lect strain transformation
TRANSCRIPT
-
7/26/2019 Lect Strain Transformation
1/29
ME 2406: Strength of Materials
Strain Transformation
Dr. Faraz Junejo
-
7/26/2019 Lect Strain Transformation
2/29
Oje!ti"es
Apply the stresstransformation methodsderived in previous chapteri.e. chapter 9 to similarlytransform strain
-
7/26/2019 Lect Strain Transformation
3/29
#lain Strain
As explained earlier, general state ofstrain in a body is represented by acombination of 3components of normalstrain ( x, y, z), and 3 components of
shear strain (xy, xz, yz).
A plane-strained element is subjected
to two components of normal strain (x,y) and one component of shear strain,
xy.
-
7/26/2019 Lect Strain Transformation
4/29
#lain Strain $%ont&.' he deformations are shown graphically
below. !ote that the normal strains are produced
by changes in length of the element in thex
and y directions, while shear strain isproduced by the relative rotation of twoadjacent sides of the element.
-
7/26/2019 Lect Strain Transformation
5/29
#lain Strain $%ont&.' !ote that plane stress does not always cause
plane strain.
"n general, unless # $, the %oisson e&ectwill prevent the simultaneous occurrence of
plane strain and plane stress. 'ince shear stress and shear
strain not a&ected by %oissons
ratio, condition of xz# yz# $reuires xz# yz# $.
-
7/26/2019 Lect Strain Transformation
6/29
#lain Strain: Sign %on"ention
o use the same convention asde*ned in %ha(ter 2.
+ith reference to di&erential
element shown, normal strainsxand yare positive if they
cause elongation along the xandyaxes respectively.
'hear strain xyis positive if the interior
angle Abecomes smaller than 9$.
-
7/26/2019 Lect Strain Transformation
7/29
#lain Strain Transformation
eneral /uations for %lain 'trainransformation are0
( )5102sin22cos22' -
xyyxyx
x +
+
+
=
( )6-102cos22sin22
''
xyyxyx
+
=
-
7/26/2019 Lect Strain Transformation
8/29
"f normal strain in the ydirection isreuired, it can be obtained from E)uation
*0+, by substituting (1 9$) for .heresult is( )7-102sin
22cos
22'
xyyxyx
y
+=
-
7/26/2019 Lect Strain Transformation
9/29
#rin!i(al Strains
+e can orientate an element at a ptsuch that the elements deformation isonly represented by normal strains,with no shear strains.
he material must be isotropic, and theaxes along which the strains occur mustcoincide with the axes that de*ne the
principal axes.
hus from /uations 9-2 and 9-3,( )8-102tan
yx
xy
p
=
-
7/26/2019 Lect Strain Transformation
10/29
#rin!i(al strains
Ma-imum in+(lane shear strain
4sing /uations 9-5, 9-6 and 9-7, we
get
( )910222
22
2,1 -
+
+
=
xyyxyx
( )1110222
22plane-in
max
-
+
= xyyx
( )10102tan -
=xy
yx
s
-
7/26/2019 Lect Strain Transformation
11/29
#rin!i(al Strains $!ont&.'
Ma-imum in+(lane shear strain
4sing /uations 9-5, 9-6 and 9-7, weget
( )12102 -avgyx
+=
-
7/26/2019 Lect Strain Transformation
12/29
Summar
8ue to Poisson efect, the state of
plane strain is not a state of plane
stress, and vice versa.
A point on a body is subjected to planestress when the surface of the body is
stress-ree.
+hen the state of strain is representedby the (rin!i(al strains, no shear
strain will act on the element.
-
7/26/2019 Lect Strain Transformation
13/29
Summar $!ont&.'
he state of strain at the point canalso be represented in terms of the
ma-imum in+(lane shear strain."n this case, an average normal
strain will also act on the element.
he element representing themaximum in-plane shear strain and
its associated average normal strainsis 4, from the element representingtheprincipal strains.
-
7/26/2019 Lect Strain Transformation
14/29
E-am(le: *A di&erential element ofmaterial at a point is
subjected to a state ofplane strain x /
,00$*0+6' y /
100$*0+6' and xy =
200$*0+6' which tends
to distort the element as
shown. Determine the
e)ui"alent strains
acting on an element
oriented at the point,
clockwise 30 rom the
original position.
-
7/26/2019 Lect Strain Transformation
15/29
E-am(le: * $!ont&.' 'ince is clocwise, then / 10, use
strain-transformation /uation :$-3 toobtain
( ) ( )( ) ( ) ( )( )
( )( )( )
( )6
'
6
6
6
'
10213
302sin2
10200
302cos102
300500
102
300500
2sin2
2cos22
=
+
+
+=
+
++
=
x
xyyxyxx
-
7/26/2019 Lect Strain Transformation
16/29
E-am(le: * $!ont&.'
'ince is clocwise, then / 10
, usestrain-transformation /uation :$-5 toobtain
( )( )( )
( ) ( )( )
( )6''
6
''
10793
302cos2
10200
302sin2
300500
2cos22sin22
=
+
=
+
=
yx
xyyxyx
-
7/26/2019 Lect Strain Transformation
17/29
E-am(le: * $!ont&.' 'train in theydirection can be obtained from
/uation :$-6 with # ;
-
7/26/2019 Lect Strain Transformation
18/29
E-am(le: * $!ont&.'
he results obtained tend to deform the
element as shown below.
-
7/26/2019 Lect Strain Transformation
19/29
E-am(le: 2A differential element of material at a point is subjected
to a state of plane strain defined by x= 350(0-6!"y= #00(0-6!" xy= $0(0-6!" %&ic& tends to distort t&e
element as s&o%n' etermine t&e principal strains at
t&e point and associated orientation of t&e element'
-
7/26/2019 Lect Strain Transformation
20/29
E-am(le: 2 $!ont&.'>rom /uation :$-7, we have rientation of the
element
/ach of these angles is measuredpositive counterclocwise, from thexaxis to the outward normals oneach face of the element.
( )
==+=
=
=
9.8514.4,17218028.828.82
)10(200350
)10(802tan
6
6
andt&atsoand)&us
p
p
yx
xyp
-
7/26/2019 Lect Strain Transformation
21/29
E-am(le: 2 $!ont&.'
#rin!i(al strains can be obtained >rom
/uation :$-9,
( )( ) ( )
( ) ( )( ) ( )6261
66
6226
22
2,1
1035310203
109.277100.75
102
80
2
200350
2
10200350
222
== =
+
+=
+
+=
xyyxyx
-
7/26/2019 Lect Strain Transformation
22/29
E-am(le: 2 $!ont&.'
#rin!i(al strains
+e can determine which of these twostrains deforms the element in the xdirection by applying /uation :$-3 with
# ; 2.:2. hus
( ) ( ) ( )
( )( )
( )6
'
6
66
'
10353
14.42sin2
1080
14.4cos10
2
20035010
2
200350
2sin2
2cos22
=
+
+
+=
+++=
x
xyyxyxx
-
7/26/2019 Lect Strain Transformation
23/29
E-am(le: 2 $!ont&.'
%rincipal strains
=ence x# ?. +hen subjected to the
principal strains, the element is distortedas shown.
-
7/26/2019 Lect Strain Transformation
24/29
E-am(le: 1
A di&erential element of material at a point is
subjected to a state of plane strain de*ned by x# ;
-
7/26/2019 Lect Strain Transformation
25/29
E-am(le: 1 $!ont&.'
rientation of the element can beobtained >rom /uation :$-:$,
!ote that this orientation is 4, from thatshown in previous /xample i.e. /xample ?as expected.
( )( )
( )
==+=
=
=
9.1309.40
,72.26118072.8172.8121080
102003502tan
6
6
and
t&atsoand)&us"
s
s
xy
yx
s
-
7/26/2019 Lect Strain Transformation
26/29
E-am(le: 1 $!ont&.'@aximum in-plane shear strain
Applying /n :$-::,
he proper sign of can be obtained by
applying /uation :$-5 with s/ 40.3.
( )
( )6
622
22
10556
10280
2200350
222
plane-in
max
plane-in
max
=
+
=
+
=
xyyx
plane-in
max
l $ & '
-
7/26/2019 Lect Strain Transformation
27/29
E-am(le: 1 $!ont&.'
@aximum in-plane shear strain
hus tends to distort the element so that theright angle between dx and dy is decreased
(positive sign convention).
( ) ( )
( )( )
( )6''
6
6
''
10556
9.402cos2
1080
9.402sin102
200350
2cos2
2sin22
=
+
=
+=
yx
xyyxyx
plane-in
max
-
7/26/2019 Lect Strain Transformation
28/29
E-am(le: 1 $!ont&.'here are associated average normal strains
imposed on the element determined from/uation :$-:?0
)&ese strains tend to
cause t&e element tocontract'
( ) ( )66 1075102
200350
2
=+=+
= yx
avg
-
7/26/2019 Lect Strain Transformation
29/29
%ourse or5 E-er!ises
*ec&anics of *aterials $t&+dition by ,'' .ibbeler
/ 0' / 0'6
/ 0'3 / 0'