtained until excess. l • White precipitate formed initially for all of them. But only the precipitate of ZnS04 dissolves 1

in excess aqueous ammonia/ NaOH(aq).• Heat respectively the two remaining solids in a test tube and place a piece of dry CoCli paper 1

in the mouth of the tube.• Only MgS04• 7比0 can turn dry CoCli paper from blue to pink.• Communication mark

Part II

10. (a) At dynamic equilibrium, the rate of forward reaction is equal to the rate of backward reaction,and not equals zero. / At dynamic equilibrium, reactants are converted to products and products are converted to reactants at equal rate. No net change is observed.

(b) 2S02(g) + 02(g尺2S03(g)Initial 2.0 mol 2.0 mol At equil. 2.0-2x 2.0-x 2x where 2x = 1.8 thus x = 0.9 878 = (1.8N]勺[0.2N]勺l.lN]V= 11.92 dm3

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(c) (i) Decrease. The reaction is exothermic. Increase in temperature will cause the equilibrium 1 position to shift to the left.

(ii) No change. A catalyst will increase the rate of forward reaction and that of backward 1 reaction to the same extent. / A catalyst has no effect on the equilibrium position.

11. (a) To ensure fair comparisons between the trials. /To ensure the concentration ofNaOH(aq) is the only variable. / The volume of NaOH(aq) used can represent the concentration of NaOH(aq) in the reaction mixtures.

(b) [Ofr(aq)] = 2.0 x (4.0/5.0) = 1.6 mo! dm一3 3 叭aq)] X 1.6 = 1.0 X 10一14

匱(aq)] = 6.25 X 10一15 moldm一3

pH=- log (6.25 x 10一15)=14.2

(c) The concentration ofNaOH(aq) 1 The shorter the time for the pink colour disappeared, the faster the reaction. An increase in 1 concentration ofNaOH(aq) will result in an increase in the reaction rate.

(d) Using colorimeter/ measuring relative transmittance/ absorbance of the mixture 1

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12. Step 1:

Mm

3

OH OH NaOH(aq)

^ NH2 ^ ✓ O-Na+

heat or

OH OH

NH2 heat 。丶H

2.Ir 。 or

OH OH

H2S04(aq) I 。丶NH2 HCI(aq)

> H

heat

Step 2: OH

I

'(yo

or

0-Na+ cone. H2S04, heat

OH

I 。丶 cone. 比S04, heat

尸C

H >

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13. (a)人人

► waterout

� 2

』(b) LiAlJ¼ / H2 (catalyst - Pt)

(c) enantiomers / optical isomers

(d) optical activity /P and Q rotate plane-polarised light to opposite directions to the same degree / extent.

(e) Correct chemical reagentCorrect observations with comparison between the tests on acetophenone and PPossible tests and the corresponding observations:Cr2o/- I It acetophenone - no change; P - from orange to green Mn04- I H+ acetophenone - no change; P - from purple to colourless Mn04- acetophenone - no change; P - formatlon of brown ppt. Mn04- I Ofr acetophenone - no change; P - formation of brown ppt. 2,4-DNP acetophenone - formation of orange ppt.; P - no change c比COOH I H+ I heat acetophenone - no change; P - pleasant odur substance formed

2,4-DNP = 2,4-dinitrophenylhydrazine

14. Electrical conductivity: aluminium> sodium> silicon = sulphur (or: silicon> sulphur) 1 Any 3 of the following items, each I mark 3 • Both aluminium and sodium have giant metallic structures with delocalised electrons so that

electrical conductivity of them is high.• The number of delocalised electrons of aluminium is more than that of sodium so that

electrical conductivity of aluminium is higher than that of sodium.• Silicon has giant covalent structure and its electrons are not mobile and cannot conduct

electricity. ORSilicon has giant covalent structure and its electrons are not mobile. But silicon is a semi­metal and can conduct electricity in some conditions.

• Suphur has simple molecular structure and its electrons are not mobile and cannot conductelectricity.

• C ommumcat1on mark

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