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  • 7/26/2019 Lect Strain Transformation

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    ME 2406: Strength of Materials

    Strain Transformation

    Dr. Faraz Junejo

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    Oje!ti"es

    Apply the stresstransformation methodsderived in previous chapteri.e. chapter 9 to similarlytransform strain

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    #lain Strain

    As explained earlier, general state ofstrain in a body is represented by acombination of 3components of normalstrain ( x, y, z), and 3 components of

    shear strain (xy, xz, yz).

    A plane-strained element is subjected

    to two components of normal strain (x,y) and one component of shear strain,

    xy.

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    #lain Strain $%ont&.' he deformations are shown graphically

    below. !ote that the normal strains are produced

    by changes in length of the element in thex

    and y directions, while shear strain isproduced by the relative rotation of twoadjacent sides of the element.

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    #lain Strain $%ont&.' !ote that plane stress does not always cause

    plane strain.

    "n general, unless # $, the %oisson e&ectwill prevent the simultaneous occurrence of

    plane strain and plane stress. 'ince shear stress and shear

    strain not a&ected by %oissons

    ratio, condition of xz# yz# $reuires xz# yz# $.

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    #lain Strain: Sign %on"ention

    o use the same convention asde*ned in %ha(ter 2.

    +ith reference to di&erential

    element shown, normal strainsxand yare positive if they

    cause elongation along the xandyaxes respectively.

    'hear strain xyis positive if the interior

    angle Abecomes smaller than 9$.

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    #lain Strain Transformation

    eneral /uations for %lain 'trainransformation are0

    ( )5102sin22cos22' -

    xyyxyx

    x +

    +

    +

    =

    ( )6-102cos22sin22

    ''

    xyyxyx

    +

    =

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    "f normal strain in the ydirection isreuired, it can be obtained from E)uation

    *0+, by substituting (1 9$) for .heresult is( )7-102sin

    22cos

    22'

    xyyxyx

    y

    +=

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    #rin!i(al Strains

    +e can orientate an element at a ptsuch that the elements deformation isonly represented by normal strains,with no shear strains.

    he material must be isotropic, and theaxes along which the strains occur mustcoincide with the axes that de*ne the

    principal axes.

    hus from /uations 9-2 and 9-3,( )8-102tan

    yx

    xy

    p

    =

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    #rin!i(al strains

    Ma-imum in+(lane shear strain

    4sing /uations 9-5, 9-6 and 9-7, we

    get

    ( )910222

    22

    2,1 -

    +

    +

    =

    xyyxyx

    ( )1110222

    22plane-in

    max

    -

    +

    = xyyx

    ( )10102tan -

    =xy

    yx

    s

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    #rin!i(al Strains $!ont&.'

    Ma-imum in+(lane shear strain

    4sing /uations 9-5, 9-6 and 9-7, weget

    ( )12102 -avgyx

    +=

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    Summar

    8ue to Poisson efect, the state of

    plane strain is not a state of plane

    stress, and vice versa.

    A point on a body is subjected to planestress when the surface of the body is

    stress-ree.

    +hen the state of strain is representedby the (rin!i(al strains, no shear

    strain will act on the element.

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    Summar $!ont&.'

    he state of strain at the point canalso be represented in terms of the

    ma-imum in+(lane shear strain."n this case, an average normal

    strain will also act on the element.

    he element representing themaximum in-plane shear strain and

    its associated average normal strainsis 4, from the element representingtheprincipal strains.

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    E-am(le: *A di&erential element ofmaterial at a point is

    subjected to a state ofplane strain x /

    ,00$*0+6' y /

    100$*0+6' and xy =

    200$*0+6' which tends

    to distort the element as

    shown. Determine the

    e)ui"alent strains

    acting on an element

    oriented at the point,

    clockwise 30 rom the

    original position.

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    E-am(le: * $!ont&.' 'ince is clocwise, then / 10, use

    strain-transformation /uation :$-3 toobtain

    ( ) ( )( ) ( ) ( )( )

    ( )( )( )

    ( )6

    '

    6

    6

    6

    '

    10213

    302sin2

    10200

    302cos102

    300500

    102

    300500

    2sin2

    2cos22

    =

    +

    +

    +=

    +

    ++

    =

    x

    xyyxyxx

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    E-am(le: * $!ont&.'

    'ince is clocwise, then / 10

    , usestrain-transformation /uation :$-5 toobtain

    ( )( )( )

    ( ) ( )( )

    ( )6''

    6

    ''

    10793

    302cos2

    10200

    302sin2

    300500

    2cos22sin22

    =

    +

    =

    +

    =

    yx

    xyyxyx

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    E-am(le: * $!ont&.' 'train in theydirection can be obtained from

    /uation :$-6 with # ;

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    E-am(le: * $!ont&.'

    he results obtained tend to deform the

    element as shown below.

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    E-am(le: 2A differential element of material at a point is subjected

    to a state of plane strain defined by x= 350(0-6!"y= #00(0-6!" xy= $0(0-6!" %&ic& tends to distort t&e

    element as s&o%n' etermine t&e principal strains at

    t&e point and associated orientation of t&e element'

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    E-am(le: 2 $!ont&.'>rom /uation :$-7, we have rientation of the

    element

    /ach of these angles is measuredpositive counterclocwise, from thexaxis to the outward normals oneach face of the element.

    ( )

    ==+=

    =

    =

    9.8514.4,17218028.828.82

    )10(200350

    )10(802tan

    6

    6

    andt&atsoand)&us

    p

    p

    yx

    xyp

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    E-am(le: 2 $!ont&.'

    #rin!i(al strains can be obtained >rom

    /uation :$-9,

    ( )( ) ( )

    ( ) ( )( ) ( )6261

    66

    6226

    22

    2,1

    1035310203

    109.277100.75

    102

    80

    2

    200350

    2

    10200350

    222

    == =

    +

    +=

    +

    +=

    xyyxyx

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    E-am(le: 2 $!ont&.'

    #rin!i(al strains

    +e can determine which of these twostrains deforms the element in the xdirection by applying /uation :$-3 with

    # ; 2.:2. hus

    ( ) ( ) ( )

    ( )( )

    ( )6

    '

    6

    66

    '

    10353

    14.42sin2

    1080

    14.4cos10

    2

    20035010

    2

    200350

    2sin2

    2cos22

    =

    +

    +

    +=

    +++=

    x

    xyyxyxx

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    E-am(le: 2 $!ont&.'

    %rincipal strains

    =ence x# ?. +hen subjected to the

    principal strains, the element is distortedas shown.

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    E-am(le: 1

    A di&erential element of material at a point is

    subjected to a state of plane strain de*ned by x# ;

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    E-am(le: 1 $!ont&.'

    rientation of the element can beobtained >rom /uation :$-:$,

    !ote that this orientation is 4, from thatshown in previous /xample i.e. /xample ?as expected.

    ( )( )

    ( )

    ==+=

    =

    =

    9.1309.40

    ,72.26118072.8172.8121080

    102003502tan

    6

    6

    and

    t&atsoand)&us"

    s

    s

    xy

    yx

    s

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    E-am(le: 1 $!ont&.'@aximum in-plane shear strain

    Applying /n :$-::,

    he proper sign of can be obtained by

    applying /uation :$-5 with s/ 40.3.

    ( )

    ( )6

    622

    22

    10556

    10280

    2200350

    222

    plane-in

    max

    plane-in

    max

    =

    +

    =

    +

    =

    xyyx

    plane-in

    max

    l $ & '

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    E-am(le: 1 $!ont&.'

    @aximum in-plane shear strain

    hus tends to distort the element so that theright angle between dx and dy is decreased

    (positive sign convention).

    ( ) ( )

    ( )( )

    ( )6''

    6

    6

    ''

    10556

    9.402cos2

    1080

    9.402sin102

    200350

    2cos2

    2sin22

    =

    +

    =

    +=

    yx

    xyyxyx

    plane-in

    max

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    E-am(le: 1 $!ont&.'here are associated average normal strains

    imposed on the element determined from/uation :$-:?0

    )&ese strains tend to

    cause t&e element tocontract'

    ( ) ( )66 1075102

    200350

    2

    =+=+

    = yx

    avg

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    %ourse or5 E-er!ises

    *ec&anics of *aterials $t&+dition by ,'' .ibbeler

    / 0' / 0'6

    / 0'3 / 0'