general information - ishik – sulaimani · general information ... shear force, and bending...

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Mechanics of Material 10/7/2017 1 General Information Assistant Lecturer: Asmaa Ab. Mustafa Email : [email protected] Department : Civil Engineering Course Title : Mechanics of Material I Code : CE 211 Credit : 3 Office Hour : Sunday 14:00 16:00 or by appointment Website : http://www.sul.ishik.edu.iq/asmaa-abdulmajeed Grade : 2 nd Year : 2017 - 2018 1 Ishik University - Sulaimani Assistant Lecturer - Asmaa Ab. Mechanics of Materials Required Textbook : *R.C. Hibbeler Mechanics of Materials”,8th Edition, Prentice Hall, Upper Saddle River, New Jersey, 2010 Additional References : *F.P. Beer, E. R. Johnston, J.T. DeWolf Mechanics of Materials”, 4th Edition, McGraw- Hill, New York, 2006 *James M. Gere, Mechanics of Materials”, 6th Edition, Professor Emeritus, Stanford University, 2008. *A.P. Boresi, R.J. Schmidt Advanced Mechanics of Materials”, 6th Edition, John Wiley & Sons, New York, 2003. *R.D. Cook and W.C. Young - Advanced Mechanics of Materials”, 2nd Ed. Prentice-Hall, Upper Saddle River, New Jersey, 1999. *J.R. Barber - "Intermediate Mechanics of Materials" McGraw-Hill, New York, 2001. 2 Ishik University - Sulaimani Assistant Lecturer - Asmaa Ab. Mechanics of Materials

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Mechanics of Material 10/7/2017

1

General Information

Assistant Lecturer: Asmaa Ab. Mustafa

Email : [email protected]

Department : Civil Engineering

Course Title : Mechanics of Material I

Code : CE 211

Credit : 3

Office Hour : Sunday 14:00 – 16:00

or by appointment

Website : http://www.sul.ishik.edu.iq/asmaa-abdulmajeed

Grade : 2nd

Year : 2017 - 2018

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Required Textbook :

*R.C. Hibbeler – “Mechanics of Materials”,8th

Edition, Prentice Hall, Upper Saddle River, New

Jersey, 2010

Additional References :

*F.P. Beer, E. R. Johnston, J.T. DeWolf – “Mechanics of Materials”, 4th Edition, McGraw- Hill, New York, 2006

*James M. Gere, “Mechanics of Materials”, 6th Edition, Professor Emeritus, Stanford University, 2008.

*A.P. Boresi, R.J. Schmidt – “Advanced Mechanics of Materials”, 6th Edition, John Wiley & Sons, New York, 2003.

*R.D. Cook and W.C. Young - “Advanced Mechanics of Materials”, 2nd Ed. Prentice-Hall, Upper Saddle River, New Jersey, 1999.

*J.R. Barber - "Intermediate Mechanics of Materials" McGraw-Hill, New York, 2001.

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Mechanics of Material 10/7/2017

2

Evaluation Criteria :

Weekly Quizzes : 10%

Assignments : 10%

Bonus Quizzes : 5%

Project : 5%

Mid-term Exam : 30%

Final Exam : 40%

Assignments :

Approximately (10) homework assignments will be given

during the term. These assignments are very important. Their

purpose is to promote your understanding of the course

material, and to provide needed practice with example

problems that are too lengthy to discuss in class. It is your

responsibility to complete each homework assignment within

one week of distribution. 3

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Weekly Quizzes :

Except for the week corresponding to the midterm, weekly

quizzes will be given once per week, during the first

fifteen minutes of lecture. In the Quiz, you will be

expected to solve one of the questions from the previous

week’s subject (possibly with slight alterations in the

numbers). The weekly quizzes will be completely closed

book although calculators will be allowed.

Midterms and Exam :

One midterms will be scheduled in addition to the final

examination. Midterm and the final exam will be closed

book. You will also be allowed to use a non-

communicating calculator.

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Mechanics of Material 10/7/2017

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Prerequisites :

Must have passed Engineering Mechanics: Statics

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Class Attendance and Absences :

Students are strongly encouraged to attend class since some

course material may only appear in lectures. Students that

miss class are responsible for obtaining class notes from a

classmate. Also students whom their absent percentage pass

20% will fail in that course automatically.

Conduct :

Students are expected to arrive at lectures on time, and to

conduct themselves during class in a professional and

respectful manner that is not disruptive to others. Please put

your cell phone in silent mode before coming to class, quiz

or exam.

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Content :

This course is an introduction to the concepts of stress,

deformation and strain in solid materials. Basic

relationships between loads, stresses, and deflections of

structural and machine elements such as rods, shafts and

beams are developed. The load carrying capacity of these

elements under tension, compression, torsion, bending and

shear forces are considered.

Course Format :

There will be daily lectures. Your active participation is

essential in making the class a success. Read the material

before class and come equipped with questions.

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Statics – Equilibrium Analysis of particles and bodies

Dynamics – Accelerated motion of particles and bodies

1.Engineering Mechanics

2.Fundamentals Concepts

Basic Quantities

Length, Mass, Time, Force

Units of Measurement

m, kg, s, N… (SI, Int. System of Units)

- Dimensional Homogeneity

- Significant Figures

Mechanics of Material 10/7/2017

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3. Static Analysis

• Force and Equilibrium

• Force System Resultants

• Structural Analysis

• Internal forces

• Friction

• Centroid and Moments of Inertia

• Virtual Work and Stability

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Chapter -1- STRESS

Outlines of this chapter :

1) Chapter Objectives

2) Introduction

3) Equilibrium of a Deformable Body

4) Stress

5) Average Normal Stress in an Axially Loaded Bar

6) Average Shear Stress

7) Allowable Stress

8) Design of Simple Connection

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UNITS:

S.I. units

will

be used

mostly,

but student

should

also know

Inch system

as well.

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1) Chapter Objectives

In this chapter we will review some of the important

principles of statics and show how they are used to

determine the internal resultant loadings in a body.

Afterwards the concepts of normal and shear stress will be

introduced, and specific applications of the analysis and

design of members subjected to an axial load or direct

shear will be discussed.

Mechanics of Material 10/7/2017

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2) Introduction

Mechanics of materials is a branch of mechanics that studies the

internal effects of stress and strain in a solid body that is subjected

to an external loading. Stress is associated with the strength of the

material from which the body is made, while strain is a measure

of the deformation of the body. In addition to this, mechanics of

materials includes the study of the body’s stability when a body

such as a column is subjected to compressive loading. A thorough

understanding of the fundamentals of this subject is of vital

importance because many of the formulas and rules of design

cited in engineering codes are based upon the principles of this

subject. 15

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3) Equilibrium of a Deformable Body

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External Loads. A body is subjected to only two types of external loads;

namely, surface forces or body forces, Fig.1–1.

Surface Forces. Surface forces are caused by the direct contact of one

body with the surface of another. In all cases these forces are distributed

over the area of contact between the bodies.

Concentrated Force, which is applied to a

point on the body. For example, the force

of the ground on the wheels of a bicycle

can be considered as a concentrated force.

If the surface loading is applied along a

narrow strip of area, the loading can be

idealized as a linear distributed load, w(s).

Here the loading is measured as having an

intensity of force/length along the strip and

is represented graphically by a series of

arrows along the line s.

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Support Reactions. The surface forces that develop at the

supports or points of contact between bodies are called

reactions.

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Equations of Equilibrium. Equilibrium of a body requires both a

balance of forces, to prevent the body from translating or having

accelerated motion along a straight or curved path, and a balance

of moments, to prevent the body from rotating. These conditions

can be expressed mathematically by two vector equations.

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Internal Resultant Loadings

In mechanics of materials, statics is primarily used to determine the

resultant loadings that act within a body.

• Normal force, N; This force acts perpendicular to the area. It is

developed whenever the external loads tend to push or pull on

the two segments of the body.

• Shear force, V; The shear force lies in the plane of the area and

it is developed when the external loads tend to cause the two

segments of the body to slide over one another.

• Torsional moment or torque, T; This effect is developed when

the external loads tend to twist one segment of the body with

respect to the other about an axis perpendicular to the area.

• Bending moment, M; The bending moment is caused by the

external loads that tend to bend the body about an axis lying

within the plane of the area.

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Point O is most often chosen at the centroid of the sectioned area.

Mechanics of Material 10/7/2017

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Example 1.1

Determine the resultant internal loadings acting on the cross section at

C of the cantilevered beam shown in Fig.1–4a.

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Example 1.2

Determine the resultant internal loadings acting on the cross

section at C of the machine shaft shown in Fig. 1–5a.The shaft is

supported by journal bearings at A and B, which only exert

vertical forces on the shaft.

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Mechanics of Material 10/7/2017

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Assignment 1.1

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Determine the internal normal force, shear force, and bending

moment at point C in the beam.

Assignment 1.2

Determine the internal normal force, shear force, and bending

moment at point C in the beam.

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Mechanics of Material 10/7/2017

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4) Stress

Normal Stress. The intensity of the force acting normal to is defined as

the normal stress, σ (sigma).

If the normal force or stress “pulls” on ΔA as shown in Fig. 1–10a, it is

referred to as tensile stress, whereas if it “pushes” on ΔA it is called compressive stress.

Shear Stress. The intensity of force acting tangent to is called the shear

stress, τ (tau).

Units. Since stress represents a force per unit area, in the International Standard or SI system, the magnitudes of both normal and shear stress are specified in the basic units of newton per square meter (N/m2) .This unit, called a Pascal (1Pa=1N/m2) is rather small, and in engineering work prefixes such as kilo-(103) symbolized by k, mega- (106) symbolized by M, or giga- (109) symbolized by G, are used to represent larger, more realistic values of stress.* Likewise, in the Foot-Pound-Second system of units, engineers usually express stress in pounds per square inch (psi) or kilo-pounds per square inch (ksi), where 1kilo-pound(kip) = 1000 lb. 27

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Sometimes stress is expressed in units N/mm2.

Where 1mm=10-3 m.

However, in the SI system, prefixes are not allowed in the

denominator of a fraction and therefore it is better to use

the equivalent

1 N/mm2 = 1 MN/m2 = 1 MPa.

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5) Average Normal Stress in an Axially Loaded Bar

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Here :

σ : Average normal stress at any point on the cross-sectional area.

P : internal resultant normal force, which acts through the centroid of

the cross-sectional area. P is determined using the method of sections

and the equations of equilibrium.

A : Cross-sectional area of the bar where is determined.

Mechanics of Material 10/7/2017

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Mechanics of Material 10/7/2017

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The bar in Fig. 1–16a has a constant width of 35 mm and a

thickness of 10 mm. Determine the maximum average

normal stress in the bar when it is subjected to the loading

shown:

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Example 1.3

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Example 1.4

The 80-kg lamp is supported by two rods AB and BC as

shown in Fig.1–17a. If AB has a diameter of 10 mm and BC

has a diameter of 8 mm, determine the average normal stress

in each rod.

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6) Average Shear Stress

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Here:

τavg = Average shear stress at the section, which is assumed

to be the same at each point located on the section.

V = Internal resultant shear force on the section determined

from the equations of equilibrium.

A= Area at the section.

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Determine the average shear stress in the 20-mm-diameter

pin at A and the 30-mm-diameter pin at B that support the

beam in Fig.1–22a.

Example 1.5

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Example 1.6

The inclined member in Fig.1–24a is subjected to a

compressive force of 600 lb. Determine the average

compressive stress along the smooth areas of contact defined

by AB and BC, and the average shear stress along the

horizontal plane defined by DB.

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Assignment 1.3

Determine the average normal stress developed on the cross

section. Sketch the normal stress distribution over the cross

section.

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Assignment 1.4

Determine the average normal stress developed in rod AB

if the load has a mass of 50 kg. The diameter of rod AB is 8

mm.

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To properly design a structural member or mechanical element

it is necessary to restrict the stress in the material to a level that

will be safe. To ensure this safety, it is therefore necessary to

choose an allowable stress that restricts the applied load to one

that is less than the load the member can fully support. There

are many reasons for doing this. For example, the load for

which the member is designed may be different from actual

loadings placed on it. The intended measurements of a

structure or machine may not be exact, due to errors in

fabrication or in the assembly of its component parts.

Unknown vibrations, impact, or accidental loadings can occur

that may not be accounted for in the design. Atmospheric

corrosion, decay, or weathering tend to cause materials to

deteriorate during service. And lastly, some materials, such as

wood, concrete, or fiber-reinforced composites, can show high

variability in mechanical properties.

7) Allowable Stress

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One method of specifying the allowable load for a member

is to use a number called the factor of safety (F.S.). The

factor of safety (F.S.) is a ratio of the failure load Ffail to

the allowable load Fallow. Here Ffail is found from

experimental testing of the material, and the factor of

safety is selected based on experience so that the above

mentioned uncertainties are accounted for when the

member is used under similar conditions of loading and

geometry. Stated mathematically,

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If the load applied to the member is linearly related to the

stress developed within the member, as in the case of using

σ = P/A and τavg = V/A , then we can also express the

factor of safety as a ratio of the failure stress σ fail (or τfail)

to the allowable stress σ allow (or τallow);∗that is,

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8) Design of Simple Connection

By making simplifying assumptions regarding the behavior of the

material, the equations σ = P/A and τavg = V/A can often be used to

analyze or design a simple connection or mechanical element. In

particular, if a member is subjected to normal force at a section, its

required area at the section is determined from,

On the other hand, if the section is subjected to an average shear force,

then the required area at the section is

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Example 1.7

The control arm is subjected to the loading shown in Fig. 1–

26a. Determine to the nearest ¼ in. the required diameter of

the steel pin at C if the allowable shear stress for the steel is

τallow = 8 ksi.

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The rigid bar AB shown in Fig. 1–29a is supported by a steel rod AC

having a diameter of 20 mm and an aluminum block having a cross-

sectional area of 1800 mm2 The 18-mm-diameter pins at A and C are

subjected to single shear. If the failure stress for the steel and

aluminum is (σ st) fail = 680 MPa and (σ al) fail = 70 MPa, respectively,

and the failure shear stress for each pin is τfail = 900 MPa determine the

largest load P that can be applied to the bar. Apply a factor of safety of

F.S.=2.

Example 1.8

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Assignment 1.5

Determine the maximum average shear stress

developed in each ¾ in-diameter bolt.

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Assignment 1.6

If each of the three nails has a diameter of 4 mm and can

withstand an average shear stress of 60 MPa, determine the

maximum allowable force P that can be applied to the

board.

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The strut is glued to the horizontal member at surface AB. If

the strut has a thickness of 25 mm and the glue can

withstand an average shear stress of 600 kPa, determine the

maximum force P that can be applied to the strut.

Assignment 1.7

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Reference :

1. Mechanics of Materials by R.C.Hibbeler, 8th Edition.