induction in pascal’s triangle - university college cork...induction in pascal’s triangle...
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Induction in Pascal’s Triangle
Pascal’s Formula, The Hockey Stick, The Binomial Formula, Sums
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Count the rows in Pascal’s triangle starting from 0. The entry on the n-th horizontal row, and k-th slanted row in Pascal’s triangle:
= number of ways to choose a set of k objects from among n given objects.
5th horizontal row
2nd slanted row 1 1
1 2 1
1
1
1
1
1
1
3 3
4 6 4
5 5 10 10
1
row 0
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Write the suitable or notations besides each entry in Pascal’s
triangle
1 1
1 2 1
1
1
1
1
1
1
3 3
4 6 4
5 5 10 10
1
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=
= =
= = =
=
=
=
=
=
=
= =
= = =
= = = =
1 1
1 2 1
1
1
1
1
1
1
3 3
4 6 4
5 5 10 10
1
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Practice with the formula
Useful note: there are as many factors above as under the quotient line. Calculate these numbers using the formula, then locate them in the triangle.
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Recall: Pascal’s formula:
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Pascal’s formula Combinatorial proof:
Suppose there are n+1 people in your class. In how many ways can a group of k+1 people be chosen?
Ways to choose a random group of k+1 people
Ways to choose a group of k+1 people if you’re not included
Ways to choose a group of k+1 people if you’re included (it remains to choose k other people from among your n classmates)
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The Hockey Stick Formula
Write down each of the numbers in the yellow line as What can you say about the sum? Can you explain your result based on Pascal’s formula?
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The Hockey Stick Formula
Sum up the 2nd slanted row:
row 0
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The Hockey Stick Formula is true for any n>1. Proof by Induction: We check the formula for small hockey sticks and then build larger hockey sticks step by step:
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The Hockey Stick Formula Step 1:
(1+3)+6=4+6=10
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The Hockey Stick Formula
Step 2: (1+3+6)+10=10+10=20
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The Hockey Stick Formula
Step 3: (1+3+6+10)+15=20+15=35
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After a while it gets boring... So let’s skip some unknown number of steps, to for some n. Presumably if we were patient enough, we could have reached this step by step, so we assume that the formula is true for this number n. Can we prove the formula at the next step, when n gets replaced by n+1? If we can do this for any random n, then the formula is always true! ... Because we can reach any natural number, no matter how large, by a sequence of consecutive steps.
1, 2, skip a few, .... , n, n+1
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The Hockey Stick Formula: Induction step:
....................................................................................................................................
If Then
We use Pascal’s formula here.
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Recap Induction:
-We checked the first few steps till we saw a pattern. -We assumed the formula true for n. -We proved the formula for n+1.
Once we understood the pattern, the last step was just a formality: All we had to do was figure out the correct notations. However, this step is necessary in order to convince ourselves (and others) that the pattern works forever, that it doesn’t break down after finitely many steps.
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The Hockey Stick Formula
Formulate other Hockey Stick type rules. Prove them by Induction.
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The Binomial Formula The entries in the n-th row of Pascal’s Triangle are exactly
the numbers coming up in the long form of
Does this pattern hold forever and why?
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Proof: by Induction. Main tool: Distributivity:
The Binomial Formula
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The expansion of
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The expansion of
Short form Long form
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The highlighted numbers are generated by the same rule as in Pascal’s triangle.
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We multiply the last row by so as to get
=
Assuming:
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The highlighted numbers are generated by the same rule as in Pascal’s triangle.
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We use Pascal’s formula for each k. We obtain the entries in the (n+1)-th row of Pascal’s triangle. We thus proved that the binomial formula also works for
=
Assuming:
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The Binomial Formula
Combinatorial Proof:
There are ways to choose k copies of x from among the n brackets. For each
such choice we get a term of the form
Pick one letter from each bracket to form a product of n letters. Sum up all product formed in this way.
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Sums
This is the n-th triangular number
Use the 2x Hockey Stick formula:
Use the 3x Hockey Stick formula:
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Sums
Check this formula in three ways:
1. By Induction. 2. Use =
Then use the sum formulas on the previous page.
3.
Add these up by columns and cancel cubes.
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