how many grams of product can be synthesized from 10.5 grams of oxygen and 3.75 grams of hydrogen?
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How many grams of product can be synthesized from 10.5 grams of oxygen and 3.75 grams of hydrogen?. How many grams of product can be synthesized from 10.5 grams of oxygen and 3.75 grams of hydrogen?. 2H 2 + O 2 2H 2 O. - PowerPoint PPT PresentationTRANSCRIPT
How many grams of product can be synthesized from 10.5 grams of oxygen and 3.75 grams of hydrogen?
2H2 + O2 2H2O
2 22
2 2
1 mole O .328 mole O10.5 g O x = =.328
32.0 g O 1 mole O
2 22
2 2
1mole H 1.875 mole H3.75 g H x = =.938
2.0 g H 2 mole H
22 22 2
2 2 2
18.0 g H O1 moleO 2 mole H O10.5 g O x x x =11.8 g H O
32.0 g O 1 mole O 1 mole H O
How many grams of gas are produced when 1.75 grams of magnesium are added to 10.0 ml of 1.5 M hydrochloric acid?
How many grams of gas are produced when 1.75 grams of magnesium are added to 10.0 ml of 1.5 M hydrochloric acid?
Mg + 2HCl MgCl2 + H2
1 mole Mg .072 mole Mg1.75 g Mg x = =.072
24.3 g Mg 1 mole Mg
1L 1.5 mole HCl .007 mole HCl10.0 ml HCl x x = =.0035
1000 ml 1 L HCl 2 mole HCl
222
2
2.0 g H1L 1.5 mole HCl 1 mole H10.0 ml HClx x x x = .015 g H
1000 ml 1L 2 mole HCl 1 mole H
How many grams of precipitate can be produced from 10.5 ml of .25M plumbous nitrate and 10.0 ml of .25 potassium iodide?
How many grams of precipitate can be produced from 10.5 ml of .25M plumbous nitrate and 10.0 ml of .25 potassium iodide?
Pb(NO3)2 + 2KI PbI2 + 2KNO3
3 2.25 mole Pb(NO ) 2.65 mole 10.5 ml x = = 2.65
1000 ml 1 mole
.25 mole KI 2.5 mole KI10.0 ml KI x = = 1.25
1000 ml 2 mole H
222
2
461.0 g PbI.25 moleKI 1 mole PbI10.0 ml KI x x x =.58 g PbI
1000 ml 2 mole KI 1 mole PbI
.002625.002625
.00125.0025
How many molecules of product can be synthesized from 30.0 grams of water and 25.0 grams of dinitrogen pentoxide?
How many molecules of product can be synthesized from 30.0 grams of water and 25.0 grams of dinitrogen pentoxide?
H2O + N2O5 2HNO3
22
2
1 mole H O .1.67 mole 30.0 g H Ox = =1.67
18.0 g H O 1 mole
2 52 5
2 5
1mole N O .232 mole25.0 g N O x = =.232
108.0 g N O 1 mole
23232 5 3 3
2 5 32 5 2 5 3
1 mole N O 2 mole HNO 6.02x10 molec HNO25.0 g N O x x x =2.79x10 molec. HNO
108.0 g N O 1 mole N O 1 mole HNO
How many grams of product can be produced when 3.05x1022 atoms of aluminum react with 3.05x1022 atoms of sulfur?
How many grams of product can be produced when 3.05x1022 atoms of aluminum react with 3.05x1022 atoms of sulfur?
2Al + 3S Al2S3
2223
1 mole Al .0507 mole Al3.05x10 atoms x = =..0254
6.02x10 atoms Al 2 mole
2223
1 mole S .0507 mole S3.05x10 atoms x = =.0169
6.02x10 atoms S 3 mole
22 2 32 32 323
2 3
150.3 g Al S1 mole Al S1 mole S3.05x10 atoms x x x =2.54 g Al S
6.02x10 atoms S 3 mole S 1 mole Al S
How many grams gas will be produced when .75 grams of aluminum react with 15.0 ml of 3.5M sulfuric acid?
How many grams gas will be produced when .75 grams of aluminum react with 15.0 ml of 3.5M sulfuric acid?
2Al + 3H2SO4 Al2(SO4)3 + 3H2
1 mole Al .028 mole Al.75 g Al x = =.014
27.0 g Al 2 mole Al
2 24 4
2 4
3.5 mole H SO .0525 mole H15.0 ml x = = .0175
1000 ml 3 mole H SOSO
222
2
2.0 g H1 mole Al 3 mole H.75 g Al x x x =.083 g H
27.0 g Al 2 mole Al 1 mole H