homotopy analysis method (ham) is applied to the maxwell system
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The Journal of Mathematics and Computer Science Vol .3 No.2 (2011) 225 - 235
Numerical solution for Maxwell's equation in metamaterials by
Homotopy Analysis Method
1. Malek Ashtar University of Technology
2. Department of Mathematics, Shahid Beheshti University, Tehran, Iran
Received: May 2011, Revised: June 2011
Online Publication: December 2011
Abstract
In this paper, the Homotopy analysis Method (HAM) is applied to the Maxwell system.
The HAM yields an analytical solution in terms of a rapidly convergent infinite power
series with easily computable terms.
1. Basic of Homotopy analysis method
We consider the following differential equation
,0)]([ uN (1)
where N is a nonlinear operator, denotes independent variable, )(u is an
unknown function, respectively. For simplicity, we ignore all boundary or initial
conditions, which can be treated in the similar way. By means of generalizing the
traditional homotopy method, Liao [7] constructs the so-called zero-order
deformation equation
)],;([)()]();([)1( 0 pNphHupLp (2)
The Journal of
Mathematics and Computer Science
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Where 1][0,p is the embedding parameter, 0h is a non-zero auxiliary parameter,
)(H
is an auxiliary function, L is an auxiliary linear operator, )(0 u is an initial guess of is
an
unknown function, respectively. It is important, that one has great freedom to choose
auxiliary things in HAM. Obviously, when = 0 = 1, it holds)()0;( 0 u , )()1;( u (3)
respectively. Thus, as p increases from 0 to 1, the solution );( p varies from the initial
guess )(0 u to the solution )(u .Expanding );( p in Taylor series with respect to p ,
we have
1
0 ,)()();(m
m
m puup (4)
Where
.);(
!
1)(
0
p
m
m
mp
p
mu
(5)
If the auxiliary linear operator, the initial guess, the auxiliary parameter h , and the
auxiliary function are properly chosen, the series (4) converges at 1p , and then we
have
,)()()(1
0
m
muuu (6)
which must be one of solutions of original nonlinear equation, as proved by Liao [1]. As
1h and ,1)( H Eq. (2) become
0)];([)]();([)1( 0 ppNupLp (7)
Which is used mostly in the homotopy perturbation method, where as the solution
obtained directly, without using Taylor series [2, 3]. According to the definition (5), the
governing equation can be deduced from the zero-order deformation equation (2).
Define the vector
)}.(,),(),({ 10 nn uuuu
Differentiating equation (7) m times with respect to the embedding parameter p and
then setting 0p and finally dividing them by m!, we have the so-called m th-order
deformation equation
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),()()]()([ 11
mmmmm uRhHuuL (8)
subject to initial condition
,0)0,( xum ,0
)0,(
t
xum (9)
Where
.)];([
)!1(
1)(
0
1
1
1
p
m
m
mmp
pN
muR
(10)
And
m =
1
0
1
1
m
m(11)
It should be emphasized that )(mu for 1m is governed by the linear equation (8)
with the linear boundary conditions that come from original problem, which can be
easily solved by symbolic computation software such as Mathematica. If Eq. (1) admits
unique solution, then this method will produce the unique solution. If equation (1) does
not possess unique solution, the HAM will give a solution among many other (possible)
solutions. For the convergence of the above method we refer the reader to [5,6, 7, 9 ].
2. The Maxwell system in meta materials
The DNG, metamaterials can be simulated using lossy Drude polarization and
magnetization modes. The governing equations for modeling wave propagation in
metamaterials are[1,4,10]
0
=
12
0 = . 1310 2 + 02 = , 1410 2 + 02 = , 15
where 0 is the vacuum permittivity,0 is the vacuum permeability, and arethe electric and magnetic plasma frequencies, respectively, and are the electric and
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magnetic damping frequencies, respectively,(, ) and(, ) are the electric andmagnetic fields, respectively, and(, )and (, )are the induced electric andmagnetic currents, respectively. The complex materials make solving the metamaterials
model more challenging, since the governing equations cannot be reduced to a simple
vector wave equation as in vacuum.
For simplicity, we assume that the modeling domain be (0,), where is abounded Lipschitz polyhedral domain in 3 with connected boundary. Furthermore,we assume that the boundary of is perfect conducting so that
= 0 On (16)Where is the unit outward normal to . Also we assume that the initial conditionsare
, 0 = 0, , 0 = 0 (17), 0 =0,, 0 =0.Lemma 2.1. There exists a unique solution for system (12)-(15). Furthermore; the
solution of the system (12)-(15) satisfies the following stability estimate [4]
0()02 + 0 ()02 + 10 2 ()02 + 10 2 ()02 0(0)02 +
0
(0)
0
2+
1
0
2
(0)
0
2+
1
0
2
(0)
0
2. (18)
Lemma 2.2. Assume that the initial conditions are divergence free.i.e.,. 00 = 0, . 00 = 0. 0 = 0, . 0 = 0 (19)Then for any time > 0, the electric field and electric current are divergence free.Similary, for any time > 0, the magnetic field and the magnetic currentaredivergence free.
3. The HAM for the Maxwell system in meta materials
In this section of the paper, we consider the Maxwell system in Meta materials. In
system (12)-(15), we carry directly to 2D by using the scalar and vector curl operators
= 21 1 2 (20) = = ( 2 , 1) (21)
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Where the upper index denotes the vector transpose. Considering the lossy propertyof metamaterials, we construct the following exact solution for the 2D transverse
electrical model (assuming all physical parameters to be one, i.e.(0 = 0 = =
=
=
= 1)
= = 12 cos sin
12 sin cos etcost
= 2 (cos cos) etcost(22)
= = 12 cos sin12 sin cos
etsin t
= 2 (cos cos) et sintTo solve the system. (1215) by means of homotopy analysis method, we choose the
linear operator
L1[1x,y,t;p] = 1x,y,t;pt L22x,y,t;p = 2x,y,t;pt L33x,y,t;p = 3x,y,t;pt (23)L4[
4
x,y,t;p
] =
4
x,y,t;p
t
L5[5x,y,t;p] = 5x,y,t;pt L6[6x,y,t;p] = 6x,y,t;pt
With the property: = 0 = 1,2,3,4,5,6where
are integral constants. The inverse L
i1operator are given by
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Li1
= . dtt0
We now define a nonlinear operator as
11,2,3 ,4 ,5 ,6 = 0 1t 3y + 4 21,2,3 ,4 ,5 ,6 = 0 2t + 3x + 531,2 ,3 ,4,5,6 = 0 3t + 2x 1y 6
41,
2,
3,
4,
5,
6=
1
02 4
t+
02 4 1 (24)
51,2,3 ,4 ,5,6 = 102 5t + 02 5 261,2 ,3,4,5 ,6 = 1
02 6t + 02 6 3
Using above definition, we construct the zeroth-order deformation equation
1 pL11x,y,t;p Ex 0x,y,t = 11[1,2,3 ,4,5,6]1 pL2 2x,y,t;p Ey 0x,y,t = 22[1,2 ,3,4,5 ,6]1 pL33x,y,t;p H0x,y,t = 33[1,2,3,4 ,5,6] (25)1 pL44x,y,t;p Jx 0x,y,t = 44[1,2 ,3,4,5,6]1
p
L
5 5x,y,t;p
Jy 0
x,y,t
=
55[
1,
2,
3,
4,
5,
6]
1 pL66x,y,t;p K0x,y,t = 66[1,2,3,4,5,6]With the initial condition:
1x,y,t;0 = Ex 0x,y,t 1x,y,t;1 = Exx,y,t
2
x,y,t;0
= Ey 0
x,y,t
2
x,y,t;1
= Ey
x,y,t
3x,y,t;0 = 0x,y,t 3x,y,t;1 = Hx,y,t
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4x,y,t;0 = Jx x,y,t 4x,y,t;1 = Jxx,y,t 5x,y,t;0 = Jy x,y,t 5x,y,t;1 = Jyx,y,t x,y,t;0 = K x,y,t x,y,t;1 = Kx,y,t Thus, we obtain the th-order deformation equations
L1 Ex mx,y,t m Ex m1x,y,t = 11 [Ex m1, Ey m1, m1, Jx m1, Jy m1, m1]L2 Ey mx,y,t m Ey m1x,y,t = 22 [Ex m1, Ey m1 , m1, Jx m1 , Jy m1, m1]
L3 Hm x,y,t m Hm1x,y,t = 33 [Ex m1, Ey m1, m1, Jx m1, Jy m1, m1] (26)L4 Jx mx,y,t m Jx m1x,y,t = 54 [Ex m1 , Ey m1, m1, Jx m1, Jy m1 , m1]L5 Jy mx,y,t m Jy m1x,y,t = 55 [Ex m1 , Ey m1, m1, Jx m1, Jy m1 , m1]L6 Hmx,y,t m Hm1x,y,t = 66 [Ex m1, Ey m1 , m1, Jx m1 , Jy m1, m1]
where
1
Ex
m
1
, Ey
m
1
,
m
1, Jx
m
1
, Jy
m
1
,
m
1
= 0
Ex m1
t
Hm1
y
+ Jx m
1
2 Ex m1, Ey m1 , m1 , Jx m1, Jy m1 , m1 = 0 Ey m1t + Hm1x + Jy m13 Ex m1, Ey m1, m1, Jx m1 , Jy m1 , m1 = 0 Hm1t + Ey m1x Ex m1y m1 (27)
4 Ex m1, Ey m1, m1 , Jx m1, Jy m1, m1 = 10 2 Jx m1t + 0 2 Jx m1 Ex m1
5 Ex m1, Ey m1 , m1, Jx m1, Jy m1, m1 =1
02 Jy
m1t + 02 Jx m1 Ey m16 Ex m1 , Ey m1, m1 , Jx m1 , Jy m1, m1 = 102 m1t + 02 m1 Hm1
Now the solution of the -th-order deformation Eq. (26) 1Ex mx,y,t = m Ex m1x,y,t + 11[1 [Ex m1, Ey m1 , m1 , Jx m1, Jy m1, m1]Ey
mx,y,t
= m Ex
m1x,y,t
+
2
1[
2
[Ex
m1, Ey
m1,
m
1 , Jx
m1, Jy
m1,
m
1]
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Hmx,y,t = m Hm1x,y,t + 31[3 Ex m1, Ey m1, m1, Jx m1 , Jy m1 , m1 (28)Jx mx,y,t = m Jx m1x,y,t + 41[4 [Ex m1, Ey m1 , m1, Jx m1 , Jy m1, m1]Jy mx,y,t = m Jx m1x,y,t + 5
1
[5 [Ex m1, Ey m1 , m1, Jx m1 , Jy m1, m1]Kmx,y,t = m Km1x,y,t + 61[3 [Ex m1 , Ey m1, m1 , Jx m1 , Jy m1, m1]We start with under initial approximations:
By means of the above iteration formula (28) ifhi = 1, we can obtain directly theother components asEx,y,t = ExEy = Ex 0x,y,t + Ex x,y,t +i=0y0x,y,t + y ix,y,t +i=0 = cos sin (cos ()+42 1+22 1 22 +
cos sin (cos ()+422+22 2 2
2
+
Hx,y,t = H0x,y,t + Hix,y,t +
i=0
=
2
cos
cos
(cos (
) + 2
3 +
3
2+
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, , = Jx
y = Jx0x,y,t + Jx x,y,t +i=0
y0
x,y,t
+
y i
x,y,t
+i=0
=
t cos
sin
4(
2
2sin (
)+2
42+
2
42+
2
42
)
222 + t cos sin 5(22sin ()+2 5 2+ 2 52+ 25 2)222 +
x,y,t = K0x,y,t + Kix,y,t
+
i=0
= t cos cos6 (2 sin (t)2 + 262 + 262 + 26222
+ We now choose: = , = , = , = , = , = , = , = ,and then obtain:
x,y,t = t cos cos6 (4 2 + 26 + 62 2
And then choose: = , = , = , = , = , = , = , = ,with this chose, we have:
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x,y,t = t cos cos (1560 + 516 + 442 + 3)96
2
Conclusion
Homotopy analysis method is a powerful method which yields a convergent series
solution for Maxwell's equation system. This method is better than numerical methods,
as it is free from rounding off errors, and does not require large computer power.
It is apparently seen that HAM is a very powerful and efficient technique in finding
analytical solutions for wide classes of linear and nonlinear problems. The results show
that HAM is a powerful mathematical tool for solving nonlinear partial differential
equations and systems of nonlinear partial differential equations.
Mathematica has been used for computations in this article.
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