lect121222
TRANSCRIPT
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ELEC344, Kevin Chen, HKUST 1
Why impedance matching?
Maximum power is delivered when the load is matched to
the line.
Impedance matching sensitive receiver components
(antenna, LNA, etc.) improves the signal-to-noise ratio ofthe system.
Impedance matching in a power distribution network (such
as antenna array feed network) will reduce amplitude and
phase errors.
Impedance matching uniquely removes the requirement for
a specific reference plane.
Provide reliable and predictable interconnections betweencomponents in a system.
Lect. 12: Impedance Matching
ELEC344, Kevin Chen, HKUST 2
Load
ZL
Matching
networkZ0
A lossless network matching an arbitrary load impedance to a
transmission line
Complexity --- Simplest design that satisfies the required
specification is generally the most preferable. Cheaper,
more reliable, less lossy.
Bandwidth --- Normally, it is desirable to match a load over
a band of frequencies. Increased bandwidth usually comes
with increased complexity, e.g. using multistage matching.
Design issues of the matching networksMultiple solutions
ELEC344, Kevin Chen, HKUST 3
Implementation --- Choose the right type of matching
networks, either tuning stub or transmission line.
Adjustability --- This maybe required for applications where a
variable load impedance occurs.
Matching with Lumped Elements (L Networks)
Network for zL inside the
1+jx circle (smith chart).
Network for zL outside the
1+jx circle (smith chart).
ELEC344, Kevin Chen, HKUST 4
L networks consist of two reactive components (inductor and
capacitor), which results in eight different configurations.
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ELEC344, Kevin Chen, HKUST 5
Analytic solution for the matching network elements
Case 1: load impedance inside the 1+jx circle --->RL>Z0
)/(1
1
0LL jXRjBjXZ ++
+=
For a match looking into the matching network, we have
Solving for X and B from the two equations for real and
imaginary parts,
22
0
22
0/
LL
LLLLL
XR
RZXRZRXB
+
+=
*Note:B is always real (RL
>Z0) and has two solutions. One solution
is capacitive (positive) and the other one is inductive (negative).
ELEC344, Kevin Chen, HKUST 6
LL
L
BR
Z
R
ZX
BX 00
1+=
and
Both solutions are applicable for impedance matching at a
single frequency. But one solution may be preferable over
the other one when other performance, e.g. frequencyresponse, is considered.
Case 2: load impedance outside the 1+jx circle --->RL
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ELEC344, Kevin Chen, HKUST 9
Example:
1
Figure 1: Transmitter to antenna matching circuit design.
ELEC344, Kevin Chen, HKUST 10
Solution:
Step 1: Compute normalized transmitter and antenna
impedances. Since no characteristic impedanceZ0 is given,
we arbitrarily selectZ0 = 75 for simplicity.
We have zT=ZT/Z0 = 2 +j 1
zA =ZA/Z0 = 1 +j 0.2
Step 2: Taking into account the first element (the shunt
capacitor) connected to the transmitter.
Move down on the circle of the constant conductance.
Step 3: Taking into account the next element (the series
inductor) connected to the transmitter.
Move up on the circle of the constant resistance.
ELEC344, Kevin Chen, HKUST 11
Step 4: Draws the complex conjugate of the antenna
impedance in the Smith Chart for maximum power
transfer. This should be the output impedance of the
matching network.
zM=zA* = 1 -j 0.2
Step 5: Find the normalized impedance of the intersection
of two circles.zTC= 1 -j 1.22 and the corresponding
admittance ofyTC= 0.4 +j 0.49.
The normalized susceptance of the shunt capacitor is
jbC=yTC- yT=j 0.69
and the normalized reactance of the inductor is
jxL =zA - zTC=j 1.02 nHZxL L 09.6/)( 0 ==
pFZbCC
73.0)/(0
==
ELEC344, Kevin Chen, HKUST 12
Design of the
matching network
using ZY Smith
Chart
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ELEC344, Kevin Chen, HKUST 13
There is another path connectingzMandzY.
What does this mean?
1 Find the normalized source and load impedances.
2 In the Smith Chart, plot circles of constant resistance andconductance that pass through the point denoting the source
impedance.
3 Plot circles of constant resistance and conductance that pass
through the point of the complex conjugate of the load
impedance.
4 Identify the intersection points between the circles in steps 2 and
3. The number of intersection points determines the number ofpossible L-section matching networks. (cont)
Procedures of designing impedance matching networks using
Smith Chart
ELEC344, Kevin Chen, HKUST 14
5 Find the values of the normalized reactances and susptances
of the inductors and capacitors by tracing a path along the
circles from the source impedance to the intersection point
and then to the conjugate of the load impedance.
--- there are usually multiple paths (multiple solutions).
6 Determine the actual values of inductors and capacitors for a
given frequency.
Design procedures cont