introduction to orbital mechanics: v, the conic sections...
TRANSCRIPT
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MAE 5540 - Propulsion Systems
Introduction to Orbital Mechanics:
!V, the Conic Sections, and Kepler’s First
Law
“Its not where you are,
its how fast you are going”
Isp=400sec
Isp=300sec
Isp=200sec
!V
m0/mf
Sutton and Biblarz, Chapter 4
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MAE 5540 - Propulsion Systems
Example 1:
Isaac Newton explains how to launch a Satellite
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MAE 5540 - Propulsion Systems
Example 2:
Sub Orbital Launch
• Still “in orbit”
Around earth center
• What is velocity
At apogee is
Zero?
• Do we still need
!V?
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MAE 5540 - Propulsion Systems
How Much Delta-V do you need?
Thrust, Weight, Lift, Drag
draggravityburnoutrequired VVVV !+!+!=!Orbit
Yes!
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MAE 5540 - Propulsion Systems
Rocket Design 101
…. How Much !V do you need to accomplish
the mission?
draggravityburnoutrequired VVVV !+!+!=!Orbit
• Obviously we have a LOT! To learn about !V!
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MAE 5540 - Propulsion Systems
Gravitational Physics• Now a bit of "gravitational physics"
Isaac Newton, (1642-1727)
Gravitational Physics
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MAE 5540 - Propulsion Systems
Orbital Velocity• Object in orbit is actually in "free-fall" that is ... the object is literally falling around the Earth (or Planet)
• When the Centrifugal Force of the "free-fall" counters the Gravitational Force ... the object is said to have achieved Orbital Velocity
V
Fgrav
Fcentrifugal
Orbital Velocity
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MAE 5540 - Propulsion Systems
N-body problem
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MAE 5540 - Propulsion Systems
Gravitational Attraction on a10,000 kg Spacecraft
0.001
0.01
0.1
10
100
10000 20000 30000 40000
Orbital Altitude, kilometers
1
Att
racti
ve F
orce, N
ew
ton
s
Attraction of Earth
Attraction of Sun
Attraction of Moon
Geo
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MAE 5540 - Propulsion Systems
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MAE 5540 - Propulsion Systems
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MAE 5540 - Propulsion Systems
Two Body Problem
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MAE 5540 - Propulsion Systems
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MAE 5540 - Propulsion Systems
Kepler’s laws
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MAE 5540 - Propulsion Systems
Conic Sections
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MAE 5540 - Propulsion Systems
Circular Orbits:Circular orbits
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MAE 5540 - Propulsion Systems
i
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MAE 5540 - Propulsion Systems
Circular Orbits
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MAE 5540 - Propulsion Systems
Elliptical Orbits:
!VT
• Adding "!V" turns a circularorbit into an elliptical orbit
Elliptical orbits
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MAE 5540 - Propulsion Systems
What is an Ellipse?
b
a
c
Geometry of an Ellipse
(-c,o) (c,o)
y
x
!
xy
rpra
ra rp+ = 2 a
perifocus
apfocus
"line of apsides"
semi-major axis
semi-minor axis
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MAE 5540 - Propulsion Systems
Ellipse Equation: Earth
Centered at origin
b
a
c
(-c,0) (0,0)
y
x!
y
rpra
(-2c,0)
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MAE 5540 - Propulsion Systems
Polar-Form of theEllipse Equation
b
a
c
(o,o)
r pr a
(-c,o)
c
Geometry of an Ellipse(Earth Centered at perifocus)
(-2c,o)
y
x+c
!
j
i
Xx+2c
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MAE 5540 - Propulsion Systems
Polar-Form of theEllipse Equation (cont'd)
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MAE 5540 - Propulsion Systems
Polar-Form of Ellipse Equation (cont'd)
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MAE 5540 - Propulsion Systems
Polar-Form of Ellipse Equation (cont'd)
• Substituting and simplifyiing
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MAE 5540 - Propulsion Systems
Polar Form of Ellipse EquationPolar-Form of the Ellipse Equation
(concluded)
• Defining the elliptical eccentricity as
• The polar form of the ellipse equation reduces to
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MAE 5540 - Propulsion Systems
Parameters of theElliptical Orbit
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MAE 5540 - Propulsion Systems
Fundamental Elliptical Orbit Definitions
Ra Rp
perigee
apogee
2a
2b“Line of Apsides”
a -- Semi-major axis
b -- Semi-minor axis
e -- Orbital eccentricity
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MAE 5540 - Propulsion Systems
Fundamental Elliptical Orbit Definitionscont’d
Orbit Apogee and Perigee (closest and farthest approaches)… semi major axis and eccentricity related to apogee and perigee radius
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MAE 5540 - Propulsion Systems
Fundamental Elliptical Orbit Definitionscont’d
Location within an Orbit: “true anomaly” "
Ra Rp
perigee
apogee
2a
2b
!
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MAE 5540 - Propulsion Systems
Coordinate TransformationsCoordinate Transformations:
i
ji r
i!
!
!
{i, j} fixed in space
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MAE 5540 - Propulsion Systems
Coordinate Transformations:(cont;d)
i
ji r
i!
!
!
• A Matrix "trick" for coordinate transform in 2-D
Coordinate Transformations
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MAE 5540 - Propulsion Systems
Orbital Velocity
rr =
a 1! e2( )
1+ e " cos #( )"rir $
{a,e} % constant
parameters of the orbit
rV =
d
dt
rr( ) =
d
dt
a 1! e2( )
1+ e " cos #( )
&
'(
)
*+ "
rir +
a 1! e2( )
1+ e " cos #( )"
d
dt
rir( )
Velocity is the derivative of position ….
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MAE 5540 - Propulsion Systems
Orbital Velocity (2)
Differentiate r
d
dt
a 1! e2( )1+ e " cos #( )
$
%&
'
() = !
a 1! e2( )1+ e " cos #( )*+ ,-
2
$
%&
'
() " !e " sin #( ) " &#( )( ) =
a 1! e2( )1+ e " cos #( )*+ ,-
$
%&
'
() "
e " sin #( )
1+ e " cos #( )*+ ,-
$
%&
'
() " &#( ) =
e " sin #( )
1+ e " cos #( )*+ ,-
$
%&
'
() " r " &#( )
Differentiate ri
d
dt
rir( ) =
d
dt ri ! cos "( ) + j ! sin "( ) ( ) = -
ri ! sin "( ) + j ! cos "( ) ( ) ! &" = &" !
ri"
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MAE 5540 - Propulsion Systems
Orbital Velocity (3)
rV =
e ! sin "( )
1+ e ! cos "( )#$ %&! r ! &"( )
'
()
*
+, !
rir+
a 1- e2( )1+ e ! cos "( )
'
()
*
+, ! &" !
ri" =
r ! &"( )e ! sin "( )
1+ e ! cos "( )#$ %&
'
()
*
+, !
rir+
ri"
#
$..
%
&//
Need Kepler’s Second Law to get
&! ="
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MAE 5540 - Propulsion Systems
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MAE 5540 - Propulsion Systems
Parabolic Trajectories:Parabolic Trajectories
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MAE 5540 - Propulsion Systems
What is a Parabola?
(0,0)
focus
y
xpp
Directrix
r
r!
• A parabola is the locus of all pointsequidistant from a fixed point (focus)and a line (Directrix)
• Cartesian form of the equation
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MAE 5540 - Propulsion Systems
Parabola EquationPolar Form
Use quadratic formulato solve
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MAE 5540 - Propulsion Systems
Parabola EquationPolar Form (cont'd)
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MAE 5540 - Propulsion Systems
Parabola EquationPolar Form (concluded)
• r must be > 0, therefore pick - sign
Perigee!
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MAE 5540 - Propulsion Systems
Hyperbolic Trajectories:
• If "V !" > 0 , then probe will approach anddepart along a hyperbolic trajectory
"Excess Hyperbolic Velocity" approach/departure" V! > 0
Parabolic approach/departure" V! = 0
Hyperbolic trajectories
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MAE 5540 - Propulsion Systems
What is a Hyperbola?
c
c
a
left focus(apfocus) (2c,0)
right focus(perifocus)
(0,0)
b
c = a + b2 2 2
!
(c,0)
• A Hyperbola is the locus of all points whosedifference from two fixed points is constant
Cartesian Equation
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MAE 5540 - Propulsion Systems
Hyperbolic Equation:polar form
c
c
a
(2c,0)
right focus(perifocus)
(0,0)
b
c = a + b2 2 2
!
(c,0)
r
c
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MAE 5540 - Propulsion Systems
Hyperbolic Equation:polar form (cont'd)
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MAE 5540 - Propulsion Systems
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MAE 5540 - Propulsion Systems
Hyperbolic Asymptotes• What is the behavior of a Hyperbola at "infinity"i.e. along away from earth
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MAE 5540 - Propulsion Systems
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MAE 5540 - Propulsion Systems
Kepler’s First Law(Summary)
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MAE 5540 - Propulsion Systems
Homework:Compound Circular Orbits:
js
is
!s
as
ap
moon
planet
jp
ip
js
is
!s
as
moon
ap
!p
!p
TralfamadorTralfamador
Strangelove
Enterprise
E nterprise
2:
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MAE 5540 - Propulsion Systems
Homework:Compound Orbits(cont'd)
• Starship Enterprise orbits alien moon Tralfamador in a circular orbit of radius as
• Moon orbits alien planet Strangelove in circular orbit with radius ap
• Alien GPS system orbiting moon gives position relative to Tralfamadorian -fixed coordinate system.
• Due to gravitational damping Tralfamador, always keeps the same face directed towards Strangelove
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MAE 5540 - Propulsion Systems
Homework:Compound Orbits(cont'd)
• Compute the position vector of the Enterprise relative to Strangelove ... in the Strangeloveian -fixed coordinate system --
• Solution should have as, ap, !s, !p as parameters
Rsp
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MAE 5540 - Propulsion Systems
Coordinate TransformationsCoordinate Transformations:
i
ji r
i!
!
!
{i, j} fixed in space
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MAE 5540 - Propulsion Systems
Homework:Circular Orbits(concluded)
• Compute the velocity vector of the Enterprise relative to Strangelove ... in the Strangeloveian -fixed coordinate system.