may the flux be with you
DESCRIPTION
May the flux be with you. Is that the finger???. Gauss’s Law 3.2. Happenings. Wednesday – You should be finished with the Electric Field and today we start Gauss’s Law Friday – Yup, more Gauss and, oh yes, a QUIZ! Watch for a new WA on Gauss to appear suddenly. - PowerPoint PPT PresentationTRANSCRIPT
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MAY THE FLUX BE WITH YOU
Gauss’s Law3.2
Is that the finger???
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Happenings Wednesday – You should be finished with
the Electric Field and today we start Gauss’s Law
Friday – Yup, more Gauss and, oh yes, a QUIZ! Watch for a new WA on Gauss to appear
suddenly.
Monday … Gauss should be history so on to new stuff. (Sorry)
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What is the electric field at the center of the square array?
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A rigid electric dipole is free to move in the electric field represented in the figure.Which one of the following phrases most accurately describes the initial motion of the dipole if it is released from rest in the position shown?
A) It moves to the left.B) It moves to the right.C) It does not move at all.D) It moves toward to the top of the page.E) It moves toward the bottom of the page.
A Bit Tricky!
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Consider the drawing, where the solid lines with arrows represent the electric field due to the charged object. An electron is placed at the point P and released at rest. Which of the following vectors represents the direction of the force, if any, on the electron?
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Which One Of These Is Possible?
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Gauss’s Law
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Let’s ask some questions of ourselves
Given a distribution of charges can we figure out the Electric Field at a point in space? Yes … just add the effects of each charge (kq/d2)
OK. How about the other direction – can we determine the distribution of charges if we know the Electric Field at a number of places. Sometimes. This is the topic that Gauss
addressed and his answer, a mathematical theorem, is quite important in solving a certain class of problems.
Let’s take a look…..
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Last time We can use a vector to represent a small
flat area: It’s length is proportional to the area. Its direction is perpendicular to the area The area need not be square, round or
anything else. It must be small. Very small. Teeny Tiny small.
There is an ambiguity in which of two ways the vector can point for a particular small area.
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What would you guess is inside the cube?
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What about now?
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How about this??
A. Positive point charge
B. Negative point charge
C. Large Sheet of charge
D. No chargeE. You can’t tell from
this
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FLUXHow Much Stuff Is There?
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An object entering a solid region is the same thing as a negative object leaving!
Think about this…..
A Strange Statement
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Sphere
Light Bulb EmittingN Photons per sec.
How many photons leave the sphere each
second?
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Sphere
Light Bulb EmittingN Photons per sec.
How many photons leave the sphere each
second?
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Sphere
Light Bulb EmittingN Photons per sec.
How many photons leave the sphere each
second?
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This was a brief intro to Gauss’s Law. Now ..
START YOUR UNITS (on G’s Law …)