joint probability distributions
DESCRIPTION
Joint Probability DistributionsTRANSCRIPT
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Chapter4TitleandOutline1
JointProbabilityDistributions
51TwoorMoreRandomVariables51.1JointProbabilityDistributions51.2MarginalProbability
Distributions51.3ConditionalProbability
Distributions51.4Independence51.5MoreThanTwoRandom
Variables
52CovarianceandCorrelation53CommonJointDistributions53.1MultinomialProbabilityDistribution53.2BivariateNormalDistribution54LinearFunctionsofRandomVariables55GeneralFunctionsofRandomVariables
CHAPTEROUTLINE
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Outline
JointProbabilityMass/DistributionFunction MarginalProbabilityDistribution Mean Variance ConditionalProbability Independence Covariance Correlation
Sec2 3
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ConceptofJointProbabilities Somerandomvariablesarenotindependentofeachother,i.e.,theytendtoberelated. Urbanatmosphericozoneandairborneparticulatemattertendtovarytogether.
Urbanvehiclespeedsandfuelconsumptionratestendtovaryinversely.
Thelength(X)ofainjectionmoldedpartmightnotbeindependentofthewidth(Y).Individualpartswillvaryduetorandomvariationinmaterialsandpressure.
Ajointprobabilitydistributionwilldescribethebehaviorofseveralrandomvariables,say,X andY.Thegraphofthedistributionis3dimensional:x,y,andf(x,y).
Chapter5Introduction 4
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Example51:SignalBarsYouuseyourcellphonetocheckyourairlinereservation.Theairlinesystem
requiresthatyouspeakthenameofyourdeparturecitytothevoicerecognitionsystem. LetYdenotethenumberoftimesthatyouhavetostateyourdeparture
city. LetXdenotethenumberofbarsofsignalstrengthonyoucellphone.
Sec51.1JointProbabilityDistributions 5
Figure51JointprobabilitydistributionofXandY.Thetablecellsaretheprobabilities.Observethatmorebarsrelatetolessrepeating.
1 2 31 0.01 0.02 0.252 0.02 0.03 0.203 0.02 0.10 0.054 0.15 0.10 0.05
x=numberofbarsofsignalstrength
y=numberoftimescity
nameisstated
Y1
Y2
Y3Y4
0
0.05
0.1
0.15
0.2
0.25
12
3x
Y1
Y2
Y3
Y4
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JointProbabilityMassFunctionDefined
Sec51.1JointProbabilityDistributions 6
The of the discrete random variables and , denoted as , , satifies:
(1) , 0 All probabilities
joint probabilit
are non-negative
(2) , 1
y mass function
XY
XY
XYx y
X Yf x y
f x y
f x y
The sum of all probabilities is 1
(3) , , (5-1)XYf x y P X x Y y
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0.15 0.10 0.05
0.02 0.10 0.05
0.02 0.03 0.20
0.01 0.02 0.25
0 1 2 3
1
2
3
4
Y = fY(y)
4
3
2
1
MarginalProbabilityDistributions(discrete)
Sec2 8
x
y
0.15 0.10 0.05
0.02 0.10 0.05
0.02 0.03 0.20
0.01 0.02 0.25
0 1 2 3
1
2
3
4
x
y
X = 1 2 3fX(x)
Xy
Yx
f x f xy
f y f xy
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Y = fY(y)
4 0.30
3 0.17
2 0.25
1 0.28
MeanandVariance
Sec2 10
0.15 0.10 0.05
0.02 0.10 0.05
0.02 0.03 0.20
0.01 0.02 0.25
0 1 2 3
1
2
3
4
x
y
X = 1 2 3fX(x) 0.20 0.25 0.55
E(X)=E(X2)=V(X)=
E(Y)=E(Y2)=V(Y)=
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JointProbabilityDensityFunctionDefined
Sec51.1JointProbabilityDistributions 11
(1) , 0 for all ,
(2) , 1
(3) , , (5-2)
XY
XY
XYR
f x y x y
f x y dxdy
P X Y R f x y dxdy
Figure52JointprobabilitydensityfunctionfortherandomvariablesX andY.Probabilitythat(X,Y)isintheregionR isdeterminedbythevolume offXY(x,y)overtheregionR.
ThejointprobabilitydensityfunctionforthecontinuousrandomvariablesX andY,denotesasfXY(x,y),satisfiesthefollowingproperties:
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JointProbabilityMassFunctionGraph
Sec51.1JointProbabilityDistributions 12
Figure53JointprobabilitydensityfunctionforthecontinuousrandomvariablesX andY ofdifferentdimensionsofaninjectionmoldedpart.Notetheasymmetric,narrowridgeshapeofthePDFindicatingthatsmallvaluesintheX dimensionaremorelikelytooccurwhensmallvaluesintheYdimensionoccur.
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Example52:ServerAccessTime1LettherandomvariableX denotethetime(msecs)untila
computerserverconnectstoyourmachine.LetY denotethetimeuntiltheserverauthorizesyouasavaliduser.X andYmeasurethewaitfromacommonstartingpoint (x
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Example52:ServerAccessTime2 Thejointprobabilitydensityfunctionis:
Weverifythatitintegratesto1asfollows:
Sec51.1JointProbabilityDistributions 14
0.001 0.002 0.002 0.0010 0
0.0020.001 0.003
0 0
,
0.0030.002
10.003 10.003
x y y xXY
x x
xx x
f x y dxdy ke dy dx k e dy e dx
ek e dx e dx
0.001 0.002 6, for 0 and 6 10x yXYf x y ke x y k
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Example52:ServerAccessTime2Nowcalculateaprobability:
Sec51.1JointProbabilityDistributions 16
Figure55RegionofintegrationfortheprobabilitythatX
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MarginalProbabilityDistributions(continuous)
RatherthansummingadiscretejointPMF,weintegrateacontinuousjointPDF.
ThemarginalPDFsareusedtomakeprobabilitystatementsaboutonevariable.
IfthejointprobabilitydensityfunctionofrandomvariablesX andY isfXY(x,y),themarginalprobabilitydensityfunctionsofX andY are:
Sec51.2MarginalProbabilityDistributions 17
,
, (5-3)
X XYy
Y XYx
f x f x y dy
f y f x y dx
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Example54:ServerAccessTime1FortherandomvariablestimesinExample52,findtheprobabilitythatYexceeds2000.
IntegratethejointPDFdirectlyusingthepicturetodeterminethelimits.
Sec51.2MarginalProbabilityDistributions 18
20000 2000 2000
2000 , ,
Dark region left dark region right dark region
XY XYx
P Y f x y dy dx f x y dy dx
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Example54:ServerAccessTime2
Alternatively,findthemarginalPDF andthenintegratethattofindthedesiredprobability.
Sec51.2MarginalProbabilityDistributions 19
0.001 0.002
0
0.002 0.001
0
0.0010.002
0
0.0010.002
3 0.002 0.001
0.001
10.001
6 10 1 for 0
yx y
Y
yy x
yxy
yy
y y
f y ke
ke e dx
eke
eke
e e y
2000
3 0.002 0.001
2000
0.002 0.0033
2000 2000
4 63
2000
6 10 1
6 100.002 0.003
6 10 0.050.002 0.003
Y
y y
y y
P Y f y dy
e e dy
e e
e e
dx
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Mean&VarianceofaMarginalDistribution
MeansE(X)andE(Y)arecalculatedfromthediscreteandcontinuousmarginaldistributions.
Sec51.2MarginalProbabilityDistributions 20
2 2 2 2
2 2 2 2
Discrete Continuous
X X XR R
Y Y YR R
X X X XR R
Y Y Y YR R
E X x f x x f x dx
E Y y f y y f y dy
V X x f x x f x dx
V Y y f y y f y dy
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0.15 0.10 0.05
0.02 0.10 0.05
0.02 0.03 0.20
0.01 0.02 0.25
0 1 2 3
1
2
3
4
ConditionalProbabilityDistributions
Sec2 21
x
y Recall that P A B
P B AP A
FromExample51P(Y=1|X=3)=P(Y=2|X=3)=P(Y=3|X=3)=P(Y=4|X=3)=
Y = 1 2 3 4f (y|X=3)
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ConditionalProbabilityDensityFunctionDefined
Sec51.3ConditionalProbabilityDistributions 23
Given continuous random variables and with joint probability density function , , the conditional probability densiy function of given =x is
, for 0
XY
XYXY x
X
X Yf x y
Y Xf x y
f y f xf x
(5-4)
which satifies the following properties:(1) 0
(2) 1
(3) for any set B in the range of Y
Y x
Y x
Y xB
f y
f y dy
P Y B X x f y dy
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0.15 0.10 0.05
0.02 0.10 0.05
0.02 0.03 0.20
0.01 0.02 0.25
0 1 2 3
1
2
3
4
Mean&VarianceofConditionalRandomVariables
Sec2 27
x
y
Y = 1 2 3 4f (y|X=3) 0.455 0.364 0.091 0.091
FromExample51P(Y=1|X=3)=0.25/0.55=0.455P(Y=2|X=3)=0.20/0.55=0.364P(Y=3|X=3)=0.05/0.55=0.091P(Y=4|X=3)=0.05/0.55=0.091
E(Y|X=3)=
V(Y|X=3)=
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Mean&VarianceofConditionalRandomVariables
TheconditionalmeanofY givenX =x,denotedasE(Y|x)orY|x is:
TheconditionalvarianceofY givenX =x,denotedasV(Y|x)or2Y|x is:
Sec51.3ConditionalProbabilityDistributions 28
(5-6)Y xy
E Y x y f y dy
2 2 2Y x Y x Y x Y xy y
V Y x y f y dy y f y V(Y|x) = E(Y2|x) 2Y|x
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JointRandomVariableIndependence
RandomvariableindependencemeansthatknowledgeofthevaluesofXdoesnotchangeanyoftheprobabilitiesassociatedwiththevaluesofY.
X andY varyindependently. DependenceimpliesthatthevaluesofX areinfluencedbythevaluesofY.
Doyouthinkthatapersonsheightandweightareindependent?
Sec51.4Independence 31
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Exercise510:IndependentRandomVariablesInaplasticmoldingoperation,
eachpartisclassifiedastowhetheritconformstocolorandlengthspecifications.
Sec51.4Independence 32
1 if the part conforms to color specs0 otherwise
1 if the part conforms to length specs0 otherwise
X
Y
Figure510(a)showsmarginal&jointprobabilities,fXY(x,y)=fX(x)*fY(y)
Figure510(b)showtheconditionalprobabilities,fY|x(y)=fY(y)
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PropertiesofIndependenceForrandomvariablesX andY,ifanyoneofthefollowingpropertiesistrue,theothersarealsotrue.ThenXandY areindependent.
Sec51.4Independence 33
(1) ,(2) for all x and y with 0
(3) for all x and y with 0
(4) P , for any sets and in the range of and , respectively. (5-7)
XY X Y
Y XY x
X YX y
f x y f x f y
f y f y f x
f y f x f y
X A Y B P X A P Y BA B X Y
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RectangularRangefor(X,Y)
ArectangularrangeforX andY isanecessary,butnotsufficient,conditionfortheindependenceofthevariables.
IftherangeofXandYisnotrectangular,thentherangeofonevariableislimitedbythevalueoftheothervariable.
IftherangeofXandYis rectangular,thenoneofthepropertiesof(57)mustbedemonstratedtoproveindependence.
Sec51.4Independence 34
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Covariance
Covarianceisameasureoftherelationshipbetweentworandomvariables.
First,weneedtodescribetheexpectedvalueofafunctionoftworandomvariables.Leth(X,Y)denotethefunctionofinterest.
Sec52Covariance&Correlation 49
, , for , discrete
, (5-13), , for , continuous
XY
XY
h x y f x y X YE h X Y
h x y f x y dxdy X Y
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Example519:E(Functionof2RandomVariables)
Sec52Covariance&Correlation 50
Figure512DiscretejointdistributionofXandY.
Task:CalculateE[(XX)(YY)]=covariance
x y f(x,y) xX yY Prod1 1 0.1 1.4 1.0 0.141 2 0.2 1.4 0.0 0.003 1 0.2 0.6 1.0 0.123 2 0.2 0.6 0.0 0.003 3 0.3 0.6 1.0 0.181 0.3 0.203 0.7
1 0.32 0.43 0.3
X = 2.4
Y = 2.0Me
a
n
covariance=
J
o
i
n
t
M
a
r
g
i
n
a
l
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***CovarianceDefined
Sec52Covariance&Correlation 51
The covariance between the random variables X and Y, denoted as cov , or is
(5-14)
The units of are units of times units of .
For example, if the units of
XY
XY X Y X Y
XY
X Y
E X Y E XY
X Y
X are feet and the units of Y are pounds,the units of the covariance are foot-pounds.
Unlike the range of variance, - .XY
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Proof )
Note,however,that , ,
Similarly,itcanbeshownthat ,thus
Sec2 52
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CovarianceandScatterPatterns
Sec52Covariance&Correlation 53
Figure513Jointprobabilitydistributionsandthesignofcov(X,Y).**Notethatcovarianceisameasureoflinearrelationship.**Variableswithnonzerocovariancearesaidtobecorrelated.
XandYareNOT
independent.
XandYareindependent.
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Example520:IntuitiveCovariance
Sec52Covariance&Correlation 54
TheprobabilitydistributionofExample51isshown.
Byinspection,notethatthelargerprobabilitiesoccurasXandYmoveinoppositedirections.Thisindicatesanegativecovariance.
1 2 31 0.01 0.02 0.252 0.02 0.03 0.203 0.02 0.10 0.054 0.15 0.10 0.05
x=numberofbarsofsignalstrength
y=numberoftimescity
nameisstated
Y1
Y2
Y3Y4
0
0.05
0.1
0.15
0.2
0.25
12
3x
Y1
Y2
Y3
Y4
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***Correlation( =rho)
Sec52Covariance&Correlation 55
The between random variables X and Y, denoted as , is
cov , (5-15)
Since 0 and 0, and cov , have the same sign.
We say that
correlation
XY
XYXY
X Y
X Y
XY
XY
X YV X V Y
X Y
is normalized, so 1 1 (5-16)Note that is dimensionless.Variables with non-zero correlation are correlated.
XY
XY
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Example521:Covariance&CorrelationDeterminethe
covarianceandcorrelation.
Sec52Covariance&Correlation 56
x y f(x,y) xX yY Prod0 0 0.2 1.8 1.2 0.421 1 0.1 0.8 0.2 0.011 2 0.1 0.8 0.8 0.072 1 0.1 0.2 0.2 0.002 2 0.1 0.2 0.8 0.023 3 0.4 1.2 1.8 0.880 0.2 1.2601 0.2 0.9262 0.23 0.4
0 0.21 0.22 0.23 0.4
X = 1.8
Y = 1.8
X= 1.1662
Y= 1.1662
S
t
D
e
v
correlation=
J
o
i
n
t
M
a
r
g
i
n
a
l
covariance=
M
e
a
n
Notethestrongpositivecorrelation.
Figure514Discretejointdistribution,f(x,y).
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Example521
Sec52Covariance&Correlation 57
Calculatethecorrelation.
Figure515Discretejointdistribution.Steepnessoflineconnectingpointsisimmaterial.
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IfX andY areindependentrandomvariables,XY =XY =0 (517)
XY =0isnecessary,butnotasufficientcondition forindependence. Figure513d(x,y plotsasacircle)providesanexampleofdependence
DESPITE havingXY =XY =0. Figure513b(x,y plotsasasquare)providesanexampleof
independence AND havingXY =XY =0.
Ingeneral,arectangularpatterindicatesindependence,andthusXY =XY =0.
But,anonrectangularpatternwouldindicatedependence.
IndependenceImplies =0
Sec52Covariance&Correlation 58
Independent XY =XY =0 Dependentbut XY =XY =0 Dependentand XY ,XY 0
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Example523:IndependenceImpliesZeroCovariance
Sec52Covariance&Correlation 59
Figure515Aplanarjointdistribution.
4 22 2
0 0
24 32
0 0
42
0
43
0
116
116 3
1 816 3
1 1 64 326 3 6 3 9
32 4 8 09 3 3
XY
E XY x y dx dy
xy dy
y dy
y
E XY E X E Y
4 22
0 0
24 3
0 0
42
0
4 22
0 0
24 22
0 0
43
0
116
116 3
1 8 1 16 416 2 3 6 2 3
116
116 2
2 1 64 816 3 8 3 3
E X x ydx dy
xy dy
y
E Y xy dx dy
xy dy
y
Let 16 for 0 2 and 0 4Show that 0
XY
XY
f xy x y x y
E XY E X E Y
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Summary1:MarginalProbabilities Marginalprobabilitydistributionfunction
ExpectationandVariance
Sec2 61
Xy
Yx
f x f xy
f y f xy
,
,
X XYy
Y XYx
f x f x y dy
f y f x y dx
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Summary2:CovarianceandCorrelation
Covariance
Correlation
IfX andY areindependentrandomvariables,XY =XY =0
TheoppositeisNOT true.
Sec2 62