justification of the required time: tas

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Justification of the required time: TAS A 188 190 192 Tl(RILIS ) 5.0E07 7.0E07 9.0E07 Tl(W) 2.5E06 3.5E06 4.5E06 Pb(RILIS ) 1.5E06 1.5E07 4.0E07 Ratio Pb/Tl 0.60 4.29 8.89 % of Pb 37.5 81.1 89.9 No of shifts 0.47 0.17 0.15 No of shifts: time required to have a minimum wish of 10 6 useful counts, taking into account the impurity of the beam, the EC/(EC+alpha) ratio, the planar efficiency (0.1), the K α flourescence yield of 0.49,

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Justification of the required time: TAS. No of shifts : time required to have a minimum wish of 10 6 useful counts, taking into account the impurity of the beam, the EC/(EC+alpha) ratio, the planar efficiency (0.1), the K α flourescence yield of 0.49, and a rate of 5E3 counts/sec in the TAS. - PowerPoint PPT Presentation

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Page 1: Justification of the required time: TAS

Justification of the required time: TAS

A 188 190 192

Tl(RILIS) 5.0E07 7.0E07 9.0E07

Tl(W) 2.5E06 3.5E06 4.5E06

Pb(RILIS) 1.5E06 1.5E07 4.0E07

Ratio Pb/Tl 0.60 4.29 8.89

% of Pb 37.5 81.1 89.9

No of shifts 0.47 0.17 0.15

No of shifts: time required to have a minimum wish of 106 useful counts, taking into account the impurity of the beam, the EC/(EC+alpha) ratio, the planar efficiency (0.1), the Kα flourescence yield of 0.49, and a rate of 5E3 counts/sec in the TAS

Page 2: Justification of the required time: TAS

Justification of the required time: coincidence of TAS&β-delayed particles

No of required shifts: 3.0 for 188Pb

9.2 h is the time required to have a minimum wish of 2x103 useful counts, assuming a branching ratio of 10-5, and efficiency of 0.3 for a particle detector and a counting rate of 10 000 counts/s in the TAS

Page 3: Justification of the required time: TAS

Justification of the required time: high resolution measurement for 188Pb

No of required shifts: 2

Assuming using 3 Ge detectors with efficiencies of ~ 0.01, a transmission of 0.5 up to the high resolution setup and the typical ISOLDE current of 2μA