good morning/afternoon. today is october 24, 2014 hw due: none chemcatalyst: using the data below,...
DESCRIPTION
Using the data below, calculate the average atomic mass of silicon. (27.98)(0.9221) + (28.98)(0.047) + (29.97)(0.0309) = amu Isotope Mass (amu)Abundance (%) Si Si SiTRANSCRIPT
HW Due: None
ChemCatalyst:
Using the data below, calculate the average atomic mass of silicon.
Get your clicker!
Today’s Objectives:
1.Identify the period, group, and block of an element2.Write an atom's electron configuration
3.Identify an atom based upon its electron configuration
Isotope Mass (amu) Abundance (%)28
14Si 27.98 92.2129
14Si 28.98 4.7030
14Si 29.97 3.09
A. ProtonsB. Neutrons C. Electrons
Protons
Neutrons
Electrons
0% 0%0%
Using the data below, calculate the average atomic mass of silicon.
(27.98)(0.9221) + (28.98)(0.047) + (29.97)(0.0309) = 28.09 amu
Isotope Mass (amu) Abundance (%)28
14Si 27.98 92.2129
14Si 28.98 4.7030
14Si 29.97 3.09
A. Closer to the mass of the isotope with the heaviest mass
B. Closer to mass of the isotope with the greatest abundance
Closer to th
e mass
of the ...
Closer to m
ass of t
he iso...
0%0%
Using the data below, calculate the average atomic mass of silicon.
(27.98)(0.9221) + (28.98)(0.047) + (29.97)(0.0309) = 28.09 amu
Isotope Mass (amu) Abundance (%)28
14Si 27.98 92.2129
14Si 28.98 4.7030
14Si 29.97 3.09
A. 7B. 9C. 18
7 9 18
0% 0%0%
A. 7B. 9C. 18
7 9 18
0% 0%0%
A. Fit into periods 6 & 7
B. Are groups 8 & 9
C. Fit into groups 6 & 7
Fit in
to periods 6
& 7
Are groups 8 &
9
Fit in
to groups 6
& 7
0% 0%0%
A. 2B. 4C. 20
2 4 20
0% 0%0%
A. 2B. 4C. 38
2 4 38
0% 0%0%
A. 1B. 2C. 3D. 4
1 2 3 4
0% 0%0%0%
A. 1B. 3C. 6D. 9
1 3 6 9
0% 0%0%0%
A. 5B. 10C. 12D. 24
5 10 12 24
0% 0%0%0%
A. 5B. 10C. 14D. 24
5 10 14 24
0% 0%0%0%
A. HB. HeC. Hg
H He Hg
0% 0%0%
A. 3B. 4C. 8
3 4 8
0% 0%0%
A. sB. pC. dD. f
s p d f
0% 0%0%0%
A. sB. pC. dD. f
s p d f
0% 0%0%0%
A. 6B. 7C. 8D. 9
6 7 8 9
0% 0%0%0%
A. Inside the nucleus
B. Outside the nucleus
Inside th
e nucleus
Outside th
e nucleus
0%0%Electrons are found orbiting the nucleus in a
particular path
Definition: the arrangement of electrons in space around a nucleus
The periodic table reveals patterns in how the electrons are arranged
Always start at hydrogen
List the boxes you have to go through to get to the atom of interest
◦ If you go through multiple boxes that have the same number/letter use a superscript to indicate how many of that type of box were passed
You must include the position of the atom of interest
Be
1s22s2
Al
1s22s22p63s23p1
Add up the superscripts! What do
you notice?
2 + 2 = 4 = atomic # of Be
2 + 2 + 6 + 2 + 1= 13 = atomic # of Al
I
1s22s22p63s23p64s23d104p65s24d105p5
Pb
1s22s22p63s23p64s23d104p65s24d105p66s24f145d106p2
How can you check your work?
Electron configurations can also be used to identify an atom
◦ Sum of subscripts = atomic #
◦ Example: 1s22s22p63s23p4
2 + 2 + 6 + 2 + 4 = 16 = atomic # 16 Element is S
The last letter/number can be found on the periodic table
◦ Example: 1s22s22p63s23p64s23d104p65s24d105p66s24f145d9
Find 5d9
5d9 = Au
He Fears Clowns!!
He
Fe Ar S
Cl O W N S
A. Group 15, period 4, p block
B. Group 15, period 4, s block
C. Group 4, period 15, p block
D. Group 4, period 15, d block
Group 15, p
eriod 4, p
block
Group 15, p
eriod 4, s
block
Group 4, p
eriod 15, p
block
Group 4, p
eriod 15, d
block
0% 0%0%0%
A. 1s22s22p63s23p64s24p5
B. 1s22s22p63s23p64s24d104p5
C. 1s22s22p63s23p64s23d104p5
1s22s22p63s2
3p64s24p5
1s22s22p63s2
3p64s24d1...
1s22s22p63s2
3p64s23d1...
0% 0%0%
A. LuB. HgC. LrD. Cd
Lu Hg Lr Cd
0% 0%0%0%
Electron Configurations Review