mamta verulkar[1]
TRANSCRIPT
Presented by:
Mrs.Mamta Verulkar
Vimaltai Tidke convent & Jr. College, Beltarodi ,
Nagpur
04/18/23 1India's Contribution to Geometry
• Mathematics is the science of structure, order and relation that develops gradually from basic practice of counting, measuring and describing the shapes of objects.
04/18/23 2India's Contribution to Geometry
Geometrical Proof
• A Geometrical proof involves writing reasoned, logical explanations that use definitions, axioms, postulates and previously proved theorems to arrive at a conclusion about a geometric statement.
04/18/23 3India's Contribution to Geometry
Square Root of 2
• The oldest value of square root of 2 is obtained from Babylonian times (1600 B.C.)
• The sexagesimal equivalent value of square root of 2 as given in the Sulvasutra is 1.24, 51, 10, 37
04/18/23 4India's Contribution to Geometry
Proof• Construct ABC such that
• AB = BC = n • AC = m, B =
•
Suppose m and n are integers
• Let us assume that m:n is the ratio in its lowest term.
A
B C
m
n
04/18/23 5India's Contribution to Geometry
n
900
n
m
AB
AC
2n
m
Draw arcs of lengths m and n with centre A
AB = AD AC = AE
• BAC and DAE coincide• ABC ADE by S.A.S. test
04/18/23 India's Contribution to Geometry 6
EBF =
04/18/23 India's Contribution to Geometry 7
090(Right angle)
BEF = = is half of right angle
BEF is right isosceles triangle.
045
Hence BE = m – n
BF = m – n
• DF = m – n• Then FDC is also right
Isosceles triangle
• FC = n – ( m – n )
= 2n - m
04/18/23 India's Contribution to Geometry 8
EBF CDF
ABC & FDC are similar
04/18/23 India's Contribution to Geometry 9
FC
AC
FD
AB
FD
FC
AB
AC
nm
mn
n
m
2
But triangle ABC is bigger in size than FDC
i.e m > 2n-m
n > m-n
But assumption is is in lowest form.
i.e is also in
lowest form
04/18/23 India's Contribution to Geometry 10
n
m
nm
mn
2
• i.e m and n have common
integral factors but it
contradicts the assumption
m:n is in lowest form.
• Therefore cannot be
expressed in form (rational
form) hence is irrational.
04/18/23 India's Contribution to Geometry 11
2n
m
2
Dutta B.B. (1932)Consider two squares whose sides are of unit length.
Divide the second square into three equal stripes I, II an III.
04/18/23 12India's Contribution to Geometry
III III
• Sub-divide the last
strip into three small squares III1, III2, III3 of
sides ⅓rd each.
04/18/23 India's Contribution to Geometry 01
III2
III1
III3
III III
III1
• Then on placing I,
II and III1 about
the first square S
in the position I’,
II’ and III1’ a new
square is formed.
04/18/23 India's Contribution to Geometry 01
I
II III1
Now divide each of the portions III2 and III3 into four equal stripes.
04/18/23 15India's Contribution to Geometry
Arrange four parts of III2,III3 as shown in figure
• Introducing a small square at the south-east corner, a large square will be formed.
04/18/23 India's Contribution to Geometry 16
)4)(3(
1
3
11
Each side of which is equal to
04/18/23 India's Contribution to Geometry 17
In order to get the
equivalent area remove
two thin stripes , say of
width x from either side
of the square.
04/18/23 India's Contribution to Geometry 18
22
)4)(3(
1
)4)(3(
1
3
112
xx
Neglecting x2 as to small
2
)4)(3(
1
12
172
x
)34)(4)(3(
1
2
1
17
12
)4)(3(
12
x
2
6271.41421568
)34)(4)(3(
1
)4)(3(
1
3
11
Side of a square after subtracting x
• In decimal form this value equals 1.41421568627
Today’s value of is 1.41421356237,a difference of
0.000021239
04/18/23 India's Contribution to Geometry 19
2
References• Book by Saraswati Amma.• Ganit Kaumidi (Mathematics book)• www.cut-the-knot.orgproofs/sq_root.shtml• httphttp://www.math.ubc.ca/~• http://www.math.ubc.ca/~cass/courses/
m309-0l1a/kong/sulbasutra_geometry.htm• Guided by Professor DR.Anant Vyawhare.
04/18/23 India's Contribution to Geometry 01