Number of Years Since 1990, x Housing Price, y3 $125,0007 $150,000

Linear Model Application1. You have been aware of a steady increase in housing prices in your neighborhood since 1990. The house across the street sold for $125,000 in 1993, and then sold again, in 1997, for $150,000. This data can be written in table format where the input represents the number of years since 1990, and the output represents the sale price of a typical house in your neighborhood.

a) Plot the two points on the grid below and sketch the line containing them. Extend the line so that it intersects the vertical axis.

b) Determine the slope of the line. What are its units of measurement? What is the practical meaning of the slope in this situation?

c) Write an equation for the line containing the two points you graphed.

d) What is the vertical intercept of the line you graphed and whose equation you wrote? What is the practical meaning of the vertical intercept in this situation?

e) Use this model to predict the price of this house in that neighborhood for the year 2005.

f) Use this model to determine the year that the price of this house was $87,500.

Slope = ($150,000 - $125,000)/(7-3 years) = $6250/yrThe housing price increased by $6250 each year.

Use any point from the table (3, 125000) and m = 6250 and use point-slope formulay -125000 = 6250(x – 3) = 6250x - 18750y = 6250x – 18750 + 125000Equation: y = 6250x + 106250

Vertical Intercept = 106250. The housing price was $106250 in 1990.

2005 – 1990 = 15, so x = 15Price = y = $6250(15) + $106250 = $200,000

Solve for x: 87500 = 6250x + 106250x = -3 1990 -3 = 1987. The price was $87,500 in 1987

2.5 3 3.5 4 4.5 5 5.5 6 6.5 7 7.5$0

$10,000

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52

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Put the inequality in“slope-intercept form” and graph it like a line:dashed if < or >, * solid if ≤ or ≥. Shade BELOW the line if < or ≤Shade ABOVE the line if > or ≥

52

5 )10 xy

6) x > -1

8) y ≤ 3

y ≤ -x +5

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sides both from4x Subtract 2054 yxsolution

9) Graph the solution to this system of inequalities:

symbol. inequality switch the and

5-by sidesboth divide Now 2045 xy

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4 xy

sidesboth from3x Subtract 623 yx

2by sidesboth Divide 632 xy

32

3

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2054 yx

623 yx

Shade ABOVE a DASHED line with slope 4/5 and y-intercept (0,4)

Shade ABOVE a SOLID line with slope -3/2 and y-intercept (0,3)

solution

14)

y ≤ -x +5

y ≤ 0

y≥ -x + 2

y ≤ -x +5

y ≤ 0

y≥ -x + 2

What did “or” mean when working with inequalities?

UNION

This means you will solve both inequalities and the solution will be

EVERYTHING in EACH SOLUTION

1st) Put each inequality in slope-intercept form and graph them.

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2

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623

632

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-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10

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y

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SOLUTION is BLUE, GREEN, and YELLOW

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10

-10-9-8-7-6-5-4-3-2-10123456789

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y

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a) Remember absolute value inequalities? The solution of|x| ≤ k an INTERSECTION.

x ≤ k AND x≥ -k

|y -2x| ≤ 3

y – 2x ≤ 3 AND y – 2x ≥ -3

Put each in slope-intercept form and graph them. The solution is theINTERSECTION of the graphs (only where the shaded regions overlap).

NOTE: If the shaded regions do not overlap in an intersection, then there is no solution. (The solution would be the empty set, )

y ≤ 2x + 3 y ≥ 2x - 3

SOLUTIO

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What are we trying to find? The possible numbers of AM and FM ads that can be purchased.LetX =the number of AM adsY = the number of FM ads

Form an inequality using the given information. What does “a maximum of” mean in mathematics?“a maximum of” means less than or equal to.What are some implied restrictions? Can the number of ads be negative?

0 10 20 30 40 50 60 700

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Possible Combinations of AM & FM ads

Number of AM ads

Num

ber o

f FM

ads

603

275

3000

75

50

75

75

30005075

30007550

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xy

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