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Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of chemical reactions and the design of the reactors in which they take place. Lecture 1 1

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Lecture 1. Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of chemical reactions and the design of the reactors in which they take place. Lecture 1 – Thursday 1/6/2011. Introduction Definitions General Mole Balance Equation Batch (BR) - PowerPoint PPT Presentation

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Page 1: Lecture 1

Chemical Reaction Engineering (CRE) is the field that studies the rates and mechanisms of

chemical reactions and the design of the reactors in which they take place.

Lecture 1

1

Page 2: Lecture 1

Lecture 1 – Thursday 1/6/2011 Introduction

Definitions

General Mole Balance Equation Batch (BR) Continuously Stirred Tank Reactor (CSTR) Plug Flow Reactor (PFR) Packed Bed Reactor (PBR)

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Chemical Reaction Engineering

Industries that Draw Heavily on Chemical Reaction Engineering (CRE) are:

CPI (Chemical Process Industries)Examples like Dow, DuPont, Amoco,

Chevron3

Chemical reaction engineering is at the heart of virtually every chemical process. It separates the chemical engineer from other engineers.

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Chemical Plant for Ethylene Glycol (Ch. 5)

Smog (Ch. 1)

Plant Safety(Ch.

11,12,13)

Lubricant Design (Ch.

9)

Cobra Bites (Ch. 8 DVD-

ROM)

Oil Recovery (Ch. 7)

Wetlands (Ch. 7 DVD-ROM)

Hippo Digestion (Ch. 2)

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http://www.umich.edu/~ess

en/

Materials on the Web and CD-ROM

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Let’s Begin CREChemical Reaction Engineering (CRE) is

the field that studies the rates and mechanisms of chemical reactions and the design of the reactors in which they take place.

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The identity of a chemical species is determined by the kind, number, and configuration of that species’ atoms.

8

A chemical species is said to have reacted when it has lost its chemical identity.

Chemical Identity

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Chemical IdentityA chemical species is said to have reacted

when it has lost its chemical identity. There are three ways for a species to loose its identity:

1. Decomposition CH3CH3 H2 + H2C=CH2

2. Combination N2 + O2 2 NO3. Isomerization C2H5CH=CH2

CH2=C(CH3)2

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The reaction rate is the rate at which a species looses its chemical identity per unit volume.

The rate of a reaction (mol/dm3/s) can be expressed as either:The rate of Disappearance of reactant: -rA

or asThe rate of Formation (Generation) of product: rP

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Reaction Rate

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Consider the isomerization A B

rA = the rate of formation of species A per unit volume

-rA = the rate of a disappearance of species A per unit volume

rB = the rate of formation of species B per unit volume

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Reaction Rate

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EXAMPLE: AB If Species B is being formed at a rate of

0.2 moles per decimeter cubed per second, i.e., rB = 0.2 mole/dm3/s

Then A is disappearing at the same rate:-rA= 0.2 mole/dm3/s

The rate of formation (generation of A) is rA= -0.2 mole/dm3/s

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Reaction Rate

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For a catalytic reaction, we refer to -rA', which is the rate of disappearance of species A on a per mass of catalyst basis. (mol/gcat/s)

NOTE: dCA/dt is not the rate of reaction

13

Reaction Rate

Page 14: Lecture 1

Consider species j: 1. rj is the rate of formation of species j

per unit volume [e.g. mol/dm3s]2. rj is a function of concentration,

temperature, pressure, and the type of catalyst (if any)

3. rj is independent of the type of reaction system (batch, plug flow, etc.)

4. rj is an algebraic equation, not a differential equation

(e.g. -rA = kCA or -rA = kCA2)14

Reaction Rate

Page 15: Lecture 1

timemole

timemole

timemole

timemole

dtdN

GFF

jSpeciesofonAccumulati

RateMolar

jSpeciesofGeneration

RateMolar

outjSpeciesofRate

FlowMolar

injSpeciesofRate

FlowMolar

jjjj

0

Fj0 FjGj

System Volume, V

15

Building Block 1: General Mole Balances

Page 16: Lecture 1

If spatially uniform:

G j rjV

If NOT spatially uniform:

2V

rj 2111 VrG jj

222 VrG jj

1V

rj1

16

Building Block 1: General Mole Balances

Page 17: Lecture 1

n

iijij VrG

1

G j lim V 0 n

rjiVii1

n

rjdV

Take limit

17

Building Block 1: General Mole Balances

Page 18: Lecture 1

General Mole Balance on System Volume V

In Out Generation Accumulation

FA 0 FA rA dV dNA

dt

FA

0

FAGA

System Volume, V

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Building Block 1: General Mole Balances

Page 19: Lecture 1

Batch Reactor Mole Balances

19

FA 0 FA rA dV dNA

dtFA 0 FA 0

dNA

dtrAV

Batch

VrdVr AA Well-Mixed

Page 20: Lecture 1

dt dNA

rAVIntegrating

Time necessary to reduce the number of moles of A from NA0 to NA.

when

A

A

N

N A

A

VrdNt

0

20

AA

AA

NNttNNt

0 0

Batch Reactor Mole Balances

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A

A

N

N A

A

VrdNt

0

NA

t21

Batch Reactor Mole Balances

Page 22: Lecture 1

CSTR Mole Balance

FA 0 FA rA dV dNA

dt

dNA

dt0Steady State

CSTR

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FA 0 FA rAV 0

V FA 0 FA

rA

VrdVr AA Well Mixed

CSTR volume necessary to reduce the molar flow rate from FA0 to FA.

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CSTR Mole Balance

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Plug Flow Reactor

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V

V VV

FA

FA

0

0

VrFF

VinGeneration

VVatOut

VatIn

AVVAVA25

Plug Flow Reactor Mole Balance

Page 26: Lecture 1

limV 0

FA V V FA V

VrA

Rearrange and take limit as ΔV0

dFA

dVrA

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This is the volume necessary to reduce the entering molar flow rate (mol/s) from FA0 to the exit molar flow rate of FA.

Plug Flow Reactor Mole Balance

Page 27: Lecture 1

Alternative Derivation – Plug Flow Reactor Mole Balance

0 0 dVrFF AAA

0dt

dN ASteady State

dtdNdVrFF A

AAA 0

PFR

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Page 28: Lecture 1

dFA

dVrA

0 dFA

dV rA

Differientiate with respect to V

A

A

F

F A

A

rdFV

0

The integral form is:

This is the volume necessary to reduce the entering molar flow rate (mol/s) from FA0 to the exit molar flow rate of FA.

28

Alternative Derivation – Plug Flow Reactor Mole Balance

Page 29: Lecture 1

dt

dNWrWWFWF AAAA

AWAWWA

Wr

WFF

0lim

0dt

dN ASteady State

PBR

Packed Bed Reactor Mole Balance

29

W

W WW

FA

FA

Page 30: Lecture 1

dFA

dW r A

Rearrange:

PBR catalyst weight necessary to reduce the entering molar flow rate FA0 to molar flow rate FA.

A

A

F

F A

A

rdFW

0

The integral form to find the catalyst weight is:

30

Packed Bed Reactor Mole Balance

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Reactor Mole Balance SummaryReactor

Differential Algebraic Integral

V FA 0 FA

rA

CSTR

Vrdt

dNA

A 0

A

A

N

N A

A

VrdNtBatch

NA

t

dFA

dVrA

A

A

F

F A

A

drdFV

0

PFRFA

V31

Page 32: Lecture 1

Reactors with Heat Effects

Propylene glycol is produced by the hydrolysis of propylene oxide:

CH2 CH CH3 H2OH2SO4 CH2 CH CH3

O

OH

OH

32

EXAMPLE: Production of Propylene Glycol in an Adiabatic CSTR

Page 33: Lecture 1

What are the exit conversion X and exit temperature T?SolutionLet the reaction be represented by

A+BC

v0

Propylene Glycol

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Evaluate energy balance terms

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AnalysisWe have applied our CRE algorithm to calculate the Conversion (X=0.84) and Temperature (T=614 °R) in a 300 gallon CSTR operated adiabatically.

X=0.84T=614 °R

T=535 °R

A+BC

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KEEPING UP

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Separations

These topics do not build upon one another.

Filtration Distillation Adsorption

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Reaction Engineering

Mole Balance Rate Laws Stoichiometry

These topics build upon one another.

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Mole BalanceRate Laws

StoichiometryIsothermal Design

Heat Effects

46

CRE Algorithm

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Mole Balance

47

Be careful not to cut corners on any of the CRE building blocks while learning this material!

Rate Laws

Page 48: Lecture 1

Mole Balance

Rate LawsStoichiometry

Isothermal DesignHeat Effects

48Otherwise, your Algorithm becomes unstable.

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End of Lecture 1

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Additional Applications of CRESupplemental Slides

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Additional Applications of CRE

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Additional Applications of CRE

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Additional Applications of CRE

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Additional Applications of CRE

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Smog (Ch. 1)

Additional Applications of CRE

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Hippo Digestion (Ch. 2)

Additional Applications of CRE

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57Chemical Plant for Ethylene Glycol (Ch. 5)

Additional Applications of CRE

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58

Oil Recovery (Ch. 7)

Wetlands (Ch. 7 DVD-ROM)

Additional Applications of CRE

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Cobra Bites (Ch. 8 DVD-ROM)

Additional Applications of CRE

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Lubricant Design (Ch. 9)

Additional Applications of CRE

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Plant Safety(Ch. 11,12,13)

Additional Applications of CRE