heat transfer co-efficient ce

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    HEAT TRANSFER CO-EFFICIENT

    Pritam Kambli

    Amruta KarbelkarVikrant YelveKshama SawantVidhi Shah

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    HOW IS HEAT TRANSFER ACCOMPLISHEDHeat can transfer between the surfaceof a solid conductor and thesurrounding medium whenever

    temperature gradient exists.

    There are three ways:

    ConductionConvectionRadiation

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    It is generally considered as the heat transfer phenomena for

    the solids

    Itfollows the Fourier Law of Heat Conduction:

    Q = -kAT

    Where,Q = transfer of heat per unit time

    k = conductive heat transfer coefficient

    A = heat transfer areaT = temperature difference between two systems

    The thermal conductivity units in SI system is W/mK.

    CONDUCTION

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    Convective heat transfer occurs when the heat istransferred from a solid surface to a moving fluid owingto the temperature difference between the solid and thefluid.

    It follows the Newtons Cooling Law of HeatConvection:

    Q = hA(T T')Where,

    Q = transfer of heat per unit timeh = convection heat transfer coefficientA = heat transfer areaT = temperature of fluidT'= temperature of solid

    CONVECTION

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    Natural ConvectionNatural convection occurs whenever heat flows

    between a solid and fluid, or between fluid layers.

    As a result of heat exchangeChange in density of effective fluid layers taken

    place, which causes upward flow of heated fluid.

    If this motion is associated with heat transfer mechanismonly, then it is called Natural Convection

    Forced ConvectionIf this motion is associated bymechanical means such as pumps, gravityor fans, the movement of the fluid isenforced.

    Convection is further classified as:

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    .

    RADIATION

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    whereQ= heat flow in input or lost heat flow , J/s = W

    h= heat transfer coefficient, W/(m2K)

    A= heat transfer surface area, m2

    = difference in temperature between the solid surface and

    surrounding fluid area, K

    HEAT TRANSFER CO-EFFICIENT?

    The efficiency of a bodys ability to transfer heat by convection to thesurrounding environment is defined by the convective heat transferco-efficient.

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    It can be estimated by dividing the thermal conductivity of theconvection fluid by a length scale.

    The heat transfer coefficient is often calculated from the Nusseltnumber.

    An understanding of convection boundary layers isnecessary to understanding convective heat transfer between asurface and a fluid flowing past it.

    Methods of calculating heat Transfer Co-efficient

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    Q hot Q cold

    Th Ti,wall

    To,wall

    Tc

    Region I : Hot Liquid-

    Solid Convection

    NEWTONS LAW OF

    CCOLING

    dqxhh .ThTiw .dA Region II : ConductionAcross Copper Wall

    FOURIERS LAW

    dqx

    k.dT

    dr

    Region III: Solid

    Cold Liquid

    Convection

    NEWTONS LAW OF

    CCOLINGdqxhc .TowTc .dA

    THERMAL

    BOUNDARY LAYER

    Energy moves from hotfluid to a surface byconvection, through thewall by conduction, andthen by convection fromthe surface to the coldfluid.

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    Experiment

    AIM:To establish wall heat transfer in packed bed and determinerelationship between nusselt number and reynolds number.

    APPARATUS: Hot water with constant inlet temperature as heatingmedium, Platform Scale balance, stop watch, weighing container, Auxiliarypiping and pumping equipment.

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    Experimental SetupA 5.0 cm copper tube is fitted with an external jacket. The packing is 3/8"

    3/8" raschigrings, labeled inside the tube up to 45.7 cm length and rest on a perforatedplate,having 45% hole area.The packed bed exchanger is equipped with thermometers to measure the inleand outlet temperatures of cold water and hot water owing respectively on thetube side and jacket side.

    DataInner diameter of packed tube (Di) = 50 mm.Outer diameter of packed tube (Do) = 60.6 mm.

    Inner diameter of jacket (Di) jacket = 86 mm.Length of packed test section = 457.2mm.Raschig Ring Dimensions: Length = 13.6 mm,Inner diameter = 7.6 mm,Outer diameter = 13.6mm.

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    PROCEDURE

    1. Admit the cold water through the packed tube and set its flow rate to thedesired value asindicated by the calibrated Rota meter.

    2. Admit hot water through the jacket at 60C and at constant flow rate of about

    10 kg/min.

    3. When the steady state is reached, record the inlet and outlet temperatures ofcold water andhot water.

    4. Determine the exact flow rates of cold water and hot fluid by weighing theliquids collectedin a known interval of time.

    5. Repeat the above procedure for several low rates. Flow rate of cold water inthe packed bed

    should be in the range of 2 to 7 kg/min for constant operating conditions of

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    Method of Calculation

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    PRO LEMA steel pipe of diameter 10cm ismaintained at 170oC and exposed to air at30oC. Length of the pipe is 2m and is kepthorizontally. Find the heat lost by pipe perhour. Following are the properties at mean

    temperature.Thermal conductivity = 0.0322W/m/KKinematic Viscosity = 23.3X10-6

    Prandlt number = 0.69

    For horizontal cylinders:Nu =hL/k = 0.53(Gr.Pr)1/4{104

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    Formulae UsedGr = BgmL3/2

    Pr = Cp./k

    B = 1/T

    Q = hAt

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    REFERENCE

    www.wikipedia.com

    Lab manual of chemical engineering, exp no.19, heat transfer inPacked bed.

    Unit operation of chemical engineering, mccabe and smith, 5thedition,Pg.403 to pg.465.

    Heat transfer co-efficient experiment in fin surface, pdf.

    http://www.wikipedia.com/http://www.wikipedia.com/