institute of aeronautical engineering - · pdf file · 2016-04-30institute of...

INSTITUTE OF AERONAUTICAL ENGINEERING (Autonomous)

Dundigal Hyderabad -500 043

CIVIL ENGINEERING

TUTORIAL QUESTION BANK

2015 - 2016

Course Name STRUCTURAL ANALYSIS -I

Course Code A40115

Class II B Tech II Semester

Branch Civil Engineering

Year 2015 ndash 2016

Course Faculty Ms K Varsha Reddy Assistant Professor

OBJECTIVES

To meet the challenge of ensuring excellence in engineering education the issue of quality needs to be

addressed debated and taken forward in a systematic manner Accreditation is the principal means of quality assurance in higher education The major emphasis of accreditation process is to measure the

outcomes of the program that is being accredited

In line with this Faculty of Institute of Aeronautical Engineering Hyderabad has taken a lead in incorporating philosophy of outcome based education in the process of problem solving and career

development So all students of the institute should understand the depth and approach of course to be

taught through this question bank which will enhance learnerrsquos learning process

1 To introduce design concept and process of structures

2 To review analysis of statically determinate structures

3 To understand the deformations of structures under loading 4 To introduce flexibility method for analysis of statically indeterminate structures

5 To introduce stiffness method for analysis of statically indeterminate structures

PART ndash A (SHORT ANSWER QUESTIONS)

S No Question Blooms Taxonomy

Level Program Outcome

UNIT ndash I

1 Define static indeterminacy Remember 1

2 Explain different types of indeterminacies Remember 1

3 Explain internal indeterminacy Understanding amp

Remember 1

4 Define Tension Coefficient Understanding amp

Remember 1

5 State Kinematic indeterminacy Understanding amp 1



Remember

6 Write different methods for computing deflection of determinate beam Understanding amp

Remember 1

7 Define Internal Stability Understanding amp

Remember 1

8 What are the different types of frames based on stability Understanding amp

Remember 1

9 What are the different types of frames and explain the same with neat diagrams

Understanding amp Remember

1

10 Define External stability Understanding amp

Remember 1

11 Define Degree of Indeterminacy Remember 1

12 What is equilibrium condition Remember 1

13

To find degree of indeterminacy of structures as given below

Remember

1

14


Remember

1

15 Differentiate between method of joints amp method of sections Remember 1

16 Explain a pin-jointed frame with a sketch Remember 1

17 Define a redundant force Remember 1

18 What is a portal frame Remember 1

19 What are the assumptions made in finding out the forces in a frame Remember 1

20 Explain briefly about tension coefficient method Remember 1

UNIT ndash II

1 Define term deflection of a beam Remember 1

2 State conjugate beam theorem Remember 1

3 Write relation between load shear force and bending moment acting on a structure


1

4 State moment area theorems Understanding amp

Remember 1

5 Define strain energy Understanding amp

Remember 1

6 State the castaglianos theorem Understanding amp

Remember 1

7 A steel rod has a square cross section of 10mm x 10mm and a length of 2M Calculate strain energy when a stress of 400 Mpa is produced by stretching it Take E = 200 Gpa

Analyze and evaluate 12

8 Calculate Strain energy due to shear stress for a member which has a length of 05M 120mm Diameter and a pull of 5KN Take E = 200 Gpa


9 What is the temperature effect on three hinged arches Understanding amp

Remember 1

10 How three hinged arch is different from two hinged arch and explain it Understanding amp 1



Remember

11 What are temperature stresses Explain Remember 1

12 Define Force Work energy Remember 1

13 State Eddyrsquos Theorem Remember 1

14 What is degree of static indeterminacy of a three hinged and two hinged arch


1

15 Give expression for strain energy due to axial force Understanding amp

Remember 1

16 Give expression for strain energy due to bending moment Understanding amp

Remember 1

17 Give expression for strain energy due to shear deformation Understanding amp

Remember 1

18 Define radial shear and normal thrust Remember 1

19 Give the equation for a parabolic arch whose springing is at different levels


1

20 Define linear arch Understanding amp

Remember 1

UNIT ndash III

1 What are the reaction values for propped cantilever beam when it carries point load

Remember 1

2 Calculate maximum bending moment for a propped cantilever beam which carries a udl of 10Knm for a span of 2m


3 Calculate point of contra flexure for propped cantilever beam has a 4m length carries point load of 20KN at free end


4 Difference between cantilever beam and propped cantilever beam Understanding amp

Remember 1

5 Calculate deflection at mid span for a propped cantilever beam of load 10Knm for a span of 4m


6 What is the effect of sinking of support for fixed beam Understanding amp

Remember 1

7 What is effect of rotation Analyze and evaluate 1

8 Calculate slope and deflection for a fixed beam of load 10Knm for a span of 4m


9 Difference between propped cantilever beam and fixed beam Understanding amp

Remember 1

10 A fixed beam of length 3m is subjected to two point loads 9KN at the middle third point Calculate Bending moment at the fixed end


11 What is a propped cantilever Remember 1

12 What is a Fixed beam Remember 1

13 What are the reaction values for propped cantilever beam when it carries uniformly distributed load

Remember 12

14 What is point of contra flexure Understanding amp

Remember 1

15 Define prop Remember 1

16 What are the reaction values for fixed beam when it carries point load


12

17 What are the reaction values for fixed beam when it carries uniformly distributed load


1

18 Define deflection Remember 1

19 Define slope Remember 1

20 Give boundary conditions for a propped cantilever beam Understanding amp 1



Remember

UNIT ndash IV

1 State Clapeyronrsquos three moment theorem and write equation also Remember 1

2 What is the effect of sinking of support in Three moment theorem Remember 1

3 Explain Continuous beam with neat diagram Understanding amp

Remember 1

4 Derive Slope deflection equation in continuous beam Understanding amp

Remember 1

5 What is the effect of sinking of support in slope deflection method Understanding amp

Remember 1

6 Define stiffness and relative stiffness of a member with different far end conditions


1

7 Define Carry over factor Understanding amp

Remember 1

8 Define Distribution factor and its importance at fixed end and simply support end


1

9 Define Elastic curve Understanding amp

Remember 1

10 Importance of Elastic curves in beams Understanding amp

Remember 1

11 Write down the equilibrium equations used in slope deflection method


1

12 What is the basic assumption made in slope deflection method Understanding amp

Remember 1

13 What is the moment at a hinged end of a simple beam Understanding amp

Remember 1

14 Write down the slope deflection equation for fixed end support Understanding amp

Remember 1

15 What are the quantities in terms of which the unknown moments are expressed in slope deflection method

Remember 1

16 Say true or false and if false justify your answer ldquoslope deflection method is a force methodrdquo


1

17 What are the reasons for sway in portal frames Understanding amp

Remember 1

18 What are the sign conventions used in slope deflection method Remember 1

19 State the limitations of slope deflection method Understanding amp

Remember 1

20 Write the fixed end moments for a beam carrying a central clockwise moment

Remember 1

UNIT ndash V Understanding amp Remember

1 Explain the term ldquoFocal Lengthrdquo Understanding amp

Remember 1

2 Define Influence Line Understanding amp

Remember 1

3 List out the uses of Influence lines Understanding amp

Remember 1

4 State Muller Breslau‟s Principle Understanding amp

Remember 1

5 Where do you get rolling loads in practice Understanding amp

Remember 1

6 What is meant by absolute maximum bending moment in a beam Understanding amp

Remember 1



7 Where do you have the absolute maximum bending moment in a simply supported beam when a series of wheel loads cross it


1

8 What do you understand by the term reversal of stresses Understanding amp

Remember 1

9 State the location of maximum shear force in a simple beam with any kind of loading


1

10 What is the absolute maximum bending moment due to a moving udl longer


1

11 State Maxwell-Betti‟s theorem Understanding amp

Remember 1

12 What is meant by maximum shear force diagram Understanding amp

Remember 1

13 State the location of maximum shear force in a simple beam wit h any kind of loading


1



1

15 Name the type of rolling loads for which the absolute maximum bending moment occurs at the mid span of a beam


1


Remember 1

17 What is the absolute maximum bending moment due to a moving udl longer than the span of a simply supported beam


1


Remember 1

19 Draw influence lines for support reactions in a simply supported beam Understanding amp

Remember 1

20 What do you understand by an influence line for bending moment Understanding amp

Remember 1

PART ndash B (PROBLEM SOLVING AND CRITICAL THINKING QUESTIONS)

S No Question Blooms Taxonomy Level

Program Outcome

UNIT ndash I

1 Differentiate between pin-jointed and rigid jointed plane frames Understanding amp Analyze

12

2 Using method of Tension Coefficient analysis determine the forces in the members of the plane truss shown in fig

Analyze and evaluate

1234

3 Fig shows the plan of a tripod the feet P Q R being in the horizontal plan and the apex S being 4m above the plane Horizontal loads of 125kN and 200kN are applied at D as shown Find the forces in all the members assuming that all the joints are pin joints


1234


Program Outcome

4 Analyze the plane truss shown in figure using the method Tension

Coefficients and find the forces in the members


1234

5 Using the Method of joints the cantilever plan truss shown in figure Find the member forces


1234

6 Calculate the forces in members of pin jointed space truss shown in figure using Tension Coefficient method


1234

7 Each bar of the truss shown in fig 2 has a cross section of 625mm2 Calculate the horizontal deflection of the joint C use method of joints


1234


Program Outcome

8 A portal frame ABCD is hinged at AampD and has rigid joints The frame is

loaded as shown in Fig Analyze the frame using minimum strain energy method Plot the bending moment diagram


1234

9 Determine the vertical and horizontal deflections of the free end of the lamp post shown in fig 1 Take EI = 16000kN- m2


1234

10 Determine the vertical and horizontal deflection at the free end of the bent shown in fig 4 Use the unit load method Assume uniform flexural rigidity EI throughout


1234

11 Determine the force in the members of the truss shown in figure The cross sectional area of vertical and horizontal members is 4000mm2 and that of the diagonal is 6000 mm2 Use method of joints


1234


Program Outcome

12

Find the forces in the members of truss shown in figure The cross sectional area and youngrsquos modulus of all the members are the same Use method of joints


1234

13

Find the forces developed in all the members of truss shown in fig if the temperature of member AC goes up by 20degc Take the co efficient of thermal expansion α=12X10-6degc Cross sectional area of all the members is 2500mm2 and youngrsquos modulus is 200KNmm2 Use method of joints


1234

14

Determine the force in the members of the truss shown in figure The cross sectional area of vertical and horizontal members is 4000mm2 and that of the diagonal is 6000 mm2 Use method of sections


1234

15 Find the forces in the members of truss shown in figure The cross sectional area and youngrsquos modulus of all the members are the same Use method of sections


1234


Program Outcome

16

Find the forces developed in all the members of truss shown in fig if the temperature of member AC goes up by 20degc Take the co efficient of thermal expansion α=12X10-6degc Cross sectional area of all the members is 2500mm2 and youngrsquos modulus is 200KNmm2 Use method of sections


1234

17

Determine the force in the members of the truss shown in figure The cross sectional area of vertical and horizontal members is 4000mm2 and that of the diagonal is 6000 mm2 Use tension coefficient method


1234

18

Find the forces in the members of truss shown in figure The cross sectional area and youngrsquos modulus of all the members are the same Use tension coefficient method


1234

19

Find the forces developed in all the members of truss shown in fig if the temperature of member AC goes up by 20degc Take the co efficient of thermal expansion α=12X10-6degc Cross sectional area of all the members is 2500mm2 and youngrsquos modulus is 200KNmm2 Use tension coefficient method


1234


Program Outcome

20

A two span continuous truss is loaded as shown All the members are of the same material and have the same cross sectional area Find the reaction at the central support C also find the forces in all the members AB BF FG HI GI GD of the truss


1234

UNIT - II

1 A circular three hinged arch of span 25m with a central rise of 5m is hinged at the crown and the end supports It carries a point load of 100 kN at 6m from the left support Calculate i The reaction at the supports ii Moment at 5m from the left support

Apply Analyze and evaluate

1234

2 A three hinged circular arch of span 16m and rise 4m is subjected to two point loads of 100 kN and 80 kN at the left and right quarter span points respectively Find the reaction at the supports Find also the bending moment radial shear and normal thrust at 6m from left support


1234

3 A symmetrical three hinged arch has a span of 50 amp rise 5m Find the maximum bending moment at a quarter point of the arch caused by a uniformly distributed load of 10kNm which occupies any portion of the span Indicate the position of the load for this condition


1234

4 A three hinged parabolic arch of span 30m and rise 5m carries a uniformly distributed load of 40kN per meter on the whole span and a point load of 200kN at a distance of 5m from the right end Find the horizontal thrust resultant reaction bending moment and normal thrust at a section 5m from the left end


1234

5 A three hinged parabolic arch has supports at different levels having span 20m and carries a UDL of 30kNm over the left half of the span The left support is 5m below the crown and the right support is 4m below the crown Draw the BMD Also find the normal thrust and radial shear at a section 4m from the left support


1234

6 Explain briefly about strain energy in elastic system Analyze and evaluate

1234

7 Derive expression for strain energy Analyze and evaluate

1234

8 Derive expression for strain energy due to axial load Analyze and evaluate

1234

9 Derive expression for strain energy due to bending Analyze and 1234


Program Outcome

evaluate

10 Derive expression for strain energy due to shear deformation Analyze and evaluate

1234

11 Explain unit load method Analyze and

evaluate 1234

12 Write short notes on strain energy Analyze and

evaluate 1234

13 Calculate the deflection at centre o a simple beam ACB subjected to varying load of zero from A to w kNm at C and zero at B Take EI as constant


1234

14 Define arch What are the applications of arches Analyze and

evaluate 1234

15 Explain the different types of arches Analyze and

evaluate 1234

16 State and explain eddyrsquos theorem Analyze and

evaluate 1234

17 Write short notes on analysis of three hinged arches Analyze and

evaluate 1234

18 Explain about linear arch Analyze and

evaluate 1234

19 Why is a arch preferred over a straight beam Explain Analyze and

evaluate 1234

20 Explain why the moment is zero at all points in a three hinges parabolic arch


1234

UNIT - III

1 A cantilever of length 10 m carries udl of 800Nm length over the whole length The free end of the cantilever is supported on a prop The prop sinks by 5mm If E=3X105Nmm2 and I=10 8 mm 4 then the prop reaction

Understanding Analyze amp Evaluate

1234

2 A cantilever of length 8m carries udl of 2Knm run over the whole length The cantilever is propped rigidly at the free end If E=1X105Nmm2 and I=10 8 mm 4 then determine reaction at the rigid prop and deflection at the center


1234

3 A cantilever of length 5m carries a point load of 24kn at its center The cantilever is propped rigidly at the free end Determine the reaction at the rigid prop


1234

4 A cantilever of length 4m carries a UDL of 1Knm run over the whole span length The cantilever is propped rigidly at the free end If the value of If E=2X105Nmm2 and I=10 8 mm 4 Determine the reaction at the rigid prop and deflection at the center


1234

5 A cantilever of length 8 m carries UDL of 08Knm length over the whole length The free end of the cantilever is supported on a prop The prop sinks by 5mm If E=2X105Nmm2 and I=10 8 mm 4 then the prop reaction


1234

6 A fixed beam AB 5m long carries a point load of 48kn at its center the moment of inertia of the beam is 5x107 mm4 and value of E for the beam materials is 2x105 Nmm2 Determine Fixed end moments at A and B and Deflection under the load


1234

7 A fixed beam of length 5m carries a point load of 20KN at a distance of Analyze and 1234


Program Outcome

2m from A Determine the fixed end moments and deflection under the load if the flexural rigidity of the beam is 1x104 Knm2

evaluate

8 A fixed beam of length 6m carries point loads of 20kn and 15kn at distance 2m and 4m from the left end A Find the fixed end moments and the reactions at the supports Draw BM and SF diagrams


1234

9 A fixed beam of length 3m carries tow point loads of 30kn each at a distance of 1m from both ends Determine the fixing moments and draw BM diagram


1234

10 A fixed beam AB of length 6m carries a uniformly distributed load 3knm over the left half of the span together with a point load of 4kn at a distance of 45m from the left end Determine the fixing end moments and support reactions


1234

11 A fixed beam of span lsquoLrsquo is subjected to UDL throughout wm What is end moments and moment at the centre


1234

12 Draw SFD and BMD for a propped cantilever beam span lsquoLrsquo subjected to UDL throughout wm


1234

13 Draw SFD and BMD for a propped cantilever beam span lsquoLrsquo subjected to point load at free end


1234

14 Draw the SF and BM Diagrams (qualitative) of a fixed beam of L m long carries a point load W at the midpoint


1234

15

For the propped cantilever shown in fig Calculate the BM


1234

16 A cantilever of length 6m carries a point load of 48 kN at its centre The cantilever is propped rigidly at the free end Determine the reaction at the rigid prop


1234

17 A fixed beam AB of length 6m carries point loads of 160 kN and 120kN at a distance of2m and 4m from the left end A Find the fixed end moments and the reactions at the supports Draw BM and SF diagrams


1234

18

A fixed beam of 8m span carries a UDL of 40 kNm run over 4m length starting from left end and a concentrated load of 80kN at a distance of 6m from the left end Find

i Moments at the supports

ii Deflection at centre of the beam

Take EI = 15000 kNm2


1234

19 A fixed beam of 6m length is loaded with two equal point loads of 150kN each at distance of 2m from each support Draw the BMD and SFD E = 2 x 108 kNm2 I = 8 x 108 mm4


1234

20

A fixed beam of span 8 m carries an udl of 2 kNm over a length of 4 m from the left support and a concentrated load of 10 kN at a distance of 6m from the left support Find the fixed end moments and draw the BM and SF diagrams


1234

UNIT - IV


Program Outcome

1 A 3-span continuous beam ABCD has fixed end supports On end span AB= 6m there is udl of 20 kNm while on CD = 5 m there is a point load of 80 kN at mid span on the central span BC = 5 m there is a point load of 50kN at 3m from B If the moment of inertia of BC is twice that of AB and CD analyse by moment distribution method and sketch the BMD

Analyze amp evaluate

1234

2 If support B of the continuous beam of Question No 1 settles by 30 mm obtain the support moments by slope deflection method taking I = 400 cm4 and E= 2times105 Nmm2 Sketch the BMD


1234

3 Using Slope Deflection method obtain the support moments for the 2-span continuous beam shown below Sketch BMD


1234

4 Using Claperoyn‟s method finds the support movements for the 2-span continuous beam loaded as shown below figure 2 Sketch the BMD


1234

5 Using moment distribution method analyse the 2-span continuous beam ABC having end supports A and C fixed There is a load of 5 kN in span AB=5 m at 3 m from A while on span BC there is a load of 8 kN at 25 m from C Sketch the BMD


1234

6 If the end spans A and C of the beam given in Question No2 are simply supported analyse using slope deflection method Sketch the BMD


1234

7 Analyze two span continuous beam ABC in which support B sinks by 5mm by slope deflection method Then draw Bending moment amp Shear force diagram Take EI constant and draw Elastic curve


1234

8 Analyze continuous beam ABCD by slope deflection method and then draw bending moment diagram Take EI constant


1234


Program Outcome

9 Analyse the continuous beam ABCD shown in figure by slope deflection

method The support B sinks by 15mm Take E=200x105 KNm2 and I=120x106m4


1234

10 Three span continuous beam ABCD is fixed at A and continuous over B C and D The beam subjected to loads as shown Analyse the beam by slope deflection method and draw bending moment and shear force diagram


1234

11

A Continuous beam ABCD fixed at A and D and continuous over supports B and C The span AB=5m carries a central concentrated load of 10kN The span BC=4m carries a uniformly distributed load of 4 kNm over the entire span of BC The span CD=6m carries a non central concentrated load of 8 kN acting at a distance of 2m from the end D Analyze the beam and draw bending moment diagram using slope deflection method


1234

12

A Continuous beam ABCD fixed at A and D and continuous over supports B and C The span AB=5m carries a central concentrated load of 10kN The span BC=4m carries a uniformly distributed load of 4 kNm over the entire span of BC The span CD=6m carries a non central concentrated load of 8 kN acting at a distance of 2m from the end D Analyze the beam and draw bending moment diagram using moment distribution method


1234

13

A continuous beam ABC consist of span AB=3m and BC=4m the ends A and C being fixed AB and BC carry uniformly distributed loads of intensity 4kNm and 5kNm respectively Find the support moments and draw the bending moment diagram for the beam using slope deflection method The beam is of uniform section throughout


1234

14

A continuous beam ABC consist of span AB=3m and BC=4m the ends A and C being fixed AB and BC carry uniformly distributed loads of intensity 4kNm and 5kNm respectively Find the support moments and draw the bending moment diagram for the beam using moment distribution method The beam is of uniform section throughout


1234

15 Analyze the beam shown in fig by slope deflection method and draw the SFD and BMDEI=Constant


1234


Program Outcome

16

Analyze the beam shown in fig by moment distribution method and draw the SFD and BMDEI=Constant


1234

17

Analyze the continuous beam ABCD shown in fig by slope deflection method Take EI=Constant Also sketch the shear force and Bending Moment diagram


1234

18

Analyze the continuous beam ABCD shown in fig by moment distribution method Take EI=Constant Also sketch the shear force and Bending Moment diagram


1234

19

Analyze the continuous beam shown in fig by slope deflection method Support B settles by 8mm and C settles by 12 mm I=60000cm4 E=210x106kNm2Draw the SFD and BMD


1234

20

Analyze the continuous beam shown in fig by moment distribution method Support B settles by 8mm and C settles by 12 mm I=60000cm4 E=210x106kNm2Draw the SFD and BMD


1234

UNIT - V

1 Two point loads of 125kN and 250kN spaced 4m in figure 1 apart cross a girder of 175m from left to right with the 125kN load leading Draw the influence line for the bending moment and find the value of maximum bending moment at a section C 75m from the left hand support Also find the absolute maximum bending moment due the given load system

Understanding amp Analyze

1234


Program Outcome

Figure 1

2 Four wheel load of 759 amp 6 kN cross a girder of span 225m from the left to right followed by an UDL of 5kNm of 4m length The 7kN load is leading The spacing between the loads are shown in fig 2 The head of UDL is 3m from the last load of 6kN Using influence lines calculate the shear force and bending moment at a section 8m form the left support when the 5kN load is at the center of span

Figure 2


1234

3 Draw the influence line diagrams for the forces in the members P Q amp R of the truss shown in fig 3

Figure 3


1234

4 Draw the influence lines for the members U1U2 L2L3 U3L3 amp U4L4 of the deck type girder shown in figure 4


1234

5 Sketch the influence line diagram for SF and B M at 4 m from the left end of a simply-supported girder of span 10 m Hence find the maximum SF and maximum BM at the section if two wheel loads of 8 kN and 16 kN spaced 2 m apart move from left to right


1234

6 Illustrate the procedure to find the forces in the members of a Pratt truss due to moving loads using the influence line diagrams


1234

7 A UDL of intensity 10 kNm and 4 m long crosses a simply supported girder of 12 m span Sketch the IL diagrams for SF and BM at 13


1234


Program Outcome

span Hence find the maximum SF and BM at the section Find also the absolute maximum SF and BM

8 A UDL of intensity 20 kNm and 5 m long crosses a simply supported girder of 15 m span Sketch the IL diagrams for SF and BM at mid span Hence find the maximum SF and BM at the section Find also the absolute maximum SF and BM


1234

9 Sketch the influence line diagram for SF and B M at 5 m from the right end of a simply-supported girder of span 15 m Hence find the maximum SF and maximum BM at the section if two wheel loads of 10 kN and 18 kN spaced 4 m apart move from left to right


1234

10 Four wheel load of 4 6 8 6 and 4 kN cross a girder of span 25m from the left to right The 10 kN load is leading The spacing between each load is 25m Using influence lines calculate the shear force and bending moment at a section 8m form the left support when the 8 kN load is at the center of span


1234

11

A system of four loads 80 160 160 and 120 kN crosses a simply supported beam of span 25m with the 120 kN load leading The loads are equally spaced at 1m Determine the values of the following using influence lines

i Maximum bending moment at a section 10m from left support and

ii ii Absolute maximum shear force and bending moment in the beam


1234

12

A beam has a span of 24m draw the influence line diagram for the bending moment and shear force at a section 8m from the left and also determine maximum bending moment and shear force at this section due to two point loads of 10kN and 6kN at a fixed distance of 2m apart rolling from left to right with 6kN load leading


1234

13

A simply supported beam has a span of 16mis subjected to a UDL(dead load) of 5kNm and a UDL(live load) of 8kNm (longer than the span) travelling from left to right Draw the ILD for shear force and bending moment at a section 4m from left end Use these diagrams to determine the maximum shear force and bending moment at this section


1234

14 Draw the influence line for MB for the continuous beam ABC simply supported at A and C using Muller Breslau`s principle AB=3m BC=4mEI is constant


1234

15 Draw the influence line diagram for the propped reaction of a propped cantilever beam having span 6m EI=Constant


1234

16

Determine the influence line diagram for bending moment at a point D the middle point of span AB of a continuous beam ABC of span AB=6m and BC=4m simply supported at supports AB and C Compute the ordinates at every 1m interval


1234

17

The warren girder of 25m span is made of 5 panels of 5m each The diagonals are inclined at 60deg to the horizontal Draw the influence line diagram for force in upper chord member in the second panel from left Hence evaluate the forces in it when there is load of 60 kN at each lower joint


1234

18 Draw the influence line for RA for the continuous beam ABC of span AB = BC = 4m simply supported at A B ampC Compute the ordinates at every 1m interval EI = constant


1234


Program Outcome

19





1234



1234

PART ndash C (ANALYTICAL QUESTIONS)


Program Outcome

UNIT ndash I

1 What are the different methods for analysis of Frames Write the assumptions made in analyzing perfect frame

Understanding 12

2 Determine the forces in the members of the cantilever truss shown in fig method of joints


2345

3 For the truss shown in Fig Determine reactions at the two supports P and Q and forces in the members using method of joints


2345

4 Find the forces in the members of truss shown in fig using method of joints


2345


Program Outcome

5 In the cantilever truss shown in fig Calculate reaction at A using method

of joints


2345

6 Calculate force in the member BC for truss shown in fig


2345

7 Determine the forces in all the members of a truss shown in fig below by method of joints


2345


Program Outcome

8 Find the force in all members of the truss shown in Figure 1255 by

method of joints


2345

9 Determine the forces in all the members of a truss shown in fig below by method of sections


2345

10 Find the force in all members of the truss shown in Figure 1255 by method of sections


2345


Program Outcome

11

Determine the forces in the members of the cantilever truss shown in fig method of sections


2345

12

For the truss shown in Fig Determine reactions at the two supports P and Q and forces in the members using method of sections


2345

13

Find the forces in the members of truss shown in fig using method of sections


2345

14 In the cantilever truss shown in fig Calculate reaction at A using method of sections


2345


Program Outcome

15

Determine the forces in the members of the cantilever truss shown in fig using tension coefficient method


2345

16

For the truss shown in Fig Determine reactions at the two supports P and Q and forces in the members using tension coefficient method


2345

17 Find the forces in the members of truss shown in fig using tension coefficient method


2345


Program Outcome

18

In the cantilever truss shown in fig Calculate reaction at A using tension coefficient method


2345

19

Determine the forces in all the members of a truss shown in fig below by tension coefficient method


2345

20

Find the force in all members of the truss shown in Figure 1255 by tension coefficient method


2345


Program Outcome

UNIT - II

1 The strain energy due to bending in the cantilever beam shown in fig


2345

2 The strain energy stored in member AB of the pin joined truss shown in fig


2345

3 A simply supported beam of span ldquolrdquo and flexural rigidity bdquoEI‟ carries a unit point load at its center What is the strain energy in the beam due to bending


2345

4 Calculate the strain energy stored in a simply supported beam of span bdquol‟ and flexural rigidity bdquoEI‟ due to central concentrated load bdquoW‟


2345

5 If the strain energy absorbed in a cantilever beam in bending under its own weight is bdquoK‟ times greater then the strain energy absorbed in an identical simply supported beam in bending under its own weight the then what could be the magnitude


2345

6 A three hinged arch is shown in fig Calculate horizontal thrust


2345

7 A three hinged arch parabolic arch ABC has a span o 20m and central rise of 4m The arch has hinges at the ends and at the center A train of two point loads of 20Kn and 10Kn 5m apart crosses this arch from left to right with 20Kn load leading Calculate maximum thrust induced at the support


2345

8 For the three hinged parabolic arch shown in fig what is the value of horizontal thrust


2345


Program Outcome

9 Calculate horizontal thrust at support bdquoA‟ in a three hinged arch shown

in fig


2345

10 A three hinged semicircular arch of radius R carries a uniformly distributed load W per unit run over the whole span What will be the horizontal thrust


2345

11 An axial pull of 40 kN is suddenly applied to a steel rod 2m long and 1000mm2 in cross section Calculate the strain energy that can be absorbed if E = 200 GNm2


2345

12

A cantilever of rectangular section breadth b depth d and of length l carries uniformly distributed load spread from free end to the mid section of the cantilever Using Castiglianorsquos theorem find Slope and deflection due to bending at the free end


2345

13 A beam 4m in length is simply supported at the ends and carries a uniformly distributed load of 6 kNm length Determine the strain energy stored in the beam Take E = 200 GPa and I = 1440 cm4


2345

14

A beam simply supported over a span of 3m carries a UDL of 20 kNm over the entire span The flexural rigidity EI = 225 MNm2 Using Castiglianorsquos theorem determine the deflection at the centre of the beam


2345

15

For the beam shown in fig find the slope and deflection at lsquoCrsquo


2345

16

For the truss shown in fig find the total strain energy stored

E 2 times 105 Nmm2 Area AB 100 mm2 BC 100 mm2

AC 80 mm2


2345


Program Outcome

17 Compare the bending moments of a three hinged arch ACB of span L rise h hinged at crown C and carrying a point load P at a distance L4 from A with a straight beam carrying same load


2345

18 Show that the bending moment of a three hinged parabolic arch carrying a uniformly distributed load is zero at any cross section


2345

19

A three hinged circular arch of span 20m and rise 5m is subjected to two point loads of 150 kN and 100 kN at the left and right quarter span points respectively Find the reaction at the supports Find also the bending moment radial shear and normal thrust at 8m from left support


2345

20

A symmetrical three hinged arch has a span of 60 amp rise 6m Find the maximum bending moment at a quarter point of the arch caused by a uniformly distributed load of 15kNm which occupies any portion of the span Indicate the position of the load for this condition


2345

UNIT - III

1 A cantilever ABC of length is fixed at the end A and is simply supported at an intermediate support B The cantilever carries a uniformly distributed load wunit length over the whole span Determine the position of the support B so that reactions at A and B are equal


2345

2 A beam AB of length L simply supported at the ends and propped at mid span carries a udl of w per unit length Calculate the prop reaction and plot the bending moment diagram


2345

3 A cantilever of uniform cross section carries a udl wunit length What upward force must be applied at the end to reduce the deflection there to zero


2345

4 For the propped beam shown in Fig Determine the reaction R and sketch the shear force and bending moment diagrams


2345

5 A 5m long fixed beam AB is hinged at the point H 3M from the end A thus forming two concentrated cantilever AH and BH A load of 86Kn acts at a distance of 2m from the left end A Find the reaction at the hinge and the fixing moments at A and B Takes IAH=2IBH


2345

6 A fixed-ended beam of 9m span carries udl of 15Knm (including its own weight) and two pint loads of 200kn at the third point in the span Assuming rigid end fixing Find the fixing moment


2345


Program Outcome

7 For a rigidly fixed beam AB of 5m span carrying udl of 10Knm over the entire span locate the points of contraflexure and draw the SF and BM diagrams


2345

8 A beam built in at both the ends is loaded with a triangular loading on its one half of the span the other load half carries no load The load gradually increases from zero at the fixed end to 15Knm at mid span The span of the beam is 5m Determine the bending moments


2345

9 A beam of uniform cross section and 5m length is built in at each end It carries a udl of 10Knm extending from 3m from one end and a concentrated load of 20Kn 1m from the other end Sketch the BM diagram giving principal numerical values


2345

10 A beam fixed at both ends is prismatic It carries a load of varying intensity zero at the end to wunit length at the center Determine the fixed moments


2345

11

A fixed beam AB of 8m span carries a point load of 100 kN at its mid span and a uniformly distributed load of 20 kNm throughout its entire span Find the following (i) Fixing moments at the ends and (ii) Reactions at the supports Also draw the SF and BM diagrams


2345

12 What are the fixed end moments for a fixed beam of length l subjected to a concentrated load 2W at a distance a from left end


2345

13 Derive a relation fro prop reaction for a simply supported beam with uniformly distributed load and propped t the centre


2345

14 A Steel fixed beam AB of span 6 m is 60 mm wide and 100 mm deep The support B sinks down by 6 mm Fine the fixing moments at A and B Take E = 200 GPa


2345

15 Derive and sketch the shear force bending moment and deflection of a propped cantilever beam subjected o udl over the entire span


2345

16 What are the advantages and disadvantages of a fixed beam Analyze and

evaluate 2345

17 A fixed beam AB of length 3m is having moment of inertia I=3 x 106 mm4 the support B sinks down by 3mm If E = 2 x 105 Nmm2 Find the fixing moments


2345

18

For the fixed beam shown in fig what is the fixed end moment at A and B


2345

19 Draw BMD for a propped cantilever beam span lsquo2Lrsquo subjected to UDL throughout wm


2345

20 A fixed beam of span lsquoLrsquo is subjected to UDL throughout 2wm What is end moments and moment at the centre


2345

UNIT - IV

1 A continuous beam ABC consists of two consecutive spans of 4m each and carries a distributed load of 60Knm run The end A is fixed and the end C simply supported Find the support moments and the reactions


2345

2 Analyze the continuous beam shown in fig if the support B sinks by 1cm Analyze and 2345


Program Outcome

The section is constant throughout E=200Gpa and I=8500cm4

evaluate

3 Draw SF and BM diagrams for a continuous beam loaded as shown I fig


2345

4 A continuous beam ABCD 20m long is continuous over 3 spans AB=8m BC=4m CD=8m Moment of inertia is 2I that of BC is I and that of CD is 2I There is a UDL load of 1500 Nm over spans AB and BC On the span CD there is a central load of 4000N The ends are fixed and during loading the support B sinks by 1cm Find the fixed end moments using slope deflection method I=1600cm4 and E=200GPa


2345

5 A continuous beam ABCD 18m long is continuous over 3 spans AB=8m BC=4m CD=8m Moment of inertia is constant over the whole span A concentrated load of 4000N is acting of AB at 3m from support A There is a UDL load of 1000 Nm on BC On the span CD there is a central load of 4000N The ends are fixed and during loading the support B sinks by 1cm Find the fixed end moments using slope deflection method I=1600cm4 and E=200GPa


2345

6 Analyze the continuous beam ABCD 3l long using slope deflection method is continuous over 3 spans with a uniformly distributed load of w per unit length AB=BC=CD=l The beam is of constant section throughout its length and supports remain at same level after loading


2345



2345



2345



2345

10 A continuous beam ABCD 18m long is continuous over 3 spans AB=8m BC=4m CD=8m Moment of inertia is constant over the whole span A


2345


Program Outcome

concentrated load of 4000N is acting of AB at 3m from support A There is a UDL load of 1000 Nm on BC On the span CD there is a central load of 4000N The ends are fixed and during loading the support B sinks by 1cm Analyze using elastic curve I=1600cm4 and E=200GPa

11

A continuous beam ABCD of uniform cross-section is loaded

as shown in Figure Find the following (i) Bending moments

at the supports (ii) Reactions at the supports Also draw BM

and SF diagrams


2345

12

A continuous beam ABCD in shown in Fig Draw SFD and

BMD indicating the salient points (AUC NovDec 2011)


2345

13

Draw the SF and BM diagrams for the beam shown in the

fig Use three moment equation (AUC AprMay 2012)


2345

14

A fixed beam AB of length 8m carries point loads of 150 kN

and 120kN at a distance of 3m and 4m from the left end A

Find the fixed end moments and the reactions at the supports

Draw BM and SF diagrams


2345

15

A continuous beam ABC 8m long consists of two spans AB = 4m and BC = 5m The span AB carries a load of 80 kNm while the span BC carries a load of 30 kNm Find the support moments and the reactions at the supports


2345

16



2345

17

Analyse the following beam


2345


Program Outcome

18


fig


2345

19

For the fixed beam shown in fig what is the fixed end

moment at A and B


2345

20 A fixed beam of span lsquo2Lrsquo is subjected to UDL throughout wm What is end moments and moment at the centre


2345

UNIT - V

1 For simply support beam 10M ILD is drawn for BM at a section 4m from the let hand support The maximum BM at the section due to moving load of 160KN is equal to


2345

2 A udl of 30Knm and 4m length rolls over a span of 16M The absolute maximum BM in KN-M is


2345

3 A number of wheel loads 3t 4t 5t and 6t spaced 2m 3m and 3m respectively with the 3t load leading from left to right To find the maximum BM at 8m from A what load must be placed at what section


2345

4 Three wheel loads 10t 26t and 24t spaced 2m apart roll on a girder from left to right with the 10t load leading The girder has a span of 20m For the condition of maximum bending moment at a section 8m from the left end what load should be placed at the section


2345

5 A beam PQRS is 18m long and is simply supported at points Q and R 10m apart Overhang PQ and RS are 3m and 5m respectively A train of two point loads of 150Kn and 100Kn 5m apart crosses this beam from left to right with 100Kn load leading What is the maximum sagging moment under 150Kn


2345

6 For above problem the passage of loads what are the maximum and minimum reactions at support R in Kn respectively


2345

7 What is the variation of influence line for stresses unction in a statically Analyze and evaluate

2345

8 What is the shape of influence line diagram for the maximum bending moment is respect of a simply support beam


2345

9 Five concentrated loads 40Kn 120Kn 100Kn and 80Kn spaced at equal distance of 3m between them cross from left to right of a SS beam of


2345


Program Outcome

span 40m with the 40Kn load leading What load gives the maximum bending moment at section C 15m from left

10 What is the area of influence line diagram for the reaction at the hinged end of a uniform propped cantilever beam of span L


2345

11

A beam ABC is supported at A B and C as shown in Fig 7 It has the

hinge at D Draw the influence lines for (1) reactions at A B and C (2) shear to the right of B (3) bending moment at E


2345

12

Construct the influence line for the reaction at supports A and B for the beam of span 10m The beam structure is shown in Figure


2345

13

Construct the influence line for support reaction at B for the given beam as shown in Fig


2345

14

Construct the influence line for shearing point C of the beam


2345

15

Construct the influence line for the moment at point C of the beam shown in Figure


2345

16



2345

17

Construct the influence line for a) reaction at A and B b) shear at point C c) bending moment at point C of the beam in the figure below


2345


Program Outcome

18

Construct the influence line for - the reaction at A C and E - the shear at D - the moment at D


2345

19

Construct the influence line for a) shear before and after support B b) moment at point B of the beam in the figure below


2345

20

Construct the influence line for - shear before and after support C - moment at point C


2345

Prepared by K Varsha Reddy Assistant Professor

HOD CIVIL ENGINEERING



Remember

6 Write different methods for computing deflection of determinate beam Understanding amp

Remember 1

7 Define Internal Stability Understanding amp

Remember 1

8 What are the different types of frames based on stability Understanding amp

Remember 1

9 What are the different types of frames and explain the same with neat diagrams


1

10 Define External stability Understanding amp

Remember 1

11 Define Degree of Indeterminacy Remember 1

12 What is equilibrium condition Remember 1

13


Remember

1

14


Remember

1

15 Differentiate between method of joints amp method of sections Remember 1

16 Explain a pin-jointed frame with a sketch Remember 1

17 Define a redundant force Remember 1

18 What is a portal frame Remember 1

19 What are the assumptions made in finding out the forces in a frame Remember 1

20 Explain briefly about tension coefficient method Remember 1

UNIT ndash II

1 Define term deflection of a beam Remember 1

2 State conjugate beam theorem Remember 1

3 Write relation between load shear force and bending moment acting on a structure


1

4 State moment area theorems Understanding amp

Remember 1

5 Define strain energy Understanding amp

Remember 1

6 State the castaglianos theorem Understanding amp

Remember 1

7 A steel rod has a square cross section of 10mm x 10mm and a length of 2M Calculate strain energy when a stress of 400 Mpa is produced by stretching it Take E = 200 Gpa


8 Calculate Strain energy due to shear stress for a member which has a length of 05M 120mm Diameter and a pull of 5KN Take E = 200 Gpa


9 What is the temperature effect on three hinged arches Understanding amp

Remember 1

10 How three hinged arch is different from two hinged arch and explain it Understanding amp 1



Remember






1


Remember 1


Remember 1


Remember 1




1


Remember 1

UNIT ndash III


Remember 1






Remember 1




Remember 1





Remember 1






Remember 12


Remember 1




12



1






Remember

UNIT ndash IV




Remember 1


Remember 1


Remember 1



1


Remember 1



1


Remember 1


Remember 1



1


Remember 1


Remember 1


Remember 1


Remember 1



1


Remember 1



Remember 1


Remember 1



Remember 1


Remember 1


Remember 1


Remember 1


Remember 1


Remember 1





1


Remember 1



1



1


Remember 1


Remember 1



1



1



1


Remember 1



1


Remember 1


Remember 1


Remember 1



Program Outcome

UNIT ndash I


12



1234



1234


Program Outcome




1234



1234



1234



1234


Program Outcome




1234



1234



1234



1234


Program Outcome

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234


Program Outcome

20



1234

UNIT - II



1234



1234



1234



1234



1234


1234


1234


1234



Program Outcome

evaluate


1234


evaluate 1234


evaluate 1234



1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234



1234

UNIT - III



1234



1234



1234



1234



1234



1234



Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345





Remember






1


Remember 1


Remember 1


Remember 1




1


Remember 1

UNIT ndash III


Remember 1






Remember 1




Remember 1





Remember 1






Remember 12


Remember 1




12



1






Remember

UNIT ndash IV




Remember 1


Remember 1


Remember 1



1


Remember 1



1


Remember 1


Remember 1



1


Remember 1


Remember 1


Remember 1


Remember 1



1


Remember 1



Remember 1


Remember 1



Remember 1


Remember 1


Remember 1


Remember 1


Remember 1


Remember 1





1


Remember 1



1



1


Remember 1


Remember 1



1



1



1


Remember 1



1


Remember 1


Remember 1


Remember 1



Program Outcome

UNIT ndash I


12



1234



1234


Program Outcome




1234



1234



1234



1234


Program Outcome




1234



1234



1234



1234


Program Outcome

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234


Program Outcome

20



1234

UNIT - II



1234



1234



1234



1234



1234


1234


1234


1234



Program Outcome

evaluate


1234


evaluate 1234


evaluate 1234



1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234



1234

UNIT - III



1234



1234



1234



1234



1234



1234



Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345





Remember

UNIT ndash IV




Remember 1


Remember 1


Remember 1



1


Remember 1



1


Remember 1


Remember 1



1


Remember 1


Remember 1


Remember 1


Remember 1



1


Remember 1



Remember 1


Remember 1



Remember 1


Remember 1


Remember 1


Remember 1


Remember 1


Remember 1





1


Remember 1



1



1


Remember 1


Remember 1



1



1



1


Remember 1



1


Remember 1


Remember 1


Remember 1



Program Outcome

UNIT ndash I


12



1234



1234


Program Outcome




1234



1234



1234



1234


Program Outcome




1234



1234



1234



1234


Program Outcome

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234


Program Outcome

20



1234

UNIT - II



1234



1234



1234



1234



1234


1234


1234


1234



Program Outcome

evaluate


1234


evaluate 1234


evaluate 1234



1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234



1234

UNIT - III



1234



1234



1234



1234



1234



1234



Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345







1


Remember 1



1



1


Remember 1


Remember 1



1



1



1


Remember 1



1


Remember 1


Remember 1


Remember 1



Program Outcome

UNIT ndash I


12



1234



1234


Program Outcome




1234



1234



1234



1234


Program Outcome




1234



1234



1234



1234


Program Outcome

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234


Program Outcome

20



1234

UNIT - II



1234



1234



1234



1234



1234


1234


1234


1234



Program Outcome

evaluate


1234


evaluate 1234


evaluate 1234



1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234



1234

UNIT - III



1234



1234



1234



1234



1234



1234



Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome




1234



1234



1234



1234


Program Outcome




1234



1234



1234



1234


Program Outcome

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234


Program Outcome

20



1234

UNIT - II



1234



1234



1234



1234



1234


1234


1234


1234



Program Outcome

evaluate


1234


evaluate 1234


evaluate 1234



1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234



1234

UNIT - III



1234



1234



1234



1234



1234



1234



Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome




1234



1234



1234



1234


Program Outcome

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234


Program Outcome

20



1234

UNIT - II



1234



1234



1234



1234



1234


1234


1234


1234



Program Outcome

evaluate


1234


evaluate 1234


evaluate 1234



1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234



1234

UNIT - III



1234



1234



1234



1234



1234



1234



Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234


Program Outcome

20



1234

UNIT - II



1234



1234



1234



1234



1234


1234


1234


1234



Program Outcome

evaluate


1234


evaluate 1234


evaluate 1234



1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234



1234

UNIT - III



1234



1234



1234



1234



1234



1234



Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

16



1234

17



1234

18



1234

19



1234


Program Outcome

20



1234

UNIT - II



1234



1234



1234



1234



1234


1234


1234


1234



Program Outcome

evaluate


1234


evaluate 1234


evaluate 1234



1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234



1234

UNIT - III



1234



1234



1234



1234



1234



1234



Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

20



1234

UNIT - II



1234



1234



1234



1234



1234


1234


1234


1234



Program Outcome

evaluate


1234


evaluate 1234


evaluate 1234



1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234



1234

UNIT - III



1234



1234



1234



1234



1234



1234



Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

evaluate


1234


evaluate 1234


evaluate 1234



1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234


evaluate 1234



1234

UNIT - III



1234



1234



1234



1234



1234



1234



Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome


evaluate



1234



1234



1234



1234



1234



1234



1234

15



1234



1234



1234

18






1234



1234

20



1234

UNIT - IV


Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome



1234



1234



1234



1234



1234



1234



1234



1234


Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome




1234



1234

11



1234

12



1234

13



1234

14



1234



1234


Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

16



1234

17



1234

18



1234

19



1234

20



1234

UNIT - V



1234


Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

Figure 1


Figure 2


1234


Figure 3


1234



1234



1234



1234



1234


Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome




1234



1234



1234

11





1234

12



1234

13



1234



1234



1234

16



1234

17



1234



1234


Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

19





1234



1234



Program Outcome

UNIT ndash I


Understanding 12



2345



2345



2345


Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome


of joints


2345



2345



2345


Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome


method of joints


2345



2345



2345


Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

11



2345

12



2345

13



2345



2345


Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

15



2345

16



2345



2345


Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

18



2345

19



2345

20



2345


Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

UNIT - II



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome


in fig


2345



2345



2345

12



2345



2345

14



2345

15



2345

16



AC 80 mm2


2345


Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome



2345



2345

19



2345

20



2345

UNIT - III



2345



2345



2345



2345



2345



2345


Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome



2345



2345



2345



2345

11



2345



2345



2345



2345



2345


evaluate 2345



2345

18



2345



2345



2345

UNIT - IV



2345



Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome


evaluate



2345



2345



2345



2345



2345



2345



2345



2345


Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome


11




and SF diagrams


2345

12




2345

13




2345

14






2345

15



2345

16



2345

17



2345


Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

18


fig


2345

19


moment at A and B


2345



2345

UNIT - V



2345



2345



2345



2345



2345



2345


2345



2345



2345


Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome




2345

11




2345

12



2345

13



2345

14



2345

15



2345

16



2345

17



2345


Program Outcome

18



2345

19



2345

20



2345




Program Outcome

18



2345

19



2345

20



2345



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