incomplete block designs. randomized block design we want to compare t treatments group the n = bt...
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Incomplete Block Designs
Randomized Block Design
• We want to compare t treatments• Group the N = bt experimental units into b
homogeneous blocks of size t.• In each block we randomly assign the t treatments
to the t experimental units in each block.• The ability to detect treatment to treatment
differences is dependent on the within block variability.
Comments• The within block variability generally increases
with block size.• The larger the block size the larger the within
block variability.• For a larger number of treatments, t, it may not be
appropriate or feasible to require the block size, k, to be equal to the number of treatments.
• If the block size, k, is less than the number of treatments (k < t)then all treatments can not appear in each block. The design is called an Incomplete Block Design.
Commentsregarding Incomplete block designs
• When two treatments appear together in the same block it is possible to estimate the difference in treatments effects.
• The treatment difference is estimable.
• If two treatments do not appear together in the same block it not be possible to estimate the difference in treatments effects.
• The treatment difference may not be estimable.
Example• Consider the block design with 6 treatments
and 6 blocks of size two.
• The treatments differences (1 vs 2, 1 vs 3, 2 vs 3, 4 vs 5, 4 vs 6, 5 vs 6) are estimable.
• If one of the treatments is in the group {1,2,3} and the other treatment is in the group {4,5,6}, the treatment difference is not estimable.
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Definitions
• Two treatments i and i* are said to be connected if there is a sequence of treatments i0 = i, i1, i2, … iM = i* such that each successive pair of treatments (ij and ij+1) appear in the same block
• In this case the treatment difference is estimable.
• An incomplete design is said to be connected if all treatment pairs i and i* are connected.
• In this case all treatment differences are estimable.
Example• Consider the block design with 5 treatments
and 5 blocks of size two.
• This incomplete block design is connected.
• All treatment differences are estimable.
• Some treatment differences are estimated with a higher precision than others.
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Analysis of unbalanced Factorial Designs
Type I, Type II, Type III
Sum of Squares
Sum of squares for testing an effect
modelComplete ≡ model with the effect in.
modelReduced ≡ model with the effect out.
Reduced Completemodel modelEffectSS RSS RSS
Type I SS
• Type I estimates of the sum of squares associated with an effect in a model are calculated when sums of squares for a model are calculated sequentially
Example
• Consider the three factor factorial experiment with factors A, B and C.
The Complete model
• Y = + A + B + C + AB + AC + BC + ABC
A sequence of increasingly simpler models
1. Y = + A + B + C + AB + AC + BC + ABC
2. Y = + A+ B + C + AB + AC + BC
3. Y = + A + B+ C + AB + AC
4. Y = + A + B + C+ AB
5. Y = + A + B + C
6. Y = + A + B
7. Y = + A
8. Y =
Type I S.S.
2 1model modelABCSS RSS RSS I
3 2model modelBCSS RSS RSS I
4 3model modelACSS RSS RSS I
5 4model modelABSS RSS RSS I
6 5model modelCSS RSS RSS I
7 6model modelBSS RSS RSS I
8 7model modelASS RSS RSS I
Type II SS
• Type two sum of squares are calculated for an effect assuming that the Complete model contains every effect of equal or lesser order. The reduced model has the effect removed ,
The Complete models
1. Y = + A + B + C + AB + AC + BC + ABC (the three factor model)
2. Y = + A+ B + C + AB + AC + BC (the all two factor model)
3. Y = + A + B + C (the all main effects model)
The Reduced models
For a k-factor effect the reduced model is the all k-factor model with the effect removed
2 1model modelABCSS RSS RSS II
2modelABSS RSS Y A B C AC BC RSS II
3modelASS RSS Y B C RSS II
2modelACSS RSS Y A B C AB BC RSS II
2modelBCSS RSS Y A B C AB AC RSS II
3modelBSS RSS Y A C RSS II
3modelCSS RSS Y A B RSS II
Type III SS
• The type III sum of squares is calculated by comparing the full model, to the full model without the effect.
Comments
• When using The type I sum of squares the effects are tested in a specified sequence resulting in a increasingly simpler model. The test is valid only the null Hypothesis (H0) has been accepted in the previous tests.
• When using The type II sum of squares the test for a k-factor effect is valid only the all k-factor model can be assumed.
• When using The type III sum of squares the tests require neither of these assumptions.
An additional Comment
• When the completely randomized design is balanced (equal number of observations per treatment combination) then type I sum of squares, type II sum of squares and type III sum of squares are equal.
Example
• A two factor (A and B) experiment, response variable y.
• The SPSS data file
Using ANOVA SPSS package
Select the type of SS using model
ANOVA table – type I S.S
Tests of Between-Subjects Effects
Dependent Variable: Y
11545.858a 8 1443.232 45.554 .000
61603.201 1 61603.201 1944.440 .000
3666.552 2 1833.276 57.865 .000
809.019 2 404.509 12.768 .000
7070.287 4 1767.572 55.792 .000
760.361 24 31.682
73909.420 33
12306.219 32
SourceCorrected Model
Intercept
A
B
A * B
Error
Total
Corrected Total
Ty pe I Sumof Squares df
MeanSquare F Sig.
R Squared = .938 (Adjusted R Squared = .918)a.
ANOVA table – type II S.S
Tests of Between-Subjects Effects
Dependent Variable: Y
11545.858a 8 1443.232 45.554 .000
61603.201 1 61603.201 1944.440 .000
3358.643 2 1679.321 53.006 .000
809.019 2 404.509 12.768 .000
7070.287 4 1767.572 55.792 .000
760.361 24 31.682
73909.420 33
12306.219 32
SourceCorrected Model
Intercept
A
B
A * B
Error
Total
Corrected Total
Ty pe IISum ofSquares df
MeanSquare F Sig.
R Squared = .938 (Adjusted R Squared = .918)a.
ANOVA table – type III S.S
Tests of Between-Subjects Effects
Dependent Variable: Y
11545.858a 8 1443.232 45.554 .000
52327.002 1 52327.002 1651.647 .000
2812.027 2 1406.013 44.379 .000
1010.809 2 505.405 15.953 .000
7070.287 4 1767.572 55.792 .000
760.361 24 31.682
73909.420 33
12306.219 32
SourceCorrec ted Model
Intercept
A
B
A * B
Error
Total
Correc ted Total
Ty pe IIISum ofSquares df
MeanSquare F Sig.
R Squared = .938 (Adjusted R Squared = .918)a.
Incomplete Block Designs
Balanced incomplete block designs
Partially balanced incomplete block designs
DefinitionAn incomplete design is said to be a Balanced Incomplete Block Design.
1. if all treatments appear in exactly r blocks.• This ensures that each treatment is estimated with
the same precision• The value of is the same for each treatment pair.
2. if all treatment pairs i and i* appear together in exactly blocks.• This ensures that each treatment difference is
estimated with the same precision.• The value of is the same for each treatment pair.
Some IdentitiesLet b = the number of blocks.
t = the number of treatmentsk = the block sizer = the number of times a treatment appears in the experiment. = the number of times a pair of treatment appears together in the same block
1. bk = rt• Both sides of this equation are found by counting the
total number of experimental units in the experiment.
2. r(k-1) = (t – 1)• Both sides of this equation are found by counting the
total number of experimental units that appear with a specific treatment in the experiment.
BIB DesignA Balanced Incomplete Block Design(b = 15, k = 4, t = 6, r = 10, = 6)
Block Block Block 1 1 2 3 4 6 3 4 5 6 11 1 3 5 6
2 1 4 5 6 7 1 2 3 6 12 2 3 4 6
3 2 3 4 6 8 1 3 4 5 13 1 2 5 6
4 1 2 3 5 9 2 4 5 6 14 1 3 4 6
5 1 2 4 6 10 1 2 4 5 15 2 3 4 5
An Example A food processing company is interested in comparing the taste of six new brands (A, B, C, D, E and F) of cereal.
For this purpose: • subjects will be asked to taste and compare these
cereals scoring them on a scale of 0 - 100. • For practical reasons it is decided that each subject
should be asked to taste and compare at most four of the six cereals.
• For this reason it is decided to use b = 15 subjects and a balanced incomplete block design to assess the differences in taste of the six brands of cereal.
The design and the data is tabulated below:
Subject Taste Scores (Brands)
1 51 (A) 55 (B) 69 (C) 83 (D) 2 48 (A) 87 (D) 56 (E) 22 (F) 3 65 (B) 91 (C) 67 (E) 35 (F) 4 42 (A) 48 (B) 65 (C) 43 (E) 5 36 (A) 58 (B) 69 (D) 7 (F) 6 79 (C) 85 (D) 56 (E) 25 (F) 7 54 (A) 60 (B) 90 (C) 21 (F) 8 62 (A) 92 (C) 94 (D) 63 (E) 9 39 (B) 71 (D) 47 (E) 11 (F) 10 51 (A) 59 (B) 84 (D) 51 (E) 11 39 (A) 74 (C) 61 (E) 25 (F) 12 69 (B) 78 (C) 78 (D) 22 (F) 13 63 (A) 74 (B) 59 (E) 32 (F) 14 55 (A) 74 (C) 78 (D) 34 (F) 15 73 (B) 83 (C) 92 (D) 68 (E)
Analysis for the Incomplete Block Design
Recall that the parameters of the design where b = 15, k = 4, t = 6, r = 10, = 6
Block Totals j 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 G
Bj 258 213 258 198 170 245 225 311 168 245 199 247 228 241 316 3522
Treat Totals and Estimates of Treatment Effects
Treat Treat Total (Ti) j(i) Bj/k Diff = Qi Treat Effects (i)
(A) 501 572 -71 -7.89 (B) 600 578.25 21.75 2.42 (C) 795 624.5 170.5 18.94 (D) 821 603.5 217.5 24.17 (E) 571 595.25 -24.25 -2.69 (F) 234 548.5 -314.5 -34.94
)(ij denotes summation over all blocks j containing treatment i.
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Qii
Anova Table for Incomplete Block Designs Sums of Squares
yij2 = 234382
Bj2/k = 213188
Qi2 = 181388.88
Anova Sums of Squares
SStotal = yij2 –G2/bk = 27640.6
SSBlocks = Bj2/k – G2/bk = 6446.6
SSTr = (Qi2 )/(r – 1) = 20154.319
SSError = SStotal - SSBlocks - SSTr = 1039.6806
Anova Table for Incomplete Block Designs
S o u r c e S S d f M S F
B l o c k s 6 4 4 6 . 6 0 1 4 4 6 0 . 4 7 1 7 . 7 2 T r e a t 2 0 1 5 4 . 3 2 5 4 0 3 0 . 8 6 1 5 5 . 0 8 E r r o r 1 0 3 9 . 6 8 4 0 2 5 . 9 9
T o t a l 2 7 6 4 0 . 6 0 5 9
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