ipe-etap case-0039.pdf

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  • 8/10/2019 IPE-ETAP CASE-0039.pdf

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    IndependentPowerEngineers NeverTrusttheMachine,trusttheengineer!

    1

    Whoarewe?IPE(IndependentPowerEngineers) isanonprofitorganizationpassionateaboutthe

    powerengineering industry. Ourmainmandate is to testandexpose thedifferent

    issuesanddysfunctionsofdifferentpowersystemsimulationsoftwares.Pleasenote

    thatallofour testsaremadeavailablealsoonYouTube for transparency.Look for

    IndependentPowerEngineersonYouTubetogetaccesstoourlatestvideos.

    Product ETAP

    Manufacturer OTI(OperationTechnologyInc)

    Version 6, 7.1, 7.5, 11,12.0 and 12.5

    Revision Allversions

    Operatingsystem Windows7/64Bit

    Systemproperties [email protected]:2.00GB

    ETAPCASE

    0039

    Analysis All Load Flow Methods( Adaptive Newton Raphson, Newton Raphson, Fast Decoupled,

    AcceleratedGaussSeidel)

    Analysisdetail Precision=0.000000001,MaxNo.ofIteration=9999

    Issue Wrong results, The incoming current to a node and outgoing current from node are not

    equal?

    Reason WrongCalculation/ConvergencewhenR(Resistance)isHigherthanInductanceR>2X

    (LVCables)

    Proposedsolution none

    ETAPCASE0039Overview:

    Wedecided

    to

    remodel

    an

    extremely

    simple

    real

    network

    to

    test

    the

    Load

    Flow

    engine

    for

    load

    flow

    in

    ETAP

    12.5.

    Themodelconsistsofasource, twocables (Selected fromETAP library),Twosimilar inductionsmotors (Selected

    fromETAPDatabase).

    Figure1:SimpleNetworkmodeling

  • 8/10/2019 IPE-ETAP CASE-0039.pdf

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    IndependentPowerEngineers NeverTrusttheMachine,trusttheengineer!

    2

    Source(SCrating=40MVA,X/R=10,0.46KV,Isc=50KA)

    Motor No.1& 2,: (0.415KV, 100 HP, PF=85.22%, Eff= 95.23%, LRC=625.4%, PF(Locked Rotor)=30.99%,

    LRT=103.8%,MaxT=198.4%,Ns=1800,Nr=1782,Slip=1.02%,In=127.8A),ModelSingle2:Singlecagewithdeep

    bar,H=1.44,LoadModel:TL=100w3

    CableNo.1(CABLEC001):3X1C95mm2,ICEA,AL,1KV,Rubber,(R=0.37671ohm/1000m,

    X=0.13884

    ohm/1000

    m,

    Y=0.0),

    Length=150m

    CableNo.2(CABLEC002):3X1C35mm2,ICEA,AL,1KV,Rubber,(R=0.37671ohm/1000m,

    X=0.13884ohm/1000m.Y=0.0),Length=200m

    BusbarNo.1NominalVoltage:460V

    BusbarNo.2and3NominalVoltages:415V

    Observation

    Werunloadflowinalltheloadflowmethodsandfollowingresultswillbeobtained.

    Figure2:Loadflowresults,demonstratingbranchescurrents

    Aboveresultswillbeobtainedwithoutanywarnings.

    Doyouthinkresultsarecorrect?WejustwanttoanalysesresultsaboutBusbarsincoming/outgoingCurrents:

    B002:incomingActivecurrentis259x0.869=225.07