introduction to mixture applications example 1: a jar contains 20 ounces of a solution that is part...
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Introduction to Mixture Applications
Example 1:
A jar contains 20 ounces of a solution that is part water and part acid. If the amount of acid is 10% of the total solution, how much acid is in the solution?
First, determine what 10% is as a fraction. Recall than percent means per hundred:
10%10
100
1
10
20 ounces total
water & acid
10% acid
10%
The acid is 10% of the total:
10% of the total
10% 20
120
10
2
20
2 oz.
There are two ounces of acid in the solution.
10%
Review the expression that gave us the amount of acid:
10% of the total
10% 20 20 In decimal form …
0.10
= (percent acid)× (total amount)
10%
20
20
Introduction to Mixture Applications
Example 2:
A jar contains x ounces of a solution that is part water and part acid. If the amount of acid is 10% of the total solution, how much acid is in the solution?
x ounces total
water & acid
10% acid
10%
The acid is 10% of the total:
10% of the total
10% x
0.10 x x
= (percent acid)× (total amount)
0.10x oz.
There are 0.10x ounces of acid in the solution.
= (percent acid)× (total amount)
Introduction to Mixture Applications
Example 3:
A jar contains x ounces of a solution that is part water and part acid. If the amount of acid is 65% of the total solution, how much acid is in the solution?
= (percent acid) × (total amount)Amount acid
65% x
0.65 x
