hydraulic machines and fluid energy systems (engm...
TRANSCRIPT
![Page 1: Hydraulic Machines and Fluid Energy Systems (EngM …colleges.jazanu.edu.sa/sites/en/eng/Labs/EngM426...Jazan University Faculty of Engineering Mechanical Eng. Dept. Hydraulic Machines](https://reader031.vdocument.in/reader031/viewer/2022022501/5aa7858b7f8b9a50528c831f/html5/thumbnails/1.jpg)
Jazan University Faculty of Engineering Mechanical Eng. Dept.
Hydraulic Machines and Fluid Energy Systems
(EngM 426)
Experiment Report
Performance Curves of a Positive-Displacement Pump (Piston type)
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Student ID:
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Jazan University Faculty of Engineering Mechanical Eng. Dept.
Hydraulic Machines and Fluid Energy Systems
(EngM 426)
Experiment Report
Pumps connected in series and parallel
Student Name:
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Student ID:
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 2 of 8
1. Objective: To determine the head-discharge characteristics of two identical centrifugal pumps operating in series and parallel and to compare with the theoretical results. 2. Apparatus: Hydraulic bench, two centrifugal pumps, power meter, flowrate meter, speed meter and pressure gauges.
Ref. no. Item 1 Valve for parallel operation 2 Pump no. 2 suction pressure gauge 3 Valve for series operation 4 Pump no. 2 suction valve 5 Pump no. 1 suction valve 6 Pump no. 1 suction pressure gauge
Pump specifications: Maximum head = 20 m Maximum discharge = 0.7 Lps (42 Lpm) Maximum speed = 6000 rpm
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 3 of 8
3. Procedure: 1. Connect the two pumps in series (as shown below).
2. Switch on pumps. 3. Set the pump speeds at same constant value. 4. Start the test with the regulating valve closed. 5. Read off pressures before and after the pumps, volumetric flow rate and electrical power. 6. Partially open the valve and take the readings. 7. Repeat above step until the valve is fully open.
8. Repeat above steps for the two pumps connected in parallel (as shown below).
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 4 of 8
4. Readings: 4.1 Pumps in series Speed =
No. Volume (Litre)
Time (s)
Inlet Exit p1 (bar) p2 (bar)
1 2 3 4 5 6 7
4.1 Pumps in parallel Speed =
No. Volume (Litre)
Time (s)
Inlet Exit p1 (bar) p2 (bar)
1 2 3 4 5 6 7
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 5 of 8
5. Calculations (2 marks):
5.1. Single pump (Given)
No. Flowrate (Litre/s)
Head (m)
1 0.0 11.5 2 0.2 10.2 3 0.4 8.2 4 0.6 3.0 5 0.7 0
5.2. Pumps in series
No. Flowrate (Litre/s)
Head (m)
1 2 3 4 5 6 7
5.3. Pumps in parallel
No. Flowrate (Litre/s)
Head (m)
1 2 3 4 5 6 7
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 6 of 8
6. Sample calculations (2 marks):
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 7 of 8
7. Results and Discussion (6 marks): 7.1. Pumps in series:
Fig. 1: Head against flowrate for single pump and pumps in series compared with theoretical
result.
0
5
10
15
20
25
30
0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0
Hea
d (m
)
Q (L/s)
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 8 of 8
7.2. Pumps in parallel:
Fig. 2: Head against flowrate for single pump and pumps in parallel compared with theoretical
result.
0
5
10
15
20
25
30
0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0
Hea
d (m
)
Q (L/s)
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Jazan University Faculty of Engineering Mechanical Eng. Dept.
Hydraulic Machines and Fluid Energy Systems
(EngM 426)
Experiment Report
Performance Curves of a Centrifugal Pump
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Student ID:
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 2 of 9
1. Objective: Determine the actual performance curves of a centrifugal pump at constant speed. 2. Apparatus: centrifugal pump, hydraulic bench, power meter, flowrate meter, pressure gauges. Maximum pump head = 24 m Maximum pump discharge = 1400 L/min Maximum motor power = 4 kW Pump speed = 1450 - 2900 rpm
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 3 of 9
3. Procedure: 1. Switch on the pump. 2. Set pump speed at constant value. 3. Start the test with the regulating valve closed. 4. Read off pressures before and after the pump, volumetric flow rate and electrical power. 5. Partially open the valve and take the readings. 6. Repeat above step until the valve is fully open. 7. Change pump speed and repeat steps 3 - 6.
4. Readings: 4.1. At speed = rpm
Q (l/min) p1 (bar) p2 (bar) Power (W)
1
2
3
4
5
6
7
8
6.2. At speed = rpm
Q (l/min) p1 (bar) p2 (bar) Power (W)
1
2
3
4
5
6
7
8
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 4 of 9
5. Theory:
1
2
2
2
22 ⎟⎟⎠
⎞⎜⎜⎝
⎛++⎟⎟
⎠
⎞⎜⎜⎝
⎛++= z
gV
gp-z
gV
gpH
ρρ
dQ
AQV
42π==
power shaft
gQHρη =
Pump impeller diameter = 125 mm Suction pipe diameter = 0.065 m Discharge pipe diameter = 0.05 m β2 = 20o b2 = 20 mm
0.15m
0.3m
Din = 0.065m
Dout = 0.05m
grgHth ⎜⎜⎝−= 22π
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 5 of 9
6. Calculations (2 marks): 6.1. At speed = rpm
Q (m3/s) H (m) Pw (W) Pm (W) η (%) Hth (m) 1 2 3 4 5 6 7 8
6.2. At speed = rpm
Q (m3/s) H (m) Pw (W) Pm (W) η (%) Hth (m) 1 2 3 4 5 6 7 8
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 6 of 9
6.3. Sample calculations (2 marks): For point number ( ) of speed rpm:
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 7 of 9
7. Results and Discussion (6 marks):
Fig. 1: Pressure head against flowrate for two different speeds; compared with the theoretical
pressure head.
0
10
20
30
40
50
0 100 200 300 400 500 600
Hea
d (m
)
Q (L/min)
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 8 of 9
Fig. 2: Shaft power against flowrate for two different speeds.
0
10
20
30
40
50
0 100 200 300 400 500 600
Pow
er (W
)
Q (L/min)
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 9 of 9
Fig. 3: Pump efficiency against flowrate for two different speeds.
0
10
20
30
40
50
0 100 200 300 400 500 600
Effic
ienc
y (%
)
Q (L/min)
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 2 of 9
1. Objective: Determine the actual performance curves of a positive-displacement pump (piston type) at constant speed. 2. Apparatus: Positive-displacement pump (piston type) of maximum speed 1040rpm, hydraulic bench (max. pressure is 5 bar), power meter, flowrate meter, pressure gauges.
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 3 of 9
3. Procedure: 1. Switch on the pump in clockwise direction. 2. Set pump speed at constant value. 3. Start the test with discharge valve fully open. 4. Read off pressures before and after the pump, volumetric flow rate and brake force. 5. Partially close the valve and take the readings. 6. Repeat above step for maximum of 6 bar outlet pressure. 7. Do not fully close the valve. 8. Change pump speed and repeat steps 3 - 6.
4. Readings:
4.1. At speed = rpm
No. p1 (bar) p2 (bar) Q (l/min) Force (N) 1 2 3 4 5 6 7 8 9
6.2. At speed = rpm
No. p1 (bar) p2 (bar) Q (l/min) Force (N) 1 2 3 4 5 6 7 8 9
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 4 of 9
5. Theory:
inoutinout z
gV
gp-z
gV
gpHHHead ⎟⎟
⎠
⎞⎜⎜⎝
⎛++⎟⎟
⎠
⎞⎜⎜⎝
⎛++=−=
22
22
ρρ
( ) gQHP Power Water w ρ= ( ) ω×= T P Power Shaft m
( ) LFTorque ×=T
Arm length, L = 20 cm
power shaft
gQHρη =
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 5 of 9
6. Calculations (2 marks): 6.1. At speed = rpm
No. Head (m) Q (L/min) Pw Pm η (%) 1 2 3 4 5 6 7 8 9
6.2. At speed = rpm
No. Head (m) Q (L/min) Pw Pm η (%) 1 2 3 4 5 6 7 8 9
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 6 of 9
6.3. Sample calculations (2 marks): For point number ( ) of speed rpm:
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 7 of 9
7. Results and Discussion (6 marks):
0
5
10
15
20
25
0 10 20 30 40 50 60
Q (L
/min
)
Head (m)
Fig. 1: Flowrate against pressure head for two different speeds.
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 8 of 9
0
5
10
15
20
25
0 10 20 30 40 50 60
Pow
er (W
)
Head (m)
Fig. 2: Shaft power against pressure head for two different speeds.
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 9 of 9
0
5
10
15
20
25
0 10 20 30 40 50 60
Effic
ienc
y (%
)
Head (m)
Fig. 3: Pump efficiency against pressure head for two different speeds.
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Jazan University Faculty of Engineering Mechanical Eng. Dept.
Hydraulic Machines and Fluid Energy Systems
(EngM 426)
Experiment Report
Performance Curves of the Pelton’s Turbine
Student Name:
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Student ID:
--------------------------------
( )
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 2 of 8
1. Objective: Determine performance curves of the Pelton’s turbine for different speeds. 2. Apparatus: Pelton’s turbine, hydraulic bench, optic tachometer, band brake with two dynamometers and pressure gauge.
3. Procedure:
1. Place the turbine in the bench and connect it to the water supply of the bench. 2. Switch on the pump. 3. Fully open the control valve of the bench. 4. Take the reading necessary to calculate the volume flow rate. 5. Set the band brake free (e.g. zero torque). 6. Take the reading of the brake device (F or M), tachometer (N) and pressure gauge (p). 7. Lower the braking device. 8. Repeat steps 6-7 for different turbine speeds.
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Jazan University Faculty of Engineering Mechanical Eng. Dept.
Hydraulic Machines and Fluid Energy Systems (EngM 426)
Experiment Report
Performance Curves of Francis Turbine
Student Name:
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Student ID:
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 2 of 8
1. Objective: Determine performance curves of the Francis turbine at constant head. 2. Apparatus: Hydraulic bench, Francis turbine, brake drum, digital tachometer and pressure gauge.
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 3 of 8
3. Procedure: 1. Switch on the pump. 2. Fully open the control valve of the bench. 3. Fix guide vane position (eg. 1-10). 4. Set the brake free (e.g. zero torque). 5. Take the reading necessary to calculate the volume flow rate. 6. Take the reading of torque, speed and pressure of the inlet flow. 7. Lower the braking device for interval of about 500 rpm. 8. Repeat steps 6-7 for different turbine speeds.
4. Readings: Guide vane position =
No. Speed (rpm)
Flowrate (L/hr)
Pressure (bar)
Torque (N.m)
1
2
3
4
5
6
7
5. Calculations:
gQHPw ρ= NT velocity angulartorquePm π2×=×=
w
m
PP
=η
No. N (rpm)
Q (m3/s)
Pw (W)
Pm (W)
η (%)
1
2
3
4
5
6
7
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 4 of 8
Sample calculations:
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 5 of 8
6. Results and Discussion:
Fig. 1: Flowrate against speed.
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 6 of 8
Fig. 2: Head against speed.
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 7 of 8
Fig. 3: Mechanical power against speed.
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 8 of 8
Fig. 4: Efficiency against speed.
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 3 of 8
4. Readings: Volume = Liter Time = Seconds
No. F1 or M1 (N or g)
F2 or M2 (N or g)
Speed (rpm)
Pressure (bar)
1
2
3
4
5
6
7
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 4 of 8
5. Calculations: Mean turbine radius = 50 mm Torque arm, L = 30 mm k = 0.98 β = 165o Cv = 0.94
gHCvV j 2= gQHPw ρ=
ω×= TPm
gQH
TPP
w
m
ρωη ×
==
For force type:
( ) LFFLFarm TorqueForceTorque ×−=×=×= 12 where F is the spring force in Newton. For weight type:
( ) LgMMLFarm TorqueForceTorque ××−=×=×= 21 where M is the weight in grams.
Q = (m3/s) H = (m) Vj = (m/s) Pw = (W)
No u (m/s)
u/Vj
(φ)
Experimental Theoretical Torque (N.m)
Pm (W)
η (%)
Torque (N.m)
Pm (W)
η (%)
1 2 3 4 5 6 7
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 5 of 8
Sample calculations:
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 6 of 8
6. Results and Discussion:
Fig. 1: Experimental torque against φ (u/Vj) compared with theoretical results.
0.0
0.1
0.2
0.3
0.4
0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8
Torq
ue
U/Vj
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 7 of 8
Fig. 2: Experimental Mechanical power (Pm) against φ (u/Vj) compared with theoretical results.
0
5
10
15
20
25
30
0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8
Shaf
t Pow
er
U/Vj
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Hydraulic Machines & Fluid Energy Systems (EngM 426)
Dr. Ahmed Bagabir Page 8 of 8
Fig. 3: Experimental Efficiency (η) against φ (u/Vj) compared with theoretical results.
0
20
40
60
80
100
0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8
Effic
ienc
y (%
)
U/Vj