jawab
DESCRIPTION
Masih tentang reaksiTRANSCRIPT
∫1(A0−x )(B0−
12x )
=∫−1(A0−2B0 )
x1(A0−x )
−∫ 1( A0−2B0 )x1
(B0−12x )
¿−1(A0−2B0 )
In [ A0−x ]0x−1
(A0−2B0 )In [B0−12 x ]0
x
=kt
1[ A ]0−2[B ]0
ln[ A ]0−x[ A ]0
−1[ A ]0−2 [B ]0
ln[ A ]0−x[B ]0
=kt
1[ A ]0−2[B ]0
ln[ A ]0−x[ A ]0
=kt+1[ A ]0−2 [B ]0
ln[ A ]0−x[B ]0
y=mx+C