LIFTING LUGS ON TOP HEAD

Fz

FR(x,z)

FR(x,z,y)

FR(x.z)

xxFx

h

P

My

Fyd

Mx

yy

Mt

VIEW Y-Z VIEW X-Z

Lug Dimension:Lug width = mmB 140

B

P

HP

Lug width = mmLug thickness = mmLug radius = mmShackle/bolt pin diameter = mmPin hole diameter = mmCenter of lug from A-A = mmSwing angle = Deg.Side swing angle = Deg.Lenght of weld = mm

dh

BHR

dp

Lw90

320

140204021

7530

60

Lenght of weld mmFillet weld size used = mmAllowable load on weld = MPa

Lifting Weight & Design Load:Load ( Empty Weight = kg ) = NDinamic Factor =Total load = NNumber of lifting lug =

4721.50

Wt2.00

92635.83

W

ffw

n 3.00

46317.92

Lw 320

66.199.00

Number of lifting lugLoad per lug = N

Lug material:Lug material selected : SA 240 304LYield stress of material = MPa

Allowable stress for lug (AISC Code):Allowable bending stress = 0.66 * Sy = MPaFb 113.78

172.40Sy

nP

3.0030878.61

g yAllowable shear stress = 0.25 * Sy = MPaAllowable tension stress = 0.66 * Sy = MPaAllowable bearing stress = 0.9 * Sy = MPa

Force Acting on the Lug:At View X-Z

Resultan force = P / Sin () = NVertical force = FR(x,z) * Sin () = N

113.78155.16

35655.55

Fp

30878.61FR(x,z)

43.10FsFt

FzHorizontal force = FR(x,z) * Cos () = N

At View Y-ZTransverse force = P / Tan () = N

Resultan force = (Fy2 + FR(x,z)2)^0.5 = N

Required thickness = FR(x,z,y)/(2*Fs*(R - d/2)) = mmThickness is acceptable, since < mm

Fy

FR(x,z,y)

t20.00

Fx

0.00

35655.55

16.55

17827.77

Moment Acting on the Lug:Moment in z-direction = Fy * h = N-mmMoment in y-direction = Fz * h = N-mmMoment in x-direction = Torsion = N-mm

1337083.03Mz 0.00MyMx 0.00

Stress Analysis on lug:

Section modulus at x-axis = B * H2 / 6 = mm3

Section modulus at y-axis = B2 * H / 6 = mm3

Bending stress = Mz / Zz-z = MPa= My / Zy-y = MPa

Tensile / compressive stress = Fx / (B * H) = MPa

65333.33

Zz-z

fbz 0.00

Zy-y

9333.33

fby 20.47ft 6.37p ( )

Unity Check:ft/Ft + fbz/Fb + Fby/Fb < 1 = <

Stress is acceptable, since < 1Stress Analysis on weld:

Compression load on fillet weld per linier mm = Fx / Lw = N/mm

Section modulus of fillet weld = B2 / 3 = mm2

= B * H = mm2

6533.33

2800 00

L 55.71

Swz

0.2358

Swy

1.0000

= B * H = mmBending force at fillet weld = My / Swz = N/mm

= Mz / Swy = N/mmShear force at fillet weld = Fz / Lw = N/mm

= Fy / Lw = N/mm

Resultan force at fillet weld WR = (L2+Wbz2+Wby2+Wsz2+Wsy2)^0.5 = N/mmFillet weld size = WR / f = mm

Fillet weld size is acceptable, since < mmShear Stress at Pin Hole:

2800.00

0.00WszWsy

Swy

233.02

WbzWby

tw9.003.52

204.660.00

96.50

Shear Stress at Pin Hole:

Shear area = 2 * (R - d/2) * H = mm2

Shear stress = FR(x,z,y) / A = MPaShear stress is acceptable, since < MPa

Bearing Stress at Pin Hole:Additional check plate thickness to lug = mm

Bearing area = dp * H = mm2

Bearing stress = FR(x,z,y) / Ap = MPa

A 1000.00

43.10fs 35.66

fp 84.89

T 0

Ap 420.00g ( y) p

Bearing stress is acceptable < MPa155.16p