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    Hon Tat Hui Transmission Lines Basic Theories

    NUS/ECE EE2011

    1

    Transmission Lines Basic Theories

    1 Introduction

    At high frequencies, the wavelength is much smaller than

    the circuit size, resulting in different phases at different

    locations in the circuit.

    Quasi-static circuit theory cannot be applied. We need to

    use transmission line theory.

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    A transmission line is a two-port network connecting

    a generator circuit at the sending end to a load at the

    receiving end.

    Unlike in circuit theory, the length of a transmission line

    is of utmost importance in transmission line analysis.

    z0

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    3 AC Steady-State Analysis3.1 Distributed parameter representation

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    R = resistance per unit length, (/m)

    L = inductance per unit length, (H/m)

    G = conductance per unit length, (S/m)

    C = capacitance per unit length, (F/m)

    z= increment of length, (m)

    We use the following distributed parameters to

    characterize the circuit properties of a transmission line.

    These parameters are related to the physical properties of

    the material filling the space between the two wires.

    where, , = permittivity, permeability, conductivity

    of the surrounding medium.

    =''CL

    ='

    '

    C

    G(See Text Book No.3,

    pp. 432-433)

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    For the coaxial and two-wire transmission lines, thedistributed parameters are related to the physical

    properties and geometrical dimensions as follows:

    Surface

    resistivity ofthe conductors

    (See Text

    Book No.3,

    pp. 445-447)

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    3.2 Equations and solutionsConsider a short section z of a transmission line

    (dropping the primes onR,L, G, Chereafter) :

    Using KVL and KCL circuit theorems, we canderive the following differential equations for this

    section of transmission line.

    Generator Load

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    ( ) ( )( , ), ( , ) , 0

    ( , )( , ) ( , ) ( , ) 0

    i z tv z t R zi z t L z v z z t t

    v z z t i z t G zv z z t C z i z z t

    t

    + =

    + + + =

    By letting z0, these lead to coupled equations:

    ( , ) ( , )( , )

    ( , ) ( , )( , )

    v z t i z t Ri z t Lz t

    i z t v z t Gv z t C

    z t

    = +

    = +

    General Transmission Line Equations Coupled!

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    For sinusoidal varying voltages and currents, we can usephasor forms.

    ( ) ( ) tjezVtzv Re, =

    ( ) ( ) tjezItzi Re, =

    V(z) and I(z) are called phasors of v(z,t) and i(z,t). In

    terms of phasors, the coupled equations can be written as:

    ( )( ) ( )

    ( )( ) ( )

    dV zR j L I z

    dzdI z

    G j C V z dz

    = +

    = +

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    After decoupling,

    ( )

    ( )

    22

    2

    22

    2

    ( )

    ( )

    d V zV z

    dz

    d I zI z

    dz

    =

    =

    ( )( )j R j L G j C = + = + +

    is the complex propagation constant whose real part is

    the attenuation constant (Np/m) and whose imaginarypart

    is the phase constant (rad/m). Generally, these

    quantities are functions of .

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    Solutions to transmission line equations:

    0 0

    0 0

    ( ) ( ) ( )

    ( ) ( ) ( )

    z z

    z

    V z V z V z

    V e V e

    I z I z I z

    I e I e

    +

    +

    +

    +

    = +

    = +

    = +

    = +

    Forwardtravelling

    wave.

    Backwardtravelling

    wave.

    0 0 0 0, , ,V V I I

    + +

    = wave amplitudes in the forward andbackward directions atz= 0. (They

    are complex numbers in general.)

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    Z0 and are the two most important parameters of

    a transmission line. They depend on the

    distributed parameters (RLGC) of the line itself

    and but not the length of the line.

    CjG

    LjR

    CjG

    LjRZ

    +

    +=

    +=

    +=0

    ( )( )CjGLjRj ++=+=

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    For lossless transmission lines,R = G = 0.Parameters for lossless transmission lines

    ==

    =

    LC

    0

    11

    velocityphase ==== LCup

    jkjfjjj =====

    =

    22

    constantnpropagatiocomplex

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    LCff

    ff

    up 121

    lineiontransmissthealongwavelength

    =====

    =

    C

    L

    CjG

    LjR

    Z

    =

    ++=

    =

    impedancesticcharacteri0

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    Voltage and current along the line:

    ( )

    ( ) jkzjkz

    jkzjkz

    eIeIzI

    eVeVzV

    +

    +

    +=

    +=

    00

    00

    LjLjk

    jk

    L

    eVV

    eVeV

    z

    z

    ===

    =

    ==

    +

    +

    0

    00

    0

    0

    0

    0atvoltageincident

    0atvoltagereflected

    Define a reflection coefficient atz= 0 as L:

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    In terms of the reflection coefficient L, the totalvoltage and current can be written as:

    ( )

    ( )jkzLjkz

    jkzjkz

    jkzjkz

    eeV

    eV

    VeV

    eVeVzV

    2

    0

    2

    0

    00

    00

    1

    1

    +=

    +=

    +=

    +

    +

    +

    +

    ( )

    ( )jkzLjkz

    jkzjkz

    jkzjkz

    eeI

    eV

    Ve

    Z

    V

    eZ

    Ve

    Z

    VzI

    2

    0

    2

    0

    0

    0

    0

    0

    0

    0

    0

    1

    1

    =

    =

    =

    +

    +

    +

    +

    In subsequent analyses, we will consider only lossless

    transmission lines.

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    5 Infinitely Long Transmission LineFor an infinitely long transmission line, there can be no

    reflected wave (backward travelling wave). So for an

    infinite long transmission line, there is only a forwardtravelling wave.

    ( )

    ( )

    ( )

    ( ) 000)( Z

    zI

    zV

    zI

    zVzZ ===

    +

    +

    0=L

    ( ) ( )

    ( ) ( ) jkz

    jkz

    eIzIzI

    eVzVzV

    ++

    ++

    ==

    ==

    0

    0

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    6 Terminated Transmission Line

    Note the two coordinate systems and their relation:z= measuring from the left to the right

    = measuring from the right to the left

    loadsource

    = -z

    i

    L

    (

    )Z()

    z = -d

    = dz = 0

    = 0

    z

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    In thezcoordinate system,

    ( )

    VeVeV jkjk =+ +00

    ( )zIeIeI jkzjkz =+ + 00

    In the (= -z) coordinate system,

    ( ) IeIeI jkjk =+ + 00

    ( )zVeVeV jkzjkz =+ + 00

    We will use the coordinate system in subsequentanalyses.

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    ( ) Ljkjk

    eV

    eV ===+

    0

    0

    000

    0

    0

    0 ZI

    V=

    +

    +

    The characteristic impedance in the coordinate system is:

    The reflection coefficient at = 0 in the coordinate

    system is:

    As L is obtained at = 0 (the load position), it iscalled the reflection coefficient at the load.

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    Putting the expressions for V0+

    and V0-

    into the equationsfor the voltage and current, we have:

    ( ) ( ) ( )[ ]( ) ( )[ ]

    kjZkZI

    eeZeeZIV

    LL

    jkjkjkjkLL

    sincos

    2

    1

    0

    0

    +=

    ++=

    ( ) ( ) ( )[ ]

    ( ) ( )[ ]

    kjZkZZ

    I

    eeZeeZZ

    II

    LL

    jkjkjkjk

    LL

    sincos

    2

    1

    0

    0

    0

    0

    +=

    ++=

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    Using V() andI(

    ), we can obtain the impedanceZ(

    ) at

    an arbitrary point on the transmission line as:

    ( )( ) ( )( )

    kjZZkjZZZ

    IVZ

    L

    L

    tantan)(

    0

    00

    ++==

    The reflection coefficient at the loadL can be expressedas:

    ( )

    ( ) 00

    0

    0

    0

    0

    2

    12

    1

    ZZZZ

    ZZI

    ZZI

    VV

    L

    L

    LL

    LLL

    +=

    +

    == +

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    In fact, we can further define a reflection coefficient ()at any point on the transmission line by:

    ( )

    kj

    L

    kj

    jk

    jk

    eeV

    V

    eV

    eV 22

    0

    0

    0

    0

    pointatvoltageincident

    pointatvoltagereflected

    +

    +

    ===

    =

    ( ) ( )( )

    ( ) ( )( )00

    00

    2

    12

    1

    ZZIeV

    ZZIeV

    jk

    jk

    =

    +=

    +

    As we know (by solving the two equations on page 22

    with 0):

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    ( )( ) ( )[ ]

    ( ) ( )[ ]( )( )

    0

    0

    0

    0

    2

    12

    1

    ZZZZ

    ZZI

    ZZI

    +=

    +

    =

    Therefore, alternatively we can write,

    ( ) ( )( )

    +=

    11

    0ZZ

    Then,

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    At the position of the generator (= d),

    ( )( )kdjZZkdjZZ

    ZdZZL

    Li

    tan

    tan)(

    0

    00

    +

    +===

    ( ) kdjLi

    ii e

    ZZ

    ZZd 2

    0

    0 =+

    ===

    i

    Vg

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    Example 1A 100- transmission line is connected to a load consisted

    of a 50- resistor in series with a 10-pF capacitor.

    (a) Find the reflection coefficient L at the load for a 100-MHz signal.

    (b) Find the impedance Zin at the input end of the

    transmission line if its length is 0.125.

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    (b) d=0.125

    ( )

    ( )

    ( )

    ( )

    0

    00

    00

    0

    ( 0.125 )

    tan 4

    tan 4

    14 3717 25 5544

    29.32 60.65

    in

    L

    L

    L

    L

    Z Z

    Z jZ

    Z Z jZ

    Z jZZ

    Z jZ. - j .

    = =

    +

    = +

    +=

    +

    =

    =

    See animation Transmission Line Impedance Calculation

    Normalizedzin = 0.1437-j 0.2555

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    6.1 Voltage/current maxima and minima

    ( )

    ( )

    kj

    L

    jk

    kjjk

    jkjk

    eeV

    eV

    VeV

    eVeVV

    2

    0

    2

    0

    00

    00

    1

    1

    +

    +

    +

    +

    +=

    +=

    +=

    ( )

    ( )

    2

    0

    2

    0

    0

    1

    1

    1

    L

    j k

    L

    j k

    L

    V V e

    V e

    V

    +

    +

    +

    = +

    = +

    = +

    |L|1

    ( )2

    a complex number

    Lj k

    Le

    =

    =

    Lj

    LL e

    =

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    =L-2k

    1 +

    1

    0

    Complex plane of (1+)

    Re

    Im

    ( )2 'L kzLe

    =1 L

    1 L+

    0=m

    M

    ( )V

    See animation Transmission Line Voltage Maxima and Minima

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    ( ) ( )( )

    [ )

    max

    is maximum when 1 1 2 2

    , 0,1,2,4 2

    Note: has to be specified in the range , .

    L

    L

    L

    M

    L

    VV k n

    n

    n

    + = +

    = =

    = + =

    ( ) ( )( ) ( )

    ( )

    [ )

    min

    is minimum when 1 1

    2 2 1

    2 1 , 0,1, 2,4 4

    Note: has to be specified in the range , .

    L

    L

    Lm

    L

    V

    V k n

    n n

    = = = +

    + = + =

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    ( ) 20

    0

    0

    1

    1

    j kLI I e

    V

    Z

    +

    +

    =

    =

    As current is

    Current is maximum when voltage is minimum and

    minimum when voltage is maximum.

    ( ) ( )

    =

    ++= L

    LM n

    nI with,,2,1,0,

    4

    12

    4at

    max

    ( )

    =+= L

    Lm n

    nI with,,2,1,0,

    24at

    min

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    ( )

    ( )

    ( )( )

    0max

    0min

    voltage standing wave ratio (VSWR)

    1 1

    (dimensionless)11

    L L

    LL

    S

    V V

    V V

    +

    +

    =

    + +

    = = =

    1

    1

    +

    =

    S

    S

    L

    |V(z)|

    |V|max

    |V|min

    |I|max

    |I|min

    |I(z)|

    load load

    lmax lmax

    Define a voltage standing wave ratio (VSWR) as:

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    6.2 Power flow in a transmission line

    Power flow at any pointzon a transmission line

    is given by:

    ( ) ( ) ( ){ }zIzVzPav *Re21=

    Power delivered by the source:

    { }*Re2

    1igs IVP =

    Power dissipated in the source impedanceZg:

    { } { } { }giiigZZZ ZIIIZIVP ggg Re21

    Re2

    1Re

    2

    1 2** ===

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    Power input to the transmission line:

    ( ) ( ) ( ){ }

    { } { } { }

    =

    =

    ===

    ==

    *

    2

    *

    *

    2**

    *

    1Re

    2

    1Re

    2

    1

    Re

    2

    1Re

    2

    1Re

    2

    1

    Re21

    i

    i

    i

    ii

    iiiiiii

    avi

    ZV

    Z

    VV

    ZIIIZIV

    dIdVdPP

    ( ) ( ) ( ){ }

    { } { } { }

    =

    =

    ===

    ==

    *

    2

    *

    *

    2**

    *

    1Re

    2

    1Re

    2

    1

    Re2

    1

    Re2

    1

    Re2

    1

    00Re2

    10

    L

    L

    L

    LL

    LLLLLLL

    avL

    ZV

    Z

    VV

    ZIIIZIV

    IVPPPower dissipated in the terminal impedance:

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    Solutions

    The following information is given:

    m310

    Hz10MHz100

    ,5050,50,V60

    m,1.5,50

    8

    8

    0

    ===

    ==+===

    ==

    ccu

    f

    jZZV

    dZ

    p

    Lgg

    1.110

    0

    50 50 500.2 0.4 0.45

    50 50 50

    jLL

    L

    Z Z j j e

    Z Z j

    + = = = + =+ + +

    The reflection coefficient at the load is:

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    rad11.1,45.0Therefore, ==

    LL

    load)(from them27.009.04

    11.1

    0when,24

    Then,

    ===

    =+=

    n

    nLM

    ( )( )kdjZZkdjZZZZ

    L

    Li

    tantan

    0

    00

    ++=

    The input impedance Zi looking at the input to thetransmission line is:

    /

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    A24.048.0505050

    60

    :islineiontransmisstheinput toat thecurrentThe

    jjZZ

    VI

    ig

    g

    i =++

    =+

    =

    { } W2.750288.02

    1Re

    2

    1 2==== iiiL ZIPP

    As the transmission line is lossless, power delivered to the

    loadPL is equal to the power input to the transmission line

    Pi. Hence,

    ( )+=

    ++

    ++

    = 5050

    5.13

    2tan505050

    5.13

    2

    tan50505050 j

    jj

    jjZi

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    giig ZIVV +=

    Vi andIi are related to the source voltage Vgas:

    From the expressions ofVi, Ii, and Vg, we can find V0+

    .

    ( )( )kdjLgg

    jkd

    g

    eZZ

    eZVV

    2

    0

    0

    01

    +

    +=

    kdj

    L

    jkd

    i eeVV2

    0 1 + += ( )kdjLjkdi ee

    Z

    VI 2

    0

    0 1 +

    =

    At = d, V(d) = Vi andI(d) =Ii.

    tcoefficienreflectionsource0

    0 =+

    =

    ZZ

    ZZ

    g

    g

    g

    NUS/ECE EE2011

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    ( )

    ( )( ) ( )

    ( )( )( )

    ( )

    kj

    L

    jk

    kdj

    Lgg

    jkd

    g

    kj

    L

    jk

    kdj

    Lgg

    jkd

    g

    eeeZZ

    eVI

    ee

    eZZ

    eZVV

    2

    2

    0

    2

    2

    0

    0

    11

    1

    1

    +

    =

    +

    +

    =

    Putting V0+ into the expressions of V() andI(), we have:

    Now the voltage and current on the transmission line are

    expressed in terms of the known parameters of thetransmission line.

    NUS/ECE EE2011

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    Example 3

    A 1.05-GHz generator circuit with a series impedanceZg= 10and voltage source given by:

    is connected to a load ZL = (100 + j50) through a 50-, 67-cm-long lossless transmission line. The phase velocity of the line is

    0.7c, where c is the velocity of light in a vacuum. Find the

    instantaneous voltage and current v(,t) and i(

    ,t) on the line and

    the average power delivered to the load.

    ( ) ( ) ( )V30sin10g += ttv

    Z0 = 50 ZL

    dZg

    vg Zi

    0

    IiA

    A

    Vi

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    Solutions

    35.32.0

    67.0cm67

    m2.01005.11037.0 9

    8

    p

    ===

    ===

    d

    fu

    32

    50105010

    tcoefficienreflectionsource

    0

    0=+=+

    =

    ZZZZ

    g

    g

    g

    46.0

    0

    0 45.05050100

    5050100

    tcoefficienreflectionload

    j

    L

    L

    L

    ej

    j

    ZZ

    ZZ=

    ++

    +=

    +

    =

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    Hon Tat Hui Transmission Lines Basic Theories50

    ( ) ( )( ) ( )( )[ ]46.077.2

    22

    0

    45.020.0

    11

    =

    +=

    kjjkj

    kjL

    jkkdj

    Lgg

    jkd

    g

    eee

    eeeZZ

    eVI

    Therefore instantaneous forms are:

    ( ) ( ){ }( )[ ]{ }

    ( ) ( )23.3cos58.477.2cos18.1045.018.10Re

    Re,

    46.077.2

    ++++=+=

    =

    ktkt

    eeee

    eVtv

    tjkjjkj

    tj

    ( ) ( ){ } ( )[ ]{ }( ) ( )23.3cos09.077.2cos20.0

    45.020.0Re

    Re,

    46.077.2

    +++=

    =

    =

    ktkt

    eeee

    eIti

    tjkjjkj

    tj

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    Hon Tat Hui Transmission Lines Basic Theories51

    ( )( )

    ( )

    ( )

    4.179.21

    35.32

    tan5010050

    35.32

    tan5050100

    50

    tan

    tan

    0

    00

    j

    jj

    jj

    kdjZZ

    kdjZZZZ

    L

    Li

    +=

    ++

    ++

    =

    +

    +=

    55.13/

    28.04.179.2110

    10 jj

    ig

    g

    i ej

    e

    ZZ

    V

    I

    =++=+=

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    Hon Tat Hui Transmission Lines Basic Theories52

    Power delivered to the load

    = power input to the transmission line at AA

    { }

    { }

    { }

    { }

    Watt86.0

    4.179.21Re28.0

    2

    1

    Re21

    Re2

    1

    Re

    2

    1

    2

    2

    *

    *

    =

    +=

    =

    =

    =

    j

    ZI

    IZI

    IV

    ii

    iii

    ii

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    Hon Tat Hui Transmission Lines Basic Theories53

    7 Special Cases of Terminations in a Transmission Line

    For a matched line,ZL = Z0. Then,

    7.1 Matched line

    ( ) ( )

    ( )

    ( ) ( )( )

    linetheoflengthanyfor

    0

    tan

    tan

    0

    0

    0

    00

    000

    =+=

    =+

    +=

    ZZZZ

    ZkjZZ

    kjZZZZ

    Thus, there is no reflection on a matched line. There isonly an incident voltage. It is same as the case of an

    infinitely long line.

    Note =-z

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    Hon Tat Hui Transmission Lines Basic Theories54

    Z0

    Zin

    1

    -1

    1

    -1

    Normalized current magnitude

    1

    -1

    Normalized impedance (Zin/Z0)

    Z0

    z

    z

    z

    z0

    0

    Note:

    Normalized voltage = voltage/max. |voltage|

    Normalized current = current/max. |current|

    Normalized voltage magnitude

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    Hon Tat Hui Transmission Lines Basic Theories55

    For a short circuit,ZL = 0. Then

    7.2 Short-circuited line

    ( ) ( )kzjZkjZZ tantan 00sc

    in ==

    Normalized impedance (=-tan(kz))

    Normalized voltage magnitude

    Normalized current magnitude

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    Hon Tat Hui Transmission Lines Basic Theories56

    7.3 Open-circuited line

    For an open circuit,ZL = . Then

    ( ) ( )kzjZkjZZ cotcot 00oc

    in ==

    Normalized voltage magnitude

    Normalized impedance (=cot(kz))

    Note that:

    ( )[ ] ( )[ ]20

    00

    oc

    in

    sc

    in

    cottan

    Z

    kjZkjZZZ

    =

    =

    ( )[ ] ( )[ ]

    ( )

    k

    kjZkjZZZ

    2

    00

    oc

    in

    sc

    in

    tan

    cottan

    =

    =

    k.andcompute,and,,Given 0oc

    in

    sc

    in ZZZ

    Normalized current magnitude

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    Hon Tat Hui Transmission Lines Basic Theories

    57

    7.4 /4 transmission line terminated inZL

    7.5 /2 transmission line terminated inZL

    ( )( ) LL

    Lin

    Z

    Z

    jZZ

    jZZZZZ

    2

    0

    0

    00

    2tan

    2tan)4( =

    +

    +===

    ( )( ) LL

    Lin Z

    jZZ

    jZZZZZ =

    +

    +===

    tan

    tan)2(

    0

    00

    Zin

    Z0 ZL

    Zin

    Z0 ZL

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    Hon Tat Hui Transmission Lines Basic Theories

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    Example 4

    The open-circuit and short-circuit impedances measured atthe input terminals of a lossless transmission line of length

    1.5 m (which is less than a quarter wavelength) are j54.6

    andj103 , respectively.

    (a) FindZ0 and kof the line.

    (b) Without changing the operating frequency, find theinput impedance of a short-circuited line that is twice

    the given length.

    (c) How long should the short-circuited line be in orderfor it to appear as an open circuit at the input

    terminals?

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    S l ti

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    Hon Tat Hui Transmission Lines Basic Theories

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    Solution

    The given quantities are

    (a)

    (b) For a line twice as long, = 3 m and k =1.884 rad,

    m5.1=

    mrad628.0tan1 oc

    in

    sc

    in

    1

    ==

    ZZk

    232tan0sc

    in jkjZZ ==

    m102

    ==k

    103scin jZ =

    6.54ocin jZ =

    75scinoc

    in0 == ZZZ

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