kinetic theory and gas pressure
DESCRIPTION
Kinetic Theory and Gas Pressure. Objectives (d) define the term pressure and use the kinetic model to explain the pressure exerted by gases; (i) state the basic assumptions of the kinetic theory of gases;. Outcomes. ALL MUST Be able to define pressure. - PowerPoint PPT PresentationTRANSCRIPT
Kinetic Theory and Gas Pressure
Objectives
(d) define the term pressure and use the kinetic model to explain the pressure exerted by gases;
(i) state the basic assumptions of the kinetic theory of gases;
OutcomesALL MUST
Be able to define pressure.
Be able to use the kinetic model to describe pressure.
MOST SHOULD
Be able to state the basic assumptions of the kinetic theory of gases.
Be able to use the kinetic model to explain the pressure exerted by gases.
Be able to select and use the equation p=1/3ρv2
SOME COULD
Be able to derive the equation p=1/3ρv2
Pressure
P (Pa) = F (N) / A (m2)
Number ofmolecules
Speed (c)
cp the mostprobable speed
c the meanspeed (theaverage speedof all of themolecules)
crms the rms speedie the root meansquare speed. Auseful concept.Listen carefullyand watch how itis calculated.
The Kinetic Theory of Gases
Thermodynamics
Question (We do not have enough particles here to be realistic but it will illustrate the point!)
6 particles have the following speeds: 600, 650, 650, 700, 725, 750ms-1. Determine the most probable speed cp, the mean speed and the root mean square speed crms.
The Kinetic Theory of Gases
Thermodynamics
The most probable speed cp = 650ms-1 as there are more particles going at that speed than any other.
6 particles have the following speeds: 600, 650, 650, 700, 725, 750ms-1.
The Kinetic Theory of Gases
Thermodynamics
6 particles have the following speeds: 600, 650, 650, 700, 725, 750ms-1.
The mean speed c= (600 + 650 + 650 + 700 + 725 + 750) / 6 = 679.16ms-1.
The Kinetic Theory of Gases
Thermodynamics
The mean square speed= (6002 + 6502 + 6502 + 7002 + 7252 + 7502) / 6
6 particles have the following speeds: 600, 650, 650, 700, 725, 750ms-1.
= 2,783,125 / 6= 463854.17
The root mean square speed crms
= 46385417, .= 681.07ms-1
Assumptions of the kinetic theory of an IDEAL GAS.
1 1 A Gas consists of particles called molecules.
2 2 The molecules are in constant random motion. As many travelling in one direction as any other. The centre of mass
of the gas is at rest.
3 Intermolecular forces are negligible.
4 The duration of collisions between molecules is negligible.
5 Molecules move with constant velocity in between collisions.
6 6 The volume of gas molecules is negligible compared with the volume of the gas.
7 All collisions are totally elastic.
8 Newtonian mechanics can be applied to the collisions.
The Kinetic Theory of Gases
Thermodynamics
l
l
l
m,cx
x
y
z
If these assumptions are correct, we should be able to prove the equation of state for an ideal gas from these assumptions!
WOW!WOW!
The Kinetic Theory of Gases
Thermodynamics
l
l
l
m,cx
x
y
z
Consider the change in momentum as the particle hits the wallp = mcx - -mcx = 2mcx
Time interval between collisions t = 2l/cx
Now F=dp/dt from Newton’s second law so the force Fof one molecule hitting the wall is given by:F=p/t = 2mcx / 2l/cx = mcx
2 / l
But p = F/A so p = (mcx2 / l) / l2 = mcx
2 / l3
If there are N of them thenp = (m / l3 ) (cx1
2 + cx22 + cx3
2 +...........+ cxN2)
Note that (cx12 + cx22 + cx32 +...........+ cxN
2) / N = cx2
so p = (m / l3 ) Ncx2= N(m/V) cx
2 EQ(1)
The Kinetic Theory of Gases
Thermodynamics
so p = (m / l3 ) Ncx2= N(m/V) cx
2 EQ(1)
l
l
l
m,cx
x
y
zPythagoras’ Theorem will show thatc2 = cx
2 + cy2 + cz
2 - considering a general direction
and so c2 = cx2 + cy
2 + cz2
Due to the large no. of particles, cx2 = cy
2 = cz2
so c2 = 3 cx2
from EQ(1) we get pNm
Vc
1
32
pV Nmc1
32
So
OutcomesALL MUST
Be able to define pressure.
Be able to use the kinetic model to describe pressure.
MOST SHOULD
Be able to state the basic assumptions of the kinetic theory of gases.
Be able to use the kinetic model to explain the pressure exerted by gases.
Be able to select and use the equation p=1/3ρv2
SOME COULD
Be able to derive the equation p=1/3ρv2