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  • 7/29/2019 lect121222

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    ELEC344, Kevin Chen, HKUST 1

    Why impedance matching?

    Maximum power is delivered when the load is matched to

    the line.

    Impedance matching sensitive receiver components

    (antenna, LNA, etc.) improves the signal-to-noise ratio ofthe system.

    Impedance matching in a power distribution network (such

    as antenna array feed network) will reduce amplitude and

    phase errors.

    Impedance matching uniquely removes the requirement for

    a specific reference plane.

    Provide reliable and predictable interconnections betweencomponents in a system.

    Lect. 12: Impedance Matching

    ELEC344, Kevin Chen, HKUST 2

    Load

    ZL

    Matching

    networkZ0

    A lossless network matching an arbitrary load impedance to a

    transmission line

    Complexity --- Simplest design that satisfies the required

    specification is generally the most preferable. Cheaper,

    more reliable, less lossy.

    Bandwidth --- Normally, it is desirable to match a load over

    a band of frequencies. Increased bandwidth usually comes

    with increased complexity, e.g. using multistage matching.

    Design issues of the matching networksMultiple solutions

    ELEC344, Kevin Chen, HKUST 3

    Implementation --- Choose the right type of matching

    networks, either tuning stub or transmission line.

    Adjustability --- This maybe required for applications where a

    variable load impedance occurs.

    Matching with Lumped Elements (L Networks)

    Network for zL inside the

    1+jx circle (smith chart).

    Network for zL outside the

    1+jx circle (smith chart).

    ELEC344, Kevin Chen, HKUST 4

    L networks consist of two reactive components (inductor and

    capacitor), which results in eight different configurations.

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    ELEC344, Kevin Chen, HKUST 5

    Analytic solution for the matching network elements

    Case 1: load impedance inside the 1+jx circle --->RL>Z0

    )/(1

    1

    0LL jXRjBjXZ ++

    +=

    For a match looking into the matching network, we have

    Solving for X and B from the two equations for real and

    imaginary parts,

    22

    0

    22

    0/

    LL

    LLLLL

    XR

    RZXRZRXB

    +

    +=

    *Note:B is always real (RL

    >Z0) and has two solutions. One solution

    is capacitive (positive) and the other one is inductive (negative).

    ELEC344, Kevin Chen, HKUST 6

    LL

    L

    BR

    Z

    R

    ZX

    BX 00

    1+=

    and

    Both solutions are applicable for impedance matching at a

    single frequency. But one solution may be preferable over

    the other one when other performance, e.g. frequencyresponse, is considered.

    Case 2: load impedance outside the 1+jx circle --->RL

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    ELEC344, Kevin Chen, HKUST 9

    Example:

    1

    Figure 1: Transmitter to antenna matching circuit design.

    ELEC344, Kevin Chen, HKUST 10

    Solution:

    Step 1: Compute normalized transmitter and antenna

    impedances. Since no characteristic impedanceZ0 is given,

    we arbitrarily selectZ0 = 75 for simplicity.

    We have zT=ZT/Z0 = 2 +j 1

    zA =ZA/Z0 = 1 +j 0.2

    Step 2: Taking into account the first element (the shunt

    capacitor) connected to the transmitter.

    Move down on the circle of the constant conductance.

    Step 3: Taking into account the next element (the series

    inductor) connected to the transmitter.

    Move up on the circle of the constant resistance.

    ELEC344, Kevin Chen, HKUST 11

    Step 4: Draws the complex conjugate of the antenna

    impedance in the Smith Chart for maximum power

    transfer. This should be the output impedance of the

    matching network.

    zM=zA* = 1 -j 0.2

    Step 5: Find the normalized impedance of the intersection

    of two circles.zTC= 1 -j 1.22 and the corresponding

    admittance ofyTC= 0.4 +j 0.49.

    The normalized susceptance of the shunt capacitor is

    jbC=yTC- yT=j 0.69

    and the normalized reactance of the inductor is

    jxL =zA - zTC=j 1.02 nHZxL L 09.6/)( 0 ==

    pFZbCC

    73.0)/(0

    ==

    ELEC344, Kevin Chen, HKUST 12

    Design of the

    matching network

    using ZY Smith

    Chart

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    ELEC344, Kevin Chen, HKUST 13

    There is another path connectingzMandzY.

    What does this mean?

    1 Find the normalized source and load impedances.

    2 In the Smith Chart, plot circles of constant resistance andconductance that pass through the point denoting the source

    impedance.

    3 Plot circles of constant resistance and conductance that pass

    through the point of the complex conjugate of the load

    impedance.

    4 Identify the intersection points between the circles in steps 2 and

    3. The number of intersection points determines the number ofpossible L-section matching networks. (cont)

    Procedures of designing impedance matching networks using

    Smith Chart

    ELEC344, Kevin Chen, HKUST 14

    5 Find the values of the normalized reactances and susptances

    of the inductors and capacitors by tracing a path along the

    circles from the source impedance to the intersection point

    and then to the conjugate of the load impedance.

    --- there are usually multiple paths (multiple solutions).

    6 Determine the actual values of inductors and capacitors for a

    given frequency.

    Design procedures cont