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1.A two-digit number is such that the product of the digits is 8. When 18 is added to the number,

then the digits are reversed. The number is:

A.18 B. 24

C. 42 D.81

Answer: Option B

Explanation:

Let the ten's and unit digit be x and8respectively.

x

Then, 10x +8

+ 18 = 10 x8+ x

x x

10x2 + 8 + 18x = 80 + x

2

9x2

+ 18x - 72 = 0

x2

+ 2x - 8 = 0

(x + 4)(x - 2) = 0

x = 2.

Learn more problems on :Problems on Numbers

Discuss about this problem :Discuss in Forum

Direction (for Q.No. 2):

Each of the questions given below consists of a statement and / or a question and two statements

numbered I and II given below it. You have to decide whether the data provided in thestatement(s) is / are sufficient to answer the given question. Read the both statements and

Give answer (A) if the data in Statement I alone are sufficient to answer the question,while the data in Statement II alone are not sufficient to answer the question.

Give answer (B) if the data in Statement II alone are sufficient to answer the question,while the data in Statement I alone are not sufficient to answer the question.

Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to
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answer the question.

Give answer (D) if the data even in both Statements I and II together are not sufficient toanswer the question.

Give answer(E) if the data in both Statements I and II together are necessary to answerthe question.

2.Average age of employees working in a department is 30 years. In the next year, ten workers

will retire. What will be the average age in the next year?I. Retirement age is 60 years.

II. There are 50 employees in the department.

A.I alone sufficient while II alone not sufficient to answer

B. II alone sufficient while I alone not sufficient to answer

C. Either I or II alone sufficient to answer

D.Both I and II are not sufficient to answer

E. Both I and II are necessary to answer

Answer: Option E

Explanation:

I. Retirement age is 60 years.

II. There are 50 employees in the department.

Average age of 50 employees = 30 years.

Total age of 50 employees = (50 x 30) years = 1500 years.

Number of employees next year = 40.

Total age of 40 employees next year (1500 + 40 - 60 x 10) = 940.

Average age next year =940

years = 231years.

40 2

Thus, I and II together give the answer. So, correct answer is (E).

Learn more problems on :Problems on Ages


3.A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the samerate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest

per annum is:

A.5% B. 7%
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C. 71%

8D.10%

Answer: Option D

Explanation:

Let the rate be R% p.a.

Then,5000 x R x 2

+3000 x R x 4

= 2200.100 100

100R + 120R = 2200

R =2200

= 10.220

Rate = 10%.

Learn more problems on :Simple Interest


4.The angle of elevation of a ladder leaning against a wall is 60 and the foot of the ladder is 4.6m away from the wall. The length of the ladder is:

A.2.3 m B. 4.6 m

C. 7.8 m D.9.2 m

Answer: Option D

Explanation:

Let AB be the wall and BC be the ladder.

Then, ACB = 60 and AC = 4.6 m.

AC= cos 60 = 1
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BC 2

BC = 2 x AC= (2 x 4.6) m

= 9.2 m.

Learn more problems on :Height and Distance

Discuss about this problem :Discuss in Forum5.A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the

probability that none of the balls drawn is blue?

A.1021

B.1121

C.2

7D.

5

7

Answer: Option A

Explanation:

Total number of balls = (2 + 3 + 2) = 7.

Let S be the sample space.

Then, n(S)= Number of ways of drawing 2 balls out of 7= 7C2 `

=(7 x 6)

(2 x 1)

= 21.

Let E = Event of drawing 2 balls, none of which is blue.

n(E)= Number of ways of drawing 2 balls out of (2 + 3) balls.

=5C2

=(5 x 4)(2 x 1)

= 10.

P(E) =n(E)

=10

.n(S) 21

Learn more problems on :Probability


Direction (for Q.No. 6):

Find out the wrong number in the given sequence of numbers.

6.22, 33, 66, 99, 121, 279, 594
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A.33 B. 121

C. 279 D.594

Answer: Option C

Explanation:

Each of the number except 279 is a multiple of 11.

Learn more problems on :Odd Man Out and Series


7.P can complete a work in 12 days working 8 hours a day. Q can complete the same work in 8

days working 10 hours a day. If both P and Q work together, working 8 hours a day, in howmany days can they complete the work?

A.5

5

11 B. 5

6

11

C. 65

11D.6

6

11

Answer: Option A

Explanation:

P can complete the work in (12 x 8) hrs. = 96 hrs.

Q can complete the work in (8 x 10) hrs. = 80 hrs.

P's1 hour's work =1

and Q's 1 hour's work =1

.96 80

(P + Q)'s 1 hour's work =1

+1

=11

.96 80 480

So, both P and Q will finish the work in480

hrs.11

Number of days of 8 hours each =480

x1

=60

days = 55

days.11 8 11 11

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8.At what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide eachother?

A.51"

11B. 12

4"

11

C. 13 4 " D.16 4 "
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11 11

Answer: Option D

Explanation:

At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand.

To be coincident, it must gain 15 min. spaces.

55 min. are gained in 60 min.

15 min. are gained in60

x 15min

=164

min.55 11

The hands are coincident at 164

min. past 3.11

Learn more problems on :Clock

Discuss about this problem :Discuss in Forum9.At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but,

not together?

A.5 min. past 7 B. 52

min. past 711

C. 53

min. past 711

D.55

min. past 711

Answer: Option D

Explanation:

When the hands of the clock are in the same straight line but not together, they are 30 minute

spaces apart.

At 7 o'clock, they are 25 min. spaces apart.

Minute hand will have to gain only 5 min. spaces.

55 min. spaces are gained in 60 min.

5 min. spaces are gained in60

x 5min

= 55

min.55 11

Required time = 55

min. past 7.11
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Learn more problems on :Clock

Discuss about this problem :Discuss in Forum10.

Ifa

x - 1=b

x - 3, then the value ofx is:

b aA.

12

B. 1

C. 2 D.2

Answer: Option C

Explanation:

Given

ax - 1=

bx - 3

b aa

x - 1=a

-(x - 3) =a

(3 - x)b b b

x - 1 = 3 - x

2x = 4

x = 2.

Learn more problems on :Surds and Indices

Discuss about this problem :Discuss in Forum11.If 40% of a number is equal to two-third of another number, what is the ratio of first number

to the second number?

A.2 : 5 B. : 7

C. 5 : 3 D. : 3

Answer: Option C

Explanation:

Let 40% of A =2B

3

Then,40A

=2B

100 32A

=2B

5 3

A= 2x5 =5
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B 3 2 3

A : B = 5 : 3.

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Discuss about this problem :Discuss in Forum12.A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average

speed for the first 320 km of the tour is:

A.35.55 km/hr B. 6 km/hr

C. 71.11 km/hr D. 1 km/hr

Answer: Option C

Explanation:

Total time taken =160

+160

hrs.=

9hrs.

64 80 2

Average speed = 320 x2

km/hr= 71.11 km/hr.

9

Learn more problems on :Time and Distance


13.The rational number for recurring decimal 0.125125.... is:

A.63

487

B.119

993C.

125

999D.None of these

Answer: Option C

Explanation:

0.125125... = 0.125 =125

999

Learn more problems on :Decimal Fraction

Discuss about this problem :Discuss in Forum14..009

= .01?

A..0009 B. .09

C. .9 D.9
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Answer: Option C

Explanation:

Let.009= .01; Then x =.009=.9= .9x .01 1

Learn more problems on :Decimal Fraction


Direction (for Q.Nos. 15 - 17):

Insert the missing number.

15.1, 4, 9, 16, 25, 36, 49, (....)

A.54 B. 56

C. 64 D.81

Answer: Option C

Explanation:

Numbers are 12, 22, 32, 42, 52, 62, 72.

So, the next number is 82 = 64.



16.11, 13, 17, 19, 23, 29, 31, 37, 41, (....)

A.43 B. 7

C. 53 D.51

Answer: Option A

Explanation:

Numbers are all primes. The next prime is 43.


Discuss about this problem :Discuss in Forum17.4, -8, 16, -32, 64, (....)

A.128 B. -128
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C. 192 D.-192

Answer: Option B

Explanation:

Each number is the proceeding number multiplied by -2.

So, the required number is -128.


Discuss about this problem :Discuss in Forum18.Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound

interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is:

A.Rs. 1550 B. Rs. 1650

C. Rs. 1750 D.Rs. 2000

Answer: Option C

Explanation:

C.I.= Rs. 4000 x 1 +10

2- 4000100

= Rs. 4000 x11

x11

- 400010 10

= Rs. 840.

Sum = Rs.420 x 100

= Rs. 1750.3 x 8

Learn more problems on :Compound Interest

Discuss about this problem :Discuss in Forum19.What will be the compound interest on a sum of Rs. 25,000 after 3 years at the rate of 12

p.c.p.a.?

A.Rs. 9000.30 B. Rs. 9720

C. Rs. 10123.20 D.Rs. 10483.20E. None of these

Answer: Option C

Explanation:

Amount= Rs. 25000 x 1 + 12 3
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100

= Rs. 25000 x28

x28

x28

25 25 25

= Rs. 35123.20

C.I. = Rs. (35123.20 - 25000) = Rs. 10123.20

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Discuss about this problem :Discuss in Forum20.January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?

A.Monday B. uesday

C. Wednesday D. unday

Answer: Option B

Explanation:

The year 2007 is an ordinary year. So, it has 1 odd day.

1st day of the year 2007 was Monday.

1st day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.

Learn more problems on :Calendar

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1. A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits Rs.

1600 each on 1st

January and 1st

July of a year. At the end of the year, the amount he wouldhave gained by way of interest is:

[A].Rs. 120 [B].Rs. 121

[C].Rs. 122 [D].Rs. 123

B

Answer: Option B

Explanation:

Amount= Rs. 1600 x 1 +5

2+ 1600 x 1 +5

2 x 100 2 x 100

= Rs. 1600 x41

x41

+ 1600 x41

40 40 40

= Rs. 1600 x41 41

+ 140 40

= Rs.1600 x 41 x 81

40 x 40

= Rs. 3321.

C.I. = Rs. (3321 - 3200) = Rs. 121

WorkspaceReport error

= Rs. 1600 x

41 41

+ 140 40

= Rs.1600 x 41 x 81

40 x 40

= Rs. 3321.

C.I. = Rs. (3321 - 3200) = Rs. 121

WorkspaceReport error

Amount= Rs. 1600 x 1 + 5 2+ 1600 x 1 + 52 x 100 2 x 100

= Rs. 1600 x41

x41

+ 1600 x41

40 40 40

= Rs. 1600 x41 41

+ 140 40

= Rs. 1600 x 41 x 81


13/22

40 x 40

= Rs. 3321.

Akhila said: (Tue, Aug 31, 2010 10:35:27 AM)

How did you get 41/40 am not able to get that value please help me.

Sundar said: (Tue, Aug 31, 2010 11:27:02 AM)

Hi Akhila,

= 1 + (5/(2 x 100)

= 1 + (5/200)

= 1 + (1/40)

= (40 + 1)/40

= 41/40

Next step (41/40)^2

= 41/40 x 41/40

...

Hope you understand. Have a nice day!

Sipu said: (Fri, Nov 5, 2010 07:33:29 PM)

YA SUNDER IS CORRECT...

Bala said: (Sat, Nov 13, 2010 01:03:54 PM)

its a basic thing


14/22

where did u get 3200 in this problem

Vishal said: (Wed, Feb 23, 2011 05:01:24 PM)

Yes, its right , so in first case n (no. of years) is 1 and in second case (for july) n is 1/2 years,

so now you can directly put that values in simple formula.

Vikram said: (Fri, Feb 25, 2011 03:19:56 PM)

Give the mathemetical formula for compund interest.


15/22

Rajesh said: (Sun, Feb 27, 2011 10:07:36 AM)

@Anusha:

You told 2 cases one is half yearly(july) and other is yearly(jan). In yearly case the formula

should be p(1+r/100)^n but they used half yearly formula only.

Sukumar said: (Mon, Feb 28, 2011 03:39:22 PM)

I can't understand

[1600*41/40(41/40+1)]

2.

The difference between simple and compound interests compounded annually on a certain sumof money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:

[A].625 [B].630

[C].640 [D].650

A

Answer: Option A

Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 +4

2- x =676

x- x =51

x.100 625 625

S.I. = x x 4 x 2 =2x.100 25

51x-2x

= 1625 25

x = 625.


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3.

There is 60% increase in an amount in 6 years at simple interest. What will be the compound

interest of Rs. 12,000 after 3 years at the same rate?

A.

Rs. 2160 B.

Rs. 3120C.Rs. 3972 D.Rs. 6240E. None of these

C

Answer & Explanation

Answer: Option C

Explanation:

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R =100 x 60

= 10% p.a.100 x 6

Now, P = Rs. 12000. T = 3 years and R = 10% p.a.

C.I.= Rs. 12000 x 1 +10

3- 1100

= Rs. 12000 x331

1000

= 3972.4.

What is the difference between the compound interests on Rs. 5000 for 1 years at 4% perannum compounded yearly and half-yearly?

A.Rs. 2.04 B.Rs. 3.06

C.Rs. 4.80 D.Rs. 8.30

A


Answer: Option A

Explanation:

C.I. when interestcompounded yearly

= Rs. 5000 x 1 +4

x 1 + x 4100 100

= Rs. 5000 x26x51


17/22

25 50

= Rs. 5304.

C.I. when interest is

compounded half-yearly= Rs. 5000 x 1 +

23

100

= Rs. 5000 x

51

x

51

x

51

50 50 50= Rs. 5306.04

Difference = Rs. (5306.04 - 5304) = Rs. 2.04

5.

The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is:

A.2 B.212

C.3 D.4A


Answer: Option A

Explanation:

Amount = Rs. (30000 + 4347) = Rs. 34347.

Let the time be n years.

Then, 30000 1 +7

n= 34347100

107n=

34347=

11449=

1072

100 30000 10000 100

n = 2 years.

6.

What will be the compound interest on a sum of Rs. 25,000 after 3 years at the rate of 12p.c.p.a.?

A.Rs. 9000.30 B.Rs. 9720C.Rs. 10123.20 D.Rs. 10483.20

E. None of these

C



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Answer: Option C

Explanation:

Amount= Rs. 25000 x 1 +12

3100

= Rs. 25000 x28

x28

x28

25 25 25

= Rs. 35123.20

C.I. = Rs. (35123.20 - 25000) = Rs. 10123.20

7.

At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2

years?

A.6% B.6.5%

C.7% D.7.5%

A


Answer: Option A

Explanation:

Let the rate be R% p.a.

Then, 1200 x 1 +R

2= 1348.32100

1 +R

2=134832

=11236

100 120000 10000

1 +R

2=106

2100 100

1 +R

=106

100 100

R = 6%

8.

The least number of complete years in which a sum of money put out at 20% compound interest

will be more than doubled is:

A.3 B.4


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C.5 D.6

B


Answer: Option B

Explanation:

P 1 +20

n> 2P6

n> 2.100 5

Now,6x

6x6x6

> 2.5 5 5 5

So, n = 4 years.

9.

Albert invested an amount of Rs. 8000 in a fixed deposit scheme for 2 years at compound

interest rate 5 p.c.p.a. How much amount will Albert get on maturity of the fixed deposit?

A.Rs. 8600 B.Rs. 8620

C.Rs. 8820 D.None of these

C


Answer: Option C

Explanation:

Amount= Rs. 8000 x 1 +5

2100

= Rs. 8000 x21

x21

20 20

= Rs. 8820.

10.

The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable

half-yearly is:

A.6.06% B.6.07%

C.6.08% D.6.09%

D


Answer: Option D


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Explanation:

Amount of Rs. 100 for 1 year

when compounded half-yearly= Rs. 100 x 1 +

32 = Rs. 106.09

100

Effective rate = (106.09 - 100)% = 6.09%

11.

Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound

interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is:

A.Rs. 1550 B.Rs. 1650

C.Rs. 1750 D.Rs. 2000

C


Answer: Option C

Explanation:

C.I.= Rs. 4000 x 1 +10

2- 4000100

= Rs. 4000 x11

x11

- 400010 10

= Rs. 840.

Sum = Rs. 420 x 100 = Rs. 1750.3 x 8

12.

If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the

compound interest on the same at the same rate and for the same time?

A.Rs. 51.25 B.Rs. 52

C.Rs. 54.25 D.Rs. 60

A


Answer: Option A

Explanation:

Sum = Rs.50 x 100

= Rs. 500.2 x 5


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Amount= Rs. 500 x 1 +5

2100

= Rs. 500 x21

x21

20 20

= Rs. 551.25

C.I. = Rs. (551.25 - 500) = Rs. 51.25

13.

The difference between simple interest and compound on Rs. 1200 for one year at 10% perannum reckoned half-yearly is:

A.Rs. 2.50 B.Rs. 3

C.Rs. 3.75 D.Rs. 4E. None of these

B


Answer: Option B

Explanation:

S.I. = Rs1200 x 10 x 1

= Rs. 120.100

C.I. = Rs. 1200 x 1 +5

2- 1200 = Rs. 123.

100

Difference = Rs. (123 - 120) = Rs. 3.

14.

The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2years is Rs. 96. What is the rate of interest per annum?

A.8 B.10C.12 D.Cannot be determined

E. None of theseA


Answer: Option A

Explanation:


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15000 x 1 +

R2- 15000 -

15000 x R x 2= 96

100 100

15000 1 +R

2- 1 -2R

= 96100 100

15000 (100 + R)

2

- 10000 - (200 x R) = 9610000

R2

=96 x 2

= 643

R = 8.

Rate = 8%.

15.

The compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simpleinterest on the same sum for double the time at half the rate percent per annum is:

A.Rs. 400 B.Rs. 500C.Rs. 600 D.Rs. 800

B


Answer: Option B

Explanation:

Let the sum be Rs. P.

Then, P 1 +10

2- P = 525100

P11

2- 1 = 52510

P =525 x 100

= 2500.21

Sum = Rs . 2500.

So, S.I. = Rs.2500 x 5 x 4

= Rs. 500100

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