lecture -- transfer matrices · 2 days ago · concept of transfer matrices (6 of 15) slide 9 11...
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Advanced Computation:
Computational Electromagnetics
Transfer Matrices
Outline
• Concept of transfer matrices
• Wave vector components
• Calculating transfer matrices
• Stability of transfer matrices
Slide 2
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Slide 3
Concept of Transfer Matrices
Concept of Transfer Matrices (1 of 15)
Slide 4
Suppose it is desired to simulate four dielectric slabs.
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Concept of Transfer Matrices (2 of 15)
Slide 5
The process starts by defining the field at the input face of the device.
0
0
,
,
E x y
H x y
Concept of Transfer Matrices (3 of 15)
Slide 6
1 0
1 0
, ,?
, ,
E x y E x y
H x y H x y
How can the field at the first interface inside the device be calculated?
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Concept of Transfer Matrices (4 of 15)
Slide 7
The first transfer matrix 𝑇 is calculated by analyzing Layer 1.
1 0
1 0
, ,?
, ,
E x y E x y
H x y H x y
Concept of Transfer Matrices (5 of 15)
Slide 8
1 111 121 0
1 11 021 22
, ,
, ,
t tE x y E x y
H x y H x yt t
The transfer matrix 𝑇 is used to calculate the field at the first interface inside the device.
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Concept of Transfer Matrices (6 of 15)
Slide 9
1 111 121 0
1 11 021 22
, ,
, ,
t tE x y E x y
H x y H x yt t
Now the field at the first interface inside the device is known.
Concept of Transfer Matrices (7 of 15)
Slide 10
The second transfer matrix 𝑇 is calculated by analyzing Layer 2.
1 111 121 0
1 11 021 22
, ,
, ,
t tE x y E x y
H x y H x yt t
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Concept of Transfer Matrices (8 of 15)
Slide 11
2 2 1 111 12 11 122 0
2 2 1 12 021 22 21 22
, ,
, ,
t t t tE x y E x y
H x y H x yt t t t
The second transfer matrix 𝑇 is used to calculate the field at the second interface inside the device.
Concept of Transfer Matrices (9 of 15)
Slide 12
2 2 1 111 12 11 122 0
2 2 1 12 021 22 21 22
, ,
, ,
t t t tE x y E x y
H x y H x yt t t t
Now the field at the second interface inside the device is known.
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Concept of Transfer Matrices (10 of 15)
Slide 13
The third transfer matrix 𝑇 is calculated by analyzing Layer 3.
2 2 1 111 12 11 122 0
2 2 1 12 021 22 21 22
, ,
, ,
t t t tE x y E x y
H x y H x yt t t t
Concept of Transfer Matrices (11 of 15)
Slide 14
3 3 2 2 1 111 12 11 12 11 123 0
3 3 2 2 1 13 021 22 21 22 21 22
, ,
, ,
t t t t t tE x y E x y
H x y H x yt t t t t t
The third transfer matrix 𝑇 is used to calculate the field at the third interface inside the device.
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Concept of Transfer Matrices (12 of 15)
Slide 15
3 3 2 2 1 111 12 11 12 11 123 0
3 3 2 2 1 13 021 22 21 22 21 22
, ,
, ,
t t t t t tE x y E x y
H x y H x yt t t t t t
Now the field at the third interface inside the device is known.
Concept of Transfer Matrices (13 of 15)
Slide 16
3 3 2 2 1 111 12 11 12 11 123 0
3 3 2 2 1 13 021 22 21 22 21 22
, ,
, ,
t t t t t tE x y E x y
H x y H x yt t t t t t
The fourth transfer matrix 𝑇 is calculated by analyzing Layer 4.
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4 4 3 3 2 2 1 111 12 11 12 11 12 11 124 0
4 4 3 3 2 2 1 14 021 22 21 22 21 22 21 22
, ,
, ,
t t t t t t t tE x y E x y
H x y H x yt t t t t t t t
Concept of Transfer Matrices (14 of 15)
Slide 17
The fourth transfer matrix 𝑇 is used to calculate the field at the output face of the device.
4 4 3 3 2 2 1 111 12 11 12 11 12 11 124 0
4 4 3 3 2 2 1 14 021 22 21 22 21 22 21 22
, ,
, ,
t t t t t t t tE x y E x y
H x y H x yt t t t t t t t
Concept of Transfer Matrices (15 of 15)
Slide 18
Finally the field at the output face the device is known.
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4 4 3 3 2 2 1 111 12 11 12 11 12 11 124 0
4 4 3 3 2 2 1 14 021 22 21 22 21 22 21 22
, ,
, ,
t t t t t t t tE x y E x y
H x y H x yt t t t t t t t
The Global Transfer Matrix
Slide 19
Alternatively, all of the intermediate transfer matrices can be multiplied together to calculate the global transfer matrix that directly relates the field at the input and output faces.
Global Transfer Matrix
𝑇 𝑇 𝑇 𝑇 𝑇
Slide 20
Wave Vector Components
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Calculation of the Wave Vector Components
Slide 21
The components kx and ky are determined by the incident wave and are equal throughout the entire device. The kz component is different in each layer and is calculated from the dispersion relation in that layer.
0 r,inc r,inc
0 r,inc r, c
,inc
,inc in
sin cos
sin sin
x
y
x
y
k k
k
k
k k
2 2 2, 0 r, r,z i i i x yk k k k
Layer #i
kx and ky are Continuous Throughout Device
Slide 22z
xinck
kx
refk -kz,air
kxkz,air
22 2,air 0 airz xk k n k
,inc 0 ai
,inc a
r
0 ir
cos sin
cosz
x
k k n
k k n
kx
kz,11k
22 2,1 0 1z xk k n k
1n
2n
3n
kx
kz,22k
22 2,2 0 2z xk k n k
kx
kz,33k
22 2,3 0 3z xk k n k
kx
kz,airtrnk
22 2 2,trn 0 air ,airz x zk k n k k
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Slide 23
Calculating Transfer Matrices
Geometry of an Intermediate Layer
Slide 24
Layer i Layer i+1Layer i-1
0iψ
1 0 1i ik L ψ
iL
0i ik Lψ
1 0iψ
1iL 1iL
1icic1ic
i izψ
is a local z‐coordinate inside the ith layer that starts at zero at the layer’s left side.
iz0
iz
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Enforce the Boundary Conditions
Slide 25
Field inside the ith layer:
,
,
,
,
i i
x i i
y i i zi i i i
x i i
y i i
E z
E zz e
H z
H z
λψ W c
Boundary conditions at the first interface:
Boundary conditions at the second interface:
1 0 1
1 0 1
1 1
0
i i
i i i
k Li i i i
k L
e
λ
ψ ψ
W c Wc
0
0 1
1 1
0
i i
i i i
k Li i i i
k L
e
λ
ψ ψ
W c W c
Must include k0 in the exponential to normalize Li-1 because the parameter i-1 expects to multiply a normalized coordinate.
Note: Must equate the field on either side of the interfaces and not the mode coefficients c.
The Transfer Matrix
Slide 26
The transfer matrix Ti of the ith layer is defined as:
Start with the boundary condition equation from the second interface and rearrange terms…
1i i i c T c
iT0 01
1 1 1 1 i i i ik L k Li i i i i i i ie e
λ λW c W c c W W c
011
i ik Li i ie
λT W W…then read off the transfer matrix.
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Slide 27
Stability of Transfer Matrices
The Multi‐Layer Problem
Slide 28
The diagram below is focused on the ith layer somewhere in the middle of a stack of multiple layers.
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Forward Waves in the ith Layer
Slide 29
Recall that the wave number 𝑘 is in general complex. Waves can oscillate, decay or both.
k k jk decayoscillation
Backward Waves in the ith Layer
Slide 30
Due to reflections at the interfaces, there will be backward waves. These can also oscillate, decay or both.
k k jk decayoscillation
k k jk decayoscillation
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Waves According to Transfer Matrices
Slide 31
In terms of signs, transfer matrices treat all waves as forward propagating, even the backward waves.
k k jk decayoscillation
k k jk decayoscillation
?
,
,
,
,
i i
x i i
y i i zi i i i
x i i
y i i
E z
E zz e
H z
H z
λψ W c
Pure Transfer Matrices are Unstable
Slide 32
Transfer matrices treat all waves as if they are forward propagating. Backward waves that also decay increase exponentially and become numerically unstable.
k k jk decayoscillation
k k jk explodebackward
oscillation
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The Fix – Identify Forward and Backward Waves
Slide 33
Clearly, the first part of the fix is to identify forward and backward propagating waves.
This can be accomplished by calculating the Poynting vector ℘ associated with the eigen‐modes and looking at the sign of the z component. Be careful! A normalized magnetic field is being used.
0 0
0
1
z x y y x
y xz x y
z x y y x
E H
E H E H
H HE E
j j
E H E Hj
0.32 0.32 0 0
0 0 0.32 0.32
0 0 0.95 0.95
0.95 0.95 0 0
i i
i i
W
3.0 0 0 0
0 3.0 0 0
0 0 3.0 0
0 0 0 3.0
i
i
i
i
λ
Rearrange the Eigen Modes
Slide 34
Now that it is known which eigen‐modes are forward and backward propagating, they can be rearranged to group them together.
0.32 0.32 0 0
0 0 0.32 0.32
0 0 0.95 0.95
0.95 0.95 0 0
i i
i i
W
3.0 0 0 0
0 3.0 0 0
0 0 3.0 0
0 0 0 3.0
i
i
i
i
λ
0.32 0 0.32 0
0 0.32 0 0.32
0 0.95 0 0.95
0.95 0 0.95 0
i i
i i
W
Also need to adjust the vertical positions of the eigen‐values so that 𝛌 remains a diagonal matrix.
rearrangeeigen‐modes
Original Matrices Rearranged Matrices
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New Interpretation of the Matrices
Slide 35
3.0 0 0 0
0 3.0 0 0
0 0 3.0 0
0 0 0 3.0
i
i
i
i
λ
0.32 0 0.32 0
0 0.32 0 0.32
0 0.95 0 0.95
0.95 0 0.95 0
i i
i i
W
x
y
x
y
E
E
H
H
E E
H H
zz
z
ee
e
λλ
λ
W WW
W W
0
0
The matrices are now partitioned into forward and backward propagating elements.
x
y
x
y
E
E
H
H
3.0 0 3.0 0
0 3.0 0 3.0
i i
i i
λ λNote: For anisotropic materials, all the eigen‐vectors and eigen‐values are in general unique.
Revised Solution to Differential Equation
Slide 36
The matrix differential equation and its original solution was
zdz e
dz
λψ
Ωψ 0 ψ W c
After distinguishing between forward and backward propagating waves and grouping them in the matrices, the solution can be written as
z
E E
zH H
ez
e
λ
λ
0W W cψ
W W c0
There are now separate mode coefficients c+ and c- for forward and backward propagating modes, respectively.
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