l-2/t-1ime date: 30/0112012

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. .

L-2/T-1IME Date: 30/0112012'BANGLADESH UNIVERSITY OF ENGINEERING AND TECHNOLOGY, DHAKA

L-2/T-l B. Sc. Engineering Examinations 2010-2011

Sub: EEE 259 (Electrical and Electronic Technology)

Full Marks: 280 Time: 3 Hours

USE SEPARATE SCRIPTS FOR EACH SECTION-_._--_ ....~----_....._-_._ ..._--- ..._-_._--_ .._ _-_ __ ..__._-

SECTION-A

There are FOUR questions in this section. Answer any THREE.

The figures in the margin indicate full marks.

. 1. (a) How does the voltage buildup in a shunt DC generator during starting? What could

cause voltage buildup failure on starting? How can these problems be remedied? Explain

briefly with appropriate diagrams. (20)(b) What types of losses are present in a real DC machine? Draw the power flow diagram

for DC machines. (11%)(c) The magnetization curve for a shunt DC generator is given in Figure for Q. l(c).

Following informations are given: RA = 0.5 n, RF = 57.5 n, Radj = 0 - 100 n.Determine:

(i) the critical resistance.

(ii) the value of Radjto produce an internal voltage of 270 V.

(iii) the value of internally generated voltage when Radj= 100 n.

(15)

2. (a) Derive the torque-speed characteristics of shunt and series DC motors and compare

between them. (14 %)(b) Explain briefly Ward-Leonard speed control system for dc motors. What are the

advantages and disadvantages of this system? (20)(c) A 20 hp, 220 V, 1500 r.p.m. DC shunt motor with compensating winding has an

armature resistance of 0.01 n. It's no-load speed is 1500 r.p.m. The field circuit is

composed' of an internal resistance.of 20 n and an adjustable resistance which can be

varied between 0 - 150 n. There are 1000 turns per pole on the field windings. Calculate

(assuming no armature reaction) speed of the motor when input current is 75 A, 125 A

and 175 A. (Assume Radj= 75 n). (12)

3. (a) Draw the exact equivalent circuit of a transformer. From this obtain the approximate

equivalent circuit by making reasonable assumptions. (11 %)(b) Describe briefly the open circuit and short circuit tests of a transformer with necessary

diagrams. Discuss how different parameters of the equivalent circuit can be obtained

from these tests. (20)

(c) For the circuit shown in Fig. for Q. 3(c) calculate the value of Eout and Ip. (Assume

frequency = 60 Hz). :2. > (15)Contd P12

=2=

EEE259 (ME)

4. (a) Prove that a set of balanced three-phase currents can produce a rotating magnetic field.

(b) Draw the equivalent circuits of synchronous motor and generator.

(c) A 220 V, 60 Hz, 8 pole Y connected induction motor has following parameters:

Rl = 0.15 n, R2 = 0.2 n, Xl = 0.45 n, X2 = 0.45 n XM = 29.8 nFor a slip of2.8% at the rated voltage and frequency, find the motor's

(i) Starting torque

(ii) Speed

(iii) Power factor

(iv) Converted and output power

(v) induced torque,

(vi) load torque

(vii) efficiency

Given that rotational losses are 940 Wand are assumed to be constant. The core loss is

lumped in with the rotational loss.

SECTION -B

There are FOUR questions in this section. Answer any THREE.

The questions are of equal value.

5. (a) Describe diode equivalent circuits models.

(b) Draw input and output waveform of bridge rectifier in a same plot. (Consider

practical diodes). Also prove for a bridge rectifier, the ripple factor is 1.21. (Consider

Ideal diodes).

(c) Assuming the diodes to be ideal, find the values of I and V in the circuits. Consider

constant voltage drop model diode.

(11%)(10)

(25)

- 10" ill/1i7T

Contd P/3

•

=3=

EEE 259 (ME}

6. (a) Considering constant voltage drop model diode, draw output waveform for the

following circuit.

.....1--....

~ -t--_._.__ __-__._..- ----- -~.._ - _"V,._ .. 0

----- --- - 5.';1 -,.-- ---". -_ ......:..- - __..

---~~--------c.-------,-"-,,~,,,~=,=,,-,~. t.~_.-_._\._- _._-_-,o---- .

I \

1•.•.... 10:-"..I

(b) Explain the operating principle and characteristic of emitter follower circuit. Also

mention its uses.

(c) For the values of Vee = 19 V, 20 V, and 21 V, calculate the positions of Q-points for

all 3 cases. 1-- .....~------_ .._~---V"'A> ~.! '-"'-

.. 1

---........•~.-.,.'_.~~•..•~ ~.•.•..,,~.".!

.•_~ •.••-, ,.•.~_."_ft~•.•.•.....__ ••_•..•.,,_ ••••_._ •••~_,,,

........_ :--_ _ , _ -f3z ~O----~-_ ,'I

.¥.,_._~"~~.._-._ ..--,- ..~.."'"..~._~.•,.. j...........................•.•

","_ h~q _c~, j~ .._~{~ __[ I' ,,~. I: a ..~ '0{ • '''''"1: ~ ~ efc':7"'~"."

7. (a) Draw cross section diagram of cathode ray tube.

(b) Explain the operating principle of a linear variable differential transformer.

Graphically show the variation of output voltage with linear displacement for an LVDT.

8. (a) Show that the sum of the instantaneous powers in a three phase system is constant.

(b) Explain two-wattmeter method for ~-connected load with proper phasor diagram and

equations.

I-~•••• 1"""

"""

V

~300--<

~'"a..

OJ)e'l:..•... 200-0>

"0a....•...e'l:•••a..=a.. 100OJ)~--e'l:=•••a....•...=~ 0

o 1 2 3Field current, IF (A)

Figure for Question l(c)

4 5

Rsig= 5n Transformer WithRI = 0.2 n,R2 =

0.12 n, Xl = 0.41 n,X2 = 0.41n,

XM = 00, Rc= 00,

N = 100 N =10

Figure for Question 3(c)

~;/.

+Eout

RL=250n

L-2/T-l/ME Date: 22/02/2012BANGLADESH UNIVERSITY OF ENGINEERING AND TECHNOLOGY, DHAKA

L-2/T-l B. Sc. Engineering Examinations 2010-2011

Sub: ME 201 (Basic Thermodynamics)



USE SEPARATE SCRIPTS FOR EACH SECTION

SECTION-A

There are FOUR questions in this Section. Answer any THREE.P-h chart (R-13 4a) supplied. Steam Table (SI) supplied.

Assume reasonable data if necessary

1. (a) Deduce an expression of air standard thermal efficiency of a Diesel cycle engine, in

terms of compression ratio and cut-off ratio. (16 %)(b) What is the limitation of using higher compression ratio in Otto cycle engines?

Briefly explain. (15)(c) An air standard cycle operates with a compreSSIOn ratio of 16 and maXImum

temperature of 1500 °C. Air at the beginning of compression stroke is at 25°C and 1 bar

pressure. Calculate the following (15)(i) Cut-off ratio (ii) Cycle efficiency (iii) MEP.

2. (a) Briefly explain the working principle of a Turbo-Jet engine. How is the performance

of a jet engine is expressed?

(b) Define pressure ratio. Briefly discuss the effect pressure ratio on the performance of

Brayton cycle gas turbine, in relation to efficiency and net work.

(c) A simple Brayton cycle operates with a maximum and minimum temperature of 1000

°C and 30°C respectively. The pressure ratio is 6 and the isentropic efficiency of the

compressor is 85% and that of the turbine is 90%. Calculate the actual cycle efficiency.

(16 %)

(16)

(14)

(10)

(8)

(12)

3. (a) Briefly explain the role of the regenerator on the performance ofa Stirling cycle.

(b) Write a short note on "Thermo-Electric Refrigeration".

(c) Define "Equivalence Ratio". State the reasons why rich or lean air-fuel mixtures are

needed for combustion in engines.

(d) The dry volume basis analysis of natural gas in a burner shows 10% CO2, 0.5% CO,

2.5% O2 and 87% N2. Calculate the mass basis AF ratio and Equivalence ratio. Comment

on the amount of air used. (16%)

4. (a) Briefly explain "Sub-coding" and "Superheting" In a vapour compression

refrigeration cycle. (8)(b) Draw a schematic diagram of an NH3-Water vapour absorption refrigeration system

identifying the compounds. (12)Contd P12

=2=ME 201Contd ... Q. NO.4

(c) When an air conditioner is operated in summer, lots of water needs to be drained out

from it. Briefly explain this situation in relation to psychometry.

(d) An ideal vapour compression cycle using R-134a operates with an evaporator

temperature of -10°C and condenser temperature of 40°C. If the cooling capacity of the

system is 4 TR, calculate -

(i) Mass flow rate of the refrigerant

(ii) Power required to drive the compressor

(iii) COP and EER of the system.

SECTION -B

There are FOUR questions in this Section. Answer any THREE.Assume reasonable values for missing data, if any. Necessary charts are attached.

(10%)

(16)

5. (a) State the Kelvin - Planck and Clausius statements of the Second Law of

Thermodynamics and show their equivalence with an example. (26%)(b) What do you understand by 'Perpetual Motion Machine of the First and Second

kind'? (12)(c) It is known that the temperature of air rises as it is compressed. An inventor thought

about using this high-temperature air to heat buildings. He used a compressor driven by

an electric motor. The inventor claims that the compressed hot-air system is 25% more

efficient than a resistance heating system that provides an equivalent amount of heating.

Is this claim valid? Or is this an perpetual motion machine? explain. (8)

6. (a) Explain First Law of Thermodynamics as an energy conservation principle. (10)(b) Give the energy balance formula for commonly used steady flow devices. Give an

example ofIsoenthalpic Steady-flow device. (16)(c) Air at 600 kPa and 500 K enters an adiabatic nozzle that has an inlet-to-exit area ratio

of2:1. The inlet air velocity is 120 mls and leaves with a velocity of380 mls. Determinethe exit air temperature and exit pressure of the air. The relationship between properties

of air can be found from the table below: (20%)T(k) h (KJ/kg) u (KH/kg)400 400.98 286.16450 451.80 322.62500 503.02 359.49550 555.74 396.86

7. (a) Draw the pressure -vs. Volume diagram for pure substances that - (i) expand on

freezing and (ii) Contract on freezing. Show different phases on the diagrams. (14)

Contd P/3

..

..=3=

ME 201Contd ... Q. NO.7

(b) What do you understand by 'Triple Point' and 'Sublimation'? How can these be used

to serve practical purpose? (10)(c) Derive the expression of work done for a polytropic process. What happens to the

workdone expression when the process is isothermal? (16)(d) A friction less piston-cylinder device contains 2 Kg of nitrogen at 100 kPa and 300 K.

Nitrogen is now compressed slowly according to the relation pyl.4 = Constant until it

reaches a final temperature of 360 K. Calculate the work input during this process.

Assume the process to be Quasi - Equilibrium. Also take nitrogen as an ideal gas.

8. (a) How does Rankine Cycle eliminate various limitations of Camot cycle? How does it

improve the efficiency?

(b) What do you know about Superheating?

(c) Consider a regenerative cycle using steam as the working fluid steam leaves the boiler

and enter the turbine at 4 MPa, 400°C. After expansion to 400 kPa, some of the steam is

extracted from the turbine to heat the feedwater in an open feedwater heater. The pressure

in the feedwater heater is 400 kPa, and the water leaving it is saturated liquid at 400 kPa.

The steam not extracted expands to 10 kPa. Determine the cycle efficiency.

(c) What is 'Binary Yapour Power cycle'?

(25)

€)

750700650600550500450400350300250200150

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Prepared by CENTER FOR APPLIED THERMODYNAMIC STUDIES. University of IdahoCOPYRIGHT 1992 AMERICAN SOCIETY OF HEATING. REFERlGERATING AND

AIR-CONDITIONING ENGINEERS

Enthalpy (kI/kg)

~IIFIGURE Bl Pressure-enthalpy diagram for refrigerant R134a.

/J <9'" ---_.-.. .... ..'~ • -. -~. - •• -•• _-. -"""T"-

'able A.5 Saturated Steam Temperature Table Table A.5 Saturated Steam.Temperature Table (Coll/illued)

Specific Volu~e Internal Energy Enthalpy Entropy Specific Volume Internal Energy Enthalpy

Temp. Press. Sat. Sat. Sat. 'Sat. Sat. Sal. Sat. Sal. Temp. Press. Sat. . Sat. Sat. Sat. Sat. Sat. Sat. Sat.'C kPa Liquid Vapor Liquid Evap. Vapor Liquid Evap. Vapor Liquid Evap. Vapor °C MPa Liquid Vapor Liquid Evap. Vapor Liquid Evap. Vapor Liquid Evap. VaporT P. ~r v. Ur u" u. h, h,o "0 5, Sf. S. T P v, v. u, UfO U. h, h,o It, s, s" -'.0.01 0.6113 0.001 000 206.14 .00 2375.3 2375.3 .0] 2501.3 2501.4 .0000 9.1562 9.1562 250 3.973 0.001251 0.050 13 1080.39 1522.0 2602.4 J 085.36 1716.2 2801.5 2.7927 3.2802 6.0730

5 0.8721 0.001 000 147.12 20.97 2361.3 2382.3 20.98 2489.6 2510.6 .0761 8.9496 9.0257 255 4.319 0.001 263 0.045 98 1104.28 1496.7 2600.9 1109.73 1689.8 2799.5 2.8383 3.1992 6.037510 1.2276 0.001 000 106.38 42.00 2347.2 2389.2 42.01 2477.7 2519.8 .1510 8.7498 8.9008 260 4.688 0.001 276 0.042 21 1128.39 1470.6 2599.0 1134.37 1662.5 2796.9 2.8838 3.1181 6.001915 1:7051 0.001 001 77.93 62.99 2333.1 2396.1 62.99 2465.9 2528.9 .2245 8.5569 8.7814 265 5.081 0.001 289 0.038 77 1152.74 1443.9 2596.6 1159.28 1634.4 2793.6 2.9294 3.0368 5.966220 2.339 0.001 002 57.79 83.95 2319.0 2402.9 83.96 2454.1 2538.1 .2966 8.3706 8.6672 270 5.499 0.00 I 302 0.035 64 1177.36 1416.3 2593.7 1184.51 1605.2 2789.7 2.9751 2.9551 5.930125 3.169 0.001 003 43.36 104.88 2304.9 2409.8 104.89 2442.3 2547.2 .3674' 8. 1905 8.5580 275 5.942 0.001 317 0.032 79 1202.25 1387.9 2590.2 12JO.07 1574.9 2785.0 3.0208 2.8730 5.893830 4.246 0.001 004 32.89 125.78 2290.8 24 I6.6 125.79 2430.5 2556.3 .4369 8.0164 8.4533 280 6.412 0.001 332 0.030 17 1227.46 1358.7 2586.1 1235.99 1543.6 2779.6 3.0668 2.7903 5.857135 5.628 0.001 006 25.22 146.67 2276.7 2423.4 146.68 2418.6 2565.3 .5053 7.8478 8.3531 285 6.909 0.001 348 0.027 77 1253.00 1328.4 2581.4 1262.31 1511.0 2773.3 3. I 130 2.7070 5.819940 7.384 0.001 008 19.52 167.56 2262.62430. I 167.57 2406.7 2574.3 .5725 7.6845 8.2570 290 7.436 0.001 366 0.025' 57 1278.92 1297. I 2576.0 1289.07 1477.1 2766.2 3.1594 2.6227 5.782145 9.593 0.001 010 15.26 188.44 2248.4 2436'.8' 188.45 2394.8 2583.2 .6387 7.5261 8.1648 295 7.993 0.001 384 0.023 54 1305.2 1264.7 2569.9 1316.3 1441.8 2758.1 3.2062 2.5375 5.743750 ]2.349 0.001012 12.03 209.32 2234.2 2443.5 209.33 2382.7 2592.1 .7038 7.3725 8.0763 300 8.581 0.001 404 0.021 67 1332.0 1231.0 2563.0 1344.0 1404.9 2749.0 3.2534 2.4511 5.704555 15.758 0.0010l5 9.568 230.21 2219.9 2450.1 230.23 2370.7 2600.9 .7679 7.2234 7.9913 305 9.202 0.001 425 0.019948 1359.3 1195.9 2555.2 1372.4 1366.4 2738.7 3.30]0 2.3633 5.664360 19.940 0.001017 7.67 I 251.11 2205.5 2456.6 251.13 2358.5 2609.6 .8312 7.0784 7.9096 310 9.856 0.001447 0.018350 1387.1 1159.4 2546.4 1401.3 1326.0 2727.3 3.3493 2.2737 5.623065 25.03 0.001.020 6.197 272.02 2191.1 2463.1 272.06 2346.2 ~618.3 .8935 6.9375 7.8310 315 10.547 0.001472 0.016867 1415.5 1121.J 2536.6 1431.0 1283.5 2714.5 3.3982 2.1821 5.580470 31.19 0.001 023 5.042 292.95 2176.6 2469.6 292.98 2333.8 2626.8 .9549 6.8004 7.7553 320 11.274 0.001499 0.015488 1444.6 1080.9 2525.5 1461.5 1238.6 2700. I 3.4480 2.0882 5.536275 38.58 0.001 026 4.13 I 313.90 2162.0 2175.9 313.93 2321.4 2635.3 1.0155 6.6669 7.6824 330 12.845 0.001 561 0.012 996 1505.3 993.7 2498.9 1525.3 1140.6 2665.9 3.5507 1.8909 5.441780 47.39 0.001 029 3.407 334.86 2147.4 2482.2 331.91 2308.8 2643.7 1.0753 6.5369 7.6J22 340 14.586 O.OOJ638 0.010797 1570.3 894.3 2464.6 1594.2 1027.9 2622.0 3.6594 1.6763 5.335785 57.83 0.001 033 2.828 355.81 2 J 32.6 2488.4 355.90 2296.0 2651.9 1.J343 6.4 102 7.5445 350 16.513 0.00 J 740 0.008 813 1641.9' 776.6 2418.4 1670.6 893.4 2563.9 3.7777 1.4335 5.211290 70.14. 0.001 036 2.361 376.85 2117.7 2494.5 376.92 2283.2 2660.1 I. 1925 6.2866 7.4 791 ~ 360 18.651 0.00 J 893 0.006 945 1725.2 626.3 2351.5 1760.5 720.5 2481.0 3.9147 1.1379 5.052695 84.55 0.001 040 .. l..982 397.88 2102.7 2500.6 397.96 2~70.2 2668.1 1.2500 6.1659 7.4159 370 21.03 0.002 213 0.004 925 1844.0 384.5 2228.5 1890.5 441.6 2332.1 4.1106 . .6865 4.797 I..

374.14 22.09 0.003 155 0.003 155 2029.6 0 2029.6 2099.3 o 2099.3 4.4298 o 4.4298100 0.10135 0.001014 1.6729 418.94 2087.6 2506.5 419.04 2257.0 2676.1 1.3069 6.0480 7.3549105 O.I20 82 0:00 I 048 1.4194 440.02 2072.3 2512.4 440.15 2243.7 2683.8 1.3630 5.9328 7.2958

SOURCI': Reproduced from loseph H. Keenan. FrederickG. Keyes, Philip G. Hill. and Joan G. Moor~, Sfca", Table.r (New York: J.ohn Wiley &J 10 0.143 27 0.00 I 052 1.2102 461.14 2057.0 2518.1 461.30 2230.2 2691.5 1.4185 5.8202 7.2387 Sons, Inc., 1969) with permission. '.J 15 0.169 06 0.001 056 1.0366 482.30 2041.4 2523.7 482.48 2216.5 2699.0 1.4734 5.7100 7.1833120 0.198 53 0.00 I 060 0.8919 503.50 2025.8 2529.3 503.71 2202.6 2706.3 1.5276 5.6020 7.1296 Table A.6 Saturated Steam Pressure Table125 0.2321 0.001 06.5 0.7706 524.74 2009.9 2534.6 524.99 2188.5 2713.5 1.5813 5.4962 7.0775130 0.2701 0.001 070 0.6685 546.02 1993.9 2539.9 546.31 2174.2 2720.5 1.6344 5.3925 7.0269 Specific Volume Internal Energy Enthalpy Entropy135 0.3130 0.001 075 0.5822 567.35 1977.7 2545.0 567.69 2159.6 2727.3 1.6870 5.2907 6.9777140 0.36J3 0.001 080 0.5089 588.74 1961.3 2550.0 589.13 2144.7 2733.9 1.7391 5.1908 6.9299 Press. Temp. Sat. Sat. Sat. Sat. Sat. Sat. Sat. Sat.145 0.4 I54 0.001 085 0.4463 610.18 1944.7 2554.9 610.63 2]29.6 2740.3 1.7907 5.0926 6.8833 kPa' °C ' 'Liquid Vapor Liquid E\'ap. Vapor Liquid Evap. Vapor Liquid Evap. Vapor150 0.4758 0.001091 0.3928 631.68 1927.9 2559.5 632.2Q. 2114.3 2746.5 1.8418 4.9960 6,8379 p T V, u, h, hI. ".155 0.5431 0.001 096 0.3468 653.24 1910.8 2564.] 653.84 2098.6 . 2752.4 1.8925 4.9010 6.7935 v. U," u. -'r Sfg S.

J60 0.6178 0.001 102 0.3071 674.87 1893.5 2568.1 675.55 2082.6 2758. J 1.9427 4.8075 6.7502 0.6113 0.01 0.001 000 205.14 .00 2375.3 2375.3 .01 2501.3 2'!;01.4 .0000 9.1562 9.1562165 0.7005 0.001 108 0.2727 696.56 1876.0 2572.5 697.34 2066.2 2763.5 1.9925 4.7153 6.7078 1.0. 6.98 0.001 000 129.21 29.30 2355.7 2385.0 29.30 2484.9 2514.2 .1059 8.8697 8,9756170 0:7917 0.001 114 . 0.2428 718.33 1858.1 2576.5 719.21 2049.5, 2768.7 2.0419 4.6244 6.6663 1.5 13.03 0.001 001 87.98 54.7] 2338.6 2393.3 54.71 2470.6 2525.3 .1957 8.6322 8.8279175 0.8920 0.001 12 I 0.2168 7<10.17 1840.0 2580.2 741.17 2032.4 2773.6 2.0909 4.5347 6.6256 2.0 17.50 0.001 001 67.00 73.48 2326.0 2399.5 73.48 2460.0 2533.5 .2607 8.4629 8.7237180 1.0021 0.001 127 0.19405 762.09 1821.6 2583.7 763.22 2015.0 2778.2 2.1396 4.446J 6.5857 2.5 21.08 0.001 002 54.25 88.18 2315.9 2404.4 88.49 2451.6 2540.0 .3120 8.331 I 8.6432185 1.1227 0.001 134 0.17409 784. I 0 1802.9 2587.0 785.37 1997. I 2782.4 2.1879 4.3586 6.5465 3.0 24.08 0.001 003 45.67 101.04 2307.5 2408.5 101.05 2444.5 2545.5 .3545 8.2231 8.5776190 1.254'4 0.001 141 0.15654 806.19 17S:U 2590.0 807.62 1978.8 2786.4 2.2359 4.2720 6.5079 4.0 28.96 0.001 004 34.80 121.45 2293.7 2415.2 121.46 2132.9 2554.4 .4226 8.0520 8.4746195 1.3978 0.001 149 0.14105 828.37 1764.4 2592.8 829.98 1960.0 2790.0 2.2835 4.1863 6.1698 5.0 32.88 0.001 005 28.19 137.81 2282.7 2420.5 137.82 2423.7 2561.5 .4764 7.9187 8.3951200 1.5538 0.001 157 0.12736 850.65 1744.7 2595.3 852.45 1940.7 2793.2 2.3309 4.1014 6.4323 7.5 40.29 0.001 008 19.24 168,78 2261.7 2430.5 J68.79 2406.0 2574.8 .5764 7.6750 8.2515205 1.7230 0.001 164 0.11521 873.04 1724.5 2597.5 875.04 1921.0 2796.0 2.?780 4.0172 6.3952 10 45.81 0.001 ell 0 14.67 191.82 2246.1 2437.9 191.83 2392.8 2584.7 .6493 7.5009 8.1502210 1.9062 0.001 173 0.10441 895.53 1703.9 2599.5 89776 1900.7 2798.5 2.4248 3,9337 6.3585 15 53.97 0.001 014 10.02 225.92 2222.8 2448.7 225.94 2373.1 2599.1 .7549 7.2536 8.0085215 2.104 OOCI 181 0.094 79 918.14 1682.9 260 I.] 920.62 1879.9 2800.5 2.4714 3.8507 6.322] 20 60.06 0.001017 7.649 .251.38 2205.1 2456.7 251.40 2358.3 2609.7 .8320 7.0766 7.9085220 2.318 0.001 190 0086 19 940.87 1661.5 2602.4 94362 1858.5 2802. I 2.5178' 3.7683 6.286] 25 64.97 0.001 020 6.204 271.90 2191.2 2463. J 271.93 2346.3 2618.2 .8931 6.9383 7.8314. 225 2.548 0.001 199 0.07849 96:1.73 1639.6 2603.3 966.78 1836.5 2803.:\ 2.5639 3.6863 6.2503 30 69.10 0.001 022 5.229 289.20 2179.2 2468.4 289.23 2336.1 2625.3 .9439 6.8247 7.7686230 2.795 0.001 209 0.071 58 986.74 1617.2 2603.9 990.12 1813.8 280'1.0 2.6099 3.60-J7 6.2146 40 75.87 0.001 027 3.993 317.53 2159.5 2477.0 317.58 2319.2 2636.8 1.0259 6.6411 7.6700235 :,.060 0.001 219 0.065 37 1009.89 J594.2 2604.1 lO13.62 1790.5 2804.2 2.6558 3.52:,3 6.1791 50 . 81.33 0.001 030 3.240 310.41 2143.4 2483.9 340..19 23051 2645.9 1.0910 6.5029 7.5939240 3.344 0.001 229 0.059 76 10:>3.21 15708 2604.0 1037.32 J 766.5 2"803.8 2.7015 3.4122 6.1137 75 91.78 0.001037 2.217 :\84.31 21 12.4 24967 384.39 2278.6 2663.0 1.2130 6.2434 74564' 245 3.618 0.0012'10 0.05171 1056.71 1546.7 2603.1 106 J.2:, 11'11.7 2803.0 27472 3.%12 6.1083)vIPa .0.100 99.63 0.001 013 1.6940 417.36 2088.7 2506.1 417.46 2258.0 267S.5 1.3026 6.0568 7.3594• 0.125 105.99 0.001 018 1.3749 441.19 2069.3 2513.5 414.32 2211.0 2685.4 1.3740 5.9104 7.2844

0.150 111.37 0.001 053 I. I 593 466.94 2052.7 2519.7 '167.1 J 2226.5 2693.6 1.4336 5.7897 7.2233Telllp. v h s u 0.175 J 16.06 0.001 057 1.0036 186.80 2038.1 2524.9 486.99 22136 2700.6 1.4849 5.6868 7.17179 °C m3/kg kJ/kg kJ/kg K kJ/kg 0.200 120.23 0.001 061 0.8857 504.49 2025.0 2529.5 501.70 2201.9 2706.7 1.5301 5.5970 7.1271PACt: 1/~~ 0.225 124.00 0.001 064 0.7933 520.47 2013. I 2533.6 520.72 2 I91.3 2712.1 1.5706 5.5173 7.0878

)0'

..,0 ,'-;., , @).

OUReE;. Reproduced from Joseph H, Keenan. Frederick G. Keyes. Philip .G. Hill, and Joan G. Moore, Steam TilhI,'s (New York: John 'Vile)' &:.OIlS. Inc .. 1969) wilh permission.

•. PAGE 2i4

••

Table A.6 Saturated Steam Pressure Table (Continued)

SpecifIC Volume

6.89596.92997.17067.37897.56627.8985

6.66286.81587.0384 .7.23287.40897.57167.86738.13338.37708.60338.81539.01539.20509.38559.5575 ,

8.1913.8:45588.69878.92449.13629.33609.52569.70609.8780

h

3484.93702.43926.54157.3.4395.14639.44890.25146.85408.8

u

2553.6 2738.62564.5 2752.8.2646.8 2860:52726.1 2964.22804.83066.82964.4. 3273.4 ~

3129.23300.23477.93662.43853.94052.04256 ..54467.04682.8

2576.8 2769.12630.6 2839.32715.5 2950.02797.2 3056.52878.2 3 I61.72959.7 3267.13126.0 3480.63297.9 3699.43476.2 3924.23661.1 4155.63852.8 4393.74051.0 4638.24255.6 4889. I4466.1 5145.94681.8 5407.9

P = .10 MPa (99.63)

2506.7 2676.2 7.36142582.8 2776.4 7.61342658. I 2875.3 7.83432733.7 2974.3 8.03332810.4 3074.3 8.21582967.9 3278.2 8.54353131.6 3488.1 8.83423301.9 3704.7 9.09763479.2 3928.2 9.33983663.5 4158.6 9.56523854.8 4396. I 9.77674,052.8 4640.3 9.97644257.3 4891.0 10.16594467.7 5147.6 10.3463

.4683.5 5409.5 10.5 I83

P = .40 MPa (143.63)

p = .40 MPa (143.63)

p = .80 MPa (170.43)

v

.2404

.2608

.2931

.3241

.3544

.3843

.4433

.5018

.5601

.6181

.6761

.7340

.7919

.8497

.9076

.4625

.4708

.5342

.5951

.6548

.7726

1.6940 2506.1 2675.5 7.3594

1.69581.93642.1722.4062.6393.1033.5654.0284.4904.9525.;414 .5.8756.3::176.7997.260

.88931.00551.12151.23721.35291.46851.584{l1.69961.8151

6.99197.07787.31157.51667.70228.0330

7.5939

7.69477.94018.15808.35568.53738.86429.15469.4178:9.65999.8852

10.096710.296410.485910.6.66210.8382

8.32518.58928.83199.05769.26929.46909.65859.8389

10.0110

. 6:76006.96657.18167.37247.54647.70798.00218.26748,51078.73678.94869.14859.33819.51859.6906

hu

2543.6 2725.32570.8 2761.02650.7 2865.62728.7 2967.62806.7 3069.32965.6 3275.0

2511.6 2682.52585.6 2780.12659.9. 2877.72735.0 2976.0281 1.3 . 3075~52968.5 3278.93132.0 3488.73302.2 3705.13479.4 3928.53663.6 4158.93854.9 4396.34052.9 4640.54257.4 489U4467.8 5147.74683.6 5409.6

2483.9 2645.9

3130.0 3486.03300.8 3703.23478.4 3927.13662.9 4157.83854.2 4395.44052.3 4639.74256.8 4890.-14467.2 5147.14683.0 5'109.0

2567.4 2756.82638.9 2850.12720.9 2957.22801.0 3061.62881.2 3165.72962. I 3270.33 J 27.6 3482.83299.'1 3700.93477.0 3925.33661.8 4156.53853.4 4394.44051.5 4638.84256.1 .4889.64466.5 5146.34682.3 ,,408.3

P = .30 MPa (133.55)

p = .050 MPa (81.33)

P = .60 MPa (J 58.85)

v

3.240

l' = .30 MPa (133.55)

3.4183.8894.3564.8205.2846.2097.1348.0578.9819.904

10.82811.75112.67413.59714.521

.6058

.6339

.7163

.7964.,87531.0315

1.18671.34141.49571.64991.80411.95812.11212.26612.4201.

.3157

.3520

.:~938

.4344

.4742

.5)3i

.5920

.6697

.7472

.8245

.9017

.97881.05591.13301.2101

7.12727.27957.50667.70867.89268.2218

6.82137.05927.27097.45997.63297.79388.08737.35228.59528.821 I9.03299.232B9.42249.60299.7749

8.15028.17498.44798.68828.90389.10029.28139.60779.8978

10.160810.4028/0.628110.83.9611.039311.228711.409111.5811

h

2748.72855.42960.73064.23167.73271.93483.93701.73925.94156.94394.74639.14889.95146.65408.6

u

2529.5 2706.72576.9 2768.82654.4 2870.52731.2 2971.02808.6 3071.82966 ..7 3276.6

2437.9 2584.72443.9 2592.62515.5 2687.52587.9 2783.02661.3 2879.52736.0 2977.32812.1 3076.52968.9 3279.63132.3 3489.13302.5 3705.43479.6 3928.73663.8 4159.03855.0 4396.44053.0 4640.64257.5 4891.24467.9 5147.84683.7 5409.7

2561.22642.92723.52802.92882.62963.23128,43299.63477.53662.13853.64051.84256.34466.84682.5

p = .20 MPa (120.23)

p = .010 MPa (45.81)

P <;: .20 MPa (120.23)

3 I30.8 3487.1 8.5 I33330"1.4 3704.0 8.77703478.8 3927.6 9.01943663.1 4 i58.2 9.24493854.5 4395.8 9.45664052.5 4640.0 9.65634257.0 4890.7 9.84584467'.5 5147.3 10.02624683.2 5409.3 10.1982

I' = .50 MPa (151.86)

v

.8857

.95961.08031.19881.31621.5493

1.78142.0132.2442.4752.7062.9373.1683.3993.630

.. 3749.4249.4744.5226.5701.6173.7109.8041.8969.9896

1.08221.17471.26721.35961.4521

T

Silt.150200250300'100

500600700800900

1000110012001300

Sat.200250300350400500600700800900

1000110012001300

Table A) Superheated Steam Vapor Table

Sat. 14.67450 14.869

100 17.196150 19.512200 21.825250 .24.136300 26.445400 31.063500 35.679600 40.295100 44.91 I800 49.526900 54.141

1000 58.757. 1100 63.372

1200'67.9871300:. 72.602

Sat.Vapor

s.EvaI"S,g

Entropy

Sat.Liquid

s,

1.6072 5.4455 7.05271.6408 5.3801 7.02091.6718 5.3201 6.99191.7006 5.2646 6.96521.7275 5.2130 6.94051.7528 5.1647 6.9175I.7766 5.1193 6.89591.8207 5.0359 6.85651.8607 4.9606 6.82131.8973 4.8920 6.78931.9312 4.8288 6.76001.9627 4.7703 6.73311.9922 4.7158 6.70802.0200 4.6647 6.68472.0462 4.6166 6.66282.0710 4.5711 6.64212.0946 4.5280 6.62262.1172 4.4869 6.60412.1387 4.44786.58652.1792 4.3744 6.55362.2166 4.3067 6.52332.2515 4.2438 6.49532.2842 4.1850 6.46932.31 iii> - 4~i29S-6A44r2.385 J 4.0044 6.38962.4474 3.8935 6.34092.5035 3.7937 6.29722.5547 3.7028 6.25752.6457 3.5412 6.18692.7253. 3.4000 6.12532.7964 3.2737 6.070 I2.9202 3.0532 .').97343.0267 2.8625 5.88923.1211 2.6922 5.81333.2068 2.5364 5.74323.2858 2.3915 5.67723.3596 2.2544 5.6J413.4295 2.1233 5.55273.19621.9962 5.492-13.5606 1.8718 .').43233.6232 1.7485 5.37173.6848 1.6249 5.30983.7461 1.4994 5.2455:~.8079 1.3698 5.17773.8715 1.2329 5.1044:~.9!\88 1.0839 5.02284.0139 .9130 4.92694.1075 .693B 4.8013-1.3110 .2216 4.53274.4298 0 4.4298 ...

Sat.Vapor

h.EvaI"h,.

2181.5 2716.92'172.4 2721.32163.8 2725.32155.8 2729,02148.1 2732.42140.8 2735.62133.8 2738.62120.7 2743.92 I08.5 2748.72097.0 2753.02086.3 2756.82076.0 2760.32066.3 2763.52057.0 2766.42048.0 2769.12039.4 2771.6203 J.J 2773.92023. I 2776. I2015.3 2778.12000.4 2781.71986.2 2784.81972.7 2787.61959.7 2790.01947.32792:21917.9 2796.41890.7 2799.51865.2 2801.71841.0 2803. I1795.7 2804.2175!!.7 2803.41714.1 2801.41640.1 . 2794.31571.0 2784.31505.1 2772.11441.3 2758.01378.9 2742.11317.1 2724.71255.5 2705.61193.6 2684.91130.7 2662.21066.5 2637.61000.0 2610.5930.6 2580.6856.9 2547.2777.1 2509.1688.0 2464.5583.1 2409.7446.2 2334.6143.4 2165.6

o 2099.3

Enthalpy

Sal.Liquid

h,

Sat.Vapor

u.EvaI"

U11J

2002.1 2537.2 535.371991.9 2540.5 548.89]932.4 2543.6 561.471973.5 2546.4 573.251965.0 2548.9. 5134.331956.9 2551.3 594.811949.3 .2553.6 604.741934.9 2557.6 623.251921.6 2561.2 640.231909.2 2564.5 655.93J 897.5 2567.4 670.561886.5 2570.1 684.281876.1 2572.5 697.221866.1 .2574.7 709.471856.6 2576.8 721.1 I1847.4 2578.7 732.221838.6 2580.5 742.831830.2 2582.1 753.021822.0 2583.6 762.811806.3 2586.4 781.34J791.5 2588.8 798.651777.5 2591.0 814.931764.1 2592.8 830.30175-Jj'2594-:-5--'844~89 .172 1.4 2597.8 878.501693.8 2600.3 908.791668.2 2602.0 936.491644.0 2603.1 962.111599.3 2604.1 1008.421558.3 2603.7 1049.751520.0 2602.3 1087.3 I1449.3 2597.1 1151.231384.3 2589.7 1213.351323.0 2580.5 1267.001264.2 2569.8 .1316.641207.!1 2557.8 1363.261151.4 2544.4 1407.:;61096.0 2529.8 1450.11040.7 2513.7.1491.3985.0 2496.1 1:;31.';928.2 2476.8 1571.1869.8 2455.5 1610.5809.0 2431.7 1650.1744.8 2405.0 1690.3675.4 2374.~1 1732.059R.I 2~138.I 1776.5:;07.5 2293.0 1826.3:~88.5 2nO.6 1888.412!>.2 2087.1 2022.2

o 2029.6 2099.3

Imernal Energy

Sat.Liquidu,535.10548.59561.15572.90583.95594.40604.31622.77639.68655.32669.90683.56696.44708.64720.22731.27741.83751.95761.68780.09797.29813.44828.70843:16876.46906.44933.83959.11

1004.781015.431082.311147.811205.441257.55130.';.571350.:;11393.041433.71473.0151 LI1518.61585.61622.71660.21698.91739.9178:;.61842.11961.92029.6

Sat.Vapor

v.

Sat.I.iquid

VJ

0.001067 0.71870.001 070 0.65730.001 073 0.60580.001 076 0.56200.001 079 0.52430.001 081 0.49140.00 I 084 0.46250.001 088 0.41400.001 093 0.37490.001 097 0.34270.001 101 0.31570.001 104 0.29270.001 108 0.27290.001 112 0.25560.001 115 0.24040.001 118 0.22700.001 121 0.21500.001 124 0.20420.001 127 0.194440.0011330.177530.001 139. 0.J63 330.001 144 0.151250.001 149 0.140840.001 -154 0:13 i.770.0011660.113490.001 Iii 0.099630.001 187 0.08875o.ooi 197 0.079980.001 2J7 0.066680.001 235 0.057070.001 252 0.049780.001 286 0.039440.001 319 Om2 44 .0.001351 0.027370.001 384 0.023 520.001 41B 0.020480.001 452 0.0180260.001 489 0.015 9870.00 I 527 0.014 2630.00 I 567 0.012 7800.001 611 0.011 4850.001 658 0.0103370.00 I 711 0.009 3060.001 770 0.0083640.00 I 840 0.007 4890.001 924 0.0066570.002 036 0.005 8340.002 207 0.004 9520.002 742 0.003 5680.003 155 0.003 155

Temp..CT

127.44130.60133.55136.30138.88141.32143.63147.93151.86155.48158.85162.01164.97167.78170.43172.96175.38177.69179.91184.09187.99191.64195.07198.32205.76.212.422 I8.45223.99233.90242.60250.40263.99275.64285.88295.06303.40311.06318.15324.75330.93 .336.75342.24347.44352.37357.06361.54365.81369.89373.80374.11

Press.MPap

0.2500.2750.3000.3250.3500.3750.400.450.500.550.600.650.700.750.800.850.900.951.001.101.201.30

.l:4~1.501.752.002.252.53.03.5

456789

\0_"II121314J516171819202122

22.09

• ~,. to

~-'II',

.- •... . --.'- ..-'-. ..._ ... -- , .•.----- .....

Table A.7 Superheated Steam Vapor Table (Continued) Table A:7 Superheated Steam VaporTable (Continued)

T v u It s v u It s v u h s T v u h s v u h s v u h

P = 4.0 MPa (250.40) P = 4.5 MPa (257.49) P = 5.0 MPa (263.99)P = 1.00 MP. (179.91) P = 1.20 l\IPa 087.99) . P = 1.40 MPa'O 95.07)

• Sat. .04978 2602.3 2801.4 6.0701 .04406 2600.1 2798.3 6.0198 .03944 2597.1 2794.3 5.9734Sat. .19444 2583.6 2778.1 6.5865 .16333 2588.8 2784.8 6.5233 .14084 2592.8 2790.0 6.4693 275 .05457 2667.9 2886.2 6.2285 .047 30 2650.3 2863.2 6.1401 .041 41 2631.3 2838.3 6.0544200 .2060 2621.9 2827.9 6.6940 ',.16930 2612.8 2815.9 6.5898 .14302 2603.1 2803.3 6.4975 300 .05884 2725.3 2960.7 6.3615 .051 35 2712.0 2943.1 6.2828 .045 32 2698.0 2924.5 6.2084250 .2327 2709.9 2942.6 6.9247 .19234 2704.2 2935.0 6.8294 .16350 2698.3 2927.2 6.7467 350 .06645 2826.7 3092.5 6.5821 .05840 2817.8 3080.6 6.5131 .051 94 2808.7 3068.4 6.4493300 .2579 2793.2 3051.2 7.1229 .2138 2789.2 :~045.8 7.0317 .18228 2785.2 3040.4 6.9534 400 .073 41 2919.9 3213.6 6.7690 .064 75 29'13.3 3204.7 6.7047 .0578J 2906.6 3195.7 6.6459350 .2825 2875.2 3157.7 7.3011 .2345 2872.2 3153.6 7.2]2] .2003 2869.2 3149.5 7.1360 450 .08002 3010.2 3330.3 6.9363 .07074 3005.0 3323,3 6.8746 .063 30 2999.7 3316.2 6.8186400 .3066 2957.3 3263.9 7.4651 .2548 2954.9, 3260.7 7.3774 .2178 2952.5 3257.5 7,3026 500 .08643 3099,5 3445,3 7,0901 ,0765] 3095.3 3439.6 7.0301 .06857 3091.0 3433,8 6,9759500 .3541 3124.4 3478,5 7,7622 .2946 3122.8 3476,3 7,6759 .2521 3121.1 3474.1 7.6027 600 .09885 3279.] 3674.4 7,,3688 .087 65 3276.0 3670.5 7,3110 .078 69 3273.0 3666,5 7.2589600 .4011 3296.8 3697.9 8,0290 .3339 3295.6 3696.3 7,9435 ,2860 3294.4 3694.8 7.8710 700 .11095 3462.1 3905.9 7.6198 .09847 3459.9 3903,0 7.5631 .08849 3457,6 3900.1 7,5122700 .4478 3475,3 3923,1 8.2731 .3729 3474.4 3922.0 8,1881 .3195 3473,6 3920.8 8.1160 800 .12287 3650.0 4141.5 7.8502 .109 II 3648.3 4139.3 7.7942 .098 11 3646.6 4137.1 7,7440800 .4943 3660.4 4154.7 8.4996 .4118 3659.7 4153.8 8.4148 .3528 3659.0 4153.0 8,3431 900 .13469 3843.6 4382.3 8.0647 ,11965 3842.2 4380,6 8.0091 .10762 3840.7 4378,8 7,9593900 ,5407 3852.2 4392.9 8,7118 .4505 ' 3851.6 4392,2 8.6272 ,386J 3851.1 4391.5 8.5556 1000 .14645 4042.9 4628.7 8.2662 ,130 13 4041.6 4627.2 8,2108 .11707 .4040.4 4625,7 8,1612

1000 .5871 4050,5 4637.6 8.9119 .4892 4050.0 4637.0 8.8274 .4192 4049.5 4636.4 8.7559 1100 .]58 17 4248.0 4880.6 8.4567 .14056 4246.8 4879.3 8.4015 .12648 4245,6 4878,0 8,35201100 ,6335 4255.1 4888.6 9,1017 .5278 4254,6 4888,0 9.0172 .4524 4254,1 4887,5 8,9457 1200 .16987 4458.6 5138.1 8.6376 ,15098 4457.5 5136.9 8.5825 .13587 4456.3 5135.7 8.53311200 .6798. 4465.6 5145.4 9.2822 ,5665 4465.1 5144.9 9.1977 .4855 4464.7 5144.4 9.1262 1300 ,J,8156 4674.3 5400,5 8.8100 .161 39 4673.1 5399.4 8,7549 .14526 4672.0 5398.2 8,70551300 ,7261 4681.3 5407.4 9.4543 .6051 4680,9 5407.0 9.3698 ,5186 4680.4 5406.5 9.2984

P = 6.0 MPa (275.64) P = 7.0 MPa (285,88) P = 8.0 MPa (295.06)P = 1.60 MPa (201.41) p= 1.80MPa (207,15) P = 2,00 MPa (212.42)

Sat. .03244 2589.7 2784.3 5,8892 .02737 2580.5 2772,1 5.8133 .023 52 2569.8 2758.0 5.7432Sat. .12380 2596.0 2794.0 6.4218 .11042 2598.4 2797.1 6,3794 ,099 63 2600,3 2799,5 6.3409 300 .03616 2667.2 2884.2 6,0674 .02947 2632,2 2838.4 5,9305 ,02426 2590.9 2785.0 5,7906225 .13287 2644.7 2857,3 6,5518 .11673 2636.6 2846,7 6.4808 ,10377 2628.3 2835,8 6.4147 350 .042 23 2789.6 3043.0 6.3335 .03524 2769.4 3016.0 6,2283 .029 95 2747.7 2987,3 6,1301250 .141 84 2692.3 2919.2 6.6732 .12497 2686.0 2911.0 6.6066 ,III 44 2679:6 2902.5 6,5453 400 ,047 39 2892.9 3177.2 6.5408 .03993 2878,6 3158.1 ' 6.4478 ,03432 2863.8 3138.3 6.3634300 ,15862 278 I.I 3034,8 6.8844 .14021 2776,9 3029,2 6,8226 ,12547 2772,6 3023.5 6,7664 450 ,052 14 2988.9 3301.8 6.7193 .04416 2978.0 3287.1 6.6327 ,038 17 2966.7 3272.0 6.5551350 .17456 2866,1 3J45.4 7.0694 ,154,57 2863.0 3141.2 7,OJOO ,13857 2859.8 3137.0 6.9563 500. ,05665 3082,2 3422,2 6.8803 .048 14 3073.4 3410.3 6.7975 .041 75 3064.3 3398.3 6.7240400 .19005 2950.1 3254.2 7,2374 .16847 2947.7 3250,9 7,1794 .151 20 29452 3247,6 7,1271 550 ,061 OJ 3174.6 3540.6 7,0288 .05195 3J67.2 3530,9 6.9486 ,04516 ,3159,8 3521.0 .6.8778500 .2203 3119,5 3472.0 7,5390 ,19550 3117.9 3469.8 7.4825 .17568 3116.2 3467.6 7.4317 600 ,06525 3266.9 3658.4 7.1677 .05565 3260,7 ,3650.3 7.0894 ,.04845 3254.4 3642.0 7.0206600 .2500 3293.3 3693,2 7.8080 .2220 3292.1 3691.7 7.7523 .19960 3290,9 3690.1 7,7024 _._"--,._-_ ...- ___ ,__ ._. ___ '_~" __ • ____ ••• M~ ••• __ '_'_'_ 0_ •

700 ,2794 3472.7 3919.7 8.0535 2482 3471.8 -3918.5 7.9983 .2232.. ,3470,,9 ,3917,47,9487 P = 6.0 MPa (275.64) P = 7,0 MPa (285.88) P = 8.0 MPa (295.06)'.____. _ ." ._ _ _'_.~:"'" ..:._~.-.~ ....__ --;-.-:.. __ ,_..: ".c::.'_:,~,:-: ~.~ :_:.~..~. ..". _:-._:.'._.,~ • .: __ ~_~'-~" .: ":-:'::;":;.':".;•.-.:\ .~.<:~_... :-~~'",.~':. ~,,':'~'."... ___ .__

P= 1.50 MPa (201.41) P = 1.80 MPa (207.i5) P = 2.00 MPa (212.42)700 .073 52 3453,1 3894,2 7.4234 .06283 3448.5 3888.3 7.3476 :05481 3443,9 !l882.4 7.2812 '

800 .081 60 3643,1 4]32,7 7.6566 .06981 3639.5 4128.2 7.5822 .06097 3636,0 4123.8 7.5173800 .3086 3658.3 4152.1 8.2808 .2742 3657,6 4151.2 8,2258 .2467 3657.0 4150,3 8,1765

3837,8 4375.3 7.8727 .07669 3835,0 4371.8 7.7991 .067 02 3832, J 4368.3 7,7351900 ,3377 3850.5 4390.8 ' 8.4935 .3001 3849.9 4390,1 8.4386 ,2700 3849.3 4389.4 8,3895 900 .08958 7,9384 : .1000 ,09749 4037.8 4622.7 8.0751 .08350 4035.3 4619.8 8.0020 .073 01 4032,8 4616,9

1000 .3668 4049.0 4635.8 8.6938 .3260 4048.5 4635.2 8,6391 .2933 4048,0 4634.6 8,59014243.3 4875.4 '8.2661 .09027 4240,9 4872.8 8.1933 .07896 4238.6 4870.3 8.1300

1100 .3958 4253.7 4887.0 8.8837 ,3518 4253.2 4886.4 8.8290 ,3166 4252.7 4885,9 8.7800 1100 ,105368.4474 .09703 4451.7 5130.9 8,3747 .084 8~ 4449.5 5128,5 8,3115

1200 .4248 4464.2 5143.9 9,0643 ,3776 4463.7 5143.4 9,0096 .3398 4463,3 5142,9 8,9607 i 1200. .11321 4454,0 5133.3.10377 4667,3 5393.7 8.5473 .09080 4665.0 5391.5 8.4842

1300 .4538. 4679,9 5406.0 9.2364 :4034 4679.5 5405.6 9,18J8 .3631 4679.0 5405,1 9.1329 1300 ' .121 06 4669,6 5396.0 8.6199

P = 2,50 MPa (223.99) P = 3.00 MPa (233,90) P = 3.50 MPa (242.60) P = 9.0 MPa (303.40) P = 10.0 MPa (311.06) P = 12.5 MPa (327.89)

ISat. .07998 2603.1 2803.1 6.2575 .06668 2604.1 2804,2 6.1869 .057 07 2603.7 2803.4 6.1253 Sal. ,02048 2557.8 2742.] 5.6772 .018 026 2544.4 2724.7 5,6141 .013 495 2505, I 2673:8 5.4624

225 .08027 2605.6 2806.3 6.2639 325 ,02327 2646,6 2856.0 5,8712 ,019861 2610.4 2809.1 5.7568250 .087 00 2662.6 2880,1 6.4085 .07058 2644.0 2855.8 6.2872 ,058 72 2623,7 2829.2 6.1749 350 ,02580 2724:4 2956.6 6.0361 ,022 42 2699,2 2923.4 5.9443 .016 126 2624,6 2826.2 5,7118

300 .09890 2761.6 3008.8 6.6438 ,081 14 2750,1 2993.5 6.5390 .06842 2738.0 2977,5 6.4461 400 ,02993 2848.4 3117.8 6.2854 .02641 2832.4 3096,5 6,2120 ,02000 2789.3 3039.3 6,0417

350 .10976 2851.9 3126.3 6,8403 .09053 2843.7 3,115.3 6,7428 ,07678 2835.3 3104.0 6,.6579 450 .033 50 2955,2 3256,6 6,4844 .029 75 2943.4 3240.9, 6.4190 .02299 2912,5 3199.8 6.2719

400 .12010 2939.1 3239,3 7.0148 .09936 2932.8,3230.9 6.9212 ,08453 2926.4 3222,3 6.8405 500 ,03677 3055.2 3386.1 6.6576 .032 79 3045.8 3373,7 6,5966 ,02560 3021.7 3341.8 6.4618

450 ,130 14 3025.5 3350.8 7.1746 .10787 3020.4 3344.0 7,0834 .091 96 3015.3 3337,2 7,0052 550, .03987 3152,2 3511.0 6,8142 .035 64 3144,6 3500,9 6.7561 ,02801 3125.0 3475,2 6.6290

500 .13998 3112,1 3462.1 7.3234 .11619 3108.0 3456.5 7,2338 .099 18, 3103.0 3450.9 7,1572 600 ,042 85 3248.1 3633.7 6.9589 .038 37 3241.7 3625.3 6.9029 .03029 3225.4 3604.0 6.7810

600 .159 30 3288.0 3686.3 7,5960 .13243 3285.0 3682.3 7.5085 ,113 24 3282,1 3678.4 7.4339 650 .045 74 3343.6 3755.3 7.0943 .041 01 3338,2 3748.2 7.0398 ,03248 3324.4 3730.4 6.9218

I 700 .17832 3468.7 3914.5 7,8435 ,14838 3466.5 3911.7 7.7571 .12699 3464.3 3908,8 7.6837 700 ,04857 3439,3 3876.5 7.2221 ,043 58 3434.7 3870.5 7.1687 m460 3422.9 3855.3 7.0536

800 .197 16 3655.3 4148,2 8.0720 .164 14 3653.5 4145.9 7,9862 .14056 3651.8 4143.7 7,9134 800 .05409 3632.5 4119.3 7.4596 .04859 3628,9 4114,8' 7.4077 ,03869 3620.0 4103.6 7.2965

t 900 .21590 3847,9 4387.6 8.2853 .17980 3846.5 4385.9 8.1999 .15402 3845.0 4384.1 8.1276 900 .05950 3829,2 4364.8 7.6783 .05349 3826.3 4361.2 7.6272 ,042 67 3819,1 4352.5 7.5182

1000 .2346 4046.7 4633.1 8.4861 .19541 4045.4 4631.6 8.4009 .16743 4044,1 4630.1 8.3288 1000 .06485 4030.3 4614,0 7.8821 ,058 32 4027,8, 4611.0 7,8315 .04658 4021,6 4603.8 7.72374234.0 .050 45 4228,2 4858.8 7.9165

,1100 .2532 4251.5 4884.6 8.6762 ,21098 4250.3 4883.3 8,5912 ,18080 4249,2 4881.9 8.5192 1100 .070 16 4236,3 4867,7 8.0740 ,063 12 4865.1 8.0237

f1200 :2718 4462.1 5141:7 8.8569 .22652 4460,9 5140.5 8.7720 .194 15 4459.8 5139.3 8,7000 1200 .07544 4447,2 5126,2 8.2556 .067 89 4444.9 5123,.8 8,2055 .05430 4439.3 5118,0 8.0987

1300 .2905 4677.8 5404.0 9.0291 .24206 4676.6 5402.8 8.9442 .20749 4675.5 5401.7 8,8723 1300 ,080 72 4662.7 53'89,2 8.4284 .07265 4460.5 5387.0 8.3783 .058 13 4654.8 5381,4 8.2717, •,

(/i\<',E 3j4••

'"•...~-~'''''''.-''~.

~---~ ---_ .._-'_..

L-2/T-l/ME Date: 22/0112012

BANGLADESH UNIVERSITY OF ENGINEERING AND TECHNOLOGY, DHAKA

L-2/T-1 B. Sc. Engineering Examinations 2010-2011

Sub: ME 241 (Engineering Mechanics)




SECTION -A

There are FOUR questions in this Section. Answer any THREE.

Symbols indicate their usual meaning.

1. (a) A 40 kg cylinder is supported by three wires as shown in figure for Q. No. 1(a).

Determine the tension in each-wire. Use vector method. (237j )

(b) A force of magnitude 300 N acts at the point A in a plane parallel to x-y as shown in

the figure for Q. No. l(b). Replace this 300 N force by an equivalent force-couple

system at O. Use vector method.

\I

I

\-

/z

x.

Contd P12

(23)

I','

=2=

ME 241

2. (a) A frame is shown in the figure forQ. No. 2(a). Determine the force in the member

CD when P = 1.5 kN and t/J = 30°. Also determine reactions at A and B. (23 %)~-~-"- - =-"~,-="_._-,--=,-=-"._="=~,._-=-,,=-=, =.._._=., .. _-=----=-".,.=.__._-=._,.-=..... ~, ---- ••• _e ••• _-.,

B

5m

(b) Using section method determine the forces in the members DG and DF of the truss

as shown in Fig. for Q. No. 2(b). State whether the members are in tension or

compressIOn.

==,=-=="',_.:.~--'''''--,-===------'''', ..:_,-,----,,,.~---,,---

50kN 80kN 50kN

l l l I

A 10m C 10m 0 10m G 10m H

~--B 10m E 10m F

____ E~.YIY-__~,,-_&-.$_. N_2~"g~J!)------'-1___ .J,

3. (a) A glass rod AB as shown in figure for Q. No. 3(a), weighs 0.142 kg and is 150 mm

long. It is placed in a glass tumbler C in a position of equilibrium. If the tumbler is 63

mm diameter and if all surfaces are smooth, what is the angle e?_....._"----~'..,""--.----=-=.

A

c

(23)

(23%)

(b) A uniform ladder of mass 12 kg, rests against a wall and a horizontal surface as

shown in Fig. for Q. No. 3(b). If the coefficient of friction at A and B is 0.3, find the

smallest force that will prevent motion of the ladder to the left at A. (23)

Contd P/3

"

' ..

=4=

ME 241Contd ... Q. No.5

(b) The 10-kg block B is supported by the 40-kg block A which is pulled up an incline

by a constant 500 N force as shown in Figure for Q. 5(b). Neglecting friction between

the block and the incline and knowing that block B does not slip on block A, determine

the smallest allowable value of the coefficient of static friction between the blocks. (20)

6. (a) Block A moves down with a constant velocity of 1 m/s as shown in Figure for

Q. 6(a). Determine (i) the velocity of block C, (ii) the relative velocity of portion D of

the cable with respect to block A. (20)

--Eigure forQ. 6(a)

(b) As shown in Figure for Q. 6(b) a thin circular rod is supported in a vertical plane by

a bracket at A. A sprint is attached to the bracket and loosely wound around the rod of

constant k = 40 Nlm and undeformed length equal to the arc of circle AB. A 200-g collar

C, is not attached to the spring, can slide without friction along the rod. Knowing that

the collar is released from rest at an angle () with respect to the vertical, determine

(i) the smallest value of () for which the collar will pass through D and reach point A,

(ii) the velocity of the collar as it reaches point A.

Contd .... : ..... PIS

(26%)

- . ~i'"

••

=4=

ME 241Contd eo. Q. No.5

(b) The 10-kg block B is supported by the 40-kg block A which is pulled up an incline

by a constant 500 N force as shown in Figure for Q. 5(b). Neglecting friction between

the block and the incline and knowing that block B does not slip on block A, determine

the smallest allowable value of the coefficient of static friction between the blocks. (20)

6. (a) Block A moves down with a constant velocity of 1 m1s as shown in Figure for

Q. 6(a). Determine (i) the velocity of block C, (ii) the relative velocity of portion D of

the cable with respect to block A. (20)

-figure forQ. 6(a)

(b) As shown in Figure for Q. 6(b) a thin circular rod is supported in a vertical plane by

a bracket at A. A sprint is attached to the bracket and loosely wound around the rod of

constant k = 40 Nlm and undeformed length equal to the arc of circle AB. A 200-g collar

C, is not attached to the spring, can slide without friction along the rod. Knowing that

the collar is released from rest at an angle e with respect to the vertical, determine

(i) the smallest value of e for which the collar will pass through D and reach point A,

(ii) the velocity of the collar as it reaches point A.

~_-=F-=-i,glirefor Q. 6(b)

Contd PIS

(26%)

),,::-

....

=5=

ME 241

7. (a) Collars A and B are pin-connected to bar ABD and can slide along fixed rods as

shown in Figure for Q. 7(a). Knowing that at the instant shown the velocity of A is 0.9

m/s to the right, determine (i) the angular velocity of ABD, (ii) the velocity of point D. (20)

(b) A cord is wrapped around the inner drum of a wheel and pulled horizontally with a

force of 200 N as shown in Figure for Q. 7(b). The wheel has a mass of 50 kg and a

radius of gyration of 70 mm. Knowing that JLs = 0.20 and JLk = 0.15, determine the"\

acceleration of G and the angular acceleration of the wheel. (267j )

1000101 OOmm

200N

(20)

,/

1J. ,

1,II .

Figure for Q. 7(b)

(a) A uniform rod of length Land mass m is supported as shown in Figure for Q. 8(a)

with b = 0.2 L, when the cable attached to end B suddenly breaks. Determine at this

instant (i) the acceleration of end B, (ii) the reaction at the pin support. r--1

I1- '--- - ------1ii

8.

~ F--"igurefor Q~(~) _.~-~(b) Knowing that at the instant as shown in Figure for Q. 8(b) the angular velocity of rod

AB is 15 rad/s clockwise, determine (i) the angular velocity of rod BD, (ii) the velocity

of the midpoint of rod BD. (267j )~.---.---'----------

Figure for Q. 8(b)

L-2/T-l/ME Date: 07/03/2012BANGLADESH UNIVERSITY OF ENGINEERING AND TECHNOLOGY, DHAKA

L-2/T-I B. Sc. Engineering Examinations 2010-2011

Sub: MATH 261 (Vector Calculus, Matrices, Laplace Transforms and Series Solutions)

Full Marks: 280 Time: 3 HoursThe figures in the margin indicate full marks.Symbols used have their usual meanings.


SECTION -AThere are FOUR questions in this Section. Answer any THREE.

1. (a) Define the following with examples: ~ (16 %)(i) Upper Triangular Matrix (ii) Symmetric Matrix,(iii) Skew-Symmetric Matrix (iv) Trace of a Matrix,

(b) Are the following vectors linearly dependent? If so, express each of the following

vector as a linear combination of the other two. (15)Yl = (0,3, 1, -1), Y2= (6, 0, 5, 1), Y3 = (4, -7, 1,3).

(c) Determine the values of A so that the following system of linear equations

x + y + AZ = 1

x + AY+ z= A

AX + y + Z = A2

has (i) Unique solution (ii) No solution (iii) Infinitely many solutions.

2. (a) Find the eigenvalues and the corresponding eigenvectors of the matrix

A ~ l: ~;]Also find the eigenvalues of AlO and the corresponding eigenvectors.

(b) Reduce the quadratic form

q = 6xf + 3xi + 3xj - 4xlx2 - 2x2x3 + 4x3xl

to the sum of squares and find the corresponding linear transmissions. Also find its rank,index and signature.

3. (a) Find the curl ofthe gradient of <po

(b) If y = WXI, prove that w = ~ curl y, where w is a constant vector.

(c) State Green's theorem in the plane. Verify the theorem in the plane for

c

around the boundary of the region defined by y2 = 8x and x = 2.

Contd P/2

(15)

(23%)

(23)

(10)

(10)

(26%)

=2=

MATH 261

4. (a) Is E = (x3z - 2xyz)i +(xy - 3x2yz)j + (yz2 - xz)k solenoidal? If so, find vector V such

thatE = "V x V. (20)(b) State Stoke's theorem. Evaluate ffi1xF.nds for E = (2x -y)i _yz2 j - y2zk, where S

s

is the upper half surface of the sphere x2 + y2 + Z2= 1 and C is its boundary. (16 %)(c) Find the directional derivative ofP = 4e2x-y+z at the point (1, 1, - 1) in the direction

toward the point (-3,5,6). (10)

SECTION -BThere are FOUR questions in this Section. Answer any THREE.

Symbols have their usual meaning

5. (a) Find the series solution of the differential equation (x - x2)y" + (1 - 5x)y' - 4y = 0 by

the method of Fr6benius.

(b) Show that Jz(x) = J~(x) - X-I J~(x).

6. (a) Show that (i) xJ~(x) = x In+1 (x) -nJn(x).

(ii) x2J~(x) = (n2 - n - x2) In(x )+xJn+I (x).1

(iii) fPm(x )Pn(x)dx = 0, (m * n)-1

7. (a) Prove that legendre Polynomial Pn(x) is the coefficient of hn in the expansion of

-}i(1- 2xh + h2) 2

(b) Express 2x4 + 3x3 - x2 + 7x + 1 as a legendre polynomial.

(c) State and prove Heaviside's expansion formula and using this formula find

8. (a) Using laplace transformation evaluate

(36%)

(10)

(15)

(15)

(16%)

(20%)

(10)(16)

(15%)

{2-1i 2}

(b) Find (i) L j; I e-U du (16)

(c) Solve (using laplace transformation):

y"(t) - 3y'(t) + 2y(t) = 4e2t, yeO)= -3, y'(O) = 5.

(15)

'.

L-2/T-l/ME Date: 28/02/2012

BANGLADESH UNIVERSITY OF ENGINEERING AND TECHNOLOGY, DHAKA

L-2/T-1 B. Sc. Engineering Examinations 2010-2011

Sub :HUM 303 (Principles of Accounting)

Full Marks: 210 Time : 3 Hours


USE SEPARA TE SCRIPTS FOR EACH SECTION

SECTION -A


1. Mr. X with available fund of Tk. 8 million is evaluating his investment opportunities.

Two projects are now available for him with different amounts of return. Both the

projects required Tk. 8 million of investments which will provide him return for next

seven years from Project Deluxe and next 5 years from Project Supreme. The details

about the return from the projects are given below:

(Amounts are in million)

Year Project Deluxe Project Supreme

1 Tk. 1.2 Tk. 2.3

2 1.4 2.3

3 1.6 2.3

4 1.8 2.3

5 2.0 2.3

6 2.2 -

7 2.4 -

Mr. X is asking for your help in evaluating the projects and making the right decision.

As an expert, recommend Mr. X which project should he undertake under the following

evaluation techniques:

(i) Payback period method

(ii) Net present value method

(iii) Internal rate of return method

(iv) Among these three methods which one do you consider as best.

(Consider the discounting rate is 12% for your analysis).

2. (a) In what situation, absorption costing will result higher net income than variable

costing? Why?

Contd P/2

(35)

(5)

=2=

HUM 303Contd ... Q. NO.3

(b) For the income year ended on December 31, 2010; you have been gIVen the

information below: (30)

Particulars

Selling price per unit

Manufacturing costs:

Direct Material cost per unit

Direct labour cost per unit

Variable manufacturing cost per unit

Fixed manufacturing cost for the period

Selling and Administrative costs:

Variable cost per unit

Fixed cost for the period

Amount (Tk)

50

8

7

5

100,000

2

80,000

During the year, a total of 10,000 units produced but only 8500 units sold.

Requirements:

(i) Determine the unit product cost under absorption costing and variable costing

techniques.

(ii) Prepare income statement under both of the techniques.

(iii) Reconcile the amount of net income under these two techniques.

3. Crown creative inc. makes high quality Personal Digital Assistant (PDA). Sales and

production data relating to the most recent year are given below: (35)

Sales (in unit) 2800

Selling price per unit (Tk.) 265

Contribution margin ratio 60%

Annual Fixed costs (Tk.) 111,300

Management is anxious to improve the company's profit performance and has asked for

several items of information.

Requirements:

(a) Compute break-even-point in units and sales Taka.

(b) Assume that sales increases by Tk. 60,000 next year. If cost behaviour patterns

remain unchanged, by how much will the company's net income increase?

(c) Refer to the original data. Assume that next year management wants to earn a Tk.

182,850 profit. How many units will have to be sold to meet this target profit?

Contd P/3

=3=HUM 303Contd no Q. NO.3

(d) Refer to the original data. The sales manager is convinced that a 15% reduction in

the selling price combined with a Tk. 56,100 increase in advertising expenditure

would cause arumal sales in units to increase by 40%. Would you recommend that

the company should do as the sales manager suggests?

(e) Refer to the original data. Compute margin of safety both in Taka and percentage

form.

(f) (i) Compute degree of operating leverage at the present level of sales.

(ii) Assume that the company like to increase its net profit by 90% next year. By

what percentage would you expect sales to increase? Use DOL to answer.

(iii) Verify your answer to (ii) by preparing income statement.

4. (a) Classify costs in terms of behaviour. (6)(b) What is the most easiest method available to separate mixed costs into fixed and

variable? What is the major disadvantage of this method? (4)(c) The data below have been taken from the cost records of Beverly Hospital. A careful

study by the company's cost analyst has determined that if the number of X-rays taken is

7000, the average operating cost is TIc 4.14 per X-ray. If the number of X-rays taken is

3000, the average operating cost is Tk. 5.65 per X-ray. (20)Requirements:

(i) Using the high and low point method, determine the variable cost per X-ray and the

fixed cost in total.

(ii) Express the variable cost and fixed cost in the form Y = a + bx.(iii) If the number of X-rays taken in a month is 4600, what total operating X-rays cost

would you expect?

(d) Suppose that you are a furniture manufacturer. You rpoduce high quality luxurious

furniture from solid wood that is supplied by a local supplier. Your manufacturing

cost is composed of three types of costs- direct material costs, direct labour costs

and manufacturing overhead cost. Name different types of cost for your company. (5)

SECTION -B


5. Sharif and Associates was formed on May 1, 2011 by Mr. Omar Sharif. The following

transactions took place during the first month of the operation: (35)May 1: Mr. Sharif invested Tk. 50,000 cash in the business.

May 5: Hired two employees to work in the warehouse. Both of them will be paid

a total salary ofTk. 3,000 per month.

Contd P/4

=4=


May 11: Purchase furniture costing Tk. 30,000. A cash payment of Tk. 10,000 was

made immediately; the reminder will be paid in six months.

May 13: Purchase office supplies for Tk. 500 on account.

May 18: Services provided to customers worth Tk. 20,000 of which Tk. 8,000 cash

received and Tk. 12,000 on account.

May 21: Paid Tk. 400 to suppliers for accounts payable due.

May 25: Received Tk. 3,000 from customers.

May 27: Withdrew Tk. 200 for personal use.

May 31: Paid monthly salary Tk. 3,000.

Requirements:

(a) Journalize the above transactions.

(b) Prepare ledger for the following two accounts-

(i) Cash account (ii) Accounts Payable account.

6. Starline Company is owned by Mr. Star. The company prepare financial statements in

every three months. The trial balance at the end of first quarter is given below:

Dr. Cr.

Cash Tk. 5,000

Prepaid Insurance 6,000

Office Equipment 60,000

Accumulated Depreciation-Equipment Tk. 9,000

Accounts Payable 2,500

Unearned Service Revenue 6,400

Mortgage payable 30,000

Capital-Mr. Star 10,000

Service Revenue 15,100

Rental Income 7,000

Salaries Expenses 9,000

Tk. 80,000 Tk. 80,000

Other data:

(i) Prepaid insurance relates to premium paid on January 1 for one year.

(ii) The mortgage interest rate is 12% per annum. (Mortgage was taken out on

February 1,2011).

Contd P/5

(35)

=5=


(iii) Half of the unearned service revenue has been earned by March 31, 2011.

(iv) Office equipment is being depreciated Tk. 500 per month.

(v) Salaries accrued but not paid Tk. 1700 by March 31, 2011.

(vi) Rental income earned but not received Tk. 2,500.

Requirements:

(a) Prepare the adjusting entries on March 31,2011.

(b) Complete the ten column worksheet for the quarter.

7. The Mound view Motel opened for business on May 1, 2011. Its trial balance before

adjustment on May 31 follows:

Dr. Cr.

Cash Tk. 3,500

Supplies 2,200

Prepaid Insurance 2,280

Land 12,000

Lodge 60,000

Furniture 15,000

Accounts Payable Tk. 4,800

Unearned rent 3,300

Mortgage payable 35,000

Capital . 46,380

Rent Revenue 10,300

Advertising Expenses 600

Salaries expenses 3,300

Utilities Expenses 900

Tk.99,780 Tk.99,780

Other data:

(i) Prepaid insurance is a two years policy starting May 1, 2011.

(ii) A count of supplies showed Tk. 800 of unused supplies on May 31.

(iii) Annual depreciation is Tk. 3,000 on the lodge and Tk. 2700 on furniture,

(iv) The mortgage interest rate is 18% and a month's interest has to be recognized.

Tk. 2,000 of mortgage payable will be due in next month.

(v) Two-third ofthe unearned rent has been earned.

(vi) Salaries ofTk. 750 are accrued and unpaid at May 31.

Contd P/6

(35

I~'~

i

;/

.', '.'

=6=


Required:

(a) Prepare a single column income statement for the month.

(b) Prepare an owner's equity statement for the month.

(c) Prepare a classified balance sheet as on May 31.

8. (a) Write short notes (any three)-

(i) Periodicity assumption.

(ii) Matching principle.

(iii) Financial statements.

(iv) Users of accounting information.

(b) Mrs. Rahman started her own consulting firm on May 1, 2011. The following

transactions occurred during the month-

May 1: Mrs. Rahman invested Tk. 70,000 cash in the business.

May 3 Purchased Tk. 600 of supplies on account.

May 5: Paid Tk. 125 to advertise in the country news.

May 9: Receive Tk. 4,000 cash for services provided.

May 12: Withdrew Tk. 1,000 cash for personal use.

May 15: Performed Tk. 6,400 of services on account.

May 20: Paid for the supplies purchased on account on May 3.

May 23: Received a cash payment of Tk. 4,000 for services provided on account on

May 15.

May 26: Borrow Tk. 5,000 from the bank on a note payable.

May 29: Purchase office equipment for Tk. 3,100 on account.

Requirements:

Show the effects of the listed transactions on the accounting equation.

(15

(20

l-2/t-1ime date: 30/0112012

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