lecture 35: wed 15 apr ch:33.8-10

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Lecture 35: WED 15 APR Lecture 35: WED 15 APR Ch:33.8-10 Ch:33.8-10 Physics 2102 Jonathan Dowling QuickTime™ and a decompressor are needed to see this picture. QuickTime™ and a decompressor are needed to see this picture. QuickTime™ and a decompressor are needed to see this picture.

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Physics 2102 Jonathan Dowling. Lecture 35: WED 15 APR Ch:33.8-10. Reflection and Refraction. When light finds a surface separating two media (air and water, for example), a beam gets reflected (bounces) and another gets refracted (bends). - PowerPoint PPT Presentation

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Page 1: Lecture 35: WED 15 APR  Ch:33.8-10

Lecture 35: WED 15 APR Lecture 35: WED 15 APR

Ch:33.8-10Ch:33.8-10

Physics 2102Jonathan Dowling

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Page 2: Lecture 35: WED 15 APR  Ch:33.8-10

Reflection and Reflection and RefractionRefraction

Law of reflection (Light Bounces): the angle of incidence 1 equals the angle of reflection ’1. 1 = ’1

Law of reflection (Light Bounces): the angle of incidence 1 equals the angle of reflection ’1. 1 = ’1Law of Refraction (Light Bends):  

n2 sin2 =n1 sin1  Snell's Law

Law of Refraction (Light Bends):  

n2 sin2 =n1 sin1  Snell's Law

When light finds a surface separating two media (air and water, for example), a beam gets reflected (bounces) and another gets refracted (bends).

n is the index of refraction of the medium. In vacuum, n = 1. In air, n ~ 1. In all other media, n > 1.

Page 3: Lecture 35: WED 15 APR  Ch:33.8-10

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Plastic Glass Speed of Light is Slowed n>1

v ≡c / n    &    n≥1     ⇒     v≤c

n=1

n>1

Hits Sand

Road vL

vR

Turns Left

Page 4: Lecture 35: WED 15 APR  Ch:33.8-10

ExampleExampleWater has n=1.33. How much does a beam incident at 45o refracts?

n2 sin 2= n1 sin 1

sin 2= (n1 /n2) sin 1

=(1/1.33) sin 45o

=0.00982= 32o

n2 sin 2= n1 sin 1

sin 2= (n1 /n2) sin 1

=(1/1.33) sin 45o

=0.00982= 32o

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Page 5: Lecture 35: WED 15 APR  Ch:33.8-10

Water on Desert Road Water on Desert Road IllusionIllusion

The index of refraction decreases with temperature: the light gets refracted and ends up bending upwards.

We seem to see water on the road, but in fact we are looking at the sky!

The index of refraction decreases with temperature: the light gets refracted and ends up bending upwards.

We seem to see water on the road, but in fact we are looking at the sky!

Page 6: Lecture 35: WED 15 APR  Ch:33.8-10

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Water on the Desert Road Mirage

Page 7: Lecture 35: WED 15 APR  Ch:33.8-10

Chromatic DispersionChromatic DispersionThe index of refraction depends on the wavelength (color) of the light.

Page 8: Lecture 35: WED 15 APR  Ch:33.8-10

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Page 9: Lecture 35: WED 15 APR  Ch:33.8-10

The Single Rainbow

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Page 10: Lecture 35: WED 15 APR  Ch:33.8-10

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The Double Rainbow

TotalInternalReflection!

Page 11: Lecture 35: WED 15 APR  Ch:33.8-10

Total Internal Total Internal ReflectionReflection

From glass to air, the law of refraction uses n2<n1, so 2> 1: it may reach 90o or more: the ray is “reflected” instead of “refracted”.

For glass (fused quartz) n=1.46, and the critical angle is 43o: optical fibers!

Condition for TIR:n2 sin2= n1 sin1

&2    ≥ n1>1

n2~1

1

2

Page 12: Lecture 35: WED 15 APR  Ch:33.8-10

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Page 13: Lecture 35: WED 15 APR  Ch:33.8-10

The cut of the diamond favors total internal reflection. Most rays entering the top of the diamond will internally reflect until they reach the top face of the diamond where they exit. This gives diamonds their bright sparkle. A fiber optic is a glass "hair"

which is so thin that once light enters one end, it can never strike the inside walls at less than the critical angle. The light undergoes total internal reflection each time it strikes the wall.

Fiber optic cables are used to carry telephone and computer communications.

Page 14: Lecture 35: WED 15 APR  Ch:33.8-10

Fiber Optic Cables

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Page 15: Lecture 35: WED 15 APR  Ch:33.8-10

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FIBER OPTIC GUIDED MISSILE

Page 16: Lecture 35: WED 15 APR  Ch:33.8-10

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Page 17: Lecture 35: WED 15 APR  Ch:33.8-10

Polarization By Polarization By ReflectionReflection

Different polarization of light get reflected and refracted with different amplitudes (“birefringence”).

At one particular angle, the parallel polarization is NOT reflected at all! This is the “Brewster angle” B, and B + r = 90o.

ΒΒΒ =−= cos)90sin(sin 221 nnn o

1

2tannn=Β

1

2tannn=Β

Polarizing Sunglasses

Page 18: Lecture 35: WED 15 APR  Ch:33.8-10

Polarized Sunglasses

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