groups mcq sq lq marksmarks

16
Class 11: Introduction of Syllabus Groups MCQ SQ LQ Marks Mechanics 5(5) 1/2 = (5) 1 +1/2 = (16) 26 Heat and Thermodynamics 0 3(15) 0 15 Waves and Optics 4 1/2 = (5) 0 9 Electricity and Magnetism 1 3(15) 0 16 Modern Physics 1 0 1(8) 9 Marks 11 40 24 75 Heat and Temperature

Upload: others

Post on 11-Feb-2022

1 views

Category:

Documents


0 download

TRANSCRIPT

Class 11: Introduction of Syllabus

Groups

MCQ

SQ

LQ

MarksMarks

Mechanics 5(5) 1/2 = (5) 1 +1/2 = (16) 26 10

Heat and Thermodynamics

0 3(15) 0 15 9

Waves and Optics

4 1/2 = (5) 0 9 28

Electricity and Magnetism

1 3(15) 0 16 28

Modern Physics 1 0 1(8) 9 75

Marks 11 40 24 75

Heat and Temperature

Heat is a form of energy, the flow of which gives the sensation of hotness or coldness to our body. Its SI unit is Joule

and CGS unit is Calorie. Temperature is the degree of hotness or coldness of a body. Its SI unit is Kelvin and CGS unit

is Centigrade or Celsius. Heat is measured by total K.E. of the molecules of a body while temperature is measured in

terms of average K.E. of the molecules of a body. However more heat energy in a body does not necessarily mean that

it is at higher temperature. Higher the average K.E., greater the temperature of a body.

Thermal Equilibrium and Zeroth law:

When two bodies at different temperatures are placed in contact, molecules of a body at higher temperature with more

average K.E. give up some energy to the less energetic molecules of a cold body so that increase in energy of

molecules takes place towards cold body while decrease in energy takes place towards hot body and due to this reason

it is called that heat flows from hot to cold body. The change in K.E. of molecules takes place until average K.E. of

molecules or temperature of both bodies reach to the same value. This stage is called thermal equilibrium. Thus

temperature is a physical quantity which determines the direction of heat flow while only by knowing the heat

contained in two bodies we cannot predict the direction of heat flow.

Zeroth law of thermodynamics states that if two bodies are separately in thermal equilibrium with third body then

those bodies are also to be in thermal equilibrium. For eg. measuring our body temperature by using thermometer. To

know about the thermal equilibrium condition we compare their temperature readings. Two bodies in thermal

equilibrium must have the same temperature while they may or may not have the same amount of heat. On the basis of

zeroth law, temperature is that thermal property which determines whether two bodies are in thermal equilibrium or

not.

Temperature Scales:

Consider four identical thermometers scaled

on Celsius, Fahrenheit, Reaumer and Kelvin

as shown in Fig. C1(a). If all are used to

measure the temperature of same substance,

they rise up to the height but show different

readings. The conversion relation between

them is obtained by equating the common

term given below for all thermometers

π‘…π‘’π‘Žπ‘‘π‘–π‘›π‘” π‘œπ‘“ π‘‘β„Žπ‘’π‘Ÿπ‘šπ‘œπ‘šπ‘’π‘‘π‘’π‘Ÿ βˆ’ πΏπ‘œπ‘€π‘’π‘Ÿ 𝑓𝑖π‘₯𝑒𝑑 π‘π‘œπ‘–π‘›π‘‘

π‘ˆπ‘π‘π‘’π‘Ÿ 𝑓𝑖π‘₯𝑒𝑑 π‘π‘œπ‘–π‘›π‘‘ βˆ’ πΏπ‘œπ‘€π‘’π‘Ÿ 𝑓𝑖π‘₯𝑒𝑑 π‘π‘œπ‘–π‘›π‘‘

So, πΆβˆ’0

100βˆ’0=

πΉβˆ’32

212βˆ’32=

π‘…βˆ’0

80βˆ’0=

πΎβˆ’273

373βˆ’273

Q.1. At what temperature (i) Celsius and Fahrenheit scales show equal readings? (ii) Kelvin scale shows double

reading than that of Fahrenheit scale? (A: -400C, 176.70For 353.4K)

Q.2. A faulty thermometer with its lower and upper fixed points 20C and 980C respectively reads temperature of a body

400C. What will be the correct temperature of a body in centigrade unit? (Hint:40βˆ’2

98βˆ’2=

π‘₯βˆ’0

100βˆ’0) (A: 39.580C)

Q.3. A faulty thermometer with its lower and upper fixed points -20C and 1020C respectively reads temperature of a

body 200C. What will be the correct temperature of a body in Fahrenheit scale? (Hint:20+2

102+2=

πΉβˆ’32

180) (A: 70.070F)

Alternatively, first we can convert in correct Celsius reading and then convert in Fahrenheit scale.

)(1. aCFig∴

𝐢

5=

𝐹 βˆ’ 32

9=

𝑅

4=

𝐾 βˆ’ 273

5

Thermal Expansion:

The increase in size of a body due to heating is called thermal expansion. There are three types of thermal

expansions for solids. They are: 1) linear expansion 2) superficial expansion and 3) cubical expansion

1) Linear Expansion:The increase in length of a one dimensional linear solid for eg. wire or rod due to

heating is called linear expansion.

Let us consider a wire or rod of length 𝑙1at temperature πœƒ10𝐢which is

heated upto temperature πœƒ20𝐢 at which its length is 𝑙2as shown in

Fig.C2(a). Experiment shows that

Increase in length (𝑙2 βˆ’ 𝑙1) ∝ rise in temperature (πœƒ2 βˆ’ πœƒ1)

Again, Increase in length (𝑙2 βˆ’ 𝑙1) ∝ Initial length (𝑙1)

Combining both, Increase in length (𝑙2 βˆ’ 𝑙1) ∝ rise in temperature (πœƒ2 βˆ’ πœƒ1) Γ— Initial length (𝑙1)

Or, 𝑙2 βˆ’ 𝑙1 ∝ 𝑙1 Γ— (πœƒ2 βˆ’ πœƒ1)

Or, 𝑙2 βˆ’ 𝑙1 = 𝛼 𝑙1 Γ— (πœƒ2 βˆ’ πœƒ1) ; where Ξ± is called coefficient of linear expansion or linear expansivity.

Linear Expansivity (Ξ±): The coefficient of linear expansion or linear expansivity is given by

𝛼 =𝑙2βˆ’π‘™1

𝑙1(πœƒ2βˆ’πœƒ1)Where 𝑙1is initial length, (𝑙2 βˆ’ 𝑙1) is increase in length, (πœƒ2 βˆ’ πœƒ1)is rise in temperature.

Therefore, coefficient of linear expansion or linear expansivity is defined as the increase in length per

unit original length per unit rise in temperature. Its unit is 0C-1orK-1. Alpha (Ξ±) is same for given material

and it has different values for different materials. Even if original length and rise in temperature are

different, increase in length is also different and hence alpha (Ξ±) remains same for a given material.

2) Superficial Expansion:The increase in area of a two dimensional body for eg. metal sheet due to

heating is called superficial expansion.

Let us consider a bodyof area𝐴1at temperature πœƒ10𝐢which is heated

upto temperature πœƒ20𝐢 at which its area is 𝐴2as shown in Fig. C2(b).

Experiment shows that

Increase in area(𝐴2 βˆ’ 𝐴1) ∝ rise in temperature (πœƒ2 βˆ’ πœƒ1)

Again, Increase in area(𝐴2 βˆ’ 𝐴1) ∝ Initial area(𝐴1)

Combining both,

Increase in area(𝐴2 βˆ’ 𝐴1) ∝ rise in temperature (πœƒ2 βˆ’ πœƒ1) Γ— Initial area(𝐴1)

Or, 𝐴2 βˆ’ 𝐴1 ∝ 𝐴1 Γ— (πœƒ2 βˆ’ πœƒ1)

Or, 𝐴2 βˆ’ 𝐴1 = 𝛽 𝐴1 Γ— (πœƒ2 βˆ’ πœƒ1) ; where Ξ² is called coefficient of superficial expansion or superficial

expansivity.

Superficial Expansivity (Ξ²):The coefficient of superficial expansion or superficial expansivity is given

by 𝛽 =𝐴2βˆ’π΄1

𝐴1(πœƒ2βˆ’πœƒ1)Where 𝐴1is initial area, (𝐴2 βˆ’ 𝐴1) is increase in area, (πœƒ2 βˆ’ πœƒ1) is rise in temperature.

11,l

22 ,l

12 ll βˆ’

)(2. aCFig

11,A

22 ,A

)(2. bCFig

Therefore, coefficient of superficial expansion or superficial expansivity is defined as the increase in area

per unit original area per unit rise in temperature. Its unit is 0C-1, K-1. Beta (Ξ²) is same for a given

material.

3) Cubical Expansion:The increase in volume of a three dimensional body for eg. cube due to heating

is called superficial expansion.

Let us consider a bodyof volume𝑉1at temperature πœƒ10𝐢which is

heated upto temperature πœƒ20𝐢 at which its volume is 𝑉2as shown in

Fig. C2(c). Experiment shows that

Increase in volume(𝑉2 βˆ’ 𝑉1) ∝ rise in temperature (πœƒ2 βˆ’ πœƒ1)

Again, Increase in volume(𝑉2 βˆ’ 𝑉1) ∝ Initial volume(𝑉1)

Combining both,

Increase in volume(𝑉2 βˆ’ 𝑉1) ∝ rise in temperature (πœƒ2 βˆ’ πœƒ1) Γ— Initial volume(𝑉1)

Or, 𝑉2 βˆ’ 𝑉1 ∝ 𝑉1 Γ— (πœƒ2 βˆ’ πœƒ1)

Or, 𝑉2 βˆ’ 𝑉1 = 𝛾 𝑉1 Γ— (πœƒ2 βˆ’ πœƒ1) ; where Ξ³ is called coefficient of cubical expansion or cubical

expansivity.

Cubical Expansivity (Ξ³): The coefficient of cubical expansion or cubical expansivity is given by

𝛾 =𝑉2βˆ’π‘‰1

𝑉1(πœƒ2βˆ’πœƒ1)Where 𝑉1is initial volume, (𝑉2 βˆ’ 𝑉1) is increase in volume, (πœƒ2 βˆ’ πœƒ1)is rise in

temperature.

Therefore, coefficient of cubical expansion or cubical expansivity is defined as the increase in volume

per unit original volume per unit rise in temperature. Its unit is 0C-1, K-1. Gamma (Ξ³) is same for a given

material.

Relation between Ξ±, Ξ² and Ξ³:

1) Ξ± and Ξ²:

Let us consider a square sheet of area 𝐴1at temperature πœƒ10𝐢 such that length

of each side𝑙1. When it is heated, its area becomes 𝐴2at temperature πœƒ2π‘œπΆ

such that length of each side𝑙2 as shown in Fig.C2(d).

Then, 𝐴1 = 𝑙12 … … … . . (1)

𝐴2 = 𝑙22 … … … . . (2)

The coefficient of linear expansion is given by 𝛼 =𝑙2βˆ’π‘™1

𝑙1(πœƒ2βˆ’πœƒ1)

Or, 𝛼𝑙1(πœƒ2 βˆ’ πœƒ1) = 𝑙2 βˆ’ 𝑙1

Or, 𝑙2 = 𝑙1𝛼(πœƒ2 βˆ’ πœƒ1) + 𝑙1

Similarly, coefficient of superficial expansion is given by 𝛽 =𝐴2βˆ’π΄1

𝐴1(πœƒ2βˆ’πœƒ1)

Or, 𝛽𝐴1(πœƒ2 βˆ’ πœƒ1) = 𝐴2 βˆ’ 𝐴1

)(2. cCFig

11,V

22 ,V

11,A

22 ,A

)(2. dCFig

1l

2l

𝑙2 = 𝑙1{1 + 𝛼(πœƒ2 βˆ’ πœƒ1)} … … … (3)

Or, 𝐴2 = 𝐴1𝛼(πœƒ2 βˆ’ πœƒ1) + 𝐴1

Putting equation (1) and (2) in equation (4)𝑙22 = 𝑙1

2{1 + 𝛽(πœƒ2 βˆ’ πœƒ1} … … … … (5)

Putting equation (3) in (5), we get 𝑙12{1 + 𝛼(πœƒ2 βˆ’ πœƒ1)}2= 𝑙1

2{1 + 𝛽(πœƒ2 βˆ’ πœƒ1}

Or, 1 + 2𝛼(πœƒ2 βˆ’ πœƒ1) + 𝛼2(πœƒ2 βˆ’ πœƒ1)2 = 1 + 𝛽(πœƒ2 βˆ’ πœƒ1)

Since, Ξ± is very small for any material, the term containing Ξ±2 is neglected. Then,

2𝛼(πœƒ2 βˆ’ πœƒ1) = 𝛽(πœƒ2 βˆ’ πœƒ1)

2) Ξ± and Ξ³:

Let us consider a cube of volume V1 at temperature ΞΈ10C such that

length of each side is 𝑙1. When it is heated its volume becomes V2

at temperature ΞΈ20C and length of each side is 𝑙2 as shown in Fig.

C2(e).

Then, 𝑉1 = 𝑙13 … … … . . (1)

𝑉2 = 𝑙23 … … … . . (2)

The coefficient of linear expansion is given by 𝛼 =𝑙2βˆ’π‘™1

𝑙1(πœƒ2βˆ’πœƒ1)

Or, 𝛼𝑙1(πœƒ2 βˆ’ πœƒ1) = 𝑙2 βˆ’ 𝑙1

Or, 𝑙2 = 𝑙1𝛼(πœƒ2 βˆ’ πœƒ1) + 𝑙1

Similarly, coefficient of cubical expansion is given by 𝛾 =𝑉2βˆ’π‘‰1

𝑉1(πœƒ2βˆ’πœƒ1)

Or, 𝛾𝑉1(πœƒ2 βˆ’ πœƒ1) = 𝑉2 βˆ’ 𝑉1

Or, 𝑉2 = 𝑉1𝛼(πœƒ2 βˆ’ πœƒ1) + 𝑉1

Putting equation (1) and (2) in equation (4) 𝑙23 = 𝑙1

3{1 + 𝛾(πœƒ2 βˆ’ πœƒ1} … … … … (5)

Putting equation (3) in (5), we get 𝑙13{1 + 𝛼(πœƒ2 βˆ’ πœƒ1)}3= 𝑙1

3{1 + 𝛾(πœƒ2 βˆ’ πœƒ1}

Or, 1 + 3𝛼(πœƒ2 βˆ’ πœƒ1)2 + 3𝛼2(πœƒ2 βˆ’ πœƒ1) + 𝛼3(πœƒ2 βˆ’ πœƒ1)3 = 1 + 𝛾(πœƒ2 βˆ’ πœƒ1)

Since, Ξ± is very small for any material, we can neglect the terms containing higher order of alpha, Then,

3𝛼(πœƒ2 βˆ’ πœƒ1) + 0 + 0 = 𝛾(πœƒ2 βˆ’ πœƒ1)

𝐴2 = 𝐴1{1 + 𝛽 (πœƒ2

βˆ’ πœƒ1)} … … … (4)

∴ Ξ² = 2𝛼

11,V

22 ,V

)(2. eCFig

1l

2l

𝑙2 = 𝑙1{1 + 𝛼(πœƒ2 βˆ’ πœƒ1)} … … … (3)

𝑉2 = 𝑉1{1 + 𝛾(πœƒ2 βˆ’ πœƒ1)} … … … (4)

∴ 𝛾 = 3𝛼

Combining both relations,

Determination of alpha (Ξ±): Pullinger’s Apparatus Method:

An experimental arrangement to

determine linear expansivity of any

material is as shown in Fig.C2 (f).

Rod AB of length 𝑙1is taken at initial

temperatureπœƒ10𝐢. It is placed in an

evacuated metallic tube of which

three holes are used for steam inlet,

steam outlet and thermometer (T).

Lower end B of rod is fixed while

upper end A is free to expand.

Battery, Galvanometer and Key are

used to check the connection between

spherometer and point A of rod.

Spherometer is used to measure the

expansion of rod.

When spherometer touches point A of rod reading R1 of spherometer is noted. Some gap is left between

spherometer and point A of rod to provide space for expansion. Now steam is passed through steam inlet

until the final temperature πœƒ2π‘œπΆ is noted and expansion is measured by connecting spherometer leg with

point A of rod where reading of spherometer is R2. Now, R2 – R1 = Increase in length

When spherometer touches point A of rod galvanometer shows deflection. Now, coefficient of linear

expansion or linear expansivity is given by

𝛼 =πΌπ‘›π‘π‘Ÿπ‘’π‘Žπ‘ π‘’ 𝑖𝑛 π‘™π‘’π‘›π‘”π‘‘β„Ž

πΌπ‘›π‘–π‘‘π‘–π‘Žπ‘™ π‘™π‘’π‘›π‘”π‘‘β„Ž Γ— 𝑅𝑖𝑠𝑒 𝑖𝑛 π‘‘π‘’π‘šπ‘π‘’π‘Ÿπ‘Žπ‘‘π‘’π‘Ÿπ‘’=

𝑅2 βˆ’ 𝑅1

𝑙1(πœƒ2 βˆ’ πœƒ1)

By using this expression we can determine linear expansivity of any material. Simillarly we can calculate

superficial and cubical expansivity of a material by using 𝛽 = 2𝛼 π‘Žπ‘›π‘‘ 𝛾 = 3𝛼

𝛼 =𝛽

2=

𝛾

3

)(2. fCFig