leo lam © 2010-2013 signals and systems ee235 leo lam © 2010-2013 stanford the stanford linear...

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Leo Lam © 2010-2013 Signals and Systems EE235

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  • Slide 1
  • Slide 2
  • Leo Lam 2010-2013 Signals and Systems EE235
  • Slide 3
  • Leo Lam 2010-2013 Stanford The Stanford Linear Accelerator Center was known as SLAC, until the big earthquake, when it became known as SPLAC. SPLAC? Stanford Piecewise Linear Accelerator.
  • Slide 4
  • Leo Lam 2010-2013 Todays menu Today: Linear, Constant-Coefficient Differential Equation Particular Solution
  • Slide 5
  • Zero-state output of LTI system Leo Lam 2010-2013 4 Response to our input x(t) LTI system: characterize the zero-state with h(t) Initial conditions are zero (characterizing zero-state output) Zero-state output: Total response(t)=Zero-input response (t)+Zero-state output(t) T (t) h(t)
  • Slide 6
  • Zero-state output of LTI system Leo Lam 2010-2013 5 Zero-input response: Zero-state output: Total response: Total response(t)=Zero-input response (t)+Zero-state output(t) Zero-state: (t) is an input only at t=0 Also called: Particular Solution (PS) or Forced Solution
  • Slide 7
  • Zero-state output of LTI system Leo Lam 2010-2013 6 Finding zero-state output (Particular Solution) Solve: Or: Guess and check Guess based on x(t)
  • Slide 8
  • Trial solutions for Particular Solutions Leo Lam 2010-2013 7 Guess based on x(t) Input signal for time t> 0 x(t) Guess for the particular function y P
  • Slide 9
  • Particular Solution (example) Leo Lam 2010-2013 8 Find the PS (All initial conditions = 0): Looking at the table: Guess: Its derivatives:
  • Slide 10
  • Particular Solution (example) Leo Lam 2010-2013 9 Substitute with its derivatives: Compare:
  • Slide 11
  • Particular Solution (example) Leo Lam 2010-2013 10 From We get: And so:
  • Slide 12
  • Particular Solution (example) Leo Lam 2010-2013 11 Note this PS does not satisfy the initial conditions! Not 0!
  • Slide 13
  • Natural Response (doing it backwards) Leo Lam 2010-2013 12 Guess: Characteristic equation: Therefore:
  • Slide 14
  • Complete solution (example) Leo Lam 2010-2013 13 We have Complete Sol n : Derivative:
  • Slide 15
  • Complete solution (example) Leo Lam 2010-2013 14 Last step: Find C 1 and C 2 Complete Sol n : Derivative: Subtituting: Two equations Two unknowns
  • Slide 16
  • Complete solution (example) Leo Lam 2010-2013 15 Last step: Find C 1 and C 2 Solving: Subtitute back: Then add u(t): y n ( t ) y p ( t ) y ( t )
  • Slide 17
  • Another example Leo Lam 2010-2013 16 Solve: Homogeneous equation for natural response: Characteristic Equation: Therefore: Input x(t)
  • Slide 18
  • Another example Leo Lam 2010-2013 17 Solve: Particular Solution for Table lookup: Subtituting: Solving: b=-1, =-2 No change in frequency! Input signal for time t> 0 x(t) Guess for the particular function y P
  • Slide 19
  • Another example Leo Lam 2010-2013 18 Solve: Total response: Solve for C with given initial condition y(0)=3 Tada!
  • Slide 20
  • Stability for LCCDE Leo Lam 2010-2013 19 Stable with all Re( j