list of practical cs with solution

8/3/2019 List of Practical Cs With Solution

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LIST OF PRACTICALS

CLASS XII

SUBJECT : COMPUTER SCIENCE

Q1. Define a class PhoneBill in C++ with the following descriptions.

Private members:

CustomerName of type character array

PhoneNumber of type long

No_of_units of type intRent of type int

Amount of type float.

calculate( ) This member function should calculate the value of amount asRent+ cost for the units.

Where cost for the units can be calculated according to the following conditions.

No_of_units Cost

First 50 calls FreeNext 100 calls 0.80 @ unit

Next 200 calls 1.00 @ unit

Remaining calls 1.20 @ unit

Public members:* A constructor to assign initial values of CustomerName as Raju, PhoneNumber as

259461, No_of_units as 50, Rent as 100, Amount as 100.* A function accept( ) which allows user to enter CustomerName, PhoneNumber,

No_of_units and Rent and should call function calculate( ).

* A function Display( ) to display the values of all the data members on the screen.

Solution:

#include

#include

#include #include

class phonebill{private:

char CustomerName[20];

long PhoneNumber;

int No_of_units ;int Rent;

float Amount;

void calculate();public:

phonebill()

{ PhoneNumber=259461;No_of_units=50;

strcpy(CustomerName,"Raju");

Rent=100;Amount=100;

}

void accept();

void display();};

void phonebill:: calculate()
mailto:1.00@unitmailto:1.00@unit


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{

if(No_of_units=51 && No_of_units=151 && No_of_units


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Q2. Define a class Tour in C++ with the description given below :

Private Members :

TCode of type string Noofadults of type integer

Noofkids of type integer

Kilometres of type integerTotalfare of type float

Public Members :

A constructor to assign initial values as follows :TCode with the word NULL

NoofAdults as 0

NoofKids as 0Kilometres as 0

TotalFare as 0

A function AssignFare ( ) which calculates and assigns the value of the data member TotalFare as follows :

Foreach Adult

Fare(Rs) For Kilometres

500 >=1000

300 =500

200


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NoofKids=0;

Kilometres= 0;

TotalFare=0.0f;

}void Tour::EnterTour(void)

{

coutTCode;

coutNoofAdults;coutNoofKids;

coutKilometres;

AssignFare();

}

void Tour::AssignFare(void){

float fare=0.0f;

if(Kilometres>1000)

{fare = NoofAdults*500+NoofKids*250;

}else if(Kilometres>=500)

{

fare = NoofAdults*300+NoofKids*150;

}

else

fare = NoofAdults*200+NoofKids*100;Totalfare=fare;

}void Tour::ShowTour(void){

cout


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Enter distance 850

Travel List is as followsTravel Code: 101

Number Of Adults: 2

Number of kids: 3Kilometres: 850

Total Fare:1050

Q3. Define a classELECTIONwith the following specifications :

Private members :

Data : candidate_name , party , vote_receivedPublic members :

Functions : INPUT( ) to input data

DISPLAY( ) to display the details of the winner

WINNER( ) To return the details of the winner through the objectafter comparing the votes received by three candidates .

Write a suitable main ( ) function to input data in 3 objects ofELECTIONtype and display the details of th

winning candidate.

Solution:#include

#include#include

class ELECTION

{

private:char cname[20];

char party[30];

long voterecevied;public:

void input(){cout


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return(X);

}

else if ((Y.voterecevied>Z.voterecevied) && (Y.voterecevied>X.voterecevied))

{return(Y);

}

elsereturn(Z);

}

};void main()

{

ELECTION A,B,C,W;clrscr();

A.input();

B.input();

C.input();W=W.WINNER(A,B,C);

W.display();

getch();

}Output:

Enter candidates name AbhinavEnter party of the candidate name BJP

Enter the amount of vote recevied by the candidate45861

Enter candidates name Rahul

Enter party of the candidate name RJD

Enter the amount of vote recevied by the candidate56445

Enter candidates name RajeevEnter party of the candidate name CONGRESSEnter the amount of vote recevied by the candidate46466

Winning candidate

Candidate name RahulParty of the candidate RJD

The amount of vote recevied by the candidate56466

Q4. Suppose A,B,C are arrays of size m, n, m+n respectively. Array A is stored in ascending order an

array B is in descending order. Write a program using function to receive 3 arrays and their sizes to store th

elements of A and B into C in descending order.Solution:

//program to merge two arrays in a single array

//Array A is in Ascending Order & Array B is in Descending Order//Array C must be in Descending Order

#include

#include

void main(){

int m,n,k;

int a[50],b[50],c[100];


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int i,j;

clrscr();

// entering size of array

coutm;

coutn;cout


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Output:

Enter the size of 1st array A3

Enter the size of 2nd array B3

Enter values for Array A in Ascending Order

Enter value of 1 value of Array A 1

Enter value of 2 value of Array A 2Enter value of 3 value of Array A 3

Enter values for Array B in Descending OrderEnter value of 1 value of Array B 5

Enter value of 2 value of Array B 4

Enter value of 3 value of Array B 3

Merged arrays are as following....

5

43

3

2

1

Q5. Suppose A,B,C are arrays of size m, n, m+n respectively. Array A is stored in descending order an

array B is in ascending order. Write a program using function to receive 3 arrays and their sizes to store th

elements of A and B into C in descending order.

Solution:

//program to merge two arrays in a single array//Array A is in Ascending Order & Array B is in Descending Order

//Array C must be in Descending Order

#include#include

void main(){int m,n,k;

int a[50],b[50],c[100];

int i,j;

clrscr();// entering size of array

coutm;coutn;

cout


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}

i=m-1;

j=0;

k=0;for(;i>=0 && j=b[j])

{c[k]=a[i];

i=i-1;

}else

{

c[k]=b[j];j=j+1;

}

k=k+1;

}if(i>=0)

{

while(i>=0)

c[k++]=a[i--];}

else{

while(j


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12

11

10

Q6. Write program using a function SORTSCORE( ) in C++ to sort an array ofstructureExaminee in

descending order of Score using BUBBLE Sort.

Note : Assume the following definition of structure Examineestruct Examinee{

long RollNo;char Name[20];

float Score;

};Sample content of of the array (before sorting)

Roll NO. Name Score

1001 Ravyank Kapur 300

1005 Farida Khan 2891002 Anika Jain 345

1003 Gearge Peter 297

Sample content of of the array (after sorting)

Roll NO. Name Score1002 Anika Jain 345

1001 Ravyank Kapur 3001003 Gearge Peter 297

1005 Farida Khan 289

Solution:

//Bubble sorting of Structures#include

#include

#include#include

struct Examinee{long RollNo;

char Name[20];

float Score;

};void SORTSCORE(Examinee x[],int n)

{

int i,j;Examinee tmp;

for(i=0;i


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cout


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int empno;

char Ename[20];

float salary;

};

Solution:

//Program for sorting using selection sort

#include //inclusion of header file#include //inclusion of header file

#include //inclusion of header file

struct Employee{

int empno;

char Ename[20];float salary;

};

void sort(Employee x[],int n)

{int i,j,big,pos;

Employee tmp;

for(i=0;i


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gets(x[i].Ename);

coutx[i].salary;

}sort(x,n);

getch();

}

Output:

Enter number of Employees 3

Enter values for employee 1

Enter Employee No. 1

Enter Employee Name AmarEnter Salary 2100

Enter values for employee 2

Enter Employee No. 2Enter Employee Name Dilip

Enter Salary 3200

Enter values for employee 3Enter Employee No. 3

Enter Employee Name SureshEnter Salary 1100

Records after sorting are

2 Dilip 32001 Amar 2100

3 Suresh 1100

Q7. Write a program to accept salaries of some employees in an array of size accepted from user and display

the salaries in ascending order. (Use insertion sort technique to sort the salaries)Solution:

//Arranging salaries stored in an array using Insertion sort

#include

#include

#includevoid main()

{

clrscr();int sal[100],i,j,tmp,n;

coutn;sal[0]=INT_MIN;

for(i=1;i


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while(tmp


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while(beg


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{

cout


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Enter values for array

Enter value of 1 row and 1 column 11

Enter value of 1 row and 2 column 12Enter value of 1 row and 3 column 13





Original array is11 12 13

14 15 16

17 18 19

Diagonal1 : 11 15 19

Diagonal Two : 13 15 17

Q10. Write a function in C++ which accepts a 2D array of integers and its size as

arguments and displays the elements of middle row and the elements of middle column.[Assuming the 2D Array to be a square matrix with odd dimension i.e. 33, 55, 77 etc...]

Example, if the array content is

3 5 4

7 6 92 1 8

Output through the function should be :

Middle Row : 7 6 9Middle Column : 5 6 1

Solution:#include //inclusion of header file#include //inclusion of header file

void show_mid(int a[100][100],int r,int c)

{

int i,k;k=r/2;

cout


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coutr>>c;

cout


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9 7 5 8

1 2 4 9

2 5 8 1

5 6 3 2

Solution:

#include //inclusion of header file

#include //inclusion of header filevoid swaparr(int a[100][100],int r,int c)

{int i,j,tmp;

for(j=0;j


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getch();

}

Output:

Enter no. of rows and columns of array 3 3

Enter values for arrayenter value of 1 row and 1 column 1

enter value of 1 row and 2 column 2

enter value of 1 row and 3 column 3enter value of 2 row and 1 column 4


enter value of 2 row and 3 column 6enter value of 3 row and 1 column 7



Original array is

1 2 3

4 5 6

7 8 9

After swapping first and last rows array is7 8 9

4 5 6

1 2 3

Q12. Write a function in C++ which accepts an integer array and its size as arguments / parameters and

assign the elements into a two dimensional array of integers in the following format

(size must be odd)If the array is 1 2 3 4 5 If the array is 10 15 20

The output must be The output must be1 0 0 0 5 10 0 200 2 0 4 0 0 15 0

0 0 3 0 0 10 0 20

0 2 0 4 0

1 0 0 0 5

Solution:

#include

#includevoid perform(int a[100],int size)

{

int b[100][100],r,c,k=0;for(r=0;r


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{

b[r][c]=0;

}

}}

k=size-1;

for(r=0;r


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0 0 3 0 0

0 2 0 4 0

1 0 0 0 5

Q13. Write a function in C++ which accepts an integer array and its size as arguments and assign the

elements into a two dimensional array of integers in the following format:

If the array is 1,2,3,4,5,6 if the array is 1,2,3The resultant 2D array is The resultant 2D array is

1 0 0 0 0 0 1 0 0

1 2 0 0 0 0 1 2 01 2 3 0 0 0 1 2 3

1 2 3 4 0 0

1 2 3 4 5 01 2 3 4 5 6

Solution:

#include

#includevoid perform(int a[100],int size)

{

int b[100][100],r=0,k=0,i,c;

for(i=0;i


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cin>>a[i];

}

perform(a,x);

getch();}

OUTPUT:

enter the size of the array3enter the value of 1number:1

enter the value of 2number:2

enter the value of 3number:3Contents of array B is

1 0 0

1 2 01 2 3

Q14 Write a function in C++ to print the count of the word is as an independent word

in at text file DIALOGUE.TXT.For example, if the content of the file DIALOGUE. TXT is

This is his book. Is this book good?

Then the output of the program should be 2.

Solution://Program to print total no. of "is"

#include#include

#include

void perform()

{ifstream A;

A.open("DIALOGUE.TXT",ios::in);

char s[15];int c=0;

while(!A.eof()){

A.getline(s,15,' ');

if((s[0]=='i' || s[0]=='I') && (s[1]=='S' || s[1]=='s'))

{

c++;}

}

cout


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}

Output:

Enter the text for Data File

This is his book. is this book good?

Total No. of is=2

Q15 Given a binary file GAME.DAT, containing records of the following structure typestruct Game

{char GameName [20];

char Participant [30];

};

Write a function in C++ that would read contents from the file GAME.DAT and creates a file named

BASKET.DAT copying only those records from GAME.DAT where the game name is Basket Ball.

Solution:

#include

#include

#include

#includestruct Game

{

char GameName[20];char Participant[30];

};

void COPYGAME(){

Game y;

ifstream A;

A.open("GAME.DAT",ios::binary|ios::in);ofstream B;

B.open("BASKET.DAT",ios::binary|ios::out);

while(!A.eof()){

A.read((char*)&y,sizeof(Game));

if(strcmp(y.GameName,"Basket Ball")==0){

B.write((char*)&y,sizeof(Game));

}}

A.close();

B.close();

}

void main( ){

clrscr();Game x;

ofstream H;

int ch;H.open("GAME.DAT",ios::binary|ios::out);

do

{ cout


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cout


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contain only those words from the file FIRST.TXT which start with a lowercase vowel (i.e. with a, e, I

o, u).

For example if the file FIRST.TXT contains

Carry umbrella and overcoat when it rains

Then the file SECOND.TXT shall contain:

umbrella and overcoat it

Solution:

#include

#include

void vowelwords()

{

char s[20];

ifstream A;

A.open("FIRST.TXT",ios::in);

ofstream B;

B.open ("SECOND.TXT",ios::out);

while(!A.eof())

{

A.getline(s,20,' ');

if(s[0]=='a'||s[0]=='e'||s[0]=='i'||s[0]=='o'||s[0]=='u')

{

B


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{

int rno;

float m1,m2,m3;

};

Write a program using function in C++ that would read contents from the file STUDENT.DAT and

modify the marks to 35 if anybodys any marks are less than 35.Solution:

#include#include

#include

struct Student{

int rno;

float m1,m2,m3;};

void perform()

{int c=0;

Student x;

ifstream A;

A.open("STUDENT.DAT",ios::in);ofstream B;

B.open("TEMP.DAT",ios::out);

while(!A.eof()){

A.read((char*)&x,sizeof(Student));

if(x.m1


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}

void main()

{

clrscr();Student z;

int ch=1,v=0;

ofstream D;D.open("STUDENT.DAT",ios::out);

while(ch==1)

{coutz.rno;

coutz.m1>>z.m2>>z.m3;

D.write((char*)&z,sizeof(Student));

v=v+1;

coutch;

}

D.close();

ifstream E;E.open("STUDENT.DAT",ios::in);

cout


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1 45 35 56

2 87 56 35

3 67 89 90

Q18 Given a binary file TELEPHON.DAT, containing records of the following class Directory :

class Directory

{ char Name[20] ;char Address[30] ;

char AreaCode[5] ;

char phone_No[15] ;public ;

void Register( ) ; // to accept values

void Show( ) ; // to display valuesint CheckCode(char AC[ ]);// to compare area code with accepted argument

} ;

Write a program to store object of above class in the data file at first and then using a function COPYABC( ) i

C++ copy all those records having AreaCode as 123 from TELEPHON.DAT to TELEBACK.DAT.

Solution:

#include

#include

#include#include

class Directory{

private:

char Name[20];

char Address[30];char AreaCode[5];

char phone_No[15];

public:void Register( )

{cout


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void COPYABC()

{

Directory x;

ifstream A;A.open("TELEPHON.DAT",ios::binary|ios::in);

ofstream B;

B.open("TELEBACK.DAT",ios::binary|ios::out);while(!A.eof())

{

A.read((char*)&x,sizeof(x));if(x.checkcode("123")==0)

{

B.write((char*)&x,sizeof(x));}

}

A.close();

B.close();}

void main( )

{

clrscr();Directory x;

ofstream H;int ch;

H.open("TELEPHON.DAT",ios::binary|ios::out);

do

{x.Register();

H.write((char*)&x,sizeof(x));

coutch;

}while(ch==1);H.close();

COPYABC( );

cout


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}

Output:

Enter Name of customerAmar

Enter Address of customer PatnaEnter Area code123

Enter Phone number123456

Press 1 to enter more records else to stop 1

Enter Name of customerSuresh

Enter Address of customer KhagaulEnter Area code254

Enter Phone number345212


Enter Name of customerWilson

Enter Address of customer Danapur

Enter Area code123Enter Phone number789656


Contents Of Teleback.dat is as follows:Name of customer Amar

Address of customer PatnaArea code 123

Phone number 123456

Name of customer WilsonAddress of customer Danapur

Area code 123

Phone number 789656

Q19. Write a program to store, delete and display dynamically allocated Queue containing nodes of thfollowing given structure:struct NODE

{

int Itemno;

char Itemname[20];NODE *Link;

};

The Program should contain the following functions:i) push( )- to insert new element in Queue ii) pop( ) to delete an element from the Queue

iii) display() to display the element of Queue.

Solution://QUEUE USING LINKED LIST

#include

#include#include

#include

#include

struct Node{

int Itemno;

char Itemname[20];


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Node *Link;

}

*top, *newptr, *save, *ptr,*rear;

Node* Create_New_Node(int,char[]);void push_at_end(Node*);

void Display(Node*);

void pop();void main()

{

top=rear=NULL;int rno;

char ch='y',name[20];

clrscr();while(ch=='y' || ch=='Y')

{

cout


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{

if(top==NULL)

{

top=np;rear=np;

}

else{

rear->Link=np;

rear=np;}

}

void Display(Node *np){

while(np!=NULL)

{

cout


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The Queue now is :

1 Lux

2 Liril!!!

Want to pop an element? (Y/N)...y

The Queue now is :

2 Liril!!!

Want to pop an element? (Y/N)...n

Q20. Write a program to store, delete and display dynamically allocatedStackof Books implemented wit

the help of the following structure:struct Book

{

int BNo;

char BName[20];

Book *Next;

};

The Program should contain the following functions:

i) push( )- to insert new element in stack ii) pop( ) to delete an element from the stack

iii) display() to display the element of stack.

Solution:

//STACK USING LINKED LIST-Insertion in the beginning of Stack

#include

#include#include

#include

#include

struct Book{

int Bno;char Bname[20];

Book *Next;

}

*top, *newptr, *save, *ptr;Book* Create_New_Node(int n,char nm[]);

void push(Book*);

void Display(Book*);void pop();

void main(){top=NULL;

int n;

char ch='y',bn[20];clrscr();

while(ch=='y' || ch=='Y')

{

cout


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cin>>n;

cout


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void Display(Book *np)

{

while(np!=NULL)

{cout


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1 Himmat

!!!

Want to pop an element? (Y/N)...n

Q21. Write a program using arrays to implement STACKas an array. The Program must be written using

classes and objects and it must contain the following functions:i) push( )- to insert new element in stack ii) pop( ) to delete an element from the stack

iii) display() to display the element of stack.

Solution://PROGRAM TO IMPLEMENT THE STACK//

#include //inputs the header files

#include #include

class stk //begin of class

{

public:int arr[100];

int r;

stk() //constructor

{r=-1;

}void push(int);

void pop();

void display();

}; //end of class

void stk::push(int n)

{if (r>98)

{cout


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void stk::display()

{

if (r==-1){

cout


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4.Exit

Enter Choice: 1

Enter No. to insert in Stack 11

1.Insert

2.Delete3.Display

4.Exit

Enter Choice: 1

Enter No. to insert in Stack 22

1.Insert

2.Delete

3.Display

4.ExitEnter Choice: 2

No. deleted is 22

1.Insert

2.Delete3.Display

4.Exit

Enter Choice: 3

11

1.Insert2.Delete

3.Display4.ExitEnter Choice: 4

Q22. Write a program using arrays to implement QUEUE as an array. The Program must be written using

classes and objects and it must contain the following functions:

i) push( )- to insert new element in queue ii) pop( ) to delete an element from the queueiii) display() to display the element of queue.

Solution:

//PROGRAM TO IMPLEMENT THE QUEUE//#include //inputs the header files

#include

#include class que //begin of class

{

public:

int arr[100];int r;

que() //constructor

{


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r=-1;

}

void push(int);

void pop();void display();

}; //end of class

void que::push(int n)

{

if (r>98){

cout


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void main() //begin of main function

{

int ch,n;

clrscr();que ob;

while(1)

{cout


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4.Exit

Enter Choice: 2

No. deleted is 111.Insert

2.Delete

3.Display4.Exit

Enter Choice: 3

221.Insert

2.Delete

3.Display4.Exit

Enter Choice: 4

Q23. Write a program using arrays to implement CIRCULAR QUEUE as an array. The Program must bewritten using classes and objects and it must contain the following functions:

i) push( )- to insert new element in circular queue ii) pop( ) to delete an element from the queue iii)

display() to display the element of circular queue.

Solution://PROGRAM TO IMPLEMENT THE CIRCULAR QUEUE//

#include //inputs the header files#include

#include

class cirque //begin of class

{public:

int arr[100];

int front,rear,size;cirque(int s)

{front=-1;rear=-1;

size=s;

}

void insert (int);void del();

void display();

}; //end of class

void cirque::insert(int n)

{if ((front==0 && rear==size-1)||(front==rear+1))

{

cout


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else

rear++;

arr[rear]=n;

}

void cirque::del()

{ int i;if (front==-1)

{

cout


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}

void main() //begin of main function

{int ch,n;

clrscr();

cirque ob(5);while(1)

{

cout


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2.Delete

3.Display

4.Exit

Enter Choice: 2

No. deleted is 11

1.Insert2.Delete

3.Display

4.ExitEnter Choice: 3

22

1.Insert2.Delete

3.Display

4.Exit

Enter Choice: 4

Q24. An array of structure stores details of 10 students (rno, name, marks in three subjects) Write a program

to create such an array and print out a list of students who have failed in more than one subject.(Max. Marks

=100, Passing Marks =33)Solution:

//Array of Structures#include

#include

#include

#includestruct Student

{

long RollNo;char Name[20];

int m1,m2,m3;};

void main()

{

clrscr();Student x[10];

int i,c;

for(i=0;i


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if(x[i].m1


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return(s);

}

void main()

{double X,ans;

int n;

clrscr();coutX>>n;

ans=SUMFUN(X,n);cout


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SQL> insert into BOOKS values('L02','Science','Agarkar','DEF',90,15);

1 row created.

SQL>insert into BOOKS values('L03','Social','Suresh','XYZ',85,30);

1 row created.SQL> insert into BOOKS values('L04','Computer','Sumita','ABC',75,7);

1 row created.

SQL> insert into BOOKS values('L05','Telegu','Nannayya','DEF',60,25);1 row created.

SQL> insert into BOOKS values('L06','English','Wordworth','DEF',55,12);

1 row created.

SQL> create table ISSUES(Book_ID varchar2(3),Qty_Issued number(2));

Table created.

SQL> insert into ISSUES values('L02',13);

1 row created.

SQL> insert into ISSUES values('L04',5);1 row created.

SQL> insert into ISSUES values('L05',21);

1 row created.

(i) SQL>select BookName,AuthorName,Price from BOOKS where Publisher='ABC';

BOOKNAME AUTHORNAME PRICE--------------- -------------------- ----------

Maths Raman 70

Computer Sumita 75

(ii) SQL> select * from BOOKS order by price desc;

BOO BOOKNAME AUTHORNAME PUBLISHER PRICE QTY

--- --------------- -------------------- --------------- ---------- ----------L02 Science Agarkar DEF 90 15

L03 Social Suresh XYZ 85 30L04 Computer Sumita ABC 75 7L01 Maths Raman ABC 70 20

L05 Telegu Nannayya DEF 60 25

L06 English Wordworth DEF 55 12

6 rows selected.

(iii) SQL> update ISSUES set Qty_Issued=Qty_Issued-3;

3 rows updated.

(iv) SQL>select BOOKS.Book_Id,BookName,Publisher,Price,Qty,Qty_Issued from BOOKS,ISSUES

where BOOKS.Book_Id=ISSUES.Book_IDBOO BOOKNAME PUBLISHER PRICE QTY QTY_ISSUED

--- --------------- --------------- ---------- ---------- ----------

L02 Science DEF 90 15 10L04 Computer ABC 75 7 2

L05 Telegu DEF 60 25 18

(v) SQL> select sum(price) from Books where Publisher='DEF';SUM(PRICE)

----------

205


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(vi) SQL> select Publisher,min(Price) from Books GROUP BY Publisher;

PUBLISHER MIN(PRICE)

--------------- ----------

ABC 70DEF 55

XYZ 85

(vii) SQL> select price from Books,Issues where Books.Book_ID=Issues.Book_ID AND Qty_Issued=5;

no rows selected

(viii) SQL> select count(Distinct Publisher) from Books;

COUNT(DISTINCTPUBLISHER)

------------------------3

Q2. Consider the following tables EMPLOYEES and EMPSALARY. Write SQL commands for the statement

(i) to (iv) and give outputs for SQL queries (v) to (viii).

EMPLOYEES

EMPID FIRSTNAME LASTNAME ADDRESS CITY

010 George Smith 83, First Street Howard

105 Mary Jones 842 Vine Ave Losantiville

152 Sam Tones 33 Elm St. Paris215 Sarah Ackerman 440 U.S. 110 Upton

244 Manila Sengupta 24 Friends Street New Delhi

300 Robert Samuel 9 Fifth Cross Washington

335 Henry Williams 12 Moore Street Boston

400 Rachel Lee 121 Harrison St. New York

441 Peter Thompson 11 Red Road Paris

EMPSALARY

EMPID SALARY BENEFIT DESIGNATION

010 75000 15000 Manager

105 65000 15000 Manager

152 80000 25000 Director

215 75000 12500 Manager

244 50000 12000 Clerk

300 45000 10000 Clerk

335 40000 10000 Clerk

400 32000 7500 Salesman

441 28000 7500 Salesman

(i) To display Firstname, Lastname, Address and City of all employees living in Paris from the table

EMPLOYEES.

(ii) To display the contents of EMPLOYEES table in descending Order of FIRSTNAME.(iii) To display the Firstname, Lastname and Toatal salary of all Managers from the tables EMPLOYEES an

EMPSALARY, where Total salary is calculated as Salary+Benefits.

(iv) To display the Minimum salary among Managers and Clerks from the table EMPSALARY.(v) SELECT FIRSTNAME,SALARY FROM EMPLOYEES, EMPSALARY wher

DESIGNATION=Salesman AND EMPLOYEES.EMPID=EMPSALARY.EMPID;

(vi) SELECT COUNT(DISTINCT DESIGNATION) FROM EMPSALARY;

(vii) SELECT DESIGNATION,SUM(SALARY) FROM EMPSALARY GROUP BY DESIGNATIONHAVING COUNT(*)>2;

(viii) SELECT SUM(BENEFIT) FROM EMPLOYEES WHERE DESIGNATION=Clerk;


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Solution:SQL> create table EMPLOYEES(EMPID NUMBER(3),FIRSTNAME VARCHAR2(10),LASTNAMEVARCHAR2(10),ADDRESS VARCHAR2(25),CITY VARCHAR2(15));

Table created.

SQL> INSERT INTO EMPLOYEES VALUES(010,'George','Smith','83,First Street','Howard');

1 row created.

SQL> INSERT INTO EMPLOYEES VALUES(105,'Mary','Jones','842, Vine Ave','Losantiville');1 row created.SQL> INSERT INTO EMPLOYEES VALUES(152,'Sam','Tones','33elm St.','Paris');

1 row created.

SQL> INSERT INTO EMPLOYEES VALUES(215,'Sarah','Ackerman','440 U.S. 110','Upton');1 row created.

SQL> INSERT INTO EMPLOYEES VALUES(244,'Manila','Sengupta','24 Friends Street','New Delhi');

1 row created.SQL> INSERT INTO EMPLOYEES VALUES(300,'Robert','Samuel','9 Fifth Cross','Washington');

1 row created.

SQL> INSERT INTO EMPLOYEES VALUES(335,'Henry','Williams','12 Moore Street','Boston');

1 row created.SQL> INSERT INTO EMPLOYEES VALUES(400,'Rachel','Lee','121 Harrison St.','New York');

1 row created.

SQL> INSERT INTO EMPLOYEES VALUES(441,'Peter','thompson','11 Red Road','Paris');1 row created.

SQL> create table EMPSALARY(EMPID number(3),salary number(5),benefit number(5), designationvarchar2(10));

Table created.

SQL> insert into empsalary values(010,75000,15000,'Manager');

1 row created.SQL> insert into empsalary values(105,65000,15000,'Manager');

1 row created.SQL> insert into empsalary values(152,80000,25000,'Director');

1 row created.

SQL> insert into empsalary values(215,75000,12500,'Manager');1 row created.

SQL> insert into empsalary values(244,50000,12000,'Clerk');

1 row created.SQL> insert into empsalary values(300,45000,10000,'Clerk');

1 row created.

SQL> insert into empsalary values(335,40000,10000,'Clerk');1 row created.

SQL> insert into empsalary values(400,32000,7500,'Salesman');

1 row created.

SQL> insert into empsalary values(441,28000,7500,'Salesman');1 row created.

(i) SQL> select firstname,lastname,address,city from employees where city='Paris';FIRSTNAME LASTNAME ADDRESS CITY

---------- ---------- ------------------------- ---------------

Sam Tones 33elm St. Paris


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Peter thompson 11 Red Road Paris

(ii) SQL> select * from employees order by firstname;EMPID FIRSTNAME LASTNAME ADDRESS CITY

---------- ---------- ---------- ------------------------- ---------------

10 George Smith 83,First Street Howard335 Henry Williams 12 Moore Street Boston

244 Manila Sengupta 24 Friends Street New Delhi

105 Mary Jones 842, Vine Ave Losantiville441 Peter thompson 11 Red Road Paris

400 Rachel Lee 121 Harrison St. New York

300 Robert Samuel 9 Fifth Cross Washington152 Sam Tones 33elm St. Paris

215 Sarah Ackerman 440 U.S. 110 Upton

9 rows selected.

(iii) SQL> select firstname,lastname, salary+benefit "Tot. sal" from employees E,empsalary S where

E.Empid=S.Empid AND designation ='Manager';

FIRSTNAME LASTNAME Tot. sal

---------- ---------- ----------George Smith 90000

Mary Jones 80000Sarah Ackerman 87500

(iv) SQL> select designation,min(salary) from empsalary group by designation having designation = 'Manager

or designation='Clerk';DESIGNATIO MIN(SALARY)

---------- -----------

Clerk 40000Manager 65000

(v) SQL>SELECT FIRSTNAME,SALARY FROM EMPLOYEES, EMPSALARY where DESIGNATION='Salesman' AND EMPLOYEES.EMPID=EMPSALARY.EMPID;

FIRSTNAME SALARY

---------- ----------

Rachel 32000Peter 28000

(vi) SQL> SELECT COUNT(DISTINCT DESIGNATION) FROM EMPSALARY;COUNT(DISTINCTDESIGNATION)

--------------------------

4

(vii) SQL> SELECT DESIGNATION,SUM(SALARY) FROM EMPSALARY GROUP BY DESIGNATION

HAVING COUNT(*)>2;DESIGNATIO SUM(SALARY)

---------- -----------

Clerk 135000

Manager 215000

(viii) SQL> SELECT SUM(BENEFIT) FROM EMPLOYEES WHERE DESIGNATION='Clerk';

SELECT SUM(BENEFIT) FROM EMPLOYEES WHERE DESIGNATION='Clerk'


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*

ERROR at line 1:

ORA-00904: invalid column name

Q3. Study the following tables FLIGHTS and FARES and write SQL commands for the questions (i) to (iv)

and give outputs for SQL queries (v) to (vi).

TABLE : FLIGHTS

FL_NO STARTING ENDING NO_FLIGHTS NO STOPS

IC301 MUMBAI DELHI 8 0

IC799 BANGALORE DELHI 2 1

MC101 INDORE MUMBAI 3 0

IC302 DELHI MUMBAI 8 0

AM812 KANPUR BANGALORE 3 1IC899 MUMBAI KOCHI 1 4

AM501 DELHI TRIVANDRUM 1 5

MU499 MUMBAI MADRAS 3 3

IC701 DELHI AHMEDABAD 4 0

TABLE : FARES

FL_NO AIRLINES FARE TAX%

1C701 Indian Airlines 6500 10

MU499 Sahara 9400 5

AM501 Jet Airways 13450 8

IC899 Indian Airlines 8300 4



MC101 Deccan Airlines 3500 4

i. Display FL_NO and NO_FLIGHTS from KANPUR to BANGALORE from the table FLIGHTS.

ii. Arrange the contents of the table FLIGHTS in the ascending order of FL_NO.

iii. Display the FLNO and fare to be paid for the flights from DELHI to MUMBAI using the tablesFLIGHTS and FARES, where the fare to be paid = FARE +FARE*TAX%/100.

iv. Display the minimum fare Indian Airlines is offering from the table FARES.

v. SELECT FL_NO, NO_FLIGHTS, AIRLINES from FLIGHTS, FARES where STARTING=DELHI

and FLIGHTS.FL_NO=FARES.FL_NO.vi. SELECT count (distinct ENDING) from FLIGHTS.


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Q4. Consider the following tables.

Write SQL commands for the statements (i) to (iv) and give outputs for SQL queries

(v) to (viii)

(i) To display the names of all Senders from Mumbai.

(ii) To display the RecID), SenderName, SenderAddress, RecName, RecAddress for every Recipient.

(iii) To display Recipient details in ascending order of RecName.(iv) To display number of Recipients from each city.

(v) SELECT DISTINCT SenderCity FROM Sender;

(vi) SELECT A. SenderName, B.RecName FROM Sender A, Recipient B WHERE A.SenderlD =

B.SenderlD AND B.RecCity = Mumbai;(vii) SELECT RecName, RecAddress FROM Recipient WHERE RecCity NOT IN (Mumbai, Kolkata);

(viii) SELECT RecID , RecName FROM Recipient WHERE SenderID = MU02' ORSenderID=ND50';

Q5. Consider the following tables Consignors and Consignee. Write SQL commands for

the statements (i) to (iv) and give outputs for SQL queries (v) to (viii).TABLE : CONSIGNORS


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(i) To display the names of all Consignors from Mumbai.(ii) To display the CneelD, CnorName, CnorAddress, CneeName, CneeAddress for every Consignee.

(iii) To display consignee details in ascending order of CneeName.

(iv) To display number of consignors from each city,(v) SELECT DISTINCT City FROM CONSIGNEE;

(vi) SELECT A.CnorName, B.CneeName FROM Consignors A, Consignee B WHERE A.CnorID = B.CnorlD

AND B.CneeCity = Mumbai;

(vii) SELECT CneeName, CneeAddress FROM Consignee WHERE CneeCity NOT IN (Mumbai,Kolkata);

(viii) SELECT CNEEID,CNEENAME FROM CONSIGNEE WHERE CNORID='MU15' OR

CNORID='ND01';

Solution:SQL> CREATE TABLE CONSIGNORS(CnorID char(4),CnorName varchar2(15),CnorAddress

varchar2(20),City varchar2(15));Table created.

SQL> insert into consignors values('ND01','R Singhal','24, ABC Enclave','New Delhi');

1 row created.

SQL>insert into consignors values('ND02','Amit Kumar','123,PalmAvenue','New Delhi');

1 row created.SQL> insert into consignors values('MU15','R Kohli','5/A,South Street','Mumbai');

1 row created.

SQL>insert into consignors values('MU50','S Kaur','27-K,Westend','Mumbai');1 row created.

SQL> create table consignee(CneeID char(4),CnorID char(4),CneeName varchar2(15),CneeAddressvarchar2(20),CneeCity varchar2(15));

Table created.

SQL> insert into consignee values('MU05','ND01','Rahul Kishore','5,ParkAvenue','Mumbai');1 row created.

SQL> insert into consignee values('ND08','ND02','P Dhingra','16/J, Moore Enclave','New Delhi');

1 row created.SQL> insert into consignee values('KO19','MU15','A P Roy','2A, Central Avenue','Kolkata');


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1 row created.

SQL> insert into consignee values('MU32','ND02','S Mittal','P245,AB Colony','Mumbai');

1 row created.

SQL> insert into consignee values('ND48','MU50','B P Jain','13, Block D,A Vihar','New Delhi');1 row created.

(i) SQL> select CnorName from Consignors where city='Mumbai';CNORNAME

---------------

R KohliS Kaur

(ii) SQL> select CneeID,CnorName,CnorAddress,CneeName,CneeAddress from Consignors C, Consignee Ewhere C.CnorID=E.CnorID;

CNEE CNORNAME CNORADDRESS CNEENAME CNEEADDRESS

---- --------------- -------------------- --------------- --------------------

KO19 R Kohli 5/A,South Street A P Roy 2A, Central Avenue ND48 S Kaur 27-K,Westend B P Jain 13, Block D,A Vihar

MU05 R Singhal 24, ABC Enclave Rahul Kishore 5,ParkAvenue

ND08 Amit Kumar 123,PalmAvenue P Dhingra 16/J, Moore Enclave

MU32 Amit Kumar 123,PalmAvenue S Mittal P245,AB Colony

(iii) SQL> select * from consignee order by CneeName;CNEE CNOR CNEENAME CNEEADDRESS CNEECITY

---- ---- --------------- -------------------- ---------------

KO19 MU15 A P Roy 2A, Central Avenue Kolkata

ND48 MU50 B P Jain 13, Block D,A Vihar New Delhi ND08 ND02 P Dhingra 16/J, Moore Enclave New Delhi

MU05 ND01 Rahul Kishore 5,ParkAvenue Mumbai

MU32 ND02 S Mittal P245,AB Colony Mumbai

(iv) SQL>select city, count(*) from consignors group by city;CITY COUNT(*)--------------- ----------

Mumbai 2

New Delhi 2

(v) SQL> SELECT DISTINCT City FROM CONSIGNEE;

SELECT DISTINCT City FROM CONSIGNEE

*ERROR at line 1:

ORA-00904: invalid column name

SQL> SELECT DISTINCT CNEECITY FROM CONSIGNEE;

CNEECITY

---------------Kolkata

Mumbai

New Delhi

(vi) SQL>SELECT A.CNORNAME, B.CNEENAME FROM Consignors A, Consignee B WHERE

A.CNORID= B.CNORID AND B.CNEECITY = 'Mumbai';

CNORNAME CNEENAME


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--------------- ---------------

R Singhal Rahul Kishore

Amit Kumar S Mittal

SQL> SELECT A.CnorName, B.CneeName FROM Consignors A, Consignee B WHERE A.CnorID =

B.CnorlD AND B.CneeCity = 'Mumbai';

SELECT A.CnorName, B.CneeName FROM Consignors A, Consignee B WHERE A.CnorID = B.CnorlDAND B.CneeCity = 'Mumbai'

*

ERROR at line 1:ORA-00904: invalid column name

(vii) SQL> SELECT CneeName, CneeAddress FROM Consignee WHERE CneeCity NOT IN ('Mumbai','Kolkata');

CNEENAME CNEEADDRESS

--------------- --------------------

P Dhingra 16/J, Moore EnclaveB P Jain 13, Block D,A Vihar

(viii) SQL> SELECT CNEEID,CNEENAME FROM CONSIGNEE WHERE CNORID='MU15' OR

CNORID='ND01';CNEE CNEENAME

---- ---------------MU05 Rahul Kishore

KO19 A P Roy

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