isotopes atoms of the same element with different mass numbers. mass # atomic # nuclear symbol:...
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Isotopes
• Atoms of the same element with different mass numbers.
Mass #
Atomic #
• Nuclear symbol:
• Hyphen notation: carbon-12carbon-12Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
12
6 C
Isotopes
+
+
+
+
+
+
Nucleus
Electrons
Nucleus
Neutron
Proton
Carbon-12Neutrons 6Protons 6Electrons 6
Nucleus
Electrons
Carbon-14Neutrons 8Protons 6Electrons 6
+
+
+
+
+
+
Nucleus
Neutron
Proton
3 p+
3 n02e– 1e– 3 p+
4 n02e– 1e–
6Li 7Li
+
+
+Nucleus
Electrons
Nucleus
Neutron
Proton
Lithium-6Neutrons 3Protons 3Electrons 3
Nucleus
Electrons
Nucleus
Neutron
Proton
Lithium-7Neutrons 4Protons 3Electrons 3
+
+
+
Isotopes
• Chlorine-37
– atomic #:
– mass #:
– # of protons:
– # of electrons:
– # of neutrons:
17
37
17
17
20
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
Cl37
17
37
17 Cl
Relative Atomic Mass
• 12C atom = 1.992 × 10-23 g
• 1 p = 1.007276 amu
1 n = 1.008665 amu
1 e- = 0.0005486 amu
• atomic mass unit (amu)
• 1 amu = 1/12 the mass of a 12C atom+
+
+
+
+
+
Nucleus
Electrons
Nucleus
Neutron
Proton
Carbon-12Neutrons 6Protons 6Electrons 6
Average Atomic Mass
• weighted average of all isotopes
• on the Periodic Table
• round to 2 decimal places
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
Avg.AtomicMass
= (mass)(%) + (mass)(%)
100
Average Atomic Mass
• EX: Calculate the avg. atomic mass of oxygen if its abundance in nature is 99.76% 16O, 0.04% 17O, and 0.20% 18O.
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
Avg.AtomicMass
= (16)(99.76) + (17)(0.04) + (18)(0.20)
100= 16.00
amu
Average Atomic Mass
• EX: Find chlorine’s average atomic mass if approximately 8 of every 10 atoms are chlorine-35 and 2 are chlorine-37.
Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
Avg.AtomicMass
= (35)(8) + (37)(2)
10= 35.40 amu
100
90
80
70
60
50
40
30
20
10
034 35 36 37
Ab
un
dan
ce
Mass
Mass spectrum of chlorine. Elemental chlorine (Cl2) contains only two isotopes: 34.97 amu (75.53%) and 36.97 (24.47%)
AAM = (34.97 amu)(0.7553) + (36.97 amu)(0.2447)
AAM = (26.412841 amu) + (9.046559 amu)
AAM = 35.4594 amu
Cl-35
Cl-37
Cl35.4594
17
Mass Spectrophotometer
electron beam
magnetic field
gas
stream of ions of differentmasses lightest
ions
heaviest ions
Dorin, Demmin, Gabel, Chemistry The Study of Matter 3rd Edition, page 138
.
• mass spectrometry is used to experimentally determine isotopic masses and abundances • interpreting mass spectra • average atomic weights
- computed from isotopic masses and abundances - significant figures of tabulated atomic weights gives some idea of natural variation in isotopic abundances
Weighing atomsgas sampleenters here
filament currentionizes the gas
ions acceleratetowards chargedslit
magnetic fielddeflects lightest ionsmost
ions separated by massexpose film
The first mass spectrograph was built in 1919 by F. W. Aston, who received the 1922 Nobel Prize for this accomplishment
Copyright © 1997-2005 by Fred Senese
Mass Spectrometry
- +
Photographic plate
196 199 201 204
198 200 202
Mass spectrum of mercury vaporMass spectrum of mercury vapor
Hill, Petrucci, General Chemistry An Integrated Approach1999, page 320
Stream of positive ionsStream of positive ions
Mass Spectrum for Mercury
196 197 198 199 200 201 202 203 204
Mass numberMass number
Rel
ativ
e n
umb
er o
f at
oms
Rel
ativ
e n
umb
er o
f at
oms
30
25
20
15
10
5
196 199 201 204
198 200 202
Mass spectrum of mercury vaporMass spectrum of mercury vapor
The percent natural abundances The percent natural abundances for mercury isotopes are:for mercury isotopes are:
Hg-196 0.146%Hg-196 0.146% Hg-198 10.02%Hg-198 10.02% Hg-199 16.84%Hg-199 16.84% Hg-200 23.13%Hg-200 23.13% Hg-201 13.22%Hg-201 13.22% Hg-202 29.80%Hg-202 29.80% Hg-204 6.85%Hg-204 6.85%
(The photographic record has been converted to a scale of relative number of atoms)
The percent natural abundances The percent natural abundances for mercury isotopes are:for mercury isotopes are:
Hg-196 0.146%Hg-196 0.146% Hg-198 10.02%Hg-198 10.02% Hg-199 16.84%Hg-199 16.84% Hg-200 23.13%Hg-200 23.13% Hg-201 13.22%Hg-201 13.22% Hg-202 29.80%Hg-202 29.80% Hg-204 6.85%Hg-204 6.85%
(0.00146)(196) + (0.1002)(198) + (0.1684)(199) + (0.2313)(200) + (0.1322)(201) + (0.2980)(202) + (0.0685)(204) = x
0.28616 + 19.8396 + 33.5116 + 46.2600 + 26.5722 + 60.1960 + 13.974 = x
x = 200.63956 amu
Hg200.59
80
(% "A")(mass "A") + (% "B")(mass "B") + (% "C")(mass "C") + (% "D")(mass "D") + (% "E")(mass "E") + (% F)(mass F) + (% G)(mass G) = AAM
ABCDEFG
Natural uranium, atomic weight = 238.029 g/molDensity is 19 g/cm3. Melting point 1000oC.
Two main isotopes:
U238 92
U235 92
99.3%
0.7%
Because isotopes are chemically identical(same electronic structure), they cannot beseparated by chemistry.
So Physics separates them by diffusion orcentrifuge (mass spectrograph is too slow)…
Separation of Isotopes
(238 amu) x (0.993) + (235 amu) x (0.007)
236.334 amu + 1.645 amu
237.979 amu
U238
92
• Assume you have only two atoms of chlorine.• One atom has a mass of 35 amu (Cl-35)• The other atom has a mass of 36 amu (Cl-36)
• What is the average mass of these two isotopes?
35.5 amu
• Looking at the average atomic mass printed on the periodic table...approximately what percentage is Cl-35 and Cl-36?
55% Cl-35 and 45% Cl-36 is a good approximation
Cl35.453
17
Using our estimated % abundance data
55% Cl-35 and 45% Cl-36
calculate an average atomic mass for chlorine.
Cl35.453
17
Average Atomic Mass = (% abundance of isotope "A")(mass "A") + (% "B")(mass "B")
AAM = (% abundance of isotope Cl-35)(mass Cl-35) + (% abundance of Cl-36)(mass Cl-36)
AAM = (0.55)(35 amu) + (0.45)(36 amu)
AAM = (19.25 amu) + (16.2 amu)
AAM = 35.45 amu
Isotopes
Dalton was wrong.
Atoms of the same element can have different numbers of neutrons
different mass numbers
called isotopes
California WEB
C-12 vs. C-14
Naming Isotopes
• Put the mass number after the name of the element
• carbon- 12
• carbon -14
• uranium-235
California WEB
Using a periodic table and what you know about atomic number, mass, isotopes, and electrons, fill in the chart:
Element Symbol Atomic
Number
Atomic
Mass
# of protons
# of neutron
# of electron
charge
8 8 8
Potassium 39 +1
Br 45 -1
30 35 30
Atomic Number = Number of Protons
Number of Protons + Number of Neutrons = Atomic Mass
Atom (no charge) : Protons = Electrons
Ion (cation) : Protons > Electrons Ion (anion) : Electrons > Protons
Using a periodic table and what you know about atomic number, mass, isotopes, and electrons, fill in the chart:
Element Symbol Atomic
Number
Atomic
Mass
# of protons
# of neutron
# of electron
charge
8 8 8
Potassium 39 +1
Br 45 -1
30 35 30
Oxygen
Bromine
Zinc
O
K
Zn
8
19
35
16
80
19
35
30
20
65
18
36
0
0
Atomic Number = Number of Protons
Number of Protons + Number of Neutrons = Atomic Mass
Atom (no charge) : Protons = Electrons
Ion (cation) : Protons > Electrons Ion (anion) : Electrons > Protons
A N S W E R K E Y
Atomic Mass
• How heavy is an atom of oxygen?• There are different kinds of oxygen atoms.• More concerned with average atomic mass.• Based on abundance of each element in nature.• Don’t use grams because the numbers would be
too small
carbon atom
(12 amu)
Measuring Atomic Mass
• Unit is the Atomic Mass Unit (amu)• One twelfth the mass of a carbon-12 atom. • Each isotope has its own atomic mass we need
the average from percent abundance.
(1 amu)
(1 amu)(1 amu)
(1 amu)(1 amu) (1 amu)
(1 amu) (1 amu)
(1 amu) (1 amu)(1 amu) (1 amu)
Mass spectrums reflect the abundance of naturally occurring isotopes.
Hydrogen
Carbon
Nitrogen
Oxygen
Sulfur
Chlorine
Bromine
1H = 99.985% 2H = 0.015%
12C = 98.90% 13C = 1.10%
14N = 99.63% 15N = 0.37%
16O = 99.762% 17O = 0.038% 18O = 0.200%
32S = 95.02% 33S = 0.75%
34S = 4.21% 36S = 0.02%
35Cl = 75.77% 37Cl = 24.23%
79Br = 50.69% 81Br = 49.31%
Natural Abundance of Common Elements
For example….Methane
For carbon 1 in approximately 90 atoms are carbon-13
The rest are carbon-12 the isotope that is 98.9% abundant.
So, for approximately 90 methane molecules…1 carbon is carbon-13
Calculating averages
• You have five rocks, four with a mass of 50 g, and one with a mass of 60 g. What is the average mass of the rocks?
• Total mass = (4 x 50) + (1 x 60) = 260 g
• Average mass = (4 x 50) + (1 x 60) = 260 g 5 5
• Average mass = 4 x 50 + 1 x 60 = 260 g 5 5 5
California WEB
Calculating averages
• Average mass = 4 x 50 + 1 x 60 = 260 g 5 5 5
• Average mass = .8 x 50 + .2 x 60
• 80% of the rocks were 50 grams
• 20% of the rocks were 60 grams
• Average = % as decimal x mass + % as decimal x mass + % as decimal x mass +
California WEB
Isotopes
• Because of the existence of isotopes, the mass of a collection of atoms has an average value.
• Average mass = ATOMIC WEIGHT
• Boron is 20% B-10 and 80% B-11. That is, B-11 is 80 percent abundant on earth.
• For boron atomic weight= 0.20 (10 amu) + 0.80 (11 amu) = 10.8 amu
Periodic Table
• Dmitri Mendeleev developed the modern periodic table.
• Argued that element properties are periodic functions of their atomic weights.
• We now know that element properties are periodic functions of their ATOMIC NUMBERS.
Atomic Mass
Magnesium has three isotopes. 78.99% magnesium 24 with a mass of 23.9850 amu, 10.00% magnesium 25 with a mass of 24.9858 amu, and the rest magnesium 26 with a mass of 25.9826 amu. What is the atomic mass of magnesium?
If not told otherwise, the mass of the isotope is
the mass number in amu.
California WEB
IsotopeIsotopePercentPercent
AbundanceAbundanceMassMass
Mg-24 78.99 23.9850
Mg-25 10.00 24.9585
Mg-26 25.9826
24.304 amu
18.94575
2.49585
2.8606811.01
Atomic Mass
Calculate the atomic mass of copper if copper has two isotopes. 69.1% has a mass of 62.93 amu and the rest has a mass of 64.93 amu.
... )B"" )(massB"" (% )A"" )(massA"" (% (AAM) massatomic Average
Copper for amu 63.548 A.A.M.
amu 20.06337 amu 43.48463 A.A.M.
amu) .93(0.309)(64 amu) .93(0.691)(62 A.A.M.
Cu29
63.548
IsotopeIsotopePercentPercent
AbundanceAbundanceMassMass
Cu-63 69.1 62.93
Cu-65 64.93
43.48463
20.0633730.9
63.548
Protons Neutrons Electrons Mass number
Cu-65 A B 29 C
Argon D E F 40
Ba2+ 56 G H I
A. B. C.
D. E. F.
G. H. I.
Given the average atomic mass of an element is 118.21 amu and it has three isotopes (“A”, “B”, and “C”):
isotope “A” has a mass of 117.93 amu and is 87.14% abundantisotope “B” has a mass of 120.12 amu and is 12.36% abundant
Find the mass of isotope “C”. Show work for credit.
Extra Credit: What is a cation?
Given the average atomic mass of an element is 118.21 amu and it has three isotopes (“A”, “B”, and “C”):
isotope “A” has a mass of 117.93 amu and is 87.14% abundantisotope “B” has a mass of 120.12 amu and is 12.36% abundant
Find the mass of isotope “C”. Show work for credit.
Extra Credit: What is a cation?
A positively charged atom. An atom that has lost a(n) electron(s).
119.7932 amu
Protons Neutrons Electrons Mass number
Cu-65 A = 29 B = 36 29 C = 65
Argon D = 18 E = 22 F = 18 40
Ba2+ 56 G = 81 H = 54 I = 137
amu 119.7932 X
0.005 0.005
amu X 0.005 0.598966
amu X 0.005 0.598966
amu) (0.005)(X amu 14.846832 amu 102.764202 amu 118.21
amu) (0.005)(X amu) 20.12(0.1236)(1 amu) 17.93(0.8714)(1 amu 118.21
)C"" )(massC"" (% )B"" )(massB"" (% )A"" )(massA"" (% Mass Atomic Average
Given the average atomic mass of an element is 118.21 amu and it has three isotopes (“A”, “B”, and “C”):
isotope “A” has a mass of 117.93 amu and is 87.14% abundant isotope “B” has a mass of 120.12 amu and is 12.36% abundant
Find the mass of isotope “C”. Show work for credit.