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8/3/2019 JUNE+2009+Part+I+FyANVC08+V1++Ch+3,+4,+8 4,+9 2 5,+10!1!6+Vectors,+Newton's+Laws,+Torque,+Pressure

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Part I FyANVC08 Ch 3, 4, 8.4, 9.2-5, 10.1-6 Vectors, Newton's laws, Torque, Pressure NV-College

Directions Please Write your name on all of the papers on your table, NOW!

Test time 8:10-10:40

Resources Calculators, and “Formulas for the National Test in Mathematics Courses A &

B”, and the formula sheet for Physics A, FYANV-College. You may also use

one page of your own formula sheet. The page must have your name and nocalculations or solution to any problem are supposed to be on the paper .

The test: The test consists of a total of 18 problems.

For the problems short answers are not enough. They require:

• that you write down what you do, that you explain your train of thought,

• that you, when necessary, draw figures.

• When you solve problems graphically/numerically please indicate how

you have used your resources.

Problem 17 and 18 are larger problems which may take up to 60 minutes to

solve completely. These problems are of the greatest importance for the

highest grade, MVG. It is important that you try to solve them. A description

of what I will consider when evaluating your work, is attached to the problem.Try all of the problems. It can be relatively easy, even towards the end of the

test, to receive some points for partial solutions. A positive evaluation can be

given even for unfinished solutions.

Score The maximum score is 87 points 4 o6f them VG points and 3¤ Problems.

mark levels The maximum number of points you can receive for each solution is indicated

after each problem. If a problem can give 2 “Pass”-points and 1 “Pass with

distinction”- point this is written (2/1). Some problems are marked with ¤ ,

which means that they more than other problems offer opportunities to show

knowledge that can be related to the criteria for Pass with Special Distinction inAssessment Criteria 2000.

Lower limit for the mark on the test

Pass (G): 29 points

Pass with distinction (VG) : 58 points of which at least 15 “Pass with

distinction points” (VG).

Pass with special distinction (MVG): 60 points of which at least 46 VG “Pass

with distinction points”. The requirements for Pass with distinction must be

well satisfied. Your teacher will also consider how well you solve the ¤- problems. Have Fun Behzad

P 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 SumG 2 1 1 1 1 1 1 1 1 1 2 1 2 2 18

VG 2 1 1 1 1 2 1 1 2 2 1 1 2 2 1 21

G

VG

P 16a 16b 17 18a 18b 19 20a 20b 21a 21b 21c 21d 22 Sum 87 Grade

G 2 2 2 2 2 2 2 2 2 2 1 0 2 23 41

VG 1 1 2 1 4 2 4 4 2 4 25 46

MVG ¤¤¤ ¤¤¤ ¤¤¤ 10¤

G

VGMVG

Not for sale! Free to use for educational purposes! © [email protected] 1




Part IIn the multiple choice problems below, circle the correct alternative and write clearly the

correct answer in the space provided as “Alternative:”

1. A jumbo jet cruises at a constant velocity of hkm / 00012 . In such situations the

engine of the jumbo jet exerts a thrusting force of kN .120 . The acceleration of the

jet, and the force of air resistance on the jet are:

a) 0=a ,

b) hkma / 00012= ,

c) 2 / 82.9 sma = ,

d) 2 / 00012 hkma = ,

e) kN F ceresis .120tan = in the opposite direction of its motion.

f) kN F ceresis .120tan = in the same direction of its motion.

g) kN F ceresis .120tan = perpendicular direction of its motion.

h) kN F ceresis .120tan = up in the opposite direction of its weight.

Answer: Alternatives: ______________________ [2/0]

Why? Explain in the space provided below! [0/2]

2. Martina walks 9 blocks north, and then 12 blocks west. Her displacement is

a) 15 blocks north of west.

b) 21 blocks north of west.

c) 3 blocks north of west.

d) 9 blocks north.

e) 12 blocks west.

Answer: Alternative _______________ [1/0]







3. An object is thrown upwards at sm / 25 . Its acceleration at the top of its motion is:

a) 2 / 82.9 sma = downwards.

b) 2 / 82.9 sma = upwards.

c) 0=

a .d) sma / 25= downwards.

Alternative: ______________ [1/0]


Base your answers to the questions 4 to 6 on the information a

the diagram below. Note that the VG-points are given to your

explanations that give you the opportunity to demonstrate the

depth of your understandings of the physics of the problem. The

explanations

nd

must be written clearly in the space provided.

4. The applied force on the object is represented by the vector:

[

a) 1/0]

C b) D

c) B

d) A

Why? Explain. [0/1]

nswer: Alternative _______________

Explanations:

A

A

B

C

D




5. The object is [1/0]

a) at rest.

b) moving up at constant velocity.

c) moving down at constant velocity.

d) accelerating up the incline in the direction B .

e) accelerating down the incline in the direction A .f) depending on the magnitude of the friction force it could be at rest, moving down

or going up.

Answer: Alternatives: ______________________ [1/0]


6. The angle of the incline is increased. The friction force on the object

a) increases as the angle of the incline increases.

b) is constant and is independent of the angle of the incline.

c) decreases as the angle of the incline increases.

d) first increases for a while, and then decreases.

Answer: Alternative(s): ______________________ [1/0]






Base your answers to the questions 7 to 9 on the information and the diagram below. Note

that the VG-points are given to your explanations that give you the opportunity to

demonstrate the depth of your understandings of the physics of the problem. The

explanations must be written clearly in the space provided.

An object suspended from a dynamometer is lowered into a container filled with water.When the object is completely immersed into the water, volume of the water in the

container increases by 3.250 cm . The dynamometer’s reading on the air is N 805.21 .

You may need the following information:2 / 8.9 smg = , and density of water

33 / 100.1 mkgw ×= ρ

7. The object is made of

a) gold.

b) lead

c) cupper

d) iron

e) woodAnswer: Alternative(s): ______________________ [1/0]

Why? Explain your reasoning and necessary calculations in the space provided below!

[0/1]

8. If the water container was on an scale, and it was showing g.450 before immersing

the object into it, after the object is immersed into the water, the scale will read

a) g.450

b) g.250

c) N .805.21

d) N 055.22

Answer: Alternative(s): ____________________ [1/0]

Why? Draw a free-body diagram and explain your reasoning in the space providedbelow! [0/1]





9. As the object is immersed into the water the reading of dynamometer

a) increases and finally stops at N 805.21 when the object is completely immersed

into the water.

b) decreases and finally stops at N 355.19 when the object is completely immersed

into the water.

c) N 805.21

d) increases and finally stops at N 255.24 when the object is completely immersed

into the water.

e) decreases and finally stops at N 45.2 when the object is completely immersed

into the water.


Why? Draw a free-body diagram and explain your reasoning and solutions in the space

provided below! [0/2]

10. Philip is floating in fresh water. His density is 3 / 900 mkg . How many percent of his

body is above the water surface?a) %10 .

b) %20 .

c) %25

d) %30 .

e) %75 .

f) %90

Answer: Alternative: ______________________ [1/0]


provided below! [0/2]





Base your answers to the questions 11 to 13 on the information and the diagram below.

Note that the VG-points are given to your explanations that give you the opportunity to

demonstrate the depth of your understandings of the physics of the problem. The

explanations must be written clearly in the space provided.

Maximilian stands on a digital bathroom scale in an elevator. The elevator does not haveany window and is in general very quiet and is very difficult without hearing the bell and

seeing the floor-number to know if it is moving or not. Maximilian has designed an

experiment which by using it, you can calculate not only the magnitude of the acceleration

of the elevator, but you can say if it is accelerating up or down.

Maximilian weights kg0.70 .

11. The scale reads kg0.80 .

a) The elevator accelerates upwards at the rate of 2 / 8.9 sma =

b) The elevator accelerates downwards at the rate of 2 / 8.9 sma =

c) The elevator accelerates upwards at the rate of 2 / 4.1 sma =

d) The elevator accelerates downwards at the rate of 2 / 4.1 sma =



provided below!

12. The scale reads kg0.70 .

a) The elevator accelerates upwards at the rate of 2 / 8.9 sma =

b) The elevator accelerates downwards at the rate of 2 / 8.9 sma =

c) The elevator is stationary.

d) The elevator is moving up at a constant velocity

e) The elevator is moving down at a constant velocityAnswer: Alternative(s): ______________________ [2/0]

Why? Explain your reasoning and necessary calculations in the space provided below!

[0/1]





13. As illustrated below, two weights of kg0.6 and kg0.4 are suspended from the

two ends of a cm150 long light rod. The rod is uniform and its mass is kg0.1 . At

what point should the beam be picked up if it is not going to have any tendency to

rotate?

a) cm4.61 from the end kg0.6 is suspended from.

b) cm0.60 from the end kg0.6 is suspended from.

c) cm4.61 from the end kg0.4 is suspended from.

d) From the center of mass of the rod.

Answer: Alternative _______________

kg0.6 kg0.4

cm150

Why? Draw a free body diagram showing clearly all the forces and the pivot point.

Explain and show the details of your calculations in the space provided below.

[0/2]


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