lecture 28b - uc san diego | department of physics

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Physics 2B Lecture 28B "There must be a positive and negative in everything in the universe in order to complete a circuit or circle, without which there would be no activity, no motion." --John McDonald

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Page 1: Lecture 28B - UC San Diego | Department of Physics

Physics 2BLecture 28B

"There must be a positive and negative in everything in the universe in order to

complete a circuit or circle, without which there would be no activity, no motion."

--John McDonald

Page 2: Lecture 28B - UC San Diego | Department of Physics

CircuitsExampleWhat is the current (I) that flows through the battery?

AnswerReduce the circuit by equivalent resistance and then use Ohm’s Law to solve for the current.First, take the two pairs of resistors that are in parallel and find their equivalent resistance.

Page 3: Lecture 28B - UC San Diego | Department of Physics

CircuitsStart with the two resistors in the top right corner:

Answer

Then, for the two resistors in the lower left corner:

Page 4: Lecture 28B - UC San Diego | Department of Physics

CircuitsNext, combine the two pairs of resistors that are in series:

Answer

Next, combine the pair of resistors that are in parallel:

Page 5: Lecture 28B - UC San Diego | Department of Physics

CircuitsFinally, combine the pair of resistors that are in series:

Answer

We can apply Ohm’s Law for this equivalent circuit:

Page 6: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesIf you have a complicated circuit system you may have to use methods other than equivalent circuits.

The most popular of these methods are called Kirchhoff’s Rules.

Kirchhoff’s Loop RuleThe sum of potential differences across all the elements around any closed circuit must be zero.

Page 7: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesWhen applying the loop rule, first choose a closed loop and a direction (either clockwise or counter-clockwise).

This is a statement of Conservation of Energy.

You can define a “ground” where all measurements are taken with respect to.

The “ground” is defined as having 0V and has the following circuit symbol:

Page 8: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesWhen the direction of the loop and the direction of the current through a resistor are the same, we will get a voltage drop.

When the direction of the loop and the direction of the current through a resistor are opposite, we will get a gain in voltage.

loop

loop

Page 9: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesWhen the direction of the loop points in the same direction as an emf source (from negative terminal to the positive terminal), we will get a gain in voltage.

When the direction of the loop points in the opposite direction as an emf source (from positive terminal to the negative terminal), we will get a voltage drop.

loop

loop

Page 10: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesFor example, let’s analyze the upper loop using Kirchhoff’s Loop Rule in the following circuit (say we want to solve for the power dissipated by the 9Ω resistor).

There are only two circuit elements in this loop:

Page 11: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesKirchoff’s Loop Rule is nice, since you can get valuable information from an embedded part (most likely in parallel) of the circuit without breaking down the rest of the circuit.

Warning: You may not be given the direction of the currents in a circuit. In this case you have to make a choice.

Your choice of current directions is up to you, just be consistent throughout the problem.

Remember that all you need is a closed loop to use this rule.

Page 12: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s Rules

Kirchhoff’s Junction RuleThe sum of the currents entering any junction must equal the sum of the currents leaving.

There is a Kirchhoff rule that applies to currents in a circuit (in addition to loop rule).

Iin = Iout

This is a statement of Conservation of Charge.

For the diagram: I1 = I2 + I3

Page 13: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesGoing back to our previous example from last time (where we wanted power dissipated by 9Ω resistor, let’s now apply Kirchhoff’s Junction Rule.

At point c in the diagram:

From our previous attempt (with loop rule):

Page 14: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesNow we have a relationship between all of the currents in the circuit.

You can then:

Apply another Kirchhoff’s Loop Rule to solve for I3.

or try equivalent resistance to solve for I3.

In either case, solving for the current through either resistor or the power dissipated through either resistor becomes rather simple after that.

You will find that becoming skilled in BOTH equivalent resistance and Kirchhoff’s Rules will make solving circuit problems much easier.

Page 15: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesLet’s solve this circuit for the current I3 by using the lower loop.

Substituting for I1 gives us:

Page 16: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesThis means that I3 is:

We can then solve for the power dissipated by the 9Ω resistor with:

The great thing about this technique is that we can now very easily solve for the current or power dissipated through any of the resistors.

Page 17: Lecture 28B - UC San Diego | Department of Physics

Kirchhoff’s RulesWhen performing analysis on a circuit diagram:

1) Find out the variable you are looking for (may not be obvious from the way the question is stated).

2) Find out if making equivalent resistance is helpful (maybe helpful for only some of the circuit).

3) Choose directions for currents at junctions (you may have to guess, but that is okay).

4) Choose directions for voltage loops (some loops may give you redundant information).

5) Apply loop equations, junction equations, Ohm’s Law, power equations to search for desired variable.