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TRANSCRIPT
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SMALL WONDERSSR.SEC.SCHOOLJABALPUR
A CHEMISTRY PROJECT
AIM--
STUDY OF THE OXALATE IONCONTENT IN GUAVA FRUIT
Submitted in the partial Fulfilment of therequirement for CBSE 2013-2014Submitted By-
SHUBHANGI JAISWAL
Of Class XIIB
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CONTENTS# INTRODUCTION
# OBJECTIVE OF THE PROJECT
# REQUIREMENTS
# THEORY
# CHEMICAL EQUATIONS
# PROCEDURE
# PRECAUTIONS
# OBSERVATIONS
# CALCULATIONS
# CONCLUSION
# BIBLIOGRAPHY
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STUDY OF OXALATE IONCONTENT IN GUAVA FRUIT
INTRODUCTION
Guava is sweet, juicy and light or dark green coloured
fruit. It is cultivated in all parts of India. When ripe it
acquires yellow colour and has penetrating strong scent.The fruit is rich in vitamin C and minerals. It is a rich
source of oxalate and its content in the fruit varies during
different stages of ripening.
Guava fruit, usually 4 to 12 cm long, are round or oval
depending on the species. The outer skin may be rough,
often with a bitter taste, or soft and sweet. Varying
between species, the skin can be any thickness, is usually
green before maturity, but becomes yellow, maroon, or
green when ripe.
Guava fruit generally have a pronounced and typical
fragrance, similar to lemon rind but less sharp. Guava
pulp may be sweet or sour, off-white ("white" guavas) to
deep pink ("red" guavas), with the seeds in the centralpulp of variable number and hardness, again depending
on specie.
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WHAT IS OXALATE?
Oxalate is an organic acid, primarily found in plants,
animals and humans. It is not an essential molecule and
is excreted from our body in an unchanged form. Our
body either produces oxalate on its own or it converts
other molecules like vitamin C to oxalate. External
sources like the foods we eat also contribute to the
accumulation of oxalate in our body. The oxalate present
in the body is excreted in our urine as a waste. Too much
of oxalate in our urine, results in a medical condition
called as hyperoxaluria, commonly referred to as kidney
stones. Diet is looked upon as a preventive measure in
addition to medicines to treat kidney stones. Read more
on what causes kidney stones.
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OBJECTIVE OF PROJECT
In this project, we will learn to test for the
presence of oxalate ions in the guava fruit and
how its amount varies during different stages ofripening.
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REQUIREMENTSMATERIALS REQUIRED
# 100 ml Measuring Flask Pestle and Mortar
# Pestle And Mortar
#Beaker
#Titration Flask
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# Funnel
# Burtte
#Pipette
#Weight Box
#Filter Papers
#Guava Fruits
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CHEMICALS REQUIRED
--Dilute H2SO4
--N/20 KMnO4 solution
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THEORYOxalate ions are extracted from the fruit by boiling pulp
with dil. H2SO4. Then oxalate ions are estimatedvolumetrically by titrating the solution with standard
KMnO4 solution.
Titration is a common laboratory method of quantitative
chemical analysis that is used to determine the unknown
concentration of a known reactant. Because volume
measurements play a key role in titration, it is also known
as volumetric analysis. A reagent, called the titrant or
titrator, of a known concentration (a standard solution)
and volume is used to react with a solution of the analyte
or titrand, whose concentration is not known. Using a
calibrated burette or chemistry pipetting syringe to add
the titrant, it is possible to determine the exact amount
that has been consumed when the endpoint is reached.
The endpoint is the point at which the titration is
complete, as determined by an indicator (see below). This
is ideally the same volume as the equivalence pointthe
volume of added titrant at which the number of moles of
titrant is equal to the number of moles of analyte, or
some multiple thereof (as in polyprotic acids). In theclassic strong acid-strong base titration, the endpoint of a
titration is the point at which the pH of the reactant is
just about equal to 7.
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CHEMICAL EQUATIONS
Molecular Equations -2KMnO4 + 3H2SO4 ---------------------- K2SO4 +
2MnSO4 + 2H2O + 4[O]
HOOC-COOH.2H2O +[O] --------------------- 2CO2 +
2H2O x 5 Co7060
3KMnO4 + 3H2SO4 +5 HOOC-COOH.2H2O
---------------------K2SO4 + 2MnSO4 + 18H2O +
10CO
#Ionic Equations
MnO4- +16H+ + 5e ---------------------- Mn2+ + 4H2O
x 2
C2O4 --------------------- 2CO2 + 2e- x 5
2MnO4- + 16H+ + 5C2O42 - --------------------- 2Mn2+
+8H2O + 10CO2
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PROCEDURE
1. Weigh 50.0g of fresh guava and crush it to a fine pulpusing pestle-mortar.
2. Transfer the crushed pulp to beaker and add about 50
ml dil. H2SO4 to it
3. Boil the contents for about 10 minutes.
4. Cool and filter the contents in a 100 ml measuring
flask. Make the volume upto 100 ml by adding distilled
water.
5. Take 20 ml of the solution from the measuring flask
into a titration flask and add 30 ml of dilute sulphuricacid to it.
6. Heat the mixture to about 60oC and titrate it against
KMnO4 solution taken in a burette. The end point is
appearance of permanent light-pink colour.
7. Repeat the above experiment with 50.0 g of 1, 2 and 3days old guava fruit.
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PRECAUTIONS
1. KMnO4 solution is always taken in the burette.
2. Avoid the use of burette having a rubber tap as KMnO4
attacks rubber.
3. In order to get some idea about the temperature of the
solution touch the flask to the back side of your hand.When it becomes unbearable to touch, the required
temperature is reached.
4. Add about an equal volume of dil. H2SO4 to the guava
extract to be titrated (say a full test tube) before adding
KMnO4 .
5. Read the upper meniscus while taking burette reading
with KMnO4 solution.
6. In case, on addition of KMnO4 a brown ppt. appears,
this shows that either H2SO4 has not been added or has
been added in insufficient amount. In such a case, throw
away the solution and titrate again.
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OBSERVATIONS
--Weight of guava fruit taken each time = 50.0 g
Volume of guava extract taken in each titration = 20.0 ml
--N ormality of KMnO4 solution = N
Guava
extract
From
Initial
reading
of the
burette
Final
reading
of the
burette
Volume
of the
N/20
KMnO4
solution
(ml)
Strength
of
Oxalate
Fresh
Guava
One Day
Old
Guava
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CALCULATIONS
For fresh guavaN1.V1(guava extract) = N2.V2 (KMnO4 solution)
Normality of oxalate, N1 = X/200
Strength of oxalate in fresh guava extract= Normality x Eq. mass of oxalate ion
= X/200 x 44 g/litre of the diluted extract
Normality of oxalate, N1 =X/200
Strength of oxalate in one day guava extract= Normality x Eq. mass of oxalate ion
=X/200 x 44 g/litre of the diluted extract
Similarly, calculate the strength of oxalate in 1,
2 and 3 days old guava extract and interpret theresult.
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CONCLUSION
The concentration of the oxalate ion increases with
increase with ripening.
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BIBLIOGRAPHY
1. INDIAN INSTITUTE OF APPLIEDSCIENCE:http://www.ias.ac.in/currsci/aug102001/248.pdf
2. www.wikipedia.org
3. Comprehensive Practical Chemistry forClass XII
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CERTIFICATEThis is to certify that this dissertation titled
STUDY OF QUANTITY OF CAESIN
PRESENT IN DIFFERENT SAMPLES OF
MILK submitted by SHUBHANGI JAISWAL
to Chemistry department of SMALLWONDER SENIOR SEC. SCHOOL
JABALPUR, was carried under guidance and
supervision during the academic year 2013-
2014.
Principal Mrs..
SANGEETA GROVER
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ACKNOWLEDGEMENTI wish to express my deep gratitude and sincere thanksto the Principal, Ms. SANGEETA GROVER, SMALLWONDER SENIOR SEC. SCHOOL, JABALPUR for herencouragement and for all the facilities that sheprovided for this project work. I sincerely appreciate thismagnanimity by taking me into her fold for which Ishall remain indebted to her. I extend my hearty thanksto Mrs. SHRADDHA SONI, chemistry teacher, whoguided me to the successful completion of this project.I take this opportunity to express my deep sense of
gratitude for his invaluable guidance, constantencouragement, constructive comments, sympatheticattitude and immense motivation, which has sustainedmy efforts at all stages of this project work.
SHUBHANGI JAISWAL
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DECLARATIONI do hereby declare that this project work has
been originally carried under the guidance andsupervision of Mrs. SHRADDHA SONI, head
of chemistry department, SMALL WONDER
SENIOR SEC. SCHOOL, JABALPUR