ib physics 12 mr. jean september 15 th, 2015. the plan: video clip of the day 0xs
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New IA Criteria:TRANSCRIPT
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IB Physics 12
Mr. JeanSeptember 15th, 2015
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The plan:• Video clip of the day
– https://www.youtube.com/watch?v=QcdlGjAP0xs
• Conical Pendulums Investigation• Banked turns with Friction
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New IA Criteria:
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Conical Pendulum:• http://www.youtube.com/watch?v=5C4RJl
FABic
• http://www.youtube.com/watch?v=h-aStiXBaus
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Conical Pendulum Motion:
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Conical Pendulum Motion:• T = Tension in Newton's
• T cos θ is balanced by the object's weight, mg.
– Thus T * cos(θ) = mg
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Conical Pendulum Motion:• T sin θ that is the unbalanced central force
that is supplying the centripetal force necessary to keep the block moving in its circular path:
– Thus T sin θ = Fc = mac.
– Thus T sin θ = Fc = (mv2) r
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• How long does it take for the object to complete one complete circle?
• HINT: v = 2 π r f
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Banked Turns with Friction:
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Important assumptions for Banked turns with Friction:
• Fnet = Fc = Ff + Fg
• Let’s look at the frictional force first:1. Ff = μ * Fn
2. Ff = μ * Fg * cos (10)
• Ff = μmg cos(Θ)
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Let’s look at the gravitational force:1. Fg = Fg * sin(10)
• Ff = μmg sin(10)
Fnet = Fc = Ff + Fg
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Banked Curves (with friction)• The Problem: A car with the mass of
1500kg is traveling in uniform circular motion along a circular curve with radius of 50 meters on a road that is banked at 10 degrees. The coefficient of friction is 0.4.
• What is the maximum velocity in which this car can take the curve?
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• Finding the sum of all center seeking forces. (Use previous diagram to highlight forces)
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Frictional Force:
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Gravitational Force:
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Centripetal Force:
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Chapter #5• If you are wondering where we are:
• Giancoli– P. 117 to 122 Gravitational Constant– P. 122 to 127 Newton & Kepler’s Synthesis
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Newton’s Law of Universal Gravitation:
• Fg = force of gravity in newtons (N)
• m1 = first mass in kilograms (Kg)
• m2 = second mass in kilograms (Kg)• r = distance between centers of mass in meters• G = Universal Gravity Constant (***next slide
for units***)
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Universal Gravitational Constant:
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How to masses act on each other:
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• In the case of the Earth-Moon system, the moon is accelerating towards the Earth.
• The moon has a tangential component to its velocity. So it keeps moving in a circle around the Earth.
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Kepler’s Empirical Equations:• Johannes Kepler’s (1571 – 1630) was the
famous German astronomer who laid the framework for understanding planetary motion.
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Kepler’s First Law:• Planets move in elliptical orbits around the
sun. • As an average these orbits are nearly
circular.
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Kepler’s Second Law:• An imaginary line between the Sun and a
planet sweeps out equal areas in equal time intervals.
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• K = is a CONSTANT for all planet’s as they travel around the sun .
• r = average distance from sun (m)
• T = period of planet’s revolution around the sun (seconds)
Kepler’s Third Law:
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Kepler’s Third Law:
• The squared product of the period for a planet’s revolution around the Sun and the cube of the average distance from the Sun is a constant and the same for all planets.
• r = average distance from sun (m)• T = period of planet’s revolution around
the sun (s)
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Satellites in space:
• A satellite in space moves around a heavy body. To keep the satellite from smashing back into the Earth (or planet it is orbiting), scientists set the force of gravity equal to the centripetal force.
• Fg = Fc
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Example Question:• You find yourself in space. In fact you are
walking on a large asteroid. Your mass is 70kg, the asteroid has a mass of 8.0 x 105kg and the radius between the two centers of mass is 80 meters.
• What is your weight on the asteroid?
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• m1 = 70 (kg)
• m2 = 8.0 x 105 (kg) • r = 80 meters (m)
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This weekend: • Please read Giancoli Chapter #5
– P. 117 to 122 Gravitational Constant– P. 122 to 127 Newton & Kepler’s Synthesis