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IBPS PO Pre Test No 5

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  • 1IBPSPO-PT-005

    IBPSPO-PT-005

    1. 2 2. 3 3. 2 4.4 5.36. 5 7. 1 8. 4 9. 1 10. 311. 4 12. 3 13. 2 14. 1 15. 5

    (1620): B D C A E16. 4 17. 2 18. 1 19. 5 20. 3

    21. 4; Add both before ends

    22. 2; Replace were with was

    23. 1; Replace at with on

    24. 4; Replace larger with higher

    25. 4; Omit on

    26. 1 27. 3 28. 5 29. 3 30. 1

    31. 4; The series is:267 4 = 263263 (4 + 8) = 251

    251 (12 + 8) = 231231 (20 + 8) = 203

    203 (28 + 8) = 167

    32. 1;

    33. 2; The series is:45 + 1 3.5 = 48.548.5 + 2 3.5 = 55.5

    55.5 + 3 3.5 = 65

    66 + 4 3.5 = 8080 + 5 3.5 = 97.5

    34. 1; The series is:

    2856

    + 24 = 452

    2452

    + 24 = 250

    2250

    + 24 = 149

    2149

    + 24 = 98.5

    25.98

    + 24 = 73.25

    35. 4;

    36. 1; ? = 13

    2527 = 4

    37.2; ? =

    100

    585232 150 = 9.048

    38. 1; ? = 6556209845

    = 65

    39. 3; ? =

    4017717134

    = 52.525

    40. 1; ? = 15250

    20300

    25100

    = 1000

    41. 3; ? 53 + (29)2 = 125 + 841 = 966

    42. 4; ? 34990

    66870

    250510

    = 783

    43. 5; ? 52921165476 = 74 46 23 = 148

    44. 4; ? 100405090

    74

    994

    = 3645 568 = 3077

    45. 2; ? 11102

    616 1189

    44

    = 5712 356 = 5356

    46. 1; From statement A;

    Fathers present age = x years

    Monikas present age = 112

    x

    From statement C and A;

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    4x112

    = 41

    (x +4)

    4x

    112x

    = 3 x = 44 years

    Monikas age = 8 years47. 5; From statement A and C, we get

    hP

    = sin 60 and h = 13 cm P = 13 23

    And, hb

    = cos 60 b = 213

    Area of triangle = 2133

    213

    31

    = 12

    3169 cm2

    48. 3; From statement A and B;

    Part of vessel filled in 1 hr = 161

    Part of vessel filled by (pipe + leak) in1 hr = 241

    Part of vessel emptied by leak in 1hr

    = 161

    241

    = 481

    Time taken to empty the vessel = 48 hr49. 1; From statement C;

    M1 D1 = M2 D2 4 15 = 5 D2 D2 = 12 days50. 2; From all A, B and C

    Total age of 14 students and teacher is= 15 16 = 240 years

    Age of teacher = 240 14 13 = 58 years(5155):

    Unit Total Male FemaleWorkers workers workers

    I 2376 1584 792II 2112 768 1344

    III 2508 1188 1320IV 1848 1188 660V 2376 1386 990VI 1980 924 1056

    51. 2; Required percentage

    = 10092413861188118876815841188768

    = 10070381956

    28%

    52. 5; Required difference percentage

    = 1320061627038

    100 6.64%

    53. 1; Required ratio = (1188 + 1188) : (792 + 1344)

    = 2376 : 2136 = 99 : 89

    54. 3; Required ratio = 1320 : 924 = 10 : 7

    55. 4; Required percentage = 100

    105699066011887681584

    = 10027063540

    131%

    56. 1; Average height of the class

    = 2118

    21132110421

    18131811718

    = 3921972119

    = 3332

    = 110 32

    cm

    57. 4; Required answer

    = 462)12(46

    = 412

    24 = 8

    24 = 3 hrs

    58. 2; Required time = LCM of 21, 18, 24 min = 504 min

    = 8.4 hrs

    59. 5; Let the present age of Nayan and Pooja be 18x and 17xrespectively

    917x918x

    = 1415

    252x 126 = 255x 135

    3x = 9 x = 3

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    Leenas present age = 17 3 9 = 42 years

    60. 4; Ratio of profit P, Q and R = 24000 24 : 32000 24 : 30000 16 = 6 : 8 : 5

    Share of R = 195

    91200 = ` 24000

    61. 3; Let the original price be ` xThen,

    1= x0.5)(x0.5120

    x(x 0.5) = 60 x = ` 8

    62. 4; Cost price

    = 100

    1003512121235

    8.40

    = 8.68.40

    100 = ` 600

    63.2; Total work done by B in

    1510315

    = 1512

    10

    = 8 days Remaining work done by B in 8 3 = 5 days

    64. 5; Time take by the faster pipe

    = 2

    )625(36425 =

    212513

    = 10 hrs

    65. 3; Required time

    = speed

    covered be toDistance + Number of rest Time for

    each rest

    = 6012156

    856

    = 7 + 55 6012

    = 7 + 11 = 18 hrs

    66. 2; All flower is fruits (A) + Some fruits are leaves (I) = A +I = No conclusion. Hence, conclusion I does not follow.Again,No leaf is tree (E) conversion No tree is leaf (E). Hence,conclusion II follows.

    67. 1; All flowers is fruits (A) + Some fruits are leaves (I) = A+ I = No conclusion. But, the possibility holds true. Hence,conclusion I follows.Again,Some fruits are leaves (I) + No leaf is tree (E) = I + E = O =Some fruits are not tree.Now,All flower is fruit (A) + Some fruits are not tree (O) = A + O= No conclusion. Hence, conclusion II does not follow.

    68. 5; All candidates are examinees (A) + No examinee is

    a teacher (E) = A + E = E = No candidate is a teacher.Hence, conclusion I follows.Again,From aboveNo candidate is a teacher (E) + All teachers are students(A) = E + A = O* = Some students are not candidates.Hence, conclusion II follows.

    69. 5; No examinee is a teacher (E) + All teachers are students(A) = Clearly all students can never be examinee ofpossibility true. Hence, conclusion I follows.Again,No examinee is a teacher (E) + All teachers are students(A) = E + A = O* = Some students are not examinee.Clearly, possibility holds true. Hence, conclusion IIfollows.

    70. 1; Some integers are odd (I) + Each odd is digit (A) = I + A= I = Some integers are digit. Hence, conclusion I follows.Again,From above,Some integers are digit (I).Now,No number is integer (E) + Some integer are digits (I) = E+ I = O* = Some digits are not number. Hence, conclusionII does not follow.

    71. 1; Given statements:M = N Q...............(i)N < R < T............(ii)

    Combining (i) and (ii), we get

    Comparing R and Q, we getR > Q. Thus only conclusion I is true and conclusion II isnot true.

    72. 5; Given statements:D > P < N ................(i)N > L > D.................(ii)Combining (i) and (ii), we get

    We getN > P and N > DSo, P < N > D,Thus conclusion I is true.Again,We get,L > P is true, Thus conclusion II is true.

    73. 5; Given statements:K > P Q > R ...........(i)P < T > K....................(ii)

    Combining (i) and (ii), we get

  • 4 IBPSPO-PT-005

    We get,T > R. Thus conclusion I is true.Again, we getK > Q, T > P. Thus conclusion II is true.

    74. 2; Given statements:J = N R .................(i) J < T < S = Q..........(ii)Combining (i) and (ii), we get

    We get,T > R and Q > N, Thus conclusion I is not true.Again,T < Q is true. Thus conclusion II is true.

    75. 5; Given statements:P >N T .............(i)N < W > S > P......(ii)Combining (i) and (ii), we get

    We get,W > T and P > T, Thus conclusion I is true.Again,W > N and S > T or T < S, Thus conclusion II is true.

    (7680):youth participation is important qik put ntyt.................(i)it is very important pro nt yt di ....................(ii)it is strength of youth di nt que qik ne .......(iii)power of important leader que yt jd sy.......(iv)From (i), (ii) and (iii), is nt.............................(v)From (i), (ii) and (iv), important yt ..............(vi)From (iii) and (iv), of que .............................(vii)From (i), (iii) and (v), youth qik .................(viii)From (ii), (iii) and (v), it di ...........................(ix)From (i), (v), (vi) and (viii),participation put ..............................................(x)From (ii), (v), (vi) and (ix), very pro...............(xi)From (iii), (v), (vii), (viii) and (ix), strength ne ......(xii)From (iv), (vi) and (vii),power/leader jd / sy ................................(xiii)

    76. 3 77. 2 78. 4 79. 5 80. 1(8186):

    81. 2 82. 3 83. 4 84. 5 85. 1 86. 4

    (8789):

    87. 2; (87) = 1 km88. 389. 590. 2; people live only on earth.91. 3;

    Similarly

    [Here sum of the [Sum of two lettertwo letters is 27] is 27]

    92. 5; 26 3 8 4 + 20 = 4093. 194. 4;

    95. 3

  • 5IBPSPO-PT-005

    (96100):

    Persons Profession Preference

    P Teacher Watching T.V.

    Q Doctor Playing

    R Journalist Watching T.V.

    S Advocate Playing

    T Pilot Watching T.V.

    96. 2 97. 3 98. 5 99. 5 100. 4

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