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Physics Department SMK Sultan Ismail Johor Bahru ________________________________________________________________________________________________________________ http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4 Prepared by: En Adnan Shamsudin Gravitational Field A gravitational field as a region in which an object experiences a force due to gravitational attraction Gravitational Field Strength The gravitational field strength at a point in the gravitational field is the gravitational force acting on a mass of 1 kg placed at that point. Unit: N/kg Symbol: g Gravitational Field Strength Formula Gravitational Acceleration The gravitational acceleration is the acceleration of an object due to the pull of the gravitational force. Unit: ms-2 Symbol: g Important notes: Gravitational acceleration does not depend on the mass of the moving object. The magnitude of gravitational acceleration is taken to be 10ms-2. Gravitational Field Strength vs. Gravitational Acceleration Both the gravitational field strength and gravitational acceleration have the symbol, g and the same value (10ms-2) on the surface of the earth. When considering a body falling freely, the g is the gravitational acceleration. When considering objects at rest, g is the Earth’s gravitational field strength acting on it. Weight The weight of an object is defined as the gravitational force acting on the object. Unit: Newton (N)

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Page 1: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Gravitational Field A gravitational field as a region in which an object experiences a force due to gravitational

attraction

Gravitational Field Strength The gravitational field strength at a point in the gravitational field is the gravitational force

acting on a mass of 1 kg placed at that point.

Unit: N/kg

Symbol: g

Gravitational Field Strength Formula

Gravitational Acceleration The gravitational acceleration is the acceleration of an object due to the pull of the

gravitational force.

Unit: ms-2

Symbol: g

Important notes:

Gravitational acceleration does not depend on the mass of the moving object.

The magnitude of gravitational acceleration is taken to be 10ms-2.

Gravitational Field Strength vs. Gravitational Acceleration Both the gravitational field strength and gravitational acceleration have the symbol, g

and the same value (10ms-2) on the surface of the earth.

When considering a body falling freely, the g is the gravitational acceleration.

When considering objects at rest, g is the Earth’s gravitational field strength acting on

it.

Weight The weight of an object is defined as the gravitational force acting on the object.

Unit: Newton (N)

Page 2: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Differences between Weight and Mass

Weight Mass

Depends on the

gravitational field strength

Independent from the

gravitational field strength

Vector quantity Scalar Quantity

Unit Newton (N) Unit: Kilogram (kg)

Free Falling Free falling is a motion under force of gravity as the only force acting on the moving object.

Practically, free falling can only take place in vacuum.

Falling from high place

Page 3: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Acceleration = 10ms-2

Initial velocity = 0

Displacement = high of the location

Launching object upward

Acceleration = -10ms-2

Velocity at maximum height = 0

Vector and Scalar Quantity A scalar quantity is a quantity which can be fully described by magnitude only.

A vector quantity is a quantity which is fully described by both magnitude and direction.

Vector Diagram

Page 4: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

The arrow shows the direction of the vector.

The length representing the magnitude of the vector.

Equal Vector Two vectors A and B may be defined to be equal if they have the same magnitude and point

in the same direction.

Vector Addition - Triangle Method

Join the tail of the 2nd vector to the head of the 1st vector. Normally the resultant vector is

marked with double arrow.

Vector Addition - Parallelogram Method

Join the tail of the 2nd vector to the tail of the 1st vector. Normally the resultant vector is

marked with double arrow.

Addition of 2 Perpendicular Vectors

Page 5: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

If 2 vectors (a & b) are perpendicular to each others, the magnitude and direction of the

resultant vector can be determined by the following equation.

Example 1

Two forces, P and Q of magnitude 10N and 12N are perpendicular to each others. What is the

magnitude of the resultant force if P and Q are acting on an object?

Answer

Use Theorem Pythagoras

F2 = 12

2 + 10

2

F = 100144

F = 15.6 N

Example 2

12 N

F 10 N

Page 6: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Diagram above shows that four forces of magnitude 2N, 4N, 5N and 8N are acting on point

O. All the forces are perpendicular to each others. What is the magnitude of the resulatant

force that acts on point O?

Answer The resultant force of the horizntal component = 5 - 2 = 3N to the right

The resultant force of the vertical component = 8 - 4 = 4N acting downward.

Therefore, the magtitude of these 2 force components,

Vector Resolution

A vector can be resolve into 2 components which is perpendicular to each others.

Example 3

Page 7: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Diagram above shows a lorry pulling a log with an iron cable. If the tension of the cable is

3000N and the friction between the log and the ground is 500N, find the horizontal force that

acting on the log.

Answer Horizontal component of the tension = 3000 cos30o =2598N

Friction = 500N

Resultant horizontal force = 2598N - 500N =2098N

Example 4

Diagram above shows two forces of magnitude 25N are acting on an object of mass 2kg. Find

the acceleration of object P, in ms-2.

Answer Horizontal component of the forces = 25cos45o + 25cos45o = 35.36N

Vertical component of the forces = 25sin45o - 25sin45o = 0N

The acceleration of the object can be determined by the equation

F = ma

(35.36) = (2)a

a = 17.68 ms-2

Inclined Plane

Page 8: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Weight component along the plane = Wsinθ.

Weight component perpendicular to the plane = Wcosθ.

Example 5

A block of mass 2 kg is pulling along a plane by a 20N force as shown in diagram above.

Given that the fiction between block and the plane is 2N, find the magnitude of the resultant

force parallel to the plane.

Answer

First of all, let's examine all the forces or component of forces acting along the plane.

The force pulling the block, F = 20N

The frictional force Ffric = 2N

The weight component along the plane = 20sin30o = 10N

The resultant force along the plane = 20 - 2 - 10 = 8N

Vectors in Equilibrium

Page 9: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

When 3 vectors are in equilibrium, the resultant vector = 0. After joining all the vectors tail to

head, the head of the last vector will join to the tail of the first vector.

Forces in equilibrium Forces are in equilibrium means the resultant force in all directions are zero.

Example 6

Diagram above shows a load of mass 500g is hung on a string C, which is tied to 2 other

strings A and B. Find the tension of string A.

Answer

Page 10: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Tension of string C, TC = weight of the load = 5N

All forces in the system are in equilibrium, hence

Vertical component of tension A (TA) = TC

TAcos60o = TC

TA = TC/cos60o

TA = 5/cos60o = 10N

Work Work done by a constant force is given by the product of the force and the distance moved in

the direction of the force.

Unit: Nm or Joule (J)

Work is a scalar quantity.

Formula of work

Example 1

Page 11: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

A force of 50 N acts on the block at the angle shown in the diagram. The block moves a

horizontal distance of 3.0 m. Calculate the work being done by the force.

Answer Work done,

W = F × s × cos θ

W = 50 × 3.0 × cos30o = 129.9J

Formula of work 2 When the direction of force and motion are same, θ = 0o, therefore cosθ = 1

Work done,

W = F × s

Example 2

Diagram above shows a 10N force is pulling a metal. The friction between the block and the

floor is 5N. If the distance travelled by the metal block is 2m, find

a. the work done by the pulling force

b. the work done by the frictional force

Asnwer (a) The force is in the same direction of the motion. Work done by the pulling force,

W = F × s = (10)(2) = 20J

(b) The force is not in the same direction of motion, work done by the frictional force

W = F × s × cos180o= (5)(2)(-1) = -10J

Work Done Against the Force of Gravity

Page 12: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Example 3

Ranjit runs up a staircase of 35 steps. Each steps is 15cm in height. Given that Ranjit's mass

is 45kg, find the work done by Ranjit to reach the top of the staircase.

Answer In this case, Ranjit does work to overcome the gravity.

Ranjit's mass = 45kg

Vertical height of the motion, h = 35 × 0.15

Gravitational field strength, g = 10 ms-2

Work done, W = ?

W = mgh = (45)(10)(35 × 0.15) = 2362.5J

Force - Displacement Graph

In a Force-Displacement graph, work done is equal to the area in between the graph and the

horizontal axis.

Example 4

Page 13: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

The graph above shows the force acting on a trolley of 5 kg mass over a distance of 10 m.

Find the work done by the force to move the trolley.

Answer

In a Force-Displacement graph, work done is equal to the area below the graph. Therefore,

work done

Energy Energy is defined as the capacity to do work.

Work is done when energy is converted from one form to another.

Unit: Nm or Joule(J)

Kinetic Energy Kinetic energy is the energy of motion.

Example 5

Determine the kinetic energy of a 2000-kg bus that is moving with a speed of 35.0 m/s.

Answer:

Kinetic Energy, Ek = ½ mv2

Page 14: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Gravitational Potential Energy Gravitational potential energy is the energy stored in an object as the result of its vertical

position (i.e., height).

Formula:

Example 6

A ball of 1kg mass is droppped from a height of 4m. What is the maximum kinetic energy

possessed by the ball before it reached the ground?

Answer According to the principle of conservation of energy, the amount of potential energy losses is

equal to the amount of kinetic energy gain.

Maximum kinetic energy

= Maximum potentila energy losses

= mgh = (1)(10)(4) = 40J

Elastic Potential Energy Elastic potential energy is the energy stored in elastic materials as the result of their

stretching or compressing.

Formula:

Page 15: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Example 7

Diagram above shows a spring with a load of mass 0.5kg. The extention of the spring is 6cm,

find the energy stored in the spring.

Answer

The energy stored in the spring is the elastics potential energy.

Conservation of Energy and Work Done During a conversion of energy,

Amount of Work Done = Amount of Energy Converted

Example 8

A trolley of 5 kg mass moving against friction of 5 N. Its velocity at A is 4ms-1 and it stops

at B after 4 seconds. What is the work done to overcome the friction?

Answer

In this case, kinetic energy is converted into heat energy due to the friction. The work done to

overcome the friction is equal to the amount of kinetic energy converted into heat energy,

hence

Power Power is the rate at which work is done, which means how fast a work is done.

Formula:

Page 16: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Example 1

An electric motor takes 20 s to lift a box of mass 20kg to a height of 1.5 m. Find the amount

of work done by the machine and hence find the power of the electric motor.

Answer Work done,

W = mgh = (20)(10)(1.5) = 300J

Power, P =

Efficiency The efficiency of a device is defined as the percentage of the energy input that is transformed

into useful energy.

In the example above, the input power is 100J/s, the desire output power (useful energy) is

only 75J/s, the remaining power is lost as undisire output. Therefore, the efficiency of this

machine is

75/100 x 100% = 75%

Page 17: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Elasticity Elasticity is the ability of a sub-stance to recover its original shape and size after distortion.

Forces Between Atoms

The intermolecular forces consist of an attractive force and a repulsive force.

At the equilibrium distance d, the attractive force equal to the repulsive force.

If the 2 atoms are brought closer, the repulsive force will dominate, produces a net

repulsive force between the atoms.

If the 2 atoms are brought furhter, the attractive force will dominate, produces a net

attractive force between the atoms.

Graph of Forces Between 2 atoms

X0 = Equilibrium Distance

When the particles are compressed, x < x0, the repulsive force between the particles

increases.

When the particles are stressed, x > x0, the attractive force between the particles increases.

If the distance x exceeds the elastic limit, the attractive force will decreases.

Page 18: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Hooke's Law Hooke's Law states that if a spring is not stretched beyond its elastic limit, the force that

acts on it is directly proportional to the extension of the spring.

Elastic Limit The elastic limit of a spring is defined as the maximum force that can be applied to a spring

such that the spring will be able to be restored to its original length when the force is

removed.

Equation derived from Hooke's Law From Hook's Law, we can derived that

Spring Constant Spring constant is defined as the ratio of the force applied on a spring to the extension of the

spring.

It is a measure of the stiffness of a spring or elastic object.

Page 19: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Graph of Streching Force - Extension

Gradient = Spring constant

Area below the graph = Work done

F-x graph and spring constant

The higher the gradient, the greater the spring constant and the harder (stiffer) spring.

For example, the stiffness of spring A is greater than spring B.

System of Spring

Page 20: Gravitational Field Gravitational Field Strength Gravitational Field · PDF file · 2011-05-04Gravitational Field ... Use Theorem Pythagoras F2 = 122 + 102 F = 144 100 F = 15.6 N

Physics Department SMK Sultan Ismail Johor Bahru

________________________________________________________________________________________________________________

http://www.one-school.net/Malaysia/UniversityandCollege/SPM/revisioncard/physics/heat/thermal.html#4

Prepared by: En Adnan Shamsudin

Arrangement in series:

Extension = x × number of spring

Stiffness decreases

Spring constant = k/number of spring

Arrangement in parallel:

Extension = x ÷ number of spring

Stiffness increases

Spring constant = k × number of spring

Factors Affecting the Stiffness of Spring

Stiffer Less stiff

Material type of spring

Diameter of wire of

spring

Diameter of the spring

Length of the string