kimfis.docx

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Calculate the change in total internal energy for a system that releases 1,34 kj of heat and does 2,98 kj of work on the surroundings Calculate the magnitude of q for a system that does 7,05 kj of work on its surroundings and for which the change in total internal energy is -9,55 kj. Indicate whether heat is absorbed or released by the system Given the thermochemical equation for photosynthesis Calculate the solar energy required to produce 75 gram of C6H12O6 Strategy, the thermochemical equation shows that for every mole of C6H12O6 produced, 2803 kj is absorbed. We need to find out how much energy is absorbed for the production of 75 gram of C6H12O6. We must first find out how many moles there are in 75 gram of C6H12O6. Setup, The molar mass of C6H12O6 is 180g/mol, so 75gram of C6H12O6 is We will multiply the thermochemical equation, including the enthalpy change by 0,416, in order to write the equation in terms of the appropriate amount of glukosa Solution Therefore, 1,17 kj of energy in the form of sunlight is consumed in the production of 75gram of glukosa. Note that the "per mole" units in H are canceled when we multiply the thermochemical equation by the number of moles of glukosa Coba browser baru dengan terjemahan otomatis.Unduh Google Chrome Tutup Terjemahan

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Page 1: kimfis.docx

Calculate the change in total internal energy for a system that releases 1,34 kj of heat and does 2,98 kj of work on the surroundings

Calculate the magnitude of q for a system that does 7,05 kj of work on its surroundings and for which the change in total internal energy is -9,55 kj. Indicate whether heat is absorbed or released by the system

Given the thermochemical equation for photosynthesis

Calculate the solar energy required to produce 75 gram of C6H12O6

Strategy, the thermochemical equation shows that for every mole of C6H12O6 produced, 2803 kj is absorbed. We need to find out how much energy is absorbed for the production of 75 gram of C6H12O6. We must first find out how many moles there are in 75 gram of C6H12O6.

Setup, The molar mass of C6H12O6 is 180g/mol, so 75gram of C6H12O6 is

We will multiply the thermochemical equation, including the enthalpy change by 0,416, in order to write the equation in terms of the appropriate amount of glukosa

Solution

Therefore, 1,17 kj of energy in the form of sunlight is consumed in the production of 75gram of glukosa. Note that the "per mole" units in H are canceled when we multiply the thermochemical equation by the number of moles of glukosa

Coba browser baru dengan terjemahan otomatis.Unduh Google Chrome Tutup Terjemahan

Hitung perubahan total energi internal sistem yang melepaskan 1,34 kj panas dan melakukan 2,98 kj bekerja pada lingkungan

Menghitung besarnya q untuk sistem yang tidak 7,05 kj bekerja pada sekitarnya dan dimana perubahan total energi internal -9,55 kj . Menunjukkan apakah panas yang diserap atau

Calculate the change in total internal enerof heat and does 2,98 kj of w or

Page 2: kimfis.docx

dilepaskan oleh sistem

Mengingat persamaan termokimia untuk fotosintesisHitung energi surya dibutuhkan untuk menghasilkan 75 gram C6H12O6Strategi , persamaan termokimia menunjukkan bahwa untuk setiap mol C6H12O6 diproduksi, 2803 kj diserap . Kita perlu mencari tahu berapa banyak energi yang diserap untuk produksi 75 gram C6H12O6 . Pertama-tama kita harus mencari tahu berapa banyak tahi lalat yang ada di 75 gram C6H12O6 .

Setup, Massa molar C6H12O6 adalah 180g/mol , sehingga 75gram dari C6H12O6 adalah

Kami akan kalikan persamaan termokimia , termasuk perubahan entalpi dengan 0416 , untuk menulis persamaan dalam hal jumlah yang tepat dari glukosa

larutanOleh karena itu , 1,17 kj energi dalam bentuk sinar matahari dikonsumsi dalam produksi 75gram dari glukosa . Perhatikan bahwa " per mol " unit di H harus dibatalkan pada saat kita kalikan persamaan termokimia dengan jumlah mol glukosa