hrsg cycle efficiency.xlsx

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HRSG Cycle Efficiency at Different Condition Parameter Case 1 - Ideal Case 2 _Temp High Case 3-Press High Qin 3072 3317 3006 Wout 1050 1190 1100 Qout 2032 2138 1922 Win 10.32 10.3 16.5 HRSG Efficie 33.8% 35.6% 36.0% Case 1 Case 2 TU R B IN E BFP W in 1 2 3 4 P 3 = 100 B ar T 3 = 550 D eg C h 3 = ______ kJ/kg P 4 = 1 Bar T 4 = 99.6 D eg C h 4 = 2450 kJ/kg D ryness = 0.9 P 1 = 1 Bar T 1 = 99.6 D eg C h 1 = 417.4 kJ/kg P 2 = 100 B ar T 2 = 100.29 D eg C h 2 = 427.7 kJ/kg W out Q out W in Q in = _________ = _________ = _________ = _________ η th = 3,072.7 kJ/kg 1,050 kJ/kg 2,032.6 kJ/kg 10.32 kJ/kg TU R B IN E BFP W in 1 2 3 4 P 3 = 100 bar T 3 = 650 deg C h 3 = __________kJ/kg P 4 = 1 bar T 4 = 99.6 deg C h 4 = __________kJ D ryness =________ P 1 = _________bar T 1 = _________ deg C h 1 = __________kJ/kg P 2 = 100 bar T 2 = ________ deg C h 2 = __________kJ/kg W out Q out W in Q in = _________ = _________ = _________ = _________ η th = 3,744 2,550 0.947 1 99.6 417.5 427.8 100.3 3,317 1,190 2,138 10.3

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Calculation of HRSG Cycle Efficiency

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HRSG Cycle Efficiency at Different Condition

Parameter Case 1 - Ideal Case 2 _Temp High Case 3-Press HighQin 3072 3317 3006Wout 1050 1190 1100Qout 2032 2138 1922Win 10.32 10.3 16.5HRSG Efficienc 33.8% 35.6% 36.0%

Case 1

Case 2

TURBINE

BFP

Win 12

3

4

P3 = 100 BarT3 = 550 Deg Ch3 = ______ kJ/kg

P4 = 1 BarT4 = 99.6 Deg Ch4 = 2450 kJ/kgDryness = 0.9

P1 = 1 BarT1 = 99.6 Deg Ch1 = 417.4 kJ/kg

P2 = 100 BarT2 = 100.29 Deg Ch2 = 427.7 kJ/kg

Wout

Qout

Win

Qin = _________

= _________

= _________

= _________

ηth= %

3,072.7 kJ/kg

1,050 kJ/kg

2,032.6 kJ/kg

10.32 kJ/kg

TURBINE

BFP

Win 12

3

4

P3 = 100 barT3 = 650 deg Ch3 = __________kJ/kg

P4 = 1 barT4 = 99.6 deg Ch4 = __________kJ/kgDryness =_________

P1 = _________barT1 = _________ deg Ch1 = __________kJ/kg

P2 = 100 barT2 = ________ deg Ch2 = __________kJ/kg

Wout

Qout

Win

Qin = _________

= _________

= _________

= _________

ηth= %3,744

2,5500.947

199.6

417.5427.8100.3

3,317

1,190

2,138

10.3

Case 3

TURBINE

BFP

Win 12

3

4

P3 = 160 barT3 = 550 deg Ch3 = __________kJ/kg

P4 = 1 barT4 = ________ deg Ch4 = __________kJ/kgDryness =_________

P1 = _________barT1 = _________ deg Ch1 = __________kJ/kg

P2 = 160 barT2 = ________ deg Ch2 = __________kJ/kg

Wout

Qout

Win

Qin = _________

= _________

= _________

= _________

ηth= %3,440

99.62,340

0.855

199.6417.5434

100.3

3,006

1,100

1,922

16.5

TURBINE

BFP

Win 12

3

4

P3 = 100 BarT3 = 550 Deg Ch3 = ______ kJ/kg

P4 = 1 BarT4 = 99.6 Deg Ch4 = 2450 kJ/kgDryness = 0.9

P1 = 1 BarT1 = 99.6 Deg Ch1 = 417.4 kJ/kg

P2 = 100 BarT2 = 100.29 Deg Ch2 = 427.7 kJ/kg

Wout

Qout

Win

Qin = _________

= _________

= _________

= _________

ηth= %

3,072.7 kJ/kg

1,050 kJ/kg

2,032.6 kJ/kg

10.32 kJ/kg

TURBINE

BFP

Win 12

3

4

P3 = 100 barT3 = 650 deg Ch3 = __________kJ/kg

P4 = 1 barT4 = 99.6 deg Ch4 = __________kJ/kgDryness =_________

P1 = _________barT1 = _________ deg Ch1 = __________kJ/kg

P2 = 100 barT2 = ________ deg Ch2 = __________kJ/kg

Wout

Qout

Win

Qin = _________

= _________

= _________

= _________

ηth= %3,744

2,5500.947

199.6

417.5427.8100.3

3,317

1,190

2,138

10.3

TURBINE

BFP

Win 12

3

4

P3 = 160 barT3 = 550 deg Ch3 = __________kJ/kg

P4 = 1 barT4 = ________ deg Ch4 = __________kJ/kgDryness =_________

P1 = _________barT1 = _________ deg Ch1 = __________kJ/kg

P2 = 160 barT2 = ________ deg Ch2 = __________kJ/kg

Wout

Qout

Win

Qin = _________

= _________

= _________

= _________

ηth= %3,440

99.62,340

0.855

199.6417.5434

100.3

3,006

1,100

1,922

16.5