how tall is it? : the director’s stand

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How Tall Is It? : The Director’s Stand Jessica Mena, Austin Coker, Sarah Alyce Hartley, Scott Williams 5 th Period March 9

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How Tall Is It? : The Director’s Stand. Jessica Mena, Austin Coker, Sarah Alyce Hartley, Scott Williams 5 th Period March 9. 15° Angle-Scott. Tan15=x/74 .28=x/74 x=19.38 19.38ft+5.17ft=24.55ft. 5.17 ft. 15°. 74 feet. 60° Angle-Jessica. Tan60=x/12 - PowerPoint PPT Presentation

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Page 1: How Tall Is It? : The Director’s Stand

How Tall Is It? : The Director’s Stand

Jessica Mena, Austin Coker, Sarah Alyce Hartley, Scott Williams

5th PeriodMarch 9

Page 2: How Tall Is It? : The Director’s Stand

15° Angle-Scott

Tan15=x/74 .28=x/74 x=19.38

19.38ft+5.17ft=24.55ft

74 feet

5.17 ft

15°

Page 3: How Tall Is It? : The Director’s Stand

60° Angle-Jessica

Tan60=x/12 1.73=x/12 x=20.78 20.78+5.33=26.11f

t L.leg=12√3 = 20.78 20.78 + 5.33 =

26.11ft 12 feet

5.33 feet

60°

Page 4: How Tall Is It? : The Director’s Stand

30˚ Angle – Austin

Tan 30˚ = x/34ft 0.58 = x/34 X=19.63 19.63 + 5.75 =

25.38 S.Leg = 34ft/√3 Height = 34√3 / 3 Short leg = 19.63 19.63 + 5.75 =

25.38

34 feet

5.75 feet

Page 5: How Tall Is It? : The Director’s Stand

45° Angle - Sarah Alyce

Tan 45 = x/18 1 = x/18 X = 18 5.17 + 18 = 23.17

ft Leg=Leg 18 + 5.17 = 23.17

ft18 Feet

5.17 feet

Page 6: How Tall Is It? : The Director’s Stand

Conclusion

Average height = 24.8 feet

We learned that trigonometry is a very valuable tool and not just something you learn in math. It is very useful when dealing with a very tall object.