how to make tetris game

8/3/2019 How to Make Tetris Game

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Hng Dn Vit Game TETRIS

n Gin

Vi Ngn Ng C/C++ Trn DOS

Xin cho cc bn!

Chc hn chng ta cng s c ngi am m lm game v cng mun mnh c th vit c1 hoc nhiugame ,nhng khi u nh th no? ,cch lm ra sao?,cn nhng kin thc j khilm game? . lm c nhng game ln,hay,p v giao din th cc bn c th bt u lmvi nhng game nh, n gin .Mnh chc rng lm nh vy th k nng vit code ca bn stng rt nhanh v bn s t tin hn khi lm 1 game hay 1 chng trnh tng i ln.

Ci ny th theo kinh nghim ca mnh th rt ng.Ngi ta thng ni nng nht ,cht bsing nng tch cp nhng kin thc nh s c ngy bn nhn ra gi tr ca nhng g bnthn hc c.Mnh cng khng gii giang j c cng ch l 1 thng IT bnh thng,nhng bt

chc chu nn mun chia s t kinh nghim vit game n gin cho cc bn newbie(ch ccpro th em khng dm ma my u )

Writer: tauit_dnmdEmail:[email protected].

Uitstudent.com & congdongcviet.com


2/29

Li ni u

Trong Tut ny mnh s hng dn cho cc bn chi tit cch lm game Xp Gch trn Dos

nh th no: t m t gamechn cu trc d liucode hon chnh.

Ti sao mnh li bt u vi game trn DOS (mn hnh console) ? Ti v: mnh mun ai cngc th c hiu c ci TUT ny ,v lm trn DOS ri th chuyn qua lm c giao din th rtn gin.Mnh cng code game ny trn Dos v Winform(vi C#).Code demo trn C/C++ca game ny mnh ly li ca mnh code hi mi hc C/C++ nn c th n khng c hay vchun cho lm(v mi hc th ai m ch g.hihihi).

. tin v thun li khi theo di Tut ny cc bn cn phi bit cch hot ng v cchchi game Xp Gch (Tetris) Loi n gin y(V tetris c rt nhiu bin th v lut chikhc nhau). hiu r lut ca game cc bn ti ci ny v chi l hiu :

+DOS version:+Winform version(C#+GDI+):

-Mnh vit trn Complier l Microsoft Visual Studio 2008 nn 1 s hm ch c BC,TC skhng xi c nn mnh s dng 1 th vin ngoi (ngi ta vit li 1 s hm m t cndng) .Cc hm c cha trong file support.cpp.


3/29

I/ Tm hiu cu trc game.

-Lut l ca game m mnh s trnh by:

+ Game m phng game Xp Gch (Tetris),nhim v ca ngi chi l di chuyn

cc khi gch ang ri t t xung trong kch thc hnh ch nht 18 hng x 10 ct(trn mnhnh).Ch no c gch ri th khng di chuyn c ti v tr .

+Ngi chi c gng xp c nhng hng y nhng vin gch .Nu xp c 1hng s c cng im v hng s b xa .

+Nu khi gch khng th rt xung c na th nu m vn cha hin ht ra mnhnh th ngi chi s thua

-Chng ta s i xem ci game Tetris c nhng j no? Cch qun l ra sao?.Cc bn coi s ci

ny

Ci giao din chi game ,cc bn c th thy n c chia ra thnh tng vung nh ,v c ttc l 18x10 nh th, v cc bn c th thy rng cc c th c vung hoc khng c vung. Thc ra kch thc mn hnh chi game ny khng phi c nh,ngi vit game cth chn 1 kch thc khc cng c.Nhng y t chn dng 18 x 10.

Nh vy lu trng thi ca tr chi ta tm thi c th dng 1 mng 2 chiu kchthc 18x10 (18 hng x 10 ct).Khi xt n im hay cht(gameover) ta ch cn xttrn ma trn Board ny thi.

VD: int Board[18][10];

- Mi Board[i][j] s i din cho 1 vung nh v cha gi tr 0 hoc 1 :

+0 : cha c vung nh no .

+1: c vung nh .

V d vi ci hnh demo di y :


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Nhng bn cng thy rng ,c lc khi gch ca chng ta hin c 1 phn ln ma trn kchthc 18x10 (18 hng x 10 ct) thi ng khng no?

VD: Ta c khi hnh vung mi ch hin ra 1 na trn ma trn thi:

Vy 1 na trn u? Ta bit mng khng c ch s m ng khng no.Thc cht , dqun l th mnh s chn thm 4 hng v na ngha l thay v dng ma trn Board[18][10] thdng ma trn Board[22][10].Khi 4 hng u tin (0->3) c dng lm v tr tm cho cc

khi gch-cc phn ca khi gch m nm trong khu vc 4 hng u tin s khng c v lnmn hnh game.


5/29

-Vy th ngha ma trn sau khi iu chnh l.

Kt lun:

+Vy qun l t s dng 1 ma trn 2 chiu kch thc 22x10 (22 hng x10 ct) Vi ngha t gii thch trn.

+V gi tr ca ma trn Board ch c thit lp khi 1 khi gch khng th ri xung

c na.Cn trong qu trnh khi gch ri th gi tr ca ma trn ti khng thay i (vnl 0)

*Qun l khi gch:

-Chng ta bit game Xp Gch c 7 loi hnh : vung,ch Z,hnh ch L,thngng(ging cy gy)Ta thy mi khi gch c cu to t 4 hnh vung nh xp li vinhau.Ta c th coi cc khi gch nh l nhng hnh ch nht c kch thc khc nhau.

Da vo kch thc khi m mnh s chia thnh 3 loi khi c bn:


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-Cc hnh khc c to ra khi xoay cc khi c bn ny cc gc tng ng 90o, 180o ,270o.Khi xoay th c ngha ta s xoay ma trn trng thi 1 gc 90o .

V vy d qun l cc khi cng nh xy dng cc phng thc xoay khi chng ta sdng mt ma trn c kch thc Row x Col (Row hng x Col ct) xc nh hnh dng hinti ca mt khi - gi l Ma Trn Trng Thi . tit kim th mnh s dng b nh ng :

VD: int **arr;

chng hn,khi cn kch thc bao nhiu th ta cp pht by nhiu.V nh gii phng b nhkhi khng cn xi na.

- Mt khi gch,gi tr ca ma trn trng thi c xc nh l v tr no l gch s c nhs 1, khng c gch nh s 0.

VD:


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Khi trn s c biu din bng ma trn trng thi nh sau: vi Row=2 v Col=3

1 1 0

0 1 1

Nguyn l khi to khi gch:

-S dng nguyn l x l bit xy dng. Ma trn trng thi s c trng cho khi gch.to ma trn trng thi cho tng khi gch ta s dng php x l bit, s dng (Row x Col) bitc nh s t bt cao nht t tri qua phi v t trn xung di xc nh khi.

V d:

Khi 2x3 th ta x l trn 2x3=6 bit.

S tng ng vi chui nh phn 011110 v gi tr ca chui ny l 30.

Khi:

5 4 3

2 1 0

0 1 11 1 0

1 1 0

0 1 1


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Khi:


Khi:


Khi:

1 1 1

0 0 1

1 1 10 1 0


9/29


Khi:

S quy nh l 1111 cho phn bit ch khng mang gi tr biu din vlc x l s x l ring cho khi ny.

Khi:

S quy nh l 11111 cho phn bit ch khng mang gi tr biu din vlc x l s x l ring cho khi ny.

1 1 1

1 0 0


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-Do ,mi khi gch (mi hnh dng khi gch) c bn ta c 7 loi khi c bn s c 7con s i din cho n.

II/ T chc chng trnh,chn cu trc ci t.- Phn I chng ta c ni s s qua tng,cu trc ca game Tetris ny ri.Phn II ts hng dn cch vit code v t chc game.

1/ Cc hm b tr

- V trong game mnh c s dng cc hm nh gotoxy(), textcolor() ,delay() m trong VS 2k8 khng c nn phi vit li cc hm ny.Cc hm ny ch l ph thinn chng ta chp code v l c ,khng cn phi hiu cc hm ny hot ng ra saoc.

Sau y l code mu ca cc hm ny.


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enum{

BLACK,BLUE,GREEN,CYAN,RED,PURPLE,

GRAY,WHITE,LIGHTGRAY,LIGHTBLUE,LIGHTGREEN,LIGHTCYAN,LIGHTRED,LIGHTPURPLE,LIGHTYELLOW,LIGHTWHITE

};voidgotoxy(intx, inty){

COORDc;c.X = x - 1;c.Y = y - 1;

SetConsoleCursorPosition (GetStdHandle(STD_OUTPUT_HANDLE), c);}voidclrscr(){

COORDcoord;DWORDwritten;CONSOLE_SCREEN_BUFFER_INFOinfo;

coord.X = 0;coord.Y = 0;GetConsoleScreenBufferInfo(GetStdHandle(STD_OUTPUT_HANDLE), &info);FillConsoleOutputCharacter (GetStdHandle(STD_OUTPUT_HANDLE), ' ',

info.dwSize.X * info.dwSize.Y, coord, &written);gotoxy (1, 1);

}voidtextcolor(WORDcolor){

HANDLEhConsoleOutput;hConsoleOutput = GetStdHandle(STD_OUTPUT_HANDLE);

CONSOLE_SCREEN_BUFFER_INFOscreen_buffer_info;GetConsoleScreenBufferInfo(hConsoleOutput, &screen_buffer_info);

WORDwAttributes = screen_buffer_info.wAttributes;color &= 0x000f;wAttributes &= 0xfff0;wAttributes |= color;

SetConsoleTextAttribute(hConsoleOutput, wAttributes);}voidSetBGColor(WORDcolor){

HANDLEhConsoleOutput;

hConsoleOutput = GetStdHandle(STD_OUTPUT_HANDLE);

CONSOLE_SCREEN_BUFFER_INFOscreen_buffer_info;GetConsoleScreenBufferInfo(hConsoleOutput, &screen_buffer_info);

WORDwAttributes = screen_buffer_info.wAttributes;color &= 0x000f;color


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CONSOLE_CURSOR_INFOInfo;Info.bVisible = FALSE;Info.dwSize=20;SetConsoleCursorInfo (GetStdHandle (STD_OUTPUT_HANDLE), &Info);

}

2/ Cu trc game

Mnh s chn cch vit code game ny dng Structure.Mc d theo mnh thy dng class sd qun l v nhn trc quan hn.Nhng nhiu bn cha hc hng i tng (OOP) nndng Structure l hp l cho cc bn.Dng structure nn 1 s ch mnh t chc qun l chatt nn cc ban thng cm nha.ng chm em m ti nghip.

Nh mnh ni phn I th game s c qun l chung bng 1 ma trn Board[22][10]. Do mnh s khai bo ma trn ny l kiu int ,v l bin ton cc.

#defineMaxI 22#defineMaxJ 10intBoard[MaxI][MaxJ];

- xc nh v tr v khung mn hnh chi game ( tng ng vi ma trn map) ln mn hnhconsole.Lu rng nh mnh ni th Board c kch thc [22][10] nhng tht s ch vln mn hnh kch thc 18x10 ta b i 4 hng u trong ma trn Board i(c index t i =0

3).

Ta khai bo :

#defineLEFT 4#defineTOP 4

d hnh dung th bn bit .Mn hnh console c kch thc l 25 hng x 80 ct .

Sau y l hm v ci khung hin th ln mn hnh .

voidDrawBoard(){

inti,j;


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for(i=LEFT;i


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-Khi xp c 1 hng y th ta phi xa hng v cp nht li gi tr cho ma trn Board licho ng.

voidCapNhatLaiToaDo(inthang){

inti,j;for(i=hang;i>0;i--)

for(j=0;j


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Structure qun l khi gch:-Nh ni tng trn,mnh s code ha cu trc nh sau:

typedefstruct{

int **arr;intRow,Col;intiBoard,jBoard;

}KhoiGach;

+arr l 1 con tr m t Ma Trn Trng Thi cho tng loi khi gch: 4x1 ,2x2,2x3 .

Cn 2 bin Row,Col th hin kch thc ca ma trn trng thi ( arr,Row,Col s cho bithnh dng ca khi gch l hnh j).Ma trn ny dng kim tra va chm khi di chuyn khigch,xoay khi gch

+iBoard,jBoard : cho bit v tr hin ti ca Khi Gch ang nm u trn ma trnBoard[22][10] chnh l v tr ca arr[0][0] so vi ma trn Board[22][10].Khi mi khi tokhi gch th iBoard,jBoard s nm khu vc khng c hin th.


16/29

-Mnh phn tch phn I rng mnh s dng 1 con s tng trng cho tng khigch.Khi bit s i din ca n th ta ch cn dng php ton dch bt suy ra ma trn trngthi ca chng.

+15: Thng ng

+31: Hnh vung

..


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-Hm khi to thng s 1 khi gch tng ng vi s ID ca n:

KhoiGach *TaoKhoiGach(intID){

KhoiGach *pkhoigach=(KhoiGach*)malloc(sizeof(KhoiGach));switch(ID){

case 15:pkhoigach->Row=4;pkhoigach->Col=1;pkhoigach->iBoard=0;pkhoigach->jBoard=5;break;

case 31:pkhoigach->Row=pkhoigach->Col=2;pkhoigach->iBoard=2;pkhoigach->jBoard=5;break;

default:pkhoigach->Row=2;pkhoigach->Col=3;pkhoigach->iBoard=2;pkhoigach->jBoard=5;break;

}pkhoigach->arr=(int**)malloc(pkhoigach->Row*sizeof(int*));for(inti=0;iRow;i++){

pkhoigach->arr[i]=(int*)malloc(pkhoigach->Col*sizeof(int));}for(intk=0;kCol*pkhoigach->Row;k++){

pkhoigach->arr[k/pkhoigach->Col][k%pkhoigach->Col]=(ID>>(pkhoigach->Col*pkhoigach->Row-1-k))&1;

}returnpkhoigach;

}

on :

pkhoigach->arr=(int**)malloc(pkhoigach->Row*sizeof(int*));for(inti=0;iRow;i++){

pkhoigach->arr[i]=(int*)malloc(pkhoigach->Col*sizeof(int));}

Ch l cp pht b nh cho ma trn trng thi thi .Chc hn cc bn s thc mc rng nu cID=58 th sao c th to ra ma trn trng thi l:

Rt n gin thi:

V d : vi ID=58 th khi gch s c ma trn trng thi l 2x3 .Row=2,Col=3.

Ban u ma trn trng thi arr:

V Row xCol=2x3=6 (bit) .Nn ta i 58 sang s nh phn 6 di bit l: 111010

on code:

1 1 1

0 1 0

0 0 0

0 0 0


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for(intk=0;kCol*pkhoigach->Row;k++){

pkhoigach->arr[k/pkhoigach->Col][k%pkhoigach->Col]=(ID>>(pkhoigach->Col*pkhoigach->Row-1-k))&1;

}

+Ton t >> l ton t dch bt sang phi.

+arr[k/Col][k%Col]=(ID dch sang phi (RowxCol-1-k) bit ) & 1 // (php AND trong tinhc chc ai cng bit)

Vi k=0: [arr[k/Col][k%Col]=arr[0][0].

58 dch sang phi (6-1-0) bt= 111010 dch sang phi 5 bit l 000001 .Sau kthp vi 000001&1 th kt qu s l 1. ->Vy arr[0][0]=1;






58 dch sang phi (6-1-3) bt= 111010 dch sang phi 2 bit l 001110 .Sau kthp vi (001110 )&1 th kt qu s l 0. ->Vy arr[1][0]=0;

1 0 00 0 0

1 1 0

0 0 0

1 1 1

0 0 0

1 1 1

0 0 0


19/29


58 dch sang phi (6-1-4) bt= 111010 dch sang phi 1 bit l 011101 .Sau kthp vi (011101 )&1 th kt qu s l 1. ->Vy arr[1][1]=1;


58 dch sang phi (6-1-5) bt= 111010 dch sang phi 0 bit l 111010 .Sau kt

hp vi (111010 )&1 th kt qu s l 0. ->Vy arr[1][2]=0;

Vy cui cng: ta c ma trn trng thi dng vi con s ID=58. Vi cc khi gch mangID khc th cch lm cng tng t thi

Hm kim tra va chm khi di chuyn khi gch sang tri ,sang phi,ri xung:

tng:

+ xc nh xem 1 v tr i,j trn ma trn Board c di chuyn sang tri c haykhng th ta xem lin k bn tri(chnh l v tr i , j-1) ca n c gch hay cha,nu c

gch th khng di chuyn c( a[i][j]=1 th c gch v ngc li a[i][j]=0 l khng c gch).Di chuyn sang phi hay xt ri xung cng tng t nh th thi( cng xt lin k bn

phi i,j+1 hoc lin k bn di i+1,j)

+Nh vy xt nguyn khi gch (gm 4 gch nh ) c th di chuyn c th ttc cc gch nh fai di chuyn c ,nu c 1 khng di chuyn c th khi gch khng th di chuyn c.

1 1 1

0 1 0

1 1 1

0 1 0


20/29

intInside(inti,intj) //Xem i,j c thuc mng Board[22][10] hay khng?{

return (i>=0&&i=0&&j0&&Inside(i,j)&&Board[i][j-1]==0) return1;return0;

}intRight(inti,intj){

if(jiBoard+i,pkhoigach->jBoard+j :


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voidSangTrai(KhoiGach *pkhoigach){

for(inti=0;iRow;i++)for(intj=0;jCol;j++)

if(pkhoigach->arr[i][j]==1){

if(Left(pkhoigach->iBoard+i,pkhoigach->jBoard+j)==0||pkhoigach->iBoardjBoard-=1; //Dich vi tri cua bang trang thai sang trai 1 so voi Board[22][10].}

voidSangPhai(KhoiGach *pkhoigach){



if(Right(pkhoigach->iBoard+i,pkhoigach->jBoard+j)==0||pkhoigach->iBoardjBoard+=1; //Dich vi tri cua bang trang thai sang phai 1 so voiBoard[22][10].}intRoiXuong(KhoiGach *pkhoigach) //0 : khng th ri xung,1 : c th ri xung.{



if(Down(pkhoigach->iBoard+i,pkhoigach->jBoard+j)==0) return 0;}

pkhoigach->iBoard+=1; //Roi xuong 1 so voi Board[22][10] return 1;}

Hm gn gi tr cho ma trn Board khi khi gch khng ri xung c na:Khi vinhng arr[i][j] ==1 ca ma trn trng thi th ta gn gi tr bng 1 cho Board[i][j] .Vi (i,j)l ta tng ng ca (i,j) trn ma trn Board ,m cch i mnh ni trn ri.

voidGanGiaTri(KhoiGach* pkhoigach){


if(pkhoigach->arr[i][j]==1)

{ Board[pkhoigach->iBoard+i][pkhoigach->jBoard+j]=1;}


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}

-Haizz,ti y th ta cng gn xong nhng ci c bn ca game Xp Gch ri. Chng ta s tihm xoay khi gch na l coi nh xong .Ci xoay khi gch ny rt d ,bn no lm bixoay ma trn 2 chiu 1 gc 90o theo chiu kim ng h ri th ci ny rt d hiu.

Hm xoay: Xoay khi gch thc cht cc bn ch cn xoay ma trn trng thi ca khi gch 1 gc 90o theo chiu kim ng h thi ,v ma trn y khng phi l ma trn vung nnkhi xoay th kch thc ca ma trn s b thay i Row=Col,Col=Row.Ta ch cn vit 1hm xoay duy nht th c th xoay c tt c cc loi khi gch (7 loi c bn v cc khikhi c xoay khc) .Chng ta s xoay th ma trn trng thi v sau xt xem v tr ca matrn sau khi xoay tng ng trn ma trn Board c hp l hay khng (khng c ln Board[i][j] ==1 no v khng vt ra khi gii hn ca Board).Nu hp l th mi chpnhn ,cn ngc li th vn gi nguyn ma trn trng thi nh ban u.

+V trc v sau khi xoay th iBoard,jBoard khng thay i gi tr (vn gi nguyn) ci ny l cch mnh chn cho d( v x l ,rc ri thm) thi.Ch cc bn c th chncch khc xoay cho p hn.V cc bn coi ci hnh m t di y.

voidXoayKhoiGach(KhoiGach* pkhoigach){

inti,j;int ** tmpArr;inttmpRow=pkhoigach->Col;inttmpCol=pkhoigach->Row;//Cp pht b nh cho ma trn ph tmpArr.

tmpArr=(int**)malloc(tmpRow*sizeof(int*));for( i=0;i


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tmpArr[i]=(int*)malloc(tmpCol*sizeof(int));}///////////////////////////////////////////////for(i=pkhoigach->Row-1;i>=0;i--)

for(j=pkhoigach->Col-1;j>=0;j--){

tmpArr[j][pkhoigach->Row-i-1]=pkhoigach->arr[i][j];}

//Kim tra hp l.for (i=0;ijBoard+j)||

Board[pkhoigach->iBoard+i][pkhoigach->jBoard+j]==1)return;

}for(i=0;iRow;i++) free(pkhoigach->arr[i]);free(pkhoigach->arr);//Cp nht thay i sau khi xoay.pkhoigach->Col=tmpCol;pkhoigach->Row=tmpRow;pkhoigach->arr=tmpArr;

}

Khi lm vic vi b nh ng th cc bn nn cn thn xin cp pht xong v khi khng xina th phi gii phng b nh trnh tnh trng memory leak.

Hm v ,xa khi gch ln mn hnh console: Mnh ni trn th mnh dng binLEFT,TOP xc nh v tr v ma trn Board ln mn hnh console.

voidVeKhoiGach(KhoiGach* pkhoigach){

inti;intj;for(i=0;iRow;i++)

for(j=0;jCol;j++)if(pkhoigach->arr[i][j]==1&&(pkhoigach->iBoard+i)>3){

textcolor(LIGHTRED);gotoxy(LEFT+pkhoigach->jBoard+j+1,TOP+pkhoigach->iBoard+i-3);cprintf("%c",2);

}}voidXoaKhoiGach(KhoiGach *pkhoigach){

inti;intj;for(i=0;iRow;i++)

for(j=0;jCol;j++)if(pkhoigach->arr[i][j]==1&&(pkhoigach->iBoard+i)>3){

textcolor(BLACK);gotoxy(LEFT+pkhoigach->jBoard+j+1,TOP+pkhoigach->iBoard+i-3);cprintf(" ");

}}

3/ Thng tin v im,cp ,tc .

-Game th khng th thiu phn tnh im v thng tin level . tng tnh hp dn cho

game.Di y mnh demo 1 cch tnh im v kh 1 cch rt n gin cho game.Ciphn ny cc bn c th ty chnh theo mnh.Mnh khai bo 1 structure lu thng tin.


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typedefstruct{

intscore;intlevel;floatspeed;

}INFO;

+Mnh s chia game ra lm 2 cp : Cp 1 : 0->200 Cp 2 :200->300+Mi hng n c s c +10 .+Khi tng Level th speed cng nhanh hn 1 cht .+Nu c 300 tr ln th Win game.

Cc hm b tr:

voidInitGame(INFO *info){

info->level=1;info->score=0;info->speed=0.4;

}

intCapNhat(INFO *info, intscore){

info->score+=score;if(info->score>=200&&info->levellevel++;info->speed-=0.1;

}return 0; //Chua win game.

}voidVeBangDiem(INFOinfo){

textcolor(LIGHTYELLOW);gotoxy(LEFT+MaxJ+2,10);cprintf("SCORE:%3d",info.score);gotoxy(LEFT+MaxJ+2,11);cprintf("LEVEL:%3d",info.level);gotoxy(LEFT+MaxJ+2,12);cprintf("SPEED:%3f",info.speed);

}

Kim tra gameover hay khng v tnh ton s hng n im:Khi khi gch khng th rixung c na th ta kim tra:

+ Game kt thc khi khi gch khng ri xung c na m iBoard vn Row-1;if(pkhoigach->iBoardscore>=300) return 0;//Windo{

count=0;

for(j=0;jiBoard+i][j]==1) count++;


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}if(count==MaxJ){

CapNhat(infogame,20);CapNhatLaiToaDo(pkhoigach->iBoard+i);DisplayBoard();

}else

{i=i-1;

}}while(i>=0);return 1;

}

Hm tr v -1 nu game over,tr v 0 nu ngi chi win(score>=300).V trong structureKhoiGach c s dng con tr(arr-ma trn trng thi) cp pht ng nn mnh s phi vit 1hm gii phng b nh trnh vic memory leak.

voidHuyKhoiGach(KhoiGach* pkhoigach){

inti;

//Huy bo nho cua ma tran trang thai arr.for(i=0;iRow;i++) free(pkhoigach->arr[i]);free(pkhoigach->arr);///////////////////////////////////////////////////////////Sau do moi free(pkhoigach)free(pkhoigach);pkhoigach=NULL;

}

4/ Chn ngu nhin khi gch v khi gch tip theo s xut hin.

Hm ny s random 1 khi gch chi. Tr v s i din cho khi gch .

intLoai()

{ intx=rand()%7;switch(x){case 0:

return 15;break;

case 1:return 31;break;






}}

Hm v,xa khi gch tip theo s xut hin:

voidVe_Next(intID){

KhoiGach *pnext=TaoKhoiGach(ID);intiRoot=LEFT+MaxJ+5;intjRoot=TOP;


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for(inti=0;iRow;i++){

for (intj=0;jCol;j++){

if(pnext->arr[i][j]==1){

textcolor(LIGHTGREEN);gotoxy(iRoot+j,jRoot+i);cprintf("%c",2);

}}

}HuyKhoiGach(pnext);

}voidXoa_Next(){

intiRoot=LEFT+MaxJ+5;intjRoot=TOP;for(inti=0;i


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RoiXuong();break;

}VeKhoiGach(currKhoi);//V li khi gch sau khi cp nht thay

i.}

*Vng lp cho game:-Khi to gi tr ban u cho game.V khung giao din.Khi to cc tham slevel,score,speed.

Do{

- V li khi gch v ma trn Board ln mn hinh.-Trong khi cha ht INFO.speed th lp li qu trnh:

Nu c s kin nhn bn phm xy ra( if(_kbhit()) ) th

+Xa Khi gch.+X l nhn bn phm+V li khi gch sau khi thay i.

- Cho khi gch ri xung:-Nu ri xung khng c:

+Gn gi tr cho ma trn Board.S dng hm : voidGanGiaTri(KhoiGach*pkhoigach)

+Kim tra thng thua v cp nht li im.Nu gameover hoc win th kt thc

tr chi. +Hy b nh ca khi gch hin ti v sau khi to khi gch mi.

}While(!gameover hoc !win);

Code demo vng lp ca game l:

do{

VeBangDiem(info);VeKhoiGach(currKhoi);Xoa_Next();Ve_Next(IDKhoiTiepTheo);

Start=clock();do{

if(_kbhit()){

c=toupper(getch());XoaKhoiGach(currKhoi);switch(c){case'W':

XoayKhoiGach(currKhoi);break;

case'A':SangTrai(currKhoi);break;

case'D':SangPhai(currKhoi);break;


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case'S':RoiXuong(currKhoi);break;

}VeKhoiGach(currKhoi);

}End=clock();

}while(float(End-Start)/CLK_TCK


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III/ Kt Thc

+Vy l xong Tut hng dn vit game Tetris vi C/C++ .Cm n cc bn theo di tutny.Mnh hi vng c s ng h v kin ca cc bn ln sau c th vit 1 Tut khc hay

v hp cc bn hn.+Hn cc bn bi vit tip theo.C th l hng dn cch lm game Line( tt c ch l nuc th ).V nu c copy bi vit ny i ni khc th xin hay ghi r ngun v tc gi.Cm nnhu nhu.

+,mnh c nh km theo nguyn project ca game ny vit trn VS2K8.Cc bn c th tiv coi +tut ny s d hnh dung hn.

Chng trnh ti y l ht ri.Cm n qu v quan tm theo di .Xin hn gp livo chng trnh ln sau! Cm n v cho tm bit

how to make tetris game

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