handout 7 statistics in energy bands · 2017. 12. 22. · statistics in energy bands in this...
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ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Handout 7
Properties of Bloch States and Electron Statistics in Energy Bands
In this lecture you will learn:
• Properties of Bloch functions
• Periodic boundary conditions for Bloch functions
• Density of states in k-space
• Electron occupation statistics in energy bands
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Bloch Functions - Summary
• Electron energies and solutions are written as ( is restricted to the first BZ):
• The solutions satisfy the Bloch’s theorem:
and can be written as a superposition of plane waves, as shown below for 3D:
• Any lattice vector and reciprocal lattice vector can be written as:
• Volume of the direct lattice primitive cell and the reciprocal lattice first BZ are:
rkn
, and kEn
reRr knRki
kn
,
.,
j
rGkijnkn
jeV
Gkcr
.
,1
k
332211 bmbmbmG
3213 . bbb
332211 anananR
3213 . aaa
2
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Bloch Function – Product Form ExpressionA Bloch function corresponding to the wavevector and energy band “n” can always be written as superposition over plane waves in the form:
k
j
rGkijnkn
jeV
Gkcr
.
,1
The above expression can be re-written as follows:
rueV
eGceV
eV
Gkcer
knrki
j
rGijkn
rki
j
rGijn
rkikn
j
j
,.
.,
.
..,
1
1
1
Where the function is lattice periodic: ru kn
,
ru
eGceGcRru
kn
j
rGijkn
j
RrGijknkn
jj
,
.,
.,,
satisfiesBloch’s theorem
re
Rr
knRki
kn
,.
,
rue
Vr kn
rkikn
,
.,
1Note that:
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Allowed Wavevectors for Free-Electrons (Sommerfeld Model)
xLyL
zL zyx LLLV
We used periodic boundary conditions:
zyxLzyx
zyxzLyx
zyxzyLx
z
y
x
,,,,
,,,,
,,,,
The boundary conditions dictate that the allowed values of kx , ky , and kz, are such that:
z
zLki
yy
Lki
xx
Lki
Lpke
Lmke
Lnke
zz
yy
xx
21
21
21
n = 0, ±1, ±2,….
m = 0, ±1, ±2,….
p = 0, ±1, ±2,….
32V There are grid points per unit volume
of k-space
xL2
yL2
zL2
xk
yk
zk
3
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Bloch Functions – Periodic Boundary Conditions
• Any vector in the first BZ can be written as:k
332211 bbbk
where 1 , 2 , and 3 range from -1/2 to +1/2:
Reciprocal lattice for a 2D latticeDirect lattice
1b
1a
2b
2a
k
21
21
1 21
21
2 21
21
3
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Bloch Functions – Periodic Boundary Conditions
• Consider a 3D crystal made up of N1 primitive cells in the direction, N2 primitive cells in the direction and N3 primitive cells in the direction
1a
2a
3a
Assuming periodic boundary conditions in all three directions we must have:
rreaNr aNki
11.11
rreaNr aNki
22.22
rreaNr aNki
33.33
Volume of the entire crystal is: 3321332211 . NNNaNaNaNV
1a
2a
22 aN
11 aN
221
2211
:crystal2DtheFor
NN
aNaNA
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ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Bloch Functions – Periodic Boundary Conditions
The periodic boundary condition in the direction implies:
1
11
111
1111
.
2. :that recall 22
integer an is 2.
111
Nm
bamN
mmaNk
e
kjkj
aNki
Since:21
21
1 221
11 N
mN
m1 can have N1 different integral values between –N1/2 and +N1/2
Reciprocal lattice for a 2D lattice
Direct lattice
1b
1a
2b
2a
1a
k 332211 bbbk
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Bloch Functions – Periodic Boundary Conditions Similarly, the periodic boundary conditions in the directions of and imply:
3
33
2
22
333222
..
&
2.&2.
1&1 3322
N
m
Nm
maNkmaNk
ee aNkiaNki
m1 can have N1 different integral values m2 can have N2 different integral values m3 can have N3 different integral values
Reciprocal lattice for a 2D lattice
Direct lattice
1b
1a
2b
2a
2a
k
332211 bbbk
3a
Since any k-vector in the FBZ is given as:
there are N1 N2 N3 different allowed k-values in the FBZ
There are as many different allowed k-values in the FBZ as the number of primitive cells in the crystal
22&
223
332
22 N
mNN
mN
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ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Density of States in k-SpaceReciprocal lattice for a 2D lattice
332211 bbbk
222
22
2
22
Nm
NNm
223
33
3
33
Nm
NNm
221
11
1
11
Nm
NNm
1
2a
2
2a
1b
2b
11
2aN
22
2aN
Question: Since is allowed to have only discrete values, how many allowed k-values are there per unit volume of the k-space?
k
Volume of the first BZ is:
3213 . bbb
• In this volume, there are N1 N2 N3allowed k-values
• The number of allowed k-values per unit volume in k-space are:
3
33
321
3
321
2
2
V
NNN
NNN
where V is the volume of the crystal
3D Case:
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Density of States in k-Space
1b
2b
1b1D Case:
Length of the first BZ is:1
112
b
• In the first BZ, there are N1 allowed k-values • The number of allowed k-values per unit length in k-space are:
22 11
11
1 LN
N
Length of the crystal: 1111 NaNL
2D Case:
Area of the first BZ is:
2
2
2122
bb
• In the first BZ, there are N1N2 allowed k-values • The number of allowed k-values per unit area in k-space are:
222
212
21
22 A
NNNN
Area of the crystal: 2212211 NNaNaNA
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ECE 407 – Spring 2009 – Farhan Rana – Cornell University
States in k-Space and Number of Primitive Cells
k
Energy
a
a
k
Energy
a
a
1D Case:
1b
a
a
Length of the first BZ is:a
b2
11
• In the first BZ, there are N1 allowed k-values • The number of allowed k-values per unit length in k-space are:
22 11
11
1 LN
N
Length of the crystal: aNNaNL 11111
LaN 22
1
Reciprocal lattice is:
There are N1 allowed k-values in k-spaceThere are N1 allowed k-values per energy bandThere are as many allowed k-values per energy band as the number of primitive cells in the entire crystal
xaa ˆ1
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
xk
yk
)0,(1a
),0(2a
Energy
FBZ
States in k-Space and Number of Primitive Cells2D Case:
1
2a
2
2a
1b
2b
11
2aN
22
2aN
Reciprocal lattice is:
• In the first BZ, there are N1N2 allowed k-values
There are N1N2 allowed k-values per energy band
There are as many allowed k-values per energy band as the number of primitive cells in the entire crystal
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ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Statistics of Electrons in Energy Bands
k
Energy
a
a
k
Energy
a
a
kE1
kE2
kE3
1D Case:
The number of allowed k-values per unit length in k-space is L / 2therefore:
Suppose I want to find the total number of electrons in the n-th band – how should I find it?
The probability that the quantum state of wavevector is in the n-th energy band is occupied by an electron is given by the Fermi-Dirac distribution:
k
TKEkEnfne
kf
1
1
Then the total number N of electrons in the n-th band must equal the following sum over all the allowed values in k-space in the first BZ:
FBZin all
2k
n kfN
spin
kfdk
LkfN n
a
akn
222
FBZ in all
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
FBZ in all
2k
n kfN
2D Case:
The number of allowed k-values per unit area in k-space is:
kfkd
AkfN nFBZk
n
2
2
FBZ in all 222
22A
Therefore:
Need to find the total number of electrons in the n-th band
3D Case:
The number of allowed k-values per unit volume in k-space is:
kfkd
VkfN nFBZk
n
3
3
FBZ in all 222
32V
Therefore:
Statistics of Electrons in Energy Bands
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ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Band Filling at T0K for a 1D lattice
k
Energy
a
a
k
Energy
a
a
Question: suppose we have 2 electrons per primitive cell. How will the bands fill up at T0K? Where will be the Fermi level?
2 electrons per primitive cell 2N1 total number of electrons
Number of k-values per band = N1Number of quantum states per band = 2xN1
spin First band will be completely filled. All higher bands will be empty
Question: Suppose we have 3 electrons per primitive cell. How will the bands fill up at T0K?
3 electrons per primitive cell 3N1 total number of electrons
First band will be completely filled. Second band will be half filled. All higher bands will be empty
Ef for 3 electrons per primitive cell
Ef for 2 electrons per primitive cell
Ef for 4 electrons per primitive cell
Suppose the number of primitive cells = N1
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Band Filling at T0K for a 2D lattice
Question: suppose we have 2 electrons per primitive cell. How will the bands fill up at T0K? Where will be the Fermi level?
2 electrons per primitive cell 2N1N2 total number of electrons
Number of k-values per band = N1N2Number of quantum states per band = 2xN1N2
spin First band will be completely filled. All higher bands will be empty
Suppose the number of primitive cells = N1N2
Important lesson:In an energy band (whether in 1D, 2D or 3D) the total number of quantum states available is twice the number of primitive cells in the direct lattice. How the bands get filled depends on the number of electrons per primitive cell.
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ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Fermi Surfaces (3D) and Contours (2D) in Solids
xk
yk
Energy
EF
kF
Fermi circle for a free electron gas in 2D
What happens in solids when the energy bands are more complex?
xk
yk
Energy
FBZ
First energy band of a 2D lattice
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
xk
yk
Energy
FBZ
Fermi contours for different electron densities corresponding to the energy band shown on the left
FBZ
First energy band of a 2D lattice
xk
yk
xc
b ˆ2
11
xca ˆ11
yc
b ˆ2
22
yca ˆ22
Fermi Surfaces (3D) and Contours (2D) in Solids
FBZ
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ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Fermi Surfaces (3D) and Contours (2D) in Solids
Fermi surface of a simple cubic direct lattice shown inside the first BZ
Fermi surface of a FCC lattice shown inside the first BZ (the figure shows the Fermi surface of Copper)
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
Band Filling at T0K for Silicon
Electron Configuration: 1s2 2s2 2p6 3s2 3p2
Atomic number: 14
• The electrons in the outermost shell can move from atom to atom in the lattice – they are not confined to any individual atom. Their energies are described by the energy bands
• The electrons in the inner shells remain confined to individual atoms
Number of electrons in the outermost shell: 4
Silicon:
• Silicon lattice is FCC
• There are 2 Silicon atoms per primitive cell (2 basis atoms)
There are 4 electrons contributed by each Silicon atom and so there are 8 electrons per primitive cell that are available to fill the energy bands
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ECE 407 – Spring 2009 – Farhan Rana – Cornell University
2
2
1
1
1
1
Band Filling at T0K for Silicon• There are 8 electrons per unit cell available to fill the energy bands
• Recall that in each energy band the number of states available is twice the number of primitive cells in the crystal
• In Silicon, the lowest 4 energy bands will get completely filled at T0K and all the higher energy bands will be empty
Ef
1
1
1
1
FBZ (for FCC lattice)Silicon Energy Bands
ECE 407 – Spring 2009 – Farhan Rana – Cornell University
2
2
1
1
1
1
Ef
1
1
1
1
FBZ (for FCC lattice)Silicon Energy Bands
Valence band
Conduction band
Energy Bands in Silicon• The highest filled energy band is called the valence band. In silicon the valence band is double degenerate at most points in the first BZ• The lowest empty energy band is called the conduction band• In energy, the valence band maximum and the conduction band minimum need not happen at the same point in k-space (as is the case in Silicon)• The lowest energy of the conduction band is called Ec and the highest energy of the valence band is called Ev
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ECE 407 – Spring 2009 – Farhan Rana – Cornell University
k
Energy
a
a
xk
yk
Energy
FBZ