kii03 ppt 03 01 repaired]

Upload: lynnk1313

Post on 06-Apr-2018

217 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    1/12

    Slide 1- 1Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    2/12

    Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

    INTRODUCTION TO GRAPHING

    Plot points associated with orderedpairs of numbers, determine the

    quadrant in which a point lies.Find the coordinates of a point on agraph.

    Determine whether an ordered pair is asolution of an equation with twovariables.

    3.1

    a

    b

    c

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    3/12

    Slide 1- 3Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

    Objective

    Plot points associated with ordered

    pairs of numbers, determine the

    quadrant in which a point lies.

    a

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    4/12

    Slide 1- 4Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

    Points and Ordered Pairs

    To graph, or plot, points we use two perpendicular

    number lines called axes. The point at which the axes

    cross is called the origin. Arrows on the axes indicate

    the positive directions.

    Consider the pair (2, 3). The numbers in such a pair

    are called the coordinates. The first coordinate in this

    case is 2 and the second coordinate is 3.

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    5/12

    Slide 1- 5Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

    Points and Ordered Pairs continued

    To plot the point (2, 3) we start

    at the origin.

    Move 2 units in the horizontal

    direction.

    The second number 3, is

    positive. We move 3 units in

    the vertical direction (up).

    Make a dot and label the

    point.

    (2, 3)

    (2, 3)

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    6/12

    Slide 1- 6Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

    Example A Plot the point (4, 3).

    Solution

    Starting at the origin,

    we move 4 units in the

    negative horizontaldirection.

    The second number, 3, is

    positive, so we move 3

    units in the positivevertical direction (up).

    3 units up

    4 units left

    (4, 3)

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    7/12Slide 1- 7Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

    The horizontal and vertical axes divide the plane

    into four regions, or quadrants.

    In which quadrant is the

    point (3, 4) located?

    IV

    In which quadrant is thepoint (3, 4) located?

    III

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    8/12Slide 1- 8Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

    Objective

    Find the coordinates of a point on a

    graph.

    b

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    9/12Slide 1- 9Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

    Example BFind the coordinates of pointsA, B, C, D, E, F, and G.

    SolutionPointA is 5 units to the right

    of the origin and 3 units above

    the origin. Its coordinates are

    (5, 3). The other coordinatesare as follows:

    B: (2, 4)

    C: (3, 4)

    D: (3,

    2)E: (2, 3)

    F: (3, 0)

    G: (0, 2)

    AB

    C

    D

    E

    F

    G

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    10/12Slide 1- 10Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

    Objective

    Determine whether an ordered pair is

    a solution of an equation with two

    variables.

    c

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    11/12Slide 1- 11Copyright 2007 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

    ExampleC

    Determine whether each of the following pairs is a

    solution of 4y + 3x = 18: a) (2, 3); b)(1, 5).

    Solutiona) We substitute 2 forx and 3 fory.

    4y + 3x = 18

    43+ 32 | 18

    12 + 6 | 18

    18 = 18 True

    b) We substitute 1 forx and 5 fory.

    4y + 3x = 18

    45+ 31 | 18

    20 + 3 | 18

    23 = 18 False

    Since 18 = 18is true, the pair (2, 3) is a

    solution.

    Since 23 = 18is false, the pair (1, 5) is

    nota solution.

  • 8/3/2019 Kii03 Ppt 03 01 Repaired]

    12/12Slide 1- 12Copyright 2007 Pearson Education Inc Publishing as Pearson Addison-Wesley

    Graph of An Equation

    The graph of an equation is a drawing thatrepresents all its solutions.