isaac newton (1642–1727) physics 2113 lecture 06: mon 8 oct

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Physics 2113 Lecture 06: MON 8 OCT CH22: Electric Fields Physics 2113 Michael Faraday (1791–1867) Isaac Newton (1642–1727)

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Page 1: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

Physics 2113 Lecture 06: MON 8 OCT

CH22: Electric Fields

Physics 2113

Michael Faraday (1791–1867)

Isaac Newton (1642–1727)

Page 2: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

2q−12F1q+ 21F

12r

Coulomb’s law

212

2112

||||||rqqkF =

2

212

00

1085.8with 41

mNCk −×== επε

2

291099.8CmN

×k =

For charges in a VACUUM

Often, we write k as:

Electric forces are added as vectors.

Page 3: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

Electric  Fields  •  Electric  field  E  at  some  point  in  space  is  defined  as  the  force  divided  by  the  electric  charge.  

•  Force  on  charge  2  at  some  point,  by  charge  1  is  given  by  

•  Electric  field  at  that  point  is    

 21

12||||

RqkE =

!

EqF!!

=

221

12||||||

RqqkF =

!

Page 4: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

Field lines Useful way to visualize electric field. They start at a positive charge, end at negative charge. At any point in space electric field is tangential to field line. Field is proportional to how “packed” the lines are.

Page 5: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

Example

The  electric  field  lines  on  the  le=  have  twice  the  separa?on  as  those  on  the  right.      If  the  magnitude  of  the  field  at  A  is  40  N/C,  what  is  the  magnitude  of  field  at  B?  

Page 6: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

Charge  q1  on  inner  spherical  shell,  -­‐q2  on  outer.  Sketch  the  field  lines.  

Page 7: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

Electric field of a point charge

F!"= k qq0

r2 r̂,

where r̂ is a unit radial vector.

To  compute  electric  field  of  more  than  one  charges,  one  should  try  to  simplify  the  problem  by  breaking  it  to  simpler  problem.  

ˆ 32 rrq

krrq

kE !==

Page 8: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

Example •  4 charges are placed at the

corners of a square as shown. •  What is the direction of the

electric field at the center of the square?

(a) Field vanishes at the center (b) Along +y (c) Along +x

-q

-2q

+2q

+q

y

x

Page 9: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT
Page 10: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

Two  par?cles  are  fixed  to  an  x  axis:  par?cle  1  of  charge  q1=2.1x10-­‐8  C  at  x=20cm  and    par?cle  2  of  charge  q2=-­‐4q1  at  x=70cm.  At  what  coordinate  on  the  axis  is  the  net    electric  field  zero?  

Page 11: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

To simplify things, we only compute the field along the axis.

P d

x

What is the electric field at P due to the dipole?

q− q+

_E :fields ofion Superposit EE!!!

+= +

,

241

20

⎟⎠

⎞⎜⎝

⎛ −

=+dx

qEπε

!2

0

241

⎟⎠

⎞⎜⎝

⎛ +

−=−dx

qEπε

!

Electric field due to a dipole

Page 12: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

When x>>d, at distances much greater than the dipole

⎥⎥⎦

⎢⎢⎣

⎡⎟⎠

⎞⎜⎝

⎛ +−⎟⎠

⎞⎜⎝

⎛ −=

⎥⎥⎥⎥

⎢⎢⎢⎢

⎟⎠

⎞⎜⎝

⎛ +

⎟⎠

⎞⎜⎝

⎛ −

=−− 22

022

0 2242

1

2

14

dxdxqdxdx

qEπεπε

!

12

12

22

22

⎟⎠

⎞⎜⎝

⎛ +=⎟⎠

⎞⎜⎝

⎛ ±=⎟⎠

⎞⎜⎝

⎛ ± −−

−−

!∓xdx

xdxdx

Then

30

20

20 2

24

114 x

qdxd

xq

xd

xd

xqE

πεπεπε==⎥

⎤⎢⎣

⎡⎟⎠

⎞⎜⎝

⎛ +−−⎟⎠

⎞⎜⎝

⎛ ++= !!"

•  Since, 2d << x, the field is weaker than that of the point charge at large x. •  Field scales with charges, vanishes if 0→d

Page 13: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

Electric Dipole Moment

30

30 22 x

px

qdEπεπε

==

Using expression for the electric field of the dipole, we find

The direction of dipole moment is taken from negative to positive charge.

Page 14: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

The  electric  quadrupole    It  consists  of  two  dipoles  of  equal  magnitude  place  close  to  each  other  and  in  opposite  direc?ons.  

The  story  can  be  con?nued:  superposed  two  quadrupoles,  obtain  an  octupole…  hexadecupole…  All  with  fields  that  decay  faster  and  faster  with  distance.  

Page 15: Isaac Newton (1642–1727) Physics 2113 Lecture 06: MON 8 OCT

Summary

•  Electric is a property of space that characterizes how charges placed in it react to it.

•  Field lines are a quick way to visualize fields.

•  In dipoles and higher multipoles, the leading contribution to the fields cancel, leading to faster dropoff with distance in the magnitude of the fields.