kinetics lesson 4 pe diagrams
DESCRIPTION
Kinetics Lesson 4 PE Diagrams. Potential Energy Diagrams Kinetic Energy (kJ) Heat energy due to the motion of particles. Simulation Potential Energy or Enthalpy (H). ΔH means change in enthalpy - PowerPoint PPT PresentationTRANSCRIPT
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KineticsLesson 4
PE Diagrams
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Potential Energy Diagrams Kinetic Energy (kJ) Heat energy due to the motion of particles. Simulation Potential Energy or Enthalpy (H).
ΔH means change in enthalpy It is also called the heat of the reaction because it tells you how much heat or KE was produced or consumed by the reaction.
Bond Energy (kJ)
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PE + KE = Total Energy is constant Conservation of Energy PE KE ΔH Reaction Type
Decreases Increases -ve exothermic
Increases Decreases +ve endothermic
When PE (bond energy) decreases it is converted into KE which increases.
Remember that KE is heat energy, so it gets hotter and it is exothermic.
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Potential Energy Diagrams Exothermic
Show the change in potential energy or enthalpy during a successful collision.
Standard Notation: H2 + I2 → 2HI + 170 kJ
ΔH Notation: H2 + I2 → 2HI ΔH = -170 kJ
Both notations indicate an exothermic reaction. The first indicates that 170 KJ of KE are produced, while the second shows that the PE decreases by 170 KJ.
On the right
Or negative
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Lets Explore the Potential Energy Changes during a Single CollisionH2 + I2 → 2HI + 170 KJ
1. An H2 and I2 approach each other
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Lets Explore the Potential Energy Changes during a Single CollisionH2 + I2 → 2HI + 170 kJ
1. An H2 and I2 approach each other
Reactants
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Lets Explore the Potential Energy Changes during a Single CollisionH2 + I2 → 2HI + 170 kJ
1. Reactants H2 and I2 approach each other
Reactants
PE
Reaction Path
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Lets Explore the Potential Energy Changes during a Single CollisionH2 + I2 → 2HI + 170 kJ
2. They collide and become an Activated Complex
PE
Reaction Path
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Lets Explore the Potential Energy Changes during a Single CollisionH2 + I2 → 2HI + 170 kJ
2. They collide and become an Activated ComplexUnstableReaction IntermediateHigh PE Low KEBonds Break & Form
Bonds break
PE
Reaction Path
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Lets Explore the Potential Energy Changes during a Single CollisionH2 + I2 → 2HI + 170 kJ
3. New bonds form and products separate
Products
PE
Reaction Path
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Lets Explore the Potential Energy Changes during a Single CollisionH2 + I2 → 2HI + 170 kJ
3. New bonds form and products separate
Products
bonds form
PE
Reaction Path
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Lets Explore the Potential Energy Changes during a Single CollisionH2 + I2 → 2HI + 170 kJ
3. New bonds form and products separate
Products
PE
Reaction Path
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Ea(for)
Lets Explore the Potential Energy Changes during a Single CollisionH2 + I2 → 2HI + 170 kJ
3. New bonds form and products separate
Products
PE
Reaction Path
Ea(rev)
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Lets Explore the Potential Energy Changes during a Single CollisionH2 + I2 → 2HI + 170 kJ
3. New bonds form and products separate
Products
PE
Reaction Path
Ea
ΔH = -ve
Ea(rev)
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Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the activation energy is 200 kJH2 + I2 → 2HI ΔH = -170 kJ
600
400
200
0
PE (KJ)
Reaction Path
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Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the activation energy is 200 kJH2 + I2 → 2HI ΔH = -170 kJ
600 reactants
400
200
0
PE (KJ)
Reaction Path
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Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the activation energy is 200 kJH2 + I2 → 2HI ΔH = -170 kJ
600 reactants Ea
400
200
0
PE (KJ)
Reaction Path
![Page 18: Kinetics Lesson 4 PE Diagrams](https://reader035.vdocument.in/reader035/viewer/2022062517/56813653550346895d9dd95d/html5/thumbnails/18.jpg)
Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the activation energy is 200 kJH2 + I2 → 2HI ΔH = -170 kJ
600 reactants Ea
400 ΔH
200
0
PE (KJ)
Reaction Path
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Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the activation energy is 200 kJ. H2 + I2 → 2HI ΔH = -170 kJ
600 reactants Ea
400 ΔH
200
0
PE (KJ)
Reaction Path
![Page 20: Kinetics Lesson 4 PE Diagrams](https://reader035.vdocument.in/reader035/viewer/2022062517/56813653550346895d9dd95d/html5/thumbnails/20.jpg)
Potential Energy Diagrams Endothermic Standard Notation: I2 + Cl2 + 100 kJ → 2ICl
ΔH Notation: I2 + Cl2 → 2ICl ΔH = + 100 kJ
Both notations indicate an endothermic reaction. The first indicates that 100 kJ of KE are consumed, while the second shows that the PE increases by 100 kJ.
on leftor positive
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Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ. I2 + Cl2 + 100 KJ → 2ICl
PE 600
400
200
Reaction Path
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Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ. I2 + Cl2 + 100 KJ → 2ICl
PE 600
400
200
Reaction Path
![Page 23: Kinetics Lesson 4 PE Diagrams](https://reader035.vdocument.in/reader035/viewer/2022062517/56813653550346895d9dd95d/html5/thumbnails/23.jpg)
Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ. I2 + Cl2 + 100 KJ → 2ICl
PE 600
400
200
Reaction Path
![Page 24: Kinetics Lesson 4 PE Diagrams](https://reader035.vdocument.in/reader035/viewer/2022062517/56813653550346895d9dd95d/html5/thumbnails/24.jpg)
Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ. I2 + Cl2 + 100 KJ → 2ICl
PE 600
400
200
Reaction Path
![Page 25: Kinetics Lesson 4 PE Diagrams](https://reader035.vdocument.in/reader035/viewer/2022062517/56813653550346895d9dd95d/html5/thumbnails/25.jpg)
Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ. I2 + Cl2 + 100 KJ → 2ICl
PE 600
400
200
Reaction Path
ΔH = + 100 KJ
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Draw the PE diagram if the enthalpy of the reactants is 400 kJ and the energy of the activated complex is 600 kJ. I2 + Cl2 + 100 KJ → 2ICl
PE 600
400
200
Reaction Path
ΔH = + 100 KJ
![Page 27: Kinetics Lesson 4 PE Diagrams](https://reader035.vdocument.in/reader035/viewer/2022062517/56813653550346895d9dd95d/html5/thumbnails/27.jpg)
Draw the PE diagram if the enthalpy of the reactants is 400 KJ and the energy of the activated complex is 600 KJ. I2 + Cl2 + 100 KJ → 2ICl
PE 600
400
200
Reaction Path
ΔH = + 100 KJ
Ea
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Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ
600 400 200
PE (KJ)
Reaction Path
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Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ 600 400 200
PE (KJ)
Reaction Path
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Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ
600 400 200
PE (KJ)
Reaction Path
Ea (rev) = 400 kJ
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Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ
600 400 200
PE (KJ)
Reaction Path
Ea (rev) = 400 kJ
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Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ 600 Ea (for) = 200 kJ
400 200
PE (KJ)
Reaction Path
Ea (rev) = 400 kJ
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Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ 600 Ea (for) = 200 kJ
400 200
PE (KJ)
Reaction Path
Ea (rev) = 400 kJ
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Draw the PE diagram if the enthalpy of the products is 200 kJ, the Ea (for) = 200 kJ, and Ea (rev) = 400 kJ 600 Ea (for) = 200 kJ
400 200
PE (KJ)
Reaction Path
Ea (rev) = 400 kJ
ΔH = -200 kJ
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Exothermic Reaction
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Exothermic Reaction
Uncatalyzed reaction
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Exothermic Reaction
Uncatalyzed reactionCatalyzed reaction
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Exothermic Reaction
Reactants
Products
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Exothermic Reaction
Reactants
Productsstronger bonds
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Exothermic Reaction
Downhill in PEKE is produced
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Exothermic Reaction
Downhill in PEKE is produced
Ea(for)(uncat)
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Exothermic Reaction
Downhill in PEKE is produced
Ea(for)(cat)
Ea(for)(uncat)
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Exothermic Reaction
Downhill in PEKE is produced
H
Ea(for)(cat)
Ea(for)(uncat)
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Exothermic Reaction
Downhill in PEKE is produced
H
Ea(rev)(cat)Ea(for)(cat)
Ea(for)(uncat)
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Exothermic Reaction
Downhill in PEKE is produced
H
Ea(rev)(cat)Ea(for)(cat)
Ea(for)(uncat) Ea(rev)(uncat)
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PE(kJ)500
400
300
200
100
0reaction path
H forward =H reverse =Ea forward uncat =Ea reverse uncat =Ea forward cat =
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PE(kJ)500
400
300
200
100
0reaction path
H forward = -300 kJH reverse =Ea forward uncat =Ea reverse uncat =Ea forward catalyzed =
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PE(kJ)500
400
300
200
100
0reaction path
H forward = -300 kJH reverse = +300 kJEa forward uncat =Ea reverse uncat =Ea forward catalyzed =
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PE(kJ)500
400
300
200
100
0reaction path
H forward = -300 kJH reverse = +300 kJEa forward uncat = 100 kJEa reverse uncat =Ea forward catalyzed =
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PE(kJ)500
400
300
200
100
0reaction path
H forward = -300 kJH reverse = +300 kJEa forward uncat = 100 kJEa reverse uncat = 400 kJEa forward catalyzed =
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PE(kJ)500
400
300
200
100
0reaction path
H forward = -300 kJH reverse = +300 kJEa forward uncat = 100 kJEa reverse uncat = 400 kJEa forward catalyzed = 50 kJ
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PE(kJ)
reaction path
Slow rate due to high Ea
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PE(kJ)
reaction path
The only way to change the PE diagram is to add a catalyst.
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PE(kJ)
reaction path
The only way to change the PE diagram is to add a catalyst.More low energy collisions are successful!
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PE(kJ)
reaction path
Slow rate due to high Ea
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PE(kJ)500
400
300
200
100
0reaction path
Increasing the temperature does not change the diagram. It gives more collisions the required Ea and more are successful.Increasing the concentration, pressure, and surface area does not change the diagram.